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LUYN THI ĐẠI HC MÔN TOÁN – Thy Hùng Chuyên đề Nguyên hàm – Tích phân Hc trc tuyến ti: www.moon.vn Mobile: 0985.074.831 1 I. NHẮC LẠI KHÁI NIỆM VỀ VI PHÂN CỦA HÀM SỐ Vi phân ca hàm sy = f(x) được kí hiu là dy và cho bi công thc = = = ( ) ' '( ) dy df x y dx f x dx Ví d: d(x 2 – 2x + 2) = (x 2 – 2x + 2)dx = (2x – 2)dx d(sinx + 2cosx) = (sinx + 2cosx)dx = (cosx – 2sinx)dx Chú ý: Tcông thc vi phân trên ta ddàng thu được mt skết qusau ( 29 ( 29 1 2 2 2 2 d x dx dx d x = = ( 29 ( 29 1 3 3 3 3 d x dx dx d x = = ( 29 ( 29 ( 29 2 2 2 2 1 1 1 2 2 2 2 x xdx d dx dx a da x = = = ± =- - ( 29 ( 29 ( 29 3 2 3 3 3 1 1 1 3 3 3 3 x x dx d dx dx a da x = = = ± =- - ( ( 29 ( 29 ax 1 1 ln ax ln ax d b dx dx d b d x ax b a b a x + = = + = + + ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 1 1 1 sin ax sin ax ax cos ax sin 2 os2 ... 2 b dx bd b d b xdx dc x a a + = + + =- + =- ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 1 1 1 cos cos sin cos 2 sin 2 ... 2 ax b dx ax b d ax b d ax b xdx d x a a + = + + = + = ( 29 ( ( ax 2 2 1 1 1 ax ... 2 b ax b ax b x x e dx e d b de e dx de a a + + + = + = = ( 29 ( ( 29 ( 29 ( 29 2 2 2 ax 1 1 1 tan tan 2 ... 2 cos cos cos 2 d b dx dx d ax b d x a a ax b ax b x + = = + = + + ( 29 ( ( 29 ( 29 ( 29 2 2 2 ax 1 1 1 cot cot 2 ... 2 sin sin sin 2 d b dx dx d ax b d x a a ax b ax b x + = =- + =- + + II. KHÁI NIỆM VỀ NGUYÊN HÀM Cho hàm sf(x) liên tc trên mt khong (a; b). Hàm F(x) được gi là nguyên hàm ca hàm sf(x) nếu F’(x) = f(x) và được viết là () f x dx . Tđó ta có : () () f x dx Fx = Nhn xét: Vi C là mt hng snào đó thì ta luôn có (F(x) + C)’ = F’(x) nên tng quát hóa ta viết () () f x dx Fx C = + , khi đó F(x) + C được gi là mt hnguyên hàm ca hàm sf(x). Vi mt giá trcthca C thì ta được mt nguyên hàm ca hàm sđã cho. Ví d: Hàm sf(x) = 2x có nguyên hàm là F(x) = x 2 + C, vì (x 2 + C)’ = 2x Hàm sf(x) = sinx có nguyên hàm là F(x) = –cosx + C, vì (–cosx + C)’ = sinx III. CÁC TÍNH CHẤT CƠ BẢN CỦA NGUYÊN HÀM Cho các hàm sf(x) và g(x) liên tc và tn ti các nguyên hàm tương ng F(x) và G(x), khi đó ta có các tính cht sau: a) Tính cht 1: ( 29 () () f x dx f x = Chng minh: Tài liu tham kho: 01. MỞ ĐẦU VỀ NGUYÊN HÀM Thầy Đặng Việt Hùng

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  • LUYN THI I HC MN TON Thy Hng Chuyn Nguyn hm Tch phn

    Hc trc tuyn ti: www.moon.vn Mobile: 0985.074.831 1

    I. NHC LI KHI NIM V VI PHN CA HM S

    Vi phn ca hm s y = f(x) c k hiu l dy v cho bi cng thc = = =( ) ' '( )dy df x y dx f x dx V d: d(x2 2x + 2) = (x2 2x + 2)dx = (2x 2)dx d(sinx + 2cosx) = (sinx + 2cosx)dx = (cosx 2sinx)dx Ch : T cng thc vi phn trn ta d dng thu c mt s kt qu sau ( ) ( )12 2 2

    2d x dx dx d x= =

    ( ) ( )13 3 33

    d x dx dx d x= =

    ( ) ( ) ( )2 2 2 21 1 12 2 2 2xxdx d d x d x a d a x = = = = ( ) ( ) ( )32 3 3 31 1 13 3 3 3xx dx d d x d x a d a x = = = =

    ( ) ( ) ( )ax1 1 ln ax lnax

    d bdx dxd b d xax b a b a x

    += = + =

    + +

    ( ) ( ) ( ) ( )( ) ( )1 1 1sin ax sin ax ax cos ax sin 2 os2 ...2

    b dx b d b d b xdx d c xa a

    + = + + = + =

    ( ) ( ) ( ) ( )( ) ( )1 1 1cos cos sin cos2 sin 2 ...2

    ax b dx ax b d ax b d ax b xdx d xa a

    + = + + = + =

    ( ) ( ) ( )ax 2 21 1 1ax ...2b ax b ax b x xe dx e d b d e e dx d ea a+ + += + = = ( )

    ( )( ) ( ) ( )2 2 2ax1 1 1

    tan tan 2 ...2cos cos cos 2

    d bdx dxd ax b d xa aax b ax b x

    += = + =

    + +

    ( )( )

    ( ) ( ) ( )2 2 2ax1 1 1

    cot cot 2 ...2sin sin sin 2

    d bdx dxd ax b d xa aax b ax b x

    += = + =

    + +

    II. KHI NIM V NGUYN HM

    Cho hm s f(x) lin tc trn mt khong (a; b). Hm F(x) c gi l nguyn hm ca hm s f(x) nu F(x) = f(x) v c vit l ( )f x dx . T ta c : ( ) ( )f x dx F x= Nhn xt: Vi C l mt hng s no th ta lun c (F(x) + C) = F(x) nn tng qut ha ta vit ( ) ( )f x dx F x C= + , khi F(x) + C c gi l mt h nguyn hm ca hm s f(x). Vi mt gi tr c th ca C th ta c mt nguyn hm ca hm s cho. V d: Hm s f(x) = 2x c nguyn hm l F(x) = x2 + C, v (x2 + C) = 2x Hm s f(x) = sinx c nguyn hm l F(x) = cosx + C, v (cosx + C) = sinx III. CC TNH CHT C BN CA NGUYN HM

    Cho cc hm s f(x) v g(x) lin tc v tn ti cc nguyn hm tng ng F(x) v G(x), khi ta c cc tnh cht sau:

    a) Tnh cht 1: ( )( ) ( )f x dx f x = Chng minh:

    Ti liu tham kho:

    01. M U V NGUYN HM Thy ng Vit Hng

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  • LUYN THI I HC MN TON Thy Hng Chuyn Nguyn hm Tch phn

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    Do F(x) l nguyn hm ca hm s f(x) nn hin nhin ta c ( ) ( )( ) ( ) ( )f x dx F x f x = = pcm. b) Tnh cht 2: [ ]( )( ) ( ) ( ) ( )f x g x dx f x dx g x dx+ = + Chng minh:

    Theo tnh cht 1 ta c, ( ) ( ) ( )( ) ( ) ( ) ( ) ( ) ( )f x dx g x dx f x dx g x dx f x g x + = + = + Theo nh ngha nguyn hm th v phi chnh l nguyn hm ca f(x) + g(x). T ta c [ ]( )( ) ( ) ( ) ( )f x g x dx f x dx g x dx+ = + c) Tnh cht 3: ( ). ( ) ( ) , 0k f x dx k f x dx k= Chng minh:

    Tng t nh tnh cht 2, ta xt ( )( ) . ( ) . ( ) ( )k f x dx k f x k f x dx k f x dx = = pcm. d) Tnh cht 4: ( ) ( ) ( ) ..f x dx f t dt f u du= = Tnh cht trn c gi l tnh bt bin ca nguyn hm, tc l nguyn hm ca mt hm s ch ph thuc vo hm, m khng ph thuc vo bin. IV. CC CNG THC NGUYN HM

    Cng thc 1: dx x C= +

    Chng minh: Tht vy, do ( ) 1x C dx x C+ = = + Ch : M rng vi hm s hp ( )u u x= , ta c du u C= +

    Cng thc 2:n 1

    n xx dx Cn 1

    +

    = ++

    Chng minh:

    Tht vy, do 1 1

    1 1

    n nn nx xC x x dx C

    n n

    + + + = = +

    + +

    Ch : + M rng vi hm s hp ( )u u x= , ta c

    1

    1

    nn uu du C

    n

    +

    = ++

    + Vi 1 2 2 22 2

    dx dx dun x C u C

    x x u= = = + = +

    + Vi 2 21 12 dx dun C C

    x x u u= = + = +

    V d:

    a) 3

    2

    3x

    x dx C= +

    b) ( ) 54 4 22 2 5x

    x x dx x dx xdx x C+ = + = + +

    c) 1 1

    22 2 2 23 3 333 312 2 2

    3

    x x x x x x xdx dx xdx x dx C x Cx x

    = = = + = +

    d) ( ) ( ) ( ) ( )5

    4 4 2 112 1 2 1 2 12 5

    nu du xI x dx x d x I C+

    = + = + + = +

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    e) ( ) ( ) ( ) ( )2011

    2010 2010 1 311 3 1 3 1 33 2011

    nu du xI x dx x d x I C

    = = = +

    f) ( )( )

    ( ) ( )2

    2 2

    2 11 1 1 1.

