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CHAPTER 4-cost

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solution manual cost accounting chapter 4

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CHAPTER 4Multiple Choices Computational1. b 6. b2. b 7. c3. b . b4. b !. a". b 1#. AMultiple Choices Computational1. $a% Cost ofDate of Issue Purchase LotUnits x Cost Materials Issued 5/155/515 x P20= P300 5/19BI 10 x P15= 150 5/305/5 & 5/24 (5 x P20) + (10 x P18)= 280P730En&in' in(ento)*+" $,)om "-24 pu)chase% . P1/P!#2. (a)(10 x P15)+(20 x P20)+(15 x P18) =P18.22245Cost of materias iss!e"#40xP18.222=P729.88En&in' in(ento)*+".P1.222/P!1.113. $a% Cost ofDate Units Unit Cost Materials IssuedBI 10P15P1505/5 20204005/24 101818040P73#4. $c% Pu)chases0ssue& 1alanceUnit Unit Total Unit TotalDate Units Cost Units Cost Cost Units Cost CostBI 10 P15 $ $ $ 10 P15.000 P150.005/5 2020 $ $ $ 30 18.333(a) 550.005/15 $ $ 15 P18.333 P275.00 15 18.333 275.005/19 $ $ 10 18.333 183.33 5 18.333 91.%75/24 1518 $ $ $ 20 18.085(&) 3%1.%85/30 $ $ 1518.084271.2% 5 18.084 !#.42(a) (10 x P15)+(20 x P20) / 30= P18.333(&) (5 x P18.333)+(15 x P18)/20 = P18.0841". $a%Pu)chases0ssue&1alanceDate UnitsUnitCost UnitsUnitCostTotalCost UnitsUnitCost TotalBI 10 P15 $ $ $ 10 P15 P1505/5 2020 $ $ $ 30 (a) 5505/15 $ $ 15 P20 P300 15 (&) 2505/19 $ $ 10 (') 175 5 15 755/24 1518 $ $ $ 20 (") 3455/30 $ $ 15 18 270 5 15 P7"(a) (10 x P15)+(20 x P20) = P550(&) (10 x P15)+(5xP20) = P250(') (5xP20)+(5xP15) = P175(") (5xP15)+(15 x P18) = P3456. $&%Pu)chases 0ssue& 1alanceDate Units Price Amount Units Price Amount Units PriceAmount1/1 $ $ $ $ $ $ 2(000 9.775 19(5501/% 1(500 10.300 15(450 $ $ $ 3(500 10.000(a) 35(0001/7 $ $ $ 1(800 10.000 18(000 1(700 10.000 17(0001/2% 3(400 10.750 3%(550 $ $ $ 5(100 10.500(&) 53(5501/31 $ $ $ 3(200 10.500 33(%00 1(900 10.500 1!2!"#(a) (P19(550+P15(450) /(2(000+1(500)= P10.000(&) (P17(000+P3%(550)/ (1(700+3(400)= P10.5007. $c%P19(550+P15(450+P3%(550x1(900=P1!27#2%(900. $a%Recei(e& 0ssue& 1alanceBaa)'e 480xP4.80=P2(304P*30 %00xP4.90=P2(940 480xP4.80=P2(304%00xP4.90=P2(940+4% 175xP4.80=P 840 305xP4.80=P1(4%4%00xP4.90=P2(940+49 225xP4.80=P1(080 80xP4.80=P 384%00xP4.90=P2(940+50 80xP4.80=P 384200xP4.90=P 980 400xP4.90=P1(9%0P*9% 400xP4.95=P1(980 400xP4.90=P1(9%0400xP4.95=P1(980+52 310xP4.90=P1(519 90xP4.90=P 441400xP4.95=P1(980+,24 (20)xP4.90=(P98) 110xP4.90 )400xP4.95 %/P22"1!2!. $a%Recei(e& 0ssue& 1alance 3Baa)'e480xP4.80=P2(304.00P*30 %00xP4.90=P2(940 1(080xP4.85%=P5(244.48+4% 175xP4.85%=P 849.80905xP4.85%=P4(394.%8+49 225xP4.85%=P1(092.%0%80xP4.85%=P3(302.08+50 280xP4.85%=P1(359.%8400xP4.85%=P1(942.40P*9% 400xP4.95=P1(980800xP4.903=P3(922.40+52 310xP4.903= P1(519.93490xP4.903=P2(402.47+,24 (20)xP4.85%=P 97.12 510xP4.901=P224!!."!* Answers may vary due to rounding.1#. $a%Mate)ial 4uantit* Cost 5R6 6aluation-- 4%0 P140 P130 P 59(800BB 830 85 9070(550CC 1(290 120 145 154(800.. 580 %5 55 31(900P317(05011. $&%Mate)ials Cost5R6-- P%4(400 P59(800BB 70(550 74(700CC 154(800 187(050.. 37(700 31(900P32724"# P353(450Since cost is lower, use P327,450 as the inventory valuation12. $a%Mate)ials 4uantit* Cost 5R6 Total Cost Total 5R6/ro!0 I -- 4%0 P140 P130 P%4(400 P59(800 BB 830 85 90 70(550 74(700 1ota P134(950 P134(500/ro!0 II CC 1(290 120 145 P154(800 P180(500 .. 580 %5 55 37(700 31(900 1ota P192(500 P218(950!aluation Summary1asis 6aluation/ro!0 I 2+3 P134(500/ro!0 II Cost 192(5000n(ento)* 6aluation P3272###313. $b%4i)is5e" 6oo"s( ,a7 1( 2010 P129(%40Cost of 6oo"s ma)!fa't!re" 395(4401ota 'ost of 6oo"s a8aia&e525(0804i)is5e" 6oo"s( ,a7 31 (142(840)9oss o) i)8e)tor7 :rite$"o:)9(740Cost o, 'oo&s sol& P3!12!#14. $a%4i)is5e" 6oo"s( ;!)e 1 P290(540Cost 6oo"s ma)!fa't!re" 805(8201ota 'ost of 6oo"s a8aia&e1(09%(3%04i)is5e" 6oo"s( ;!)e 30( 27%(7%0)+e'o8er7 from I)8e)tor7 :rite$"o:)( 10(720)Cost o, 'oo&s sol& P#2#1". $a%Cost P 110(4922+3 (P134(315$P2%(855)107(4%0I)8e)tor7 :rite$"o:) P 3(03216. $a%Baa)'e of -o:. for I)8e)tor7