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Chemistry 12 Acid-Base Equilibrium VI Name: Date: Block: 1. Buffers Buffers An acid-base buffer is a solution that resists changes in pH following the addition of relatively small amounts of a strong acid or base. Example: Consider a solution of 1.0 M acetic acid. CH3COOH (aq) +H2O (l) ⇋ CH3COO - (aq) +H3O + (aq) Acetic acid is a weak acid – only a small percent of the weak acid is ionized CH3COOH (aq) + H2O (l) CH3COO - (aq) + H3O + (aq) I 1.0M –– 0M 0M C –x –– +x +x E 1.0M – x –– x x Ka = [CH3COOH] [CH3COO-] If a strong base was added to a solution, acetic acid will be there to neutralize the base. If a strong acid was added, there would be no species to neutralize it. In order for a buffer solution to be effective, equivalent concentrations of a weak acid and a conjugate base must be in solution. A regular acetic acid solution… An acetic acid buffer solution…

Chemistry 12 Name: Acid-Base Equilibrium VI Date: Block

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Page 1: Chemistry 12 Name: Acid-Base Equilibrium VI Date: Block

Chemistry12Acid-BaseEquilibriumVI

Name:Date:Block:

1. Buffers

Buffers

Anacid-basebufferisasolutionthatresistschangesinpHfollowingtheadditionofrelativelysmallamountsofastrongacidorbase.Example:Considerasolutionof1.0Maceticacid.

CH3COOH(aq)+H2O(l)⇋CH3COO-(aq)+H3O+(aq)

• Aceticacidisaweakacid–onlyasmallpercentoftheweakacidisionized

CH3COOH(aq) + H2O(l) ⇋ CH3COO-(aq) + H3O+(aq)I 1.0M –– 0M 0M

C –x –– +x +x

E 1.0M–x –– x x

Ka=

[CH3COOH] [CH3COO-]Ifastrongbasewasaddedtoasolution,aceticacidwillbetheretoneutralizethebase.Ifastrongacidwasadded,therewouldbenospeciestoneutralizeit.

Inorderforabuffersolutiontobeeffective,equivalentconcentrationsofaweakacidandaconjugatebasemustbeinsolution.

Aregularaceticacidsolution…Anaceticacidbuffersolution…

Page 2: Chemistry 12 Name: Acid-Base Equilibrium VI Date: Block

Considerthefollowingpairsofsolutions:

a) Circlethepairsofchemicalspeciesbelowthatcouldbeusedtoprepareabuffersolution.b) Forthepairsthatyoucircled,writethebufferequation.

HNO3andNaNO3 KFandHF HNO2andHNO3 HCOOHandLiHCOO

NaHSO4andNa2SO4 K2CO3andK2C2O4 HClandNaCl KH2PO4andK2HPO4

Page 3: Chemistry 12 Name: Acid-Base Equilibrium VI Date: Block

(Acid)BufferEquation:

CH3COOH(aq)+H2O(l)⇋CH3COO-(aq)+H3O+(aq)Because… Then…Oringeneral…Thehydroniumionconcentration(andthereforethepH)ofabuffersolutiondependson:

1. theKavalue.2. theratiooftheconcentrationoftheweakacidtoitsconjugatebase.

Usingouraceticacidexample…

CH3COOH(aq)+H2O(l)⇋CH3COO-(aq)+H3O+(aq)

[H3O+]=pH=

Page 4: Chemistry 12 Name: Acid-Base Equilibrium VI Date: Block

Now,let’sshiftoursystem!Wenowadd0.10molHClto1.0Mbuffersolutionwithnovolumechange.

• WouldweexpectthepHtodecreaseorincrease?• Wouldthesystemshiftleftorright?

CH3COOH(aq)+H2O(l)⇋CH3COO-(aq)+H3O+(aq) 1.0M 1.0M

[H3O+]=pH=

Wenowadd0.10molNaOHto1.0Mbuffersolutionwithnovolumechange.

• WouldweexpectthepHtodecreaseorincrease?• Wouldthesystemshiftleftorright?

CH3COOH(aq)+H2O(l)⇋CH3COO-(aq)+H3O+(aq) 1.0M 1.0M

[H3O+]=pH=

Add0.10MHCl Add0.10MNaOH

UnbufferedSystempH=

Add0.10MHCl Add0.10MNaOHBufferSystem

pH=

Page 5: Chemistry 12 Name: Acid-Base Equilibrium VI Date: Block

Wecanalsohaveabasicbuffer:ConsideraNH3/NH4+buffersolution:

NH3(aq)+H2O(l)⇋NH4+(aq)+OH-(aq)Because… Then…Oringeneral…Thehydroxideionconcentration(andthereforethepOHandpH)ofabuffersolutiondependson:

1. theKbvalue.2. theratiooftheconcentrationoftheweakbasetoitsconjugateacid.

UsingourNH3/NH4+example…

NH3(aq)+H2O(l)⇋NH4+(aq)+OH-(aq) 1.0M 1.0M

[OH-]=pH=

Page 6: Chemistry 12 Name: Acid-Base Equilibrium VI Date: Block

Wenowadd0.10molHClto1.0Mbuffersolutionwithnovolumechange.• WouldweexpectthepHtodecreaseorincrease?• Wouldthesystemshiftleftorright?

NH3(aq)+H2O(l)⇋NH4+(aq)+OH-(aq) 1.0M 1.0M

[OH-]=pH=

Wenowadd0.10molNaOHto1.0Mbuffersolutionwithnovolumechange.

• WouldweexpectthepHtodecreaseorincrease?• Wouldthesystemshiftleftorright?

NH3(aq)+H2O(l)⇋NH4+(aq)+OH-(aq) 1.0M 1.0M

[OH-]=pH=

Page 7: Chemistry 12 Name: Acid-Base Equilibrium VI Date: Block

Practice.Considera1.0Mhydrofluoricacidbuffersystem.a. Whatistheequation?

b. CalculatethepHofanundisturbedsystem.

c. CalculatethepHwhen0.050Mhydrobromicacidisaddedtotheoriginalbuffersystem.

d. CalculatethepHwhen0.050MMg(OH)2isaddedtotheoriginalbuffersystem.HebdenWorkbookPg.181#131–138