    2 2 2 1 2 2 12 1 2 1

    duu

    d xdxI I C Cx xx x

    += = = + = +

    + ++ +

    g) ( ) ( ) ( )3 32 21 1 2 34 5 4 5 4 5 . 4 5 4 54 4 3 8

    I x dx x d x I x C x C= + = + + = + + = + +

    Cng thc 3: lndx x Cx

    = +

    Chng minh:

    Tht vy, do ( ) 1ln lndxx C x Cx x

    + = = + Ch : + M rng vi hm s hp ( )u u x= , ta c lndu u C

    u= +

    + ( )

    1 ln 21 1 2x 2ln ax1ax ax ln 2

    2 2

    dxx k Cd ax bdx kb C

    dxb a b a k x Ck x

    = + ++ +

    = = + + + +

    = +

    V d:

    a) 4

    3 31 1 1 2 ln4

    dx xx dx x dx dx x x C

    x xx x

    + + = + + = + + +

    b) ( )3 21 1 ln 3 23 2 3 3 2 3

    duu

    d xdxI I x Cx x

    += = = + +

    + +

    c) ( )2 2 22 12 3 3 3 32 2 3 ln 2 12 1 2 1 2 1 2 2 1 2

    d xx x dxdx x dx xdx x x x Cx x x x

    ++ + = + = + = + = + + + + + + +

    Cng thc 4: sinx cosdx x C= +

    Chng minh: Tht vy, do ( )cos sin x sinx cosx C dx x C + = = + Ch : + M rng vi hm s hp ( )u u x= , ta c sinu cosdu u C= +

    + ( ) ( ) ( ) ( )1 1 1sin ax sin ax ax cos ax sin 2 os22

    b dx b d b b C xdx c x Ca a

    + = + + = + + = + V d:

    a) ( )32 2 11 1sinx sinx cos2 1 2 1 2 2 1

    d xdxx x dx x xdx dx x dx x

    x x x

    + + = + + = + =

    522 1

    cos ln 2 15 2x

    x x C= + +

    b) ( ) ( )4 33 1 3 1 3sin 2 sin 2 3 sin 2 2 os2 ln 4 34 3 4 3 2 4 4 3 2 4

    d xdxx dx xdx xd x c x x C

    x x x

    + = + = + = + +

    c) sin sinx sin32x

    x dx + +

    Ta c ( ) ( ) ( ) ( )1 1 12 ; 2 2 2 ; 3 3 32 2 2 2 3x xd dx dx d d x dx dx d x d x dx dx d x = = = = = =

    T :

    ( ) ( )1 1sin sinx sin3 sin sin 2 sin3 2 sin sin 2 2 sin3 32 2 2 2 2 3x x x x

    x dx dx xdx xdx d xd x xd x + + = + + = + +

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  • LUYN THI I HC MN TON Thy Hng Chuyn Nguyn hm Tch phn

    Hc trc tuyn ti: www.moon.vn Mobile: 0985.074.831 4

    1 12cos os2 os32 2 3x

    c x c x C= +

    Cng thc 5: cos sinxdx x C= +

    Chng minh: Tht vy, do ( )in cos cosx inxs x C x dx s C+ = = + Ch : + M rng vi hm s hp ( )u u x= , ta c cosu sindu u C= +

    + ( ) ( ) ( ) ( )1 1 1os ax os ax ax sin ax os2 sin 22

    c b dx c b d b b C c xdx x Ca a

    + = + + = + + = + V d:

    a) 4 1 5cos sin cos sin x 4 sinx cos 4 5ln 11 1

    xx x dx xdx dx dx x x x C

    x x

    + = + = + + + + + +

    b) ( )21

    cos 2 sin x os2 sinx sin 2 cos2 2

    xx x dx c xdx dx xdx x x C+ = + = +

    c) ( )2 1 os2 1 1 1 1 1 1sin os2 os2 2 sin 22 2 2 2 4 2 4

    c xxdx dx c x dx x c xd x x x C = = = = +

    Cng thc 6: 2 tancosdx

    x Cx

    = +

    Chng minh:

    Tht vy, do ( ) 2 21tan tan xcos cosdx

    x C Cx x

    + = = + Ch : + M rng vi hm s hp ( )u u x= , ta c 2 tan uos

    du Cc u

    = +

    + ( )( )

    ( ) ( )2 2 21 1 1

    tan tan 2cos cos cos 2 2

    d ax bdx dxax b C x C

    ax b a ax b a x+

    = = + + = ++ +

    V d:

    a) 2 21 1

    cos sin 2 cos sin 2 tan sin cos2cos cos 2

    dxx x dx xdx xdx x x x C

    x x

    + = + = + + +

    b) ( ) ( )( )

    ( )( )

    2 2 2

    2 1 5 41 2 1 22cos 2 1 5 4 cos 2 1 5 4 2 cos 2 1 4 5 4

    d x d xdx dxI dxx x x x x x

    = + = + =

    ( )2os 1 1tan 2 1 ln 5 42 2

    duc u x x C = +

    c) ( )( )

    ( ) ( )2os

    2 2

    3 21 1tan 3 2

    cos 3 2 2 cos 3 2 2

    duc u

    d xdxI I x Cx x

    = = = +

    Cng thc 7: 2 cot xsindx C

    x= +

    Chng minh:

    Tht vy, do ( ) 2 21cot cot xsindx

    x C Csin x x

    + = = +

    Ch : + M rng vi hm s hp ( )u u x= , ta c 2 cot usin

    du Cu

    = +

    + ( )( )

    ( ) ( )2 2 2ax1 1 1

    cot ax cot 2sin ax sin ax sin 2 2

    d bdx dxb C x Cb a b a x

    += = + + = +

    + +

    V d:

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    Hc trc tuyn ti: www.moon.vn Mobile: 0985.074.831 5

    a) 6

    5 52 2

    1 1cos 2 2 cos 2 2 sin 2 cot

    sin sin 2 3dx x

    x x dx xdx x dx x x Cx x

    + = + = + + +

    b) ( )( )

    ( ) ( ) ( )2sin

    2 2

    1 31 1 1cot 1 3 cot 1 3

    sin 1 3 3 sin 1 3 3 3

    duu

    d xdxI I x C x Cx x

    = = = + = +

    c) 2sin2 2

    22 2cot2

    sin sin2 2

    duu

    xddx xI I C

    x x

    = = = +

    Cng thc 8: x xe dx e C= +

    Chng minh:

    Tht vy, do ( )x x x xe C e e dx e C+ = = + Ch : + M rng vi hm s hp ( )u u x= , ta c u ue du e C= +

    + ( )2 2

    2 2

    11 1 2

    ax12

    x k x k

    ax b ax b ax b

    k x k x

    e dx e Ce dx e d b e C

    a ae dx e C

    + +

    + + +

    = +

    = + = +

    = +

    V d:

    a) ( ) ( )2 1 2 1 2 12 2 231 4 4 1 12 1 4.2sin 3 sin 3 2 3 sin 3x x x

    d xdxe dx e dx dx e d x x

    x x xx x

    + + + + = + = + +

    2 11 1 cot 3 82 3

    xe x x C += + + +

    b) ( )( ) ( ) ( ) ( ) ( )3 2 3 2 3 24 14 os 1 3 4 os 1 3 3 2 os 1 3 1 33 3x x xe c x dx e dx c x dx e d x c x d x+ + ++ = + = + ( )3 24 1 sin 1 3

    3 3xe x C+= +

    Cng thc 9:ln

    xx aa dx C

    a= +

    Chng minh:

    Tht vy, do lnln ln ln

    x x xx xa a a aC a a dx C

    a a a

    + = = = +

    Ch : + M rng vi hm s hp ( )u u x= , ta c u ua du a C= +

    + ( )1 1kx m kx m kx ma dx a d kx m a Ck k

    + + += + = +

    V d:

    a) ( ) ( ) ( ) 3 23 2 3 2 3 21 1 2 32 3 2 3 2 3 3 23 2 3ln 2 2ln3u

    x xa dux x x x x xI dx dx dx d x d x I C= + = + = + = + +

    b) ( ) ( ) ( ) 1 21 2 4 3 1 2 4 3 1 2 4 3 4 31 3 2 32 2 3 2 1 2 4 32 4 2ln 2 4x

    x x x x x x xe dx dx e dx d x e d x e C

    + + + + = = + = + +

    BI TP LUYN TP: 1) ( )51 2I x x dx= + 2) 3 52 71 3I x dxx = 3) ( )5 2 3 33 4 2I x x x dx= +

