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Chapter 4 The Composition of Solutions

Chapter 4 The Composition of Solutions Expressing Solubility M = Molarity = moles solute / liters of solution

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Chapter 4

Chapter 4The Composition of Solutions

The Composition of Solutions

Expressing Solubility

M = Molarity = moles solute / liters of solution

Ex - Calculate the molarity of a solution made by dissolving 23.4 g Na2SO4 in enough water to form 125 mL of solution.

Ex - What are the concentrations of each ion in the last example?

Ex - How many grams of Na2SO4 are required to make 0.350 L of 0.500 M Na2SO4

A solution of precisely known concentration is called a standard solution.Standard solutions can be made 2 ways:from the solid - the solute is added to the flask and water is added to the line on the flaskby dilution - a solution is added to the flask and water is added to further dilute the solution

For dilution: moles of solute before dilution = moles of solute after dilution.M1V1 = M2V2Ex - How much 3.0 M H2SO4 would be required to make 500 mL of 0.10 M H2SO4?

Click here to take the quiz or here is the link:

https://docs.google.com/spreadsheet/embeddedform?formkey=dE9GUm1KOEpmUmt5QVZreXg5N3NNYXc6MQ