Chemistry 205Chemical Nomenclature Bonus Quiz #1

(6 points)

1. Give a chemical name for the following compounds.

a. Na2S b. SO3 c. Mg(NO3)2

2. Write the formula for each of the following compounds.

a. Phosphorus tribromide b. Calcium iodide c. Iron(II) phosphate

Chemistry 205Chemical Nomenclature Bonus Quiz #1 (Answer Key)

1. Give a chemical name for the following compounds. a. Na2S sodium sulfide

This is a binary compound composed of a metal and a nonmetal. The –ide ending indicates a binary compound. Because sodium has only a charge of only 1+ and sulfide is 2–, there is only one formula for sodium sulfide.

b. SO3 sulfur trioxide

This is a binary compound composed of two nonmetals.The –ide ending indicates a binary compound and with two nonmetals, the number of atoms must also be given.

Chemistry 205Chemical Nomenclature Bonus Quiz #1 (Answer Key)

1. c. Mg(NO3)2 magnesium nitrate

The name magnesium can be used since the magnesium ionhas a fixed charge (2+). Since the nitrate ion has a charge of 1-, the formula must have 2 nitrate ions and no prefix isrequired.

a. Phosphorus tribromide

2. Write the formula for each of the following compounds.

PBr3

This is a binary compound composed of two nonmetals.In this case the name gives both the name and the numberfor each of the two elements in the compound. The first elementis phosphorus and there is one, and the second element(indicated by the one ending in –ide) is bromine, and thereare three.

Chemistry 205Chemical Nomenclature Bonus Quiz #1 (Answer Key)

2. b. Calcium iodide CaI2

This is a binary compound, composed of a metal and a nonmetal. The –ide ending indicates a binary compound. With a metal and a nonmetal no prefixes indicating thenumber of atoms are required. Calcium has only one charge(2+) and the iodide ion is 1–, so two iodide ions are neededTo balance the 2+ of the calcium ion.

c. Iron(II) phosphate Fe3(PO4)2

The iron(II) ion has a charge of 2+ and the charge of the phosphate ion is 3-. Therefore, theformula will require 3 iron (II) ions (total chargeof 6+) to go with 2 phosphate ions (total charge of 6-)

Chemistry 205Chemical Nomenclature Bonus Quiz #2

(6 points)

1. Give a chemical name for the following compounds.

a. N2O5 b. Fe3N2 c. Ba(OH)2

2. Write the formula for each of the following compounds.

a. Zinc bromide b. Ammonium carbonate c. Lead(IV) sulfate

Chemistry 205Chemical Nomenclature Bonus Quiz #2 (Answer Key)

1. Give a chemical name for the following compounds.

Iron(II) nitride

This is a binary compound composed of a metal and a nonmetal. The –ide ending indicates a binary compound. Because iron has two possible charges (2+ and 3+), thename must indicate which one is present. The nitride ionis always 3– and since there are two nitride ions in the compound, the total negative is 6–. The charge on the iron therefore is 2+ (3 x 2+ = 6+)

dinitrogen pentoxide

This is a binary compound composed of two nonmetals.The –ide ending indicates a binary compound and with two nonmetals, the number of atoms must also be given,di- for two nitrogens and pent- for five oxygens.

a. N2O5

b. Fe3N2

Chemistry 205Chemical Nomenclature Bonus Quiz #2 (Answer Key)

1. c. Ba(OH)2 barium hydroxide

The name barium can be used since the magnesium ionhas a fixed charge (2+). Since the hydroxide ion has a charge of 1-, the formula must have two hydroxide ions and no prefixis required.

a. Zinc bromide

2. Write the formula for each of the following compounds.

ZnBr2

This is a binary compound composed of a metal and a nonmetal. Since the zinc ion has a fixed charge of 2+ and the bromide ion has a fixed charge of 1–, the formulaFor the compound will contain one zinc ion (1 x 2+ = 2+) And two bromide ions (2 x 1– = 2–).

Chemistry 205Chemical Nomenclature Bonus Quiz #2 (Answer Key)

2. b. Ammonium carbonate

The ammonium ion has a charge of 1+ (NH41+) and the

carbonate ion has a charge of 2– (CO32–). The formula

therefore contains 2 ammonium ions (2 x 1+ = 2+) to balanceOne carbonate ion (1 x 2– = 2–).

c. Lead(IV) sulfate Pb(SO4)2

The lead(IV) ion has a charge of 4+ and the charge of the sulfate ion is 2-. Therefore, theformula will require 1 lead(IV) ion (total chargeof 4+) to go with 2 sulfate ions (total charge of 4-)

(NH4)2CO3