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    Hc trc tuyn ti: www.moon.vn Mobile: 0985.074.831 6

    4) 34 251 24 xI x dx

    xx

    = +

    5) 5

    1x + dx

    xI =

    6)

    4

    6 22 3xI dx

    x

    +=

    7) ( )2

    7

    1xI dx

    x

    = 8) ( )238 2 1I x dx= 9) ( )22

    9 2

    4xI dx

    x

    +=

    10) 4 3 2

    10 23 2 1x x xI dx

    x

    + += 11)

    2

    11x x x xI dx

    x

    = 12) 12 31 1I dxx x

    =

    13) 3

    131I x dxx

    =

    14)

    2

    14 3

    1I x dxx

    = +

    15)

    ( )2315

    2 3x xI dx

    x

    =

    16) ( )( )416 2I x x x x dx= 17) 17 51(2 3)I dxx= 18) 18 41( 3)xI dxx += 19) 19

    pisin

    2 7xI dx = +

    20) 20 sin 2 sin 3

    xI x dx = +

    21) 21 sin 2xI x dx = +

    22) 22pi 1

    sin 3 sin4 2

    xI x dx + = +

    23) 223 cos 2xI dx= 24) 224 sin 2

    xI dx=

    26) 26 2cos 4dxI

    x= 27) ( )27 2cos 2 1

    dxIx

    =

    28) ( )228 tan 2I x x dx= + 29) 429 tanI x dx= 30) 230 cotI x dx= 31) ( )31 2sin 2 3

    dxIx

    =

    +

    32) 32 1 cos6dxI

    x=

    33) 2 233 21

    cot dxI x xx

    = + +

    34) 234

    1 dx3 2

    I xx

    = + +

    35) 2351

    sin2 5

    I x dxx

    =

    36) 36

    2 dx3

    xIx

    +=

    37) 372 14 3

    xI dxx

    =

    +

    38) 38 6 5xI dx

    x=

    39) 2

    3911

    3x xI dx

    x

    + +=

    + 40)

    2

    402 5

    1x xI dx

    x

    +=

    41) 3 2

    413 2 1

    2x x xI dx

    x

    + + +=

    + 42)

    3 2

    424 4 1

    2 1x xI dx

    x

    + =

    + 43)

    2

    434 6 1

    2 1x xI dx

    x

    + +=

    +

    44) 2x 344I e dx += 45) 3 145 cos(1 ) xI x e dx = + 46) 2 1

    46 .xI x e dx +=

    47) 47 22

    sin (3 1)xI e dx

    x

    = +

    + 48) 48 22 cos

    xx eI e dx

    x

    = +

    49) ( )1 2 4 349 2 x xI e dx +=

    50) 5012x

    I dx= 51) 5127

    x

    xI dx= 52) 2 152 3 xI dx+=

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  • LUYN THI I HC MN TON Thy Hng Chuyn Nguyn hm Tch phn

    Hc trc tuyn ti: www.moon.vn Mobile: 0985.074.831 1

    1. Khi nim nguyn hm Cho hm s f xc nh trn K. Hm s F c gi l nguyn hm ca f trn K nu '( ) ( )F x f x= , x K Nu F(x) l mt nguyn hm ca f(x) trn K th h nguyn hm ca f(x) l ( ) ( )f x dx F x C= + , C R.

    Mi hm s f(x) lin tc trn K u c nguyn hm trn K. 2. Tnh cht

    '( ) ( )f x dx f x C= +

    [ ]( ) ( ) ( ) ( )f x g x dx f x dx g x dx = ( ) ( ) ( 0)kf x dx k f x dx k=

    3. Bng nguyn hm ca mt s hm s thng gp

    0dx C=

    dx x C= +

    1, ( 1)

    1x

    x dx C+

    = + +

    1

    lndx x Cx

    = +

    x xe dx e C= +

    (0 1)ln

    xx aa dx C a

    a= + <

    cos sinxdx x C= +

    sin cosxdx x C= +

    21

    tancos

    dx x Cx

    = +

    21

    cotsin

    dx x Cx

    = +

    1

    cos( ) sin( ) ( 0)ax b dx ax b C aa

    + = + +

    1

    sin( ) cos( ) ( 0)ax b dx ax b C aa

    + = + +

    1

    , ( 0)ax b ax be dx e C aa

    + += +

    1 1

    lndx ax b Cax b a

    = + ++

    V d 1. Chng minh F(x) l mt nguyn hm ca hm s f(x) bit rng

    a) ( ) (4 5)( ) (4 1)

    x

    x

    F x x ef x x e

    =

    = b)

    4

    5 3( ) tan 3 5( ) 4 tan 4 tan 3

    F x x xf x x x

    = +

    = + +

    c)

    2

    2

    2 2

    4( ) ln3

    2( )( 4)( 3)

    xF xx

    xf xx x

    +=

    + =

    + +

    d)

    2

    2

    2

    4

    2 1( ) ln2 1

    2 2( 1)( )1

    x xF xx x

    xf xx

    +

    = + +

    =

    +

    Ti liu bi ging:

    01. M U V NGUYN HM Thy ng Vit Hng

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    V d 2. Tm cc nguyn hm sau

    1) 2 1 3 ..........................................................................x x dxx

    + =

    2)4

    22 3

    ..................................................................................

    x dxx

    +=

    3) 21

    ...................................................................................

    x dxx

    =

    4)2 2

    2( 1)

    ..............................................................................

    x dxx

    =

    5) ( )3 4 ......................................................................................x x x dx+ + = 6)

    3

    1 2...............................................................................dx

    x x

    =

    7) 22sin .............................................................2x dx =

    8) 2tan ............................................................................xdx =

    9) 2cos ................................................................xdx =

    10) 2 21

    .........................................................................................

    sin .cosdx

    x x=

    11) 2 2cos 2

    ....................................................................................................................................

    sin .cosx dx

    x x=

    12) 2sin 3 cos 2 ............................................................................................x xdx =

    13) ( ) 1 .............................................................................x xe e dx =

    14) 22 .......................................................................................cosx

    x ee dxx

    + =

    15) 3 1 2 ......................................................................................................................1

    x xe dxx

    + + =

    V d 3. Tm nguyn hm F(x) ca hm s f(x) tho iu kin cho trc: a) 3( ) 4 5; (1) 3f x x x F= + = b) pi= =( ) 3 5cos ; ( ) 2f x x F

    c) 23 5

    ( ) ; ( ) 1x

    f x F ex

    = = d) 2 1 3

    ( ) ; (1)2

    xf x F

    x

    += =

    e) = =3

    21( ) ; ( 2) 0xf x F

    x f) 1( ) ; (1) 2f x x x F

    x= + =

    g) pi= =

    ( ) sin2 .cos ; ' 03

    f x x x F h) 4 3

    23 2 5( ) ; (1) 2x xf x F

    x

    += =

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    i) 3 3

    23 3 7

    ( ) ; (0) 8( 1)

    x x xf x F

    x

    + + = =

    + k) 2 pi pi( ) sin ;

    2 2 4xf x F = =

    V d 4. Cho hm s g(x). Tm nguyn hm F(x) ca hm s f(x) tho iu kin cho trc:

    a) pi = + = =

    2( ) cos ; ( ) sin ; 32

    g x x x x f x x x F

    b) pi= + = =2( ) sin ; ( ) cos ; ( ) 0g x x x x f x x x F

    c) 2( ) ln ; ( ) ln ; (2) 2g x x x x f x x F= + = = V d 5. Tm iu kin ca tham s hm s F(x) l mt nguyn hm ca hm s f(x):

    a) 3 2

    2( ) (3 2) 4 3. .( ) 3 10 4F x mx m x x

    Tm mf x x x

    = + + +

    = + b)

    2

    2

    ( ) ln 5. .2 3

    ( )3 5

    F x x mxTm mx

    f xx x

    = +

    +=

    + +

    c) 2 2

    2

    ( ) ( ) 4 . , , .( ) ( 2) 4

    F x ax bx c x xTm a b c

    f x x x x

    = + +

    =

    d) 2( ) ( ) . , , .

    ( ) ( 3)

    x

    x

    F x ax bx c eTm a b c

    f x x e

    = + +

    =

    e) 2 2

    2 2( ) ( ) . , , .( ) (2 8 7)

    x

    x

    F x ax bx c eTm a b c

    f x x x e

    = + +

    = + f)

    2

    2( ) ( ) . , , .( ) ( 3 2)

    x

    x

    F x ax bx c eTm a b c

    f x x x e

    = + +

    = +

    g) ( ) ( 1)sin sin2 sin3 . , , .2 3( ) cos

    b cF x a x x x Tm a b c

    f x x

    = + + + =

    h) 2

    2( ) ( ) 2 3

    . , , .20 30 7( )

    2 3

    F x ax bx c x

    Tm a b cx xf x

    x

    = + +

    +

    =

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    CC BIU THC VI PHN QUAN TRNG

    1. ( ) ( ) ( )2 2 21 1 12 2 2xdx d x d x a d a x= = = 6. ( ) ( ) ( )2 cot cot cotsindx d x d x a d a x

    x= = =

    2. ( ) ( ) ( )2 3 3 31 1 13 3 3x dx d x d x a d a x= = = 7. ( ) ( ) ( )2dx d x d x a d a xx = = = 3. sin (cos ) (cos ) ( cos )x dx d x d x a d a x= = = 8. ( ) ( ) ( )x x x xe dx d e d e a d a e= = = 4. cos (sin ) (sin ) ( sin )x dx d x d x a d a x= = = 9. ( ) ( ) ( )ln ln lndx d x d x a d a x

    x= = =

    5. ( ) ( ) ( )2 tan tan tancosdx d x d x a d a x

    x= = = 10. ( ) ( )1 1dx d ax b d b ax

    a a= + =

    V d 1. Tm nguyn hm ca cc hm s sau:

    a) 1 21xI dxx

    =

    + b) 2 10

    2 (1 )I x x dx= + c) 2

    3 3 1x dxIx

    =

    +

    Hng dn gii:

    a) S dng cc cng thc vi phn ( ) ( )

    ( )

    22 21 1

    2 2 2

    ln

    xxdx d d x d x a

    du d uu

    = = =

    =

    Ta c ( ) ( ) ( )

    2 2(ln ) ln 2

    1 12 2 2

    11 1 1 ln 1 .2 2 21 1 1

    du d u u Cu

    d x d xxI dx I x Cx x x

    = = ++= = = = + +

    + + +

    b) S dng cc cng thc vi phn ( ) ( )2 2 2

    1

    1 12 2 2

    1

    nn

    xxdx d d x d x a

    uu du d

    n

    +

    = = =

    = +

    Ta c ( ) ( ) ( ) ( )112

    10 102 2 22

    111 1 1 .2 22

    xI x x dx x d x C

    += + = + + = +

    c) S dng cc cng thc vi phn ( )

    ( )

    32 31

    3 3

    2

    xx dx d d x a

    du d uu

    = =

    =

    Ta c ( ) ( )3 32 3

    3 3 3 3

    1 11 2 2 1.

    3 3 31 1 2 1

    d x d xx dx xI Cx x x

    + + += = = = +

    + + +

    V d 2. Tm nguyn hm ca cc hm s sau:

    a) 24 1I x x dx= b) 5 2 1dxIx

    =

    c) 6 5 2I x dx=

    Ti liu tham kho:

    02. PP VI PHN TM NGUYN HM Thy ng Vit Hng

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    Hng dn gii:

    a) S dng cc cng thc vi phn ( ) ( )2 2 2

    1

    1 12 2 2

    1

    nn

    xxdx d d x d a x

    uu du d

    n

    +

    = = =

    = +

    Ta c ( ) ( ) ( ) ( ) ( )321 1

    2 2 2 2 22 24

    11 11 1 1 1 .2 2 3

    xI x x dx x d x x d x C

    = = = = +

    b) S dng cc cng thc vi phn ( ) ( )( )

    1 1ax ax

    2

    dx d b d ba a

    du d uu

    = + =

    =

    Ta c ( ) ( ) ( )25 52 1 2 11 2 1 .22 1 2 1 2 2 1du d u

    ud x d xdxI I x C

    x x x

    =

    = = = = +

    c) S dng cc cng thc vi phn ( ) ( )

    1

    1 1ax ax

    1

    nn

    dx d b d ba a

    uu du d

    n

    +

    = + =

    = +

    ( ) ( ) ( ) ( ) ( )3 3

    1 226

    5 22 5 21 1 15 2 5 2 2 5 2 5 2 . .2 2 2 3 3

    xxI x dx x d x x d x C C

    = = = = + = +

    V d 3. Tm nguyn hm ca cc hm s sau:

    a) 3

    7 5 4

    25

    xI dxx

    =

    b) 8 5(3 2 )dxI

    x=

    c) 3

    9ln xI dx

    x=

    Hng dn gii:

    a) S dng cc cng thc vi phn ( ) ( )43 4 4

    1

    1 14 4 4

    1

    n

    n

    xx dx d d x a d a x

    du udnu

    +

    = = =

    =

    +

    ( ) ( ) ( ) ( )4

    4 444 55134 45

    7 5 54 4

    5 55 542 1 12 5 5 . .2 2 4 85 5

    xdxxxI dx x d x C C

    x x

    = = = = + = +

    b) Ta c ( ) ( ) ( )6

    58 5

    3 21 3 2 3 2 .(3 2 ) 2 12xdxI x d x C

    x

    = = = +

    c) S dng cng thc vi phn ( )lndx d xx

    = ta c ( )3 4

    39

    ln lnln ln .4

    x xI dx x d x Cx

    = = = +

    V d 4. Tm nguyn hm ca cc hm s sau:

    a) ( )10 20103

    4 2dxIx

    =

    b) 11cos xI dx

    x= c) 12 cos sinI x x dx=

    Hng dn gii:

    a) Ta c ( ) ( ) ( )( )

    ( )2009

    201010 2010 2009

    4 23 3 3 34 2 4 2 .2 2 20094 2 4018 4 2

    xdxI x d x C Cx x

    = = = + = +

    b) S dng cc cng thc vi phn ( )

    ( )cos sin

    2

    u du d udx d x

    x

    =

    =

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    Ta c ( )11 cos cos2 2 os 2sin .2x xI dx dx c x d x x Cx x= = = = + c) S dng cc cng thc vi phn ( )( )

    cos sinsin x cos

    u du d udx d x

    =

    =

    Ta c ( ) ( ) ( )3

    31 2212

    2 cos 2 coscos sin cos cos .

    3 3x xI x x dx x d x C= = = = +

    V d 5. Tm nguyn hm ca cc hm s sau:

    a) 313 sin cosI x x dx= b) 14 5sin

    cos

    xI dxx

    = c) 415 sin cosI x xdx= Hng dn gii:

    a) S dng cc cng thc vi phn ( )( )sin coscos sin

    u du d ux dx d x

    =

    =

    Ta c ( ) ( ) ( )1 43 3

    433 41 343 33 13

    3 sinx 3 sinsin cos sinx sin

    4 4

    u du d uxI x x dx d x I C C

    =

    = = = + = +

    b) Ta c ( )4

    14 5 5 4

    cossin (cos ) 1.

    cos cos 4 4cosxx d xI dx C C

    x x x

    = = = + = +

    c) S dng cc cng thc vi phn ( )

    1

    cos sin

    1

    nn

    x dx d x

    uu du d

    n

    +

    =

    = +

    Khi ta c ( )5

    4 554 4

    15 15sin

    sin cos sin sin .5

    uu du d xI x x dx x d x I C

    =

    = = = +

    V d 6. Tm nguyn hm ca cc hm s sau:

    a) 16 tanxI dx= b) 17 sin 4 cos 4I x x dx= c) 18sin

    1 3cosx dxI

    x=

    +

    Hng dn gii:

    a) S dng cc cng thc sin x (cos )

    ln

    dx d xdu

    u Cu

    =

    = +

    Ta c ( )16 cossintan ln cos .cos cos

    d xxdxI x dx x Cx x

    = = = = +

    b) Ta c ( ) ( )17 1 1sin 4 cos 4 sin 4 cos4 4 sin 4 sin 44 4I x x dx x x d x x d x= = = ( )3 322 sin 41 sin 4

    . .

    4 3 6x xC C= + = +

    c) Ta c ( ) ( )18 cos 3cos 1sin 1 1 ln 1 3cos .1 3cos 1 3cos 3 1 3cos 3d x d xx dxI x C

    x x x

    += = = = + +

    + + +

    V d 7. Tm nguyn hm ca cc hm s sau:

    a) ( )19 22cos

    2 5sinx dxI

    x=

    b) 20cos

    4sin x 3x dxI =

    c) ( )21 tan .ln cosI x x dx= Hng dn gii:

    a) S dng cng thc vi phn 2

    cos (sin x)1

    xdx ddu d

    uu

    =

    =

    ( )( )

    ( )( )

    ( ) ( )19 2 2 22 sin 2 5sin2cos 2 2

    .

    5 5 2 5sin2 5sin 2 5sin 2 5sind x d xx dxI C

    xx x x

    = = = = +

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    b) S dng cng thc vi phn ( )cos (sin x)

    2

    xdx ddu d u

    u

    =

    =

    Ta c ( ) ( ) ( )20 sin 4sin 4sin 3cos 1 1 1 4sin x 3 .4 2 24sin x 3 4sin x 3 4sin x 3 2 4sin x 3d x d x d xxdxI C

    = = = = = +

    c) S dng cc cng thc nguyn hm c bn ( )

    2

    cossintan ln cos

    cos cos

    2

    d xxdxxdx x C

    x x

    uu du C

    = = = +

    = +

    Ta c ( ) ( ) ( ) ( ) ( ) ( )21 cossintan .ln cos ln cos ln cos ln cos ln coscos cos

    d xxI x x dx x dx x x d xx x

    = = = = = 2 2

    21ln (cos ) ln (cos )

    .

    2 2x xC I C= + = +

    V d 8. Tm nguyn hm ca cc hm s sau:

    a) 22 2tan

    cos

    xI dxx

    = b) 3

    23 4tancos

    xI dxx

    = c) 24 2tan 2 1cos 2

    xI dxx

    +=

    Hng dn gii:

    a) S dng cc cng thc ( )2

    2

    tancos

    2

    dx d xx

    uu du C

    =

    = +

    Ta c ( )2 2

    22 222 2tan tan tan

    tan . tan tan .2 2cos cos

    x dx x xI dx x x d x C I Cx x

    = = = = + = +

    b) S dng cc cng thc ( )2

    22

    tancos

    1 1 tancos

    dx d xx

    xx

    =

    = +

    Ta c ( ) ( )3 3 3 2 5 323 4 2 2tan 1tan . . tan . 1 tan (tan ) tan tan (tan )cos cos cosx dxI dx x x x d x x x d xx x x= = = + = + 6 4 6 4

    23tan tan tan tan

    .

    6 4 6 4x x x xC I C= + + = + +

    c) S dng cc cng thc ( )2 2

    2

    1 ( ) 1tan( )

    cos cos

    2

    dx d ax d axax a ax a

    uu du C

    = =

    = +

    Ta c 24 2 2 2 2 2tan 2 1 tan 2 1 tan 2 (2 ) 1 (2 )

    2 2cos 2 cos 2 cos 2 cos 2 cos 2x xdx dx x d x d xI dx

    x x x x x

    += = + = +

    2 2

    241 1 tan 2 tan 2 tan 2 tan 2

    tan 2 (tan 2 ) (tan 2 ) .2 2 4 2 4 2

    x x x xx d x d x C I C= + = + + = + +

    V d 9. Tm nguyn hm ca cc hm s sau:

    a) 25 2cotsin

    xI dxx

    = b) 26 3tan

    cos

    xI dxx

    = c) 27cot

    picos

    2

    xI dxx

    =

    +

    Hng dn gii:

    a) S dng cc cng thc ( )2

    2

    cotsin

    2

    dx d xx

    uu du C

    =

    = +

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    Ta c ( )2 2

    25 252 2cot cot cot

    cot . cot cot .2 2sin sin

    x dx x xI dx x x d x C I Cx x

    = = = = + = +

    b) S dng cc cng thc ( )

    1

    sin x cos

    1

    n

    n

    dx d xdu u Cu n

    +

    =

    = + +

    Ta c ( ) ( )3

    26 263 4 4 3 3

    cos costan sin 1 1.

    cos cos cos 3 3cos 3cosd x xx xdxI dx C C I C

    x x x x x

    = = = = + = + = +

    c) S dng cc cng thc

    ( )

    2

    cos sinpi

    cos sin21

    x dx d x

    x x

    du Cu u

    =

    + =

    = +

    Ta c ( )27 272 2cot cos cos (sin ) 1 1

    .

    pi sin . sin sin sin sin sincos

    2

    x x x dx d xI dx dx C I Cx x x x x x

    x

    = = = = = + = +

    +

    V d 10. Tm nguyn hm ca cc hm s sau:

    a) 283 xeI dx

    x= b)

    tan 2

    29 2cos

    xe dxIx

    +

    = c) 21

    30 .xI x e dx=

    d) cos31 sinxI e x dx= e) 2ln 3

    32

    xeI dxx

    +

    =

    Hng dn gii:

    a) S dng cc cng thc ( )2u u

    dx d xx

    e du e C

    =

    = +

    Ta c ( )28 283 3.2 6 6 6 .2x

    x x x xe dxI dx e e d x e C I e Cx x

    = = = = + = +

    b) S dng cc cng thc ( ) ( )2 tan tancos

    u u

    dx d x d x kx

    e du e C

    = =

    = +

    Ta c ( )tan 2

    tan 2 tan 2 tan 2 tan 229 292 2 tan 2 .cos cos

    xx x x xe dx dxI e e d x e C I e C

    x x

    ++ + + +

    = = = + = + = +

    c) S dng cc cng thc ( ) ( )2 21 1 1

    2 2u u

    x dx d x d x

    e du e C

    = =

    = +

    Ta c ( )2 2 2 2 21 1 1 2 1 130 301 1 1. 1 .2 2 2x x x x xI x e dx e x dx e d x e C I e C = = = = + = + d) S dng cc cng thc

    ( )sin cosu u

    x dx d x

    e du e C

    =

    = +

    Ta c ( )cos cos cos cos31 31sin cos .x x x xI e x dx e d x e C I e C= = = + = +

    e) S dng cc cng thc ( ) ( )ln ln

    u u

    dx d x d x kx

    e du e C

    = =

    = +

    Ta c ( ) ( )2ln 3

    2ln 3 2ln 3 2ln 3 2ln 332

    1 1ln 2ln 3 .2 2

    xx x x xe dxI dx e e d x e d x e C

    x x

    ++ + + +

    = = = = + = +

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    Vy 2ln 3

    2ln 332

    1.

    2

    xxeI dx e C

    x

    ++

    = = +

    BI TP LUYN TP: 1) 1 21

    xI dxx

    =

    + 2) 2 10

    2 (1 )I x x dx= + 3) 3cos xI dx

    x=

    4) 4 cos sinI x xdx= 5) 5 3sin

    cos

    xI dxx

    = 6) 36 sin cosI x xdx=

    7) 7 2 5xI dx

    x=

    + 4) 8 2 1

    dxIx

    =

    3) 9 5 2I xdx=

    10) 3

    10ln xI dx

    x= 11)

    2 111 .

    xI x e dx+= 12) 412 sin cosI x xdx=

    13) 13 5sin

    cos

    xI dxx

    = 14) 14 cotI x dx= 15) 15 2tancos

    xI dxx

    =

    16) tan

    16 2cos

    xeI dxx

    = 17) 17xeI dxx

    = 18) 218 1I x x dx= +

    19) 19 5(3 2 )dxI

    x=

    20) 2 320 5I x x dx= + 21) 2

    21 3 1x dxIx

    =

    +

    22) 222 1I x x dx= 23) 23 cos 1 4sinI x x dx= + 24) 224 1I x x dx= +

    25) cos25 sinxI e x dx= 26) 2 2

    26 .xI x e dx+= 27) 27

    sin1 3cos

    x dxIx

    =

    +

    28) 2128 . xI x e dx= 29) ( )sinx29 cos cosI e x x dx= + 30) 2ln 1

    30

    xeI dxx

    +

    =

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  • LUYN THI I HC MN TON Thy Hng Chuyn Nguyn hm Tch phn

    Hc trc tuyn ti: www.moon.vn Mobile: 0985.074.831 1

    1. Vi phn nhm hm a thc, hm cn

    3 4

    1 (4 5 )I x x dx= = ....................................................................................................................................

    32 3

    2 2 1 3 )I x x dx= + = .................................................................................................................................

    3 24 3 2xdxI

    x= =

    ...........................................................................................................................................

    5

    4 61 5xI dx

    x= =

    ..........................................................................................................................................

    3

    5 4

    32 3

    xI dxx

    = =

    + ......................................................................................................................................

    ( )6 222 3xdxI

    x= =

    .........................................................................................................................................

    2

    7 cos(3 4 )I x x dx= = ................................................................................................................................

    3 4

    8 sin(1 5 )I x x dx= + = ...............................................................................................................................

    24 5

    9xI xe dx += = ..........................................................................................................................................

    4

    10 2

    xe dxIx

    = = ................................................................................................................................................

    3

    11 2

    xe dxIx

    = = ..............................................................................................................................................

    12 3dxI

    x x= =

    + ...........................................................................................................................................

    2. Vi phn nhm hm lng gic

    3

    1 sin .cosI x xdx= = ...................................................................................................................................

    5

    2 cos .sinI x xdx= = ...................................................................................................................................

    3 sin . 3cos 2I x x dx= + = .........................................................................................................................

    4

    4 cos . 5 2sinI x xdx= = ..........................................................................................................................

    5sin

    2 5cosxdxI

    x= =

    +......................................................................................................................................

    Ti liu bi ging:

    02. PP VI PHN TM NGUYN HM Thy ng Vit Hng

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    Hc trc tuyn ti: www.moon.vn Mobile: 0985.074.831 2

    6sin

    1 3cosxdxI

    x= =

    ......................................................................................................................................

    ( )7 2cos

    1 2sinxdxI

    x= =

    .....................................................................................................................................

    8sin 2

    7 2cos 2xdxI

    x= =

    ......................................................................................................................................

    9sin 3

    1 2cos3xdxI

    x= =

    + .....................................................................................................................................

    10 2tan3cos

    xdxIx

    = = ...........................................................................................................................................

    11 4tancos

    xdxIx

    = = ............................................................................................................................................

    3cos 2

    12 sin .xI x e dx= = .................................................................................................................................

    2 5sin 2

    13 cos 2 .xI x e dx= = .............................................................................................................................

    2cot 1

    14 2sin

    xeI dxx

    = = ........................................................................................................................................

    15 2sin 4cot 3dxI

    x x= =

    ...........................................................................................................................

    3. Vi phn nhm hm m, loga

    1 2 1

    x

    x

    eI dxe

    = =

    .........................................................................................................................................

    3

    2 31 5

    x

    x

    eI dxe

    = =

    .....................................................................................................................................

    ( )2

    3 221 3

    x

    x

    eI dxe

    = =

    ..................................................................................................................................

    3

    4ln xI dx

    x= = ...........................................................................................................................................

    5 1 5lndxI

    x x= =

    .....................................................................................................................................

    ( )6 22 3lndxI

    x x= =

    + ..................................................................................................................................

    7 2

    ln1 4ln

    xdxIx x

    = =

    ...................................................................................................................................

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    Dng 1. i bin s cho cc hm v t

    Phng php gii:

    Nu hm f(x) c cha ( )n g x th t 1( ) ( ) . '( )n nnt g x t g x n t g x dx= = =

    Khi , ( ) ( )I f x dx h t dt= = , vic tnh nguyn hm ( )h t dt n gin hn so vi vic tnh ( ) .f x dx MT S V D MU: V d 1. Tm nguyn hm ca cc hm s sau:

    a) 1 4 1xdxIx

    =

    + b) 3 22 2I x x dx= + c)

    2

    3 1x dxI

    x=

    Hng dn gii:

    a) t

    2

    2 221

    12 4. 14 24 1 4 1 ( 1)1 84 1

    4

    t tdttdt dxxdx

    t x t x I t dtt txx

    =

    = + = + = = =

    +=

    33 (4 1)1 1 4 1 .8 3 8 3

    xtt C x C

    + = + = + +

    b) t 2 2 2 2 2 3 2 22 2 2 2 2 . ( 2).t x t x x t xdx tdt x dx x xdx t tdt= + = + = = = =

    Khi ( ) ( ) ( ) ( )5 32 25 3

    2 3 2 4 22

    2 2 22 . . 2 2 2.

    5 3 5 3

    x xt tI x x dx t t tdt t t dt C C+ +

    = + = = = + = +

    c) t ( )( )2222 2

    2 32 2

    2 1 .1 1 1 2

    1 1

    dx tdt t tdtx dxt x t x x t I

    tx t x

    =

    = = = = = =

    ( ) ( ) 5 35 322 4 2 (1 ) 2 (1 )22 1 2 2 1 2 2 15 3 5 3x xt t

    t dt t t dt t C x C = = + = + + = + +

    Khi ( ) ( ) ( ) ( )5 32 25 3

    2 3 2 4 22

    2 2 22 . . 2 2 2. .

    5 3 5 3

    x xt tI x x dx t t tdt t t dt C C+ +

    = + = = = + = +

    V d 2. Tm nguyn hm ca cc hm s sau:

    a) 4ln1 ln

    x dxIx x

    =

    + b)

    2

    5 3ln

    2 lnxdxI

    x x=

    c) 6ln 3 2lnx x dxI

    x

    +=

    Hng dn gii:

    a) t ( )2 2

    24

    ln 1 1 .2ln1 ln 1 ln1 ln2

    x t t tdtx dxt x t x Idx

    x txtdtx

    =

    = + = + = =+=

    ( ) 3 332 4(1 ln ) 2 (1 ln )2 1 2 2 1 ln 2 1 ln .3 3 3x xt

    t dt t C x C I x C + + = = + = + + = + +

    b) t 3

    2 3 2 233

    52 3

    ln 2 ln (2 ) .32 ln 2 ln .2 ln3

    x tx dx t t dt

    t x t x Idxx txt dt

    x

    =

    = = = ==

    Ti liu bi ging:

    03. PP I BIN S TM NGUYN HM P1 Thy ng Vit Hng

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    ( ) 8 58 5 3 37 4 2 23(2 ln ) 4 (2 ln )43 4 4 3 2 3 2 (2 ln )8 5 8 5x xt t

    t t t dt t C x C

    = + = + + = + +

    c) t

    2

    2

    3ln23 2ln 3 2ln

    2 2

    tx

    t x t xdx

    tdtx

    == + = +

    =

    T ta c ( )2 4 26 ln 3 2ln 3 1ln 3 2ln . . . 32 2x x dx dx tI x x t tdt t t dtx x +

    = = + = =

    ( ) ( ) ( ) ( )5 3 5 35 5 336

    3 2ln 3 2ln 3 2ln 3 2ln1.

    2 5 10 2 10 2 10 2x x x xt t t

    t C C C I C+ + + +

    = + = + = + = +

    V d 3. Tm nguyn hm ca cc hm s sau:

    a) 71x

    dxIe

    =

    b) ( )2

    8 31

    x

    x

    e dxIe

    =

    + c) 9 2 4

    dxIx x

    =

    + d) 10 4 1

    dxIx x

    =

    +

    Hng dn gii:

    a) t 2

    22

    2

    111 1 2

    21

    xx

    x x

    x

    e te t

    t e t e tdtdxe dx tdtt

    = = = =

    ==

    Khi 7 2 22 2 2 ( 1) ( 1)

    ( 1)( 1) ( 1)( 1) 1 1.( 1) 11xdx tdt dt dt t t dt dtI dt

    t t t t t tt t te

    + = = = = = =

    + + +

    71 1 1 1 1ln 1 ln 1 ln ln ln .1 1 1 1 1

    x x

    x x

    t e et t C C C I C

    t e e

    = + + = + = + = ++

    + +

    b) t ( ) ( )

    ( )22 228 33 3

    1 .21 .1 12 1 1

    x x x xx x

    xx x

    t tdte t e dx e e dxt e t e I

    te dx tdt e e

    = = + = + = = =

    = + +

    ( )2 23 2 2

    1 .2 1 1 12 2 2 2 1 .1

    x

    x

    t tdt t dtdt dt t C e Ctt t t e

    = = = = + + = + + + +

    c) t 2 2

    2 22 2 2

    2 2

    444 42 2

    4

    x tx t

    t x t x dx xdx tdtxdx tdt

    x x t

    = = = + = +

    = = =

    Khi , 9 2 22 21 1 1 ( 2) ( 2) 1

    .

    4 ( 2)( 2) 4 2 24 44 4dx dx tdt dt t t dt dtI dt

    x t t t t tt tx x x

    + = = = = = = + + + +

    ( ) 2 292 21 1 2 1 4 2 1 4 2ln 2 ln 2 ln ln ln .4 4 2 4 44 2 4 2t x x

    t t C C C I Ct x x

    + + = + + = + = + = +

    + + + + +

    d) t 4 2

    4 24 2 4 3

    34 2

    11

    1 14 2

    2( 1)

    x tx t

    t x t x dx x dx tdtx dx tdt

    x x t

    = =

    = + = + = ==

    Khi , 10 2 24 41 1 1 1 ( 1) ( 1)

    . .

    2 4 ( 1)( 1)2( 1) 11 1dx dx tdt dt t tI dt

    x t t tt tx x x

    + = = = = =

    + + +

    ( ) 44

    1 1 1 1 1 1 1ln 1 ln 1 ln ln .4 1 1 4 4 1 4 1 1

    dt dt t xt t C C C

    t t t x

    + = = + + = + = +

    + + + +

    V d 4. Tm nguyn hm ca cc hm s sau:

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    a) 11 1 2 5dxI

    x=

    + b) 12 21 2

    x dxIx

    =

    +

    c) 3

    13 3 24x dxI

    x=

    + d)

    2

    141 4ln lnx xI dx

    x

    +=

    Hng dn gii:

    a) t 2 22 5 2 5 2 55tdt

    t x t x tdt dx dx= = = =

    Khi , ( )11 2 2 1 1 2 1 21 ln 15 1 5 1 5 1 51 2 5dx t dt tI dt dt t t C

    t t tx

    + = = = = = + + + + ++

    ( )11 2 2 5 ln 2 5 1 .5I x x C = + + b) t 2 2 22 2 2 2t x t x tdt xdx xdx tdt= + = + = = Khi , 12 2

    1 (1 ) 1 (1 )1 ln 11 1 1 11 2

    x dx t dt t d tI dt dt dt t t Ct t t tx

    = = = = = = +

    +

    2 212 ln 1 2 2 .I x x C = + + +

    c) t ( )2 3

    2 33 2 3 2 3 3 22

    2

    44 34 4 43 23 22

    x tx t

    t x t x x dx t t dtt dtt dt xdx xdx

    = = = + = + =

    = =

    ( ) ( ) ( ) ( )5 22 23 2 3 33 5

    4 213 3 2

    3 4 3 443 3 34 2 .2 2 2 5 10 44

    x xt t dtx dx tI t t dt t C Ctx

    + +

    = = = = + = + +

    d) t 2 2 2 ln1 4ln 1 4ln 2 4.2ln .4

    dx x dx tdtt x t x tdt x

    x x= + = + = =

    ( )3232 214

    1 4lnln 11 4ln . .4 4 12 12

    xx dx tdt tI x t t dt C Cx

    + = + = = = + = +

    BI TP T LUYN:

    1) 14 3

    1xI dx

    x

    =

    + 2) 2 2 1

    xdxIx

    =

    +

    3) 31xI dx

    x

    += 4) 4 1 1 3

    dxIx

    =

    + +

    5) 7 1 2 1xdxI

    x=

    + 6) 3 26 1I x x dx=

    7) 37 4I x x dx= + 8) 28 3 2I x x dx=

    9) 3

    9 3 21x dxI

    x=

    + 10) 10 3 1

    dxIx x

    =

    +

    11) 11 3 2 4dxI

    x x=

    + 12) 12

    1 3ln lnx xI dxx

    +=

    13) 2

    131 1

    x

    x

    e dxIe

    =

    + 14) ( )14 21

    dxIx x

    =

    +

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    Hc trc tuyn ti: www.moon.vn Mobile: 0985.074.831 1

    Dng 2. PP lng gic ha

    Nu hm f(x) c cha 2 2a x th t 2 2 2 2 2

    (a sin ) cosa sin

    sin cos

    dx d t a t dtx t

    a x a a t a t

    = ==

    = =

    Nu hm f(x) c cha 2 2a x+ th t 2

    2 2 2 2 2

    ( tan )cos

    tan

    tancos

    = =

    = + = + =

    adtdx d a tt

    x a ta

    a x a a tt

    MT S V D MU: V d 1. Tm nguyn hm ca cc hm s sau:

    a) ( )1 2 ; 24= =dxI a

    x b) ( )22 1 ; 1= =I x dx a

    c) ( )23 2 ; 11= =x dxI a

    x d) ( )2 24 9 ; 3= =I x x dx a

    Hng dn gii:

    a) t 12 2 2(2sin ) 2cos 2cos2sin

    2cos4 4 4sin 2cos 4

    dx d t t dt dx t dtx t I dt t C

    tx t t x

    = == = = = = +

    = =

    T php t 12sin arcsin arcsin2 2x x

    x t t I C = = = +

    b) t 2 2

    (sin ) cossin

    1 1 sin cos

    dx d t t dtx t

    x t t

    = ==

    = =

    Khi 221 cos2 1 1 11 cos .cos cos2 sin 2

    2 2 2 2 4t tI x dx t t dt dt dt t dt t C+= = = = + = + +

    T 2 2

    2cos 1 sin 1sin sin 2 2sin .cos 2 1arcsint t x

    x t t t t x xt x

    = = = = =

    =

    22

    arcsin 1 12 2

    xI x x C = + +

    c) t 2 2

    (sin ) cossin

    1 1 sin cos

    dx d t t dtx t

    x t t

    = ==

    = =

    Khi , 2 2

    23 2

    sin .cos 1 os2 1 1sin sin 2

    cos 2 2 41x dx t t dt c tI t dt dt t t C

    tx

    = = = = = +

    T 2 2

    2cos 1 sin 1sin sin 2 2sin .cos 2 1arcsint t x

    x t t t t x xt x

    = = = = =

    =

    23

    arcsin 1 12 2

    xI x x C = +

    d) t 2 2

    (3sin ) 3cos3sin

    9 9 9sin 3cos

    dx d t t dtx t

    x t t

    = ==

    = =

    Khi , 2 2 2 2 2 2481 81 1 os49 9sin .3cos .3cos 81 sin .cos sin 24 4 2

    c tI x x dx t t t dt t t dt t dt dt= = = = =

    Ti liu bi ging:

    03. PP I BIN S TM NGUYN HM P2 Thy ng Vit Hng

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    Hc trc tuyn ti: www.moon.vn Mobile: 0985.074.831 2

    81 1 1 81 1os4 sin 4

    4 2 2 4 2 8tdt c t dt t C = = +

    T

    22

    2cos 1 sin 1 293sin sin 2 13 9

    arcsin3

    xt t

    x xx t t

    xt

    = =

    = =

    =

    Mt khc, 2 2 2 2

    2 2 2 2os2 1 2sin 1 2 1 sin 4 2sin 2 . os2 2. 1 . 13 9 3 9 9x x x x x

    c t t t t c t

    = = = = =

    T ta c 2 2

    4

    arcsin81 23 1 . 1 .4 2 6 9 9

    x

    x x xI C

    = +

    V d 2. Tm nguyn hm ca cc hm s sau:

    a) ( )1 2 ; 11dxI a

    x= =

    + b) 2

    2 2 5I x x dx= + + c) ( )2

    3 2; 2

    4x dxI ax

    = =

    +

    Hng dn gii:

    a) t 2 2

    21 2

    2 2

    (tan ) (1 tan ) (1 tan )tan cos

    1 tan1 1 tan

    dtdx d t t dt t dtx t I dt t Ct

    tx t

    = = = + +

    = = = = ++ + = +

    T gi thit t 1tan arctan arctan .x t t x I x C= = = +

    b) Ta c 12 2 22 2 5 ( 1) 4 ( 1) 4t xI x x dx x d x I t dt= += + + = + + + = +

    t 2

    2 222 2

    2(2 tan ) 2 coscos2 tan 22 cos cos.cos4 4 4 tan

    coscos

    dudt d u du du u duut u Iu u

    ut uuu

    = =

    = = = = + = + =

    2(sin ) 1 (1 sin ) (1 sin ) 1 (sin ) 1 (sin ) 1 1 sin(sin ) ln .

    1 sin 2 (1 sin )(1 sin ) 2 1 sin 2 1 sin 2 1 sind u u u d u d u ud u C

    u u u u u u

    + + += = = + = +

    + +

    T php t 2 2

    2 22 2 2

    1 42 tan tan 1 sin 1 os 12 os 4 4 4t t t

    t u u u c uc u t t

    = = = + = = =+ +

    T ta c 2 2

    2

    2 2

    11 11 1 sin 1 14 2 5ln ln ln .12 1 sin 2 21 1

    4 2 5

    t x

    u t x xI C C Ct xu

    t x x

    ++ +

    + + + += + = + = +

    +

    + + +

    c) t 2

    2

    2 2

    2(2 tan ) 2(1 tan )os2 tan

    4 4 tan 4

    dtdx d t t dtc tx t

    x t

    = = = +

    = + = +

    ( )2 2 2 2 2

    2 23 23 42 2

    4 tan .2(1 tan ) sin sin .cos sin . (sin )4 tan 1 tan 4 4 4cos cos2 1 tan 1 sin

    t t dt t t t dt t d tI t t dt dtt tt t

    + = = + = = =

    +

    t ( )222

    3 2 22

    1 (1 ) (1 )sin 4 4 4

    1 2 (1 )(1 )1u u u u

    u t I du du duu u uu

    + = = = =

    +

    2

    2 2 2 21 1 2 (1 ) (1 ) (1 ) (1 )

    1 1 (1 ) (1 ) (1 )(1 ) (1 ) (1 ) (1 )(1 )du du du d u d u u u dudu

    u u u u u u u u u u

    + + + = = + = +

    + + + + +

    1 1 1 1 1 1 1 1 ln 1 ln 11 1 1 1 1 1 1 1 1 1

    du dudu u u Cu u u u u u u u u u

    + = = + + +

    + + + + +

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    Hc trc tuyn ti: www.moon.vn Mobile: 0985.074.831 3

    31 1 1 1 1 1 1 1 sin 1ln ln ln .

    1 1 1 1 1 1 sin 1 sin 1 sin 1u u tC I C C

    u u u u u u t t t

    = + + = + + = + + + + + + + +

    T gi thit 2 2

    2 2 22 2 2

    1 42 tan tan 1 tan 1 os sin2 os 4 4 4x x x

    x t t t c t tc t x x

    = = = + = + = =+ +

    2

    32

    2 2 2

    11 1 4

    sin ln .4 1 1 1

    4 4 4

    x

    x xt I Cx x xx

    x x x

    + = = + ++

    + ++ + +

    V d 3. Tm nguyn hm ca cc hm s sau:

    a) 1 2 1dxI

    x=

    b) 2 2 2 4dxI

    x x=

    c) 3 2 2 2dxI

    x x=

    Hng dn gii:

    a) t 2

    21 22

    222

    1 coscos

    sin sin1 cossin

    sin sin .cot1 11 cot1 1sin

    t dtt dtdx d dxt t dx t dttx I

    t t txx tx

    t

    = =

    =

    = = =

    = =

    2 2sin (cos ) (cos ) 1 (1 cos ) (1 cos ) 1 1 cos(cos ) ln .sin 1 cos (1 cos )(1 cos ) 2 (1 cos )(1 cos ) 2 1 cos

    t dt d t d t t t td t Ct t t t t t t

    + + += = = = = +

    + +

    T php t

    2

    22 2

    12 2

    111 1 1 1os 1 sin 1 cos ln .

    sin 2 11

    x

    x xx c t t t I Ct x x x

    x

    +

    = = = = = +

    b) t 2 2

    2 2 2222

    2 2cos 2cossin sin2 sin

    8cotsin 4 4 2cot 44 4sinsin

    t dt t dtdx d dxt t t

    xtt

    x t x xxtt

    = = = =

    = =

    =

    Khi , 2 2 2 22

    2cos 1 1sin cos .8cot 4 44 sin .

    sin

    dx t dtI t dt t Ctx x tt

    = = = = +

    T 2 2

    2 222

    2 4 4 4os 1 sin 1 cos .

    sin 4x x

    x c t t t I Ct x x x

    = = = = = +

    c) ( )

    13 32 2 2 22

    ( 1)2 2 ( 1) 3 3 3

    t xdx d x dt dtI Ix x x t t

    =

    = = = =

    t 2

    2

    222

    3 3 cos3 cos

    sin sin3sin

    sin 3 3 3 cot3 3sin

    u dudt d u dudtu ut u

    ut ut

    u

    = = = =

    =

    =

    3 2 222

    3 cos sin (cos ) (cos )sin 1 cos (1 cos )(1 cos )sin . 3 cot3

    dt u du u du d u d uIu u u uu ut

    = = = = = +

    1 (1 cos ) (1 cos ) 1 1 cos(cos ) ln .2 (1 cos )(1 cos ) 2 1 cos

    u u ud u Cu u u

    + + += = +

    +

    T

    2 2

    22

    32 2 2

    3 2 21 13 3 3 1 1 1os 1 cos ln ln .sin 2 23 2 21 1

    1

    t x xt t xt c u t I C C

    u t t t x xt x

    + +

    = = = = + = +

    Ch : Tng hp cc kt qu ta thu mt s kt qu quan trng sau:

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    Hc trc tuyn ti: www.moon.vn Mobile: 0985.074.831 4

    2 21

    arc tan .dx x C

    x a a a

    = + +

    2 21 ln .

