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Copyright © 2010 Pearson Education, Inc. Chapter 5 Newton’s Laws of Motion

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Copyright © 2010 Pearson Education, Inc.

Chapter 5

Newton’s Laws of Motion

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Units of Chapter 5• Force and Mass

• Newton’s First Law of Motion

• Newton’s Second Law of Motion

• Newton’s Third Law of Motion

• The Vector Nature of Forces: Forcesin Two Dimensions

• Weight

• Normal Forces

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5-1 Force and Mass

Force: push or pull

Force is a vector – it has magnitude anddirection

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5-1 Force and Mass

Mass is the measure ofhow hard it is tochange an object’svelocity.

Mass can also bethought of as ameasure of the quantityof matter in an object.

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5-2 Newton’s First Law of Motion

If you stop pushing an object, does it stopmoving?

Only if there is friction! In the absence of anynet external force, an object will keep movingat a constant speed in a straight line, orremain at rest.

This is also known as the law of inertia.

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In order to change the velocity of anobject – magnitude or direction – a netforce is required.

An inertial reference frame is one inwhich the first law is true. Acceleratingreference frames are not inertial.

5-2 Newton’s First Law of Motion

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5-3 Newton’s Second Law of MotionTwo equal weights exert twice the force of one;this can be used for calibration of a spring:

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5-3 Newton’s Second Law of Motion

Now that we have a calibrated spring, we can domore experiments.

Acceleration is proportional to force:

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5-3 Newton’s Second Law of Motion

Acceleration is inversely proportional to mass:

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5-3 Newton’s Second Law of Motion

Combining these two observations gives

Or, more familiarly,

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5-3 Newton’s Second Law of Motion

An object may have several forces acting on it;the acceleration is due to the net force:

(5-1)

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5-3 Newton’s Second Law of Motion

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5-6 Weight

The weight of an object on the Earth’s surfaceis the gravitational force exerted on it by theEarth.

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5-3 Newton’s Second Law of Motion

Free-body diagrams:

A free-body diagram shows every force actingon an object.

• Sketch the forces

• Isolate the object of interest

• Choose a convenient coordinate system

• Resolve the forces into components

• Apply Newton’s second law to eachcoordinate direction

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Free Body Diagrams:

•Must be drawn for problems when forces are involved.

•Must be large so that they are readable.

•Draw an idealization of the body in question (a dot, abox,…). You will need one free body diagram for eachbody in the problem that will provide useful information foryou to solve the given problem.

•Indicate only the forces acting on the body. Label theforces appropriately. Do not include the forces that thisbody exerts on any other body.

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Free Body Diagrams (continued):

•A coordinate system is a must.

•Do not include fictitious forces. Remember that ma is itselfnot a force!

•You may indicate the direction of the body’s acceleration ordirection of motion if you wish, but it must be done well off tothe side of the free body diagram.

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5-3 Newton’s Second Law of MotionExample of a free-body diagram:

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5-4 Newton’s Third Law of Motion

Forces always come in pairs, acting ondifferent objects:

If object 1 exerts a force on object 2, thenobject 2 exerts a force – on object 1.

These forces are called action-reaction pairs.

Fr

Fr

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5-4 Newton’s Third Law of Motion

Some action-reaction pairs:

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Example: Consider a box resting on a table.

F1

(a) F1 is the force of the Earth onthe box, what is the interactionpartner of this force?

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F2(b) F2 is the force of the box on thetable, what is the interaction partnerof this force?

Example continued:

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External forces:

Any force on a system from a body outside of the system.

FPulling a boxacross the floor

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Internal forces:

Force between bodies of a system.

Fext

Pulling 2 boxes across the floorwhere the two boxes are attachedto each other by a rope.

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Example: Find the tension in the cord connecting the twoblocks as shown. A force of 10.0 N is applied to the right onblock 1. Assume a frictionless surface. The masses are m1= 3.00 kg and m2 = 1.00 kg.

F block 2 block 1

Assume that the rope stays taut so that both blockshave the same acceleration.

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FBD for block 2:

T F

w1

N1

x

y

x

T

w2

N2

y

FBD for block 1:

011

1

=!=

=!=

""

wNF

amTFF

y

x

022

2

=!=

==

""

wNF

amTF

y

x

Apply Newton’s 2nd Law to each block:

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amTF1

=!

amT2

=

To solve for T, a must be eliminated. Solve for a in (2)and substitute in (1).

(1)

(2)

Example continued:

These two equations containthe unknowns: a and T.

N 5.2

kg 1

kg 31

N 10

1

1

2

1

2

1

2

1

2

11

=

!!"

#$$%

&+

=

!!"

#$$%

&+

=

!!"

#$$%

&+=+!!

"

#$$%

&=

!!"

#$$%

&=='

m

m

FT

Tm

mT

m

TmF

m

TmamTF

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5-4 Newton’s Third Law of Motion

Although the forces are the same, theaccelerations will not be unless the objectshave the same mass.

Contact forces:

The force exerted byone box on the other isdifferent depending onwhich one you push.

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5-5 The Vector Nature of Forces: Forces inTwo Dimensions

The easiest way to handle forces in twodimensions is to treat each dimensionseparately, as we did for kinematics.

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5-7 Normal Forces

The normal force isthe force exerted bya surface on anobject.

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5-7 Normal Forces

The normal force may be equal to, greater than,or less than the weight.

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5-7 Normal Forces

The normal force is always perpendicular to thesurface.

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Apparent Weight

Stand on a bathroom scale.

FBD for theperson: Apply Newton’s 2nd Law:

y

yy

mamgN

mawNF

=!

=!="w

N

x

y

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The normal force is the force the scale exerts on you. ByNewton’s 3rd Law this is also the force (magnitude only) youexert on the scale. A scale will read the normal force.

( )yagmN += is what the scale reads.

When ay = 0, N = mg. The scale reads your true weight.

When ay ≠ 0, N > mg or N < mg.

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5-6 WeightApparent weight:

Your perception of your weight is based on thecontact forces between your body and yoursurroundings.

If your surroundingsare accelerating,your apparent weightmay be more or lessthan your actualweight.

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Example: A woman of mass 51 kg is standing in an elevator.If the elevator pushes up on her feet with 408 newtons offorce, what is the acceleration of the elevator?

FBD forwoman:

y

yy

mamgN

mawNF

=!

=!="

Apply Newton’s 2nd Law:

(1)w

N

x

y

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Solving (1) for ay:2

m/s 8.1!=!

=m

mgNay

The elevator could be (1) traveling upward withdecreasing speed, or (2) traveling downwardwith increasing speed.

Given: N = 408 newtons, m = 51 kg, g = 9.8 m/s2

Unknown: ay

Example continued:

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Summary of Chapter 5• Force: a push or pull

• Mass: measures the difficulty inaccelerating an object

• Newton’s first law: if the net force on anobject is zero, its velocity is constant

• Inertial frame of reference: one in which thefirst law holds

• Newton’s second law:

• Free-body diagram: a sketch showing all theforces on an object

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Summary of Chapter 5• Newton’s third law: If object 1 exerts a forceon object 2, then object 2 exerts a force – onobject 1.

• Contact forces: an action-reaction pair offorces produced by two objects in physicalcontact

• Forces are vectors

• Newton’s laws can be applied to eachcomponent of the forces independently

• Weight: gravitational force exerted by the Earthon an object

Fr

Fr

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Summary of Chapter 5• On the surface of the Earth, W = mg

• Apparent weight: force felt from contact with afloor or scale

• Normal force: force exerted perpendicular to asurface by that surface

• Normal force may be equal to, lesser than, orgreater than the object’s weight