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Chapter 6 Section 4: Factoring and Solving Polynomials Equations

Chapter 6 Section 4: Factoring and Solving Polynomials Equations

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Chapter 6 Section 4: Factoring and Solving Polynomials Equations. 1. Factor out any common monomials. SPECIAL FACTORING PATTERNS. PATTERN NAME. Difference of Two Squares. Perfect Square Trinomial. a 2 + 2ab + b 2 = (a + b) 2. PATTERN. x 2 – y 2 = (x + y)(x – y ). - PowerPoint PPT Presentation

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Page 1: Chapter  6 Section 4:  Factoring and Solving Polynomials Equations

Chapter 6Section 4: Factoring and

Solving Polynomials Equations

Page 2: Chapter  6 Section 4:  Factoring and Solving Polynomials Equations

1. Factor out any common monomials

¿3 (𝑥¿¿2−4 )¿

¿2 𝑥2(3𝑥¿¿5−2)¿

Page 3: Chapter  6 Section 4:  Factoring and Solving Polynomials Equations

SPECIAL FACTORING PATTERNS

PATT

ERN

NAM

E PA

TTER

N

EXAM

PLE

Difference of Two Squares

x2 – y2 = (x + y)(x – y)

x2 – 9 = (x + 3)(x– 3)

x2 + 12x + 36 = (x + 6)2

a2 + 2ab + b2 = (a + b)2

Perfect Square Trinomial

Page 4: Chapter  6 Section 4:  Factoring and Solving Polynomials Equations

2. Look for special patterns

x2 – 16 = (x + 4)(x– 4)

x2 + 14x + 49 = (x + 7)2

There are other special patterns that are also worth remembering

Page 5: Chapter  6 Section 4:  Factoring and Solving Polynomials Equations

SPECIAL FACTORING PATTERNS

PATT

ERN

NAM

E PA

TTER

N

EXAM

PLE

Difference of Two cubes

x3 + y3 =(x + y)(x2 –xy+ y2)

8x3 – 1 (2x - 1)(4x2 +2x+ 1)

x3 + 8= (x + 2)(x2 -2x+ 4)

x3 - y3 =(x - y)(x2 +xy+ y2)

Sum of two cubes

Page 6: Chapter  6 Section 4:  Factoring and Solving Polynomials Equations

3.Factoring by grouping1. Begin by factoring out the GCF.

1. 5x3+2x2-40x-16None

2. Arrange the four terms so that the first two terms and the last two terms have common factors.

3. If the coefficient of the third term is negative, factor out a negative coefficient from the last two terms.4. Use the reverse of the distributive property to factor each group of two terms.

5. Now factor the GCF from the result of step 4 as done in the previous section.

2. (5x3+2x2)+(-40x-16)

3. (5x3+2x2)-(40x+16)

4. x2(5x+2)-8(5x+2)

5. (5x+2)(x2-8)

Page 7: Chapter  6 Section 4:  Factoring and Solving Polynomials Equations

Factoring using quadratics

The following steps can be used to solve equations that are quadratic in form:

x4 + 3x2 -4

1. Let u equal a function of the original variable (normally the middle term)

2. Substitute u into the original equation so that it is in the form au2 + bu + c

3. Factor the quadratic equation using the methods learned earlier

4. Replace u with the expression of the original variable.

5. Factor again if necessary.

1. u=x2

2. u2+3u-4

3. (u+4)(u-1)

4. (x2+4)(x2-1)

5. (x2+4)(x-1)(x+1)

Page 8: Chapter  6 Section 4:  Factoring and Solving Polynomials Equations

Solving PolynomialsRemember

Finding zeros, solutions, and roots are different ways of saying the same thing.

So…

After you factor the polynomial, set it equal to 0.

Then solve the polynomial.

Page 9: Chapter  6 Section 4:  Factoring and Solving Polynomials Equations

Find the real-number solutions

x4 + 3x2 -4=0

(x2+4)(x-1)(x+1)=0

(x2+4=0, not real

(x+1)=0 x=-1

(x-1)=0 x=1