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Chapter 4
Chapter 4The Composition of Solutions
The Composition of Solutions
Expressing Solubility
M = Molarity = moles solute / liters of solution
Ex - Calculate the molarity of a solution made by dissolving 23.4 g Na2SO4 in enough water to form 125 mL of solution.
Ex - What are the concentrations of each ion in the last example?
Ex - How many grams of Na2SO4 are required to make 0.350 L of 0.500 M Na2SO4
A solution of precisely known concentration is called a standard solution.Standard solutions can be made 2 ways:from the solid - the solute is added to the flask and water is added to the line on the flaskby dilution - a solution is added to the flask and water is added to further dilute the solution
For dilution: moles of solute before dilution = moles of solute after dilution.M1V1 = M2V2Ex - How much 3.0 M H2SO4 would be required to make 500 mL of 0.10 M H2SO4?
Click here to take the quiz or here is the link:
https://docs.google.com/spreadsheet/embeddedform?formkey=dE9GUm1KOEpmUmt5QVZreXg5N3NNYXc6MQ