    2dx x a C

    x a a x a

    += +

    2 21 ln .

    2dx x a C

    a x a x a

    = + +

    2

    2ln .dx x x a C

    x a= + +

    BI TP LUYN TP:

    1) 2

    1 2 4x dxIx

    =

    + 2)

    2

    2 21 xI dxx

    = 3) 2

    3 24x dxI

    x=

    4) 4 21

    3 2I dx

    x x=

    5) 25 2 1I x dx= + 6) 6 22 5dxIx

    =

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    Xt nguyn hm ca hm phn thc hu t ( )( )P xI dxQ x=

    Nguyn tc gii: Khi bc ca t s P(x) ln hn Q(x) th ta phi chia a thc quy v nguyn hm c bc ca t s nh hn mu s. I. MU S L BC NHT

    Khi Q(x) = ax + b. Nu bc ca P(x) ln hn th ta chia a thc. Khi P(x) l hng s (bc bng 0) th ta c ( ) (ax ) ln ax .( ) ax ax

    P x k k d b kI dx dx b CQ x b a b a+

    = = = = + ++ +

    V d 1. Tm nguyn hm ca cc hm s sau:

    a) 14

    2 1I dx

    x=

    b) 211

    xI dxx

    +=

    c) 32 13 4

    xI dxx

    +=

    d) 2

    44

    3x xI

    x

    + +=

    +

    Hng dn gii:

    a) Ta c 14 4 (2 1) 2ln 2 1 .

    2 1 2 2 1d xI dx x C

    x x

    = = = +

    b) 21 1 2 21 2 2ln 1 .1 1 1 1

    x x dxI dx dx dx dx x x Cx x x x

    + + = = = + = + = + +

    c) ( )

    ( )( )

    3

    1 53 4 3 42 1 1 5 1 5 1 52 23 4 3 4 2 2 3 4 2 2 3 4 2 8 3 4

    x d xx dxI dx dx dx x xx x x x x

    + +

    = = = + = + =

    31 5 1 5ln 3 4 ln 3 4 .2 8 2 8

    x x C I x x C= + = +

    d) ( ) ( )2 2

    4

    34 102 2 10 2 10ln 3 .3 3 3 2

    d xx x xI x dx x dx x x Cx x x

    ++ + = = + = + = + + + + + +

    V d 2. Tm nguyn hm ca cc hm s sau:

    a) 3

    57

    2 5x xI dx

    x

    +=

    + b)

    3 2

    63 3 2

    1x x xI dx

    x

    + + +=

    c) 4 2

    74 3 2

    2 1x x xI dx

    x

    + + +=

    +

    Hng dn gii:

    a) Chia t s cho mu s ta c 3

    2

    497 1 5 21 8

    2 5 2 4 8 2 5x x

    x xx x

    += +

    + +

    Khi 3

    2 25

    497 1 5 21 1 5 21 498

    2 5 2 4 8 2 5 2 4 8 8 2 5x x dxI dx x x dx x x dx

    x x x

    + = = + = + + + +

    ( )3 2 3 22 51 5 21 49 5 21 49. . ln 2 5 .

    2 3 4 2 8 16 2 5 6 8 8 16d xx x x x x

    x x Cx

    += + = + + +

    +

    b) Ta c 3 2

    2 3 26

    3 3 2 93 6 7 3 7 9ln 1 .1 1

    x x xI dx x x dx x x x x Cx x

    + + + = = + + + = + + + +

    c) Chia t s cho mu s ta c 4 2

    3 2

    54 3 2 1 22 2

    2 1 2 2 1x x x

    x x xx x

    + + += + +

    + +

    Ti liu bi ging:

    04. NGUYN HM CA HM HU T - P1 Thy ng Vit Hng

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    Hc trc tuyn ti: www.moon.vn Mobile: 0985.074.831 2

    Khi 4 2

    3 2 3 27

    54 3 2 1 1 522 2 2 2

    2 1 2 2 1 2 2 2 1x x x dxI dx x x x dx x x x dx

    x x x

    + + +

    = = + + = + + + + +

    ( )4 3 4 32 22 11 5 1 52. ln 2 1 .4 3 2 4 2 1 2 3 2 4

    d xx x x xx x x x x C

    x

    += + + = + + + +

    +

    BI TP LUYN TP:

    1) 12 1

    3xI dx

    x

    =

    + 2)

    2

    23 1

    1x xI dx

    x

    + =

    + 3)

    3 2

    33 3 2

    1x x xI dx

    x

    + + +=

    4) 3

    47

    2 5x xI dx

    x

    +=

    + 5) 5

    14 3xI dx

    x

    +=

    4) 4 2

    65 3

    3 1x x xI dx

    x

    +=

    +

    II. MU S L TAM THC BC HAI

    Khi Q(x) = ax2 + bx + c. Ta c ba kh nng xy ra vi Q(x). TH1: Q(x) = 0 c 2 nghim phn bit x1 v x2 Nu P(x) l hng s th ta s dng thut phn tch t s c cha nghim ca mu s. Nu P(x) bc nht th ta c phn tch ( )( ) ( )( )1 2 1 2 1 2

    ( ) ( ) 1( ) ( )P x P x A BQ x a x x x x Q x a x x x x a x x x x

    = = = +

    ng nht h s hai v ta c A, B. T , quy v bi ton nguyn hm c mu s l hm bc nht xt trn. Nu P(x) c bc ln hn hoc bng 2 th ta chia a thc, quy bi ton v hai trng hp c bc ca P(x) nh trn gii. Ch : Vic phn tch a thc thnh nhn t vi cc phng trnh bc hai c h s a khc 1 phi theo quy tc

    ( )( )2 1 2+ + = ax bx c a x x x x

    V d: 2( 1)(3 1) : '.

    3 4 1 1( 1) : .3

    x x dungx x

    x x sai

    + =

    Khi t s l bc nht th ngoi cch ng nht trn, ta c th phn tch t s c cha o hm ca mu, ri tch thnh 2 nguyn hm (xem cc v d di y). V d 1. Tm nguyn hm ca cc hm s sau:

    a) 1 2 2 3dxI dx

    x x=

    b) 2 22

    3 4 1dxI

    x x=

    +

    c) 3 22 3

    3 4xI dx

    x x

    +=

    d) 4 23 4

    5 6 1xI dx

    x x

    +=

    + +

    Hng dn gii:

    a) 1 21 ( 1) ( 3) 1 1 3ln .( 1)( 3) 4 ( 1)( 3) 4 3 1 4 12 3

    dx dx x x dx dx xI dx dx Cx x x x x x xx x

    + = = = = = + + + + +

    b) 2 2 22 2 (3 1) 3( 1)2 2

    3 4 1 3 4 1 ( 1)(3 1) 4 ( 1)(3 1)dx dx dx x xI dx

    x x x x x x x x

    = = = =

    + +

    1 1 1 (3 1) 1 1 1 3 13 ln 1 ln 1 ln 3 1 ln .2 1 3 1 2 2 3 1 2 2 2 1

    dx dx d x xx x x C C

    x x x x

    = = + = + + = +

    c) 3 22 3

    3 4xI dx

    x x

    +=

    Cch 1:

    Nhn thy mu s c hai nghim x = 1 v x = 4, khi ( )( )22 3 2 3

    1 4 1 43 4x x A B

    x x x xx x

    + += = +

    + +

    ng nht ta c ( ) ( )1

    2 52 3 4 13 4 11

    5

    AA Bx A x B x

    A B B

    = = +

    + + + = +

    =

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    T 3 2

    1 112 3 1 11 1 115 5 ln 1 ln 4 .

    1 4 5 1 5 4 5 53 4x dx dxI dx dx x x C

    x x x xx x

    +

    = = + = + = + + + + +

    Vy 31 11ln 1 ln 4 .5 5

    I x x C= + + +

    Cch 2