5/28/2018 Chem 122 Wkst 11 Answers (1)
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Chem 122 Wkst #11
1) What is being oxidized and what is being reduced in the
following equation:
2H2g)! "2g) 2H2"
a. Oxidized= H;
Reduced= Ob "xidized$ "
%educed$ H
2) What is being oxidized and what is being reduced in the
following equation:
Cds) !&i"2s) ! H2"l)Cd"H)2s) ! &i"H)2s)
a. Oxidized= Cd
Reduced= NiO2b "xidized$ Cd"H)2
%educed$ &i"H)2
') What(s being oxidized and what is being reduced in the
following equation:2H2"l) ! ls) ! *n"+
,aq)l"H)+,aq) ! *n"2s)
a. Oxidized= Al
Reduced= MnO4-
b "xidized$ *n"+,
%educed$ l
+) Write the half,reactions for the following equation: -n2!aq)
! 2.e'!aq)-n+!aq) !
2.e2!aq)
"xidation: Sn2+ Sn4++ 2e-
%eduction: 2Fe3++ 2e- 2Fe2+
/) Write the half,reactions for the following equation: *n"+,aq)
! C2"+
2,aq)*n2!
aq) ! C"2aq)
"xidation: C2O42- 2CO2+ 2e
-
%eduction: 5e-+ 8H++ MnO4- Mn2++4H2O
0) Write the oerall balanced equation for the half,reactions
found in #/ show stes3)
1H++ 2MnO4-+ 5C2O4
- 2Mn2++ 8H2O + 1!CO2
4) 5alance the following redox reaction in basic solution:
C&,aq) ! *n"+,aq)C&",aq) ! *n"2s)
5/28/2018 Chem 122 Wkst 11 Answers (1)
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3CN-+ H2O + 2MnO4- 3CNO-+2MnO2+ 2OH
-
6) 7 or .8 %eduction refers to the loss of electronsa 7rue
". Fal#e
9) 7 or .8 7he cathode is the reduction half,reaction
a. $%ue
b .alse
1) ;n the laboratorns) >n2!aq) ! 2e, ?oes this half
reaction occur at the anode or cathode8
a. an(de
b cathode
12) oltaic cell is based on the half,reactions:
ln!aq)ln'!aq) ! 2e,
5r2l) ! 2e,25r,aq)
7he standard emf for this cell is 1+0 @ Asing data in endix ?=
calculate Boredfor the
reduction of ln'!to ln!
a 29 @
b ' @
c. )!.3*
d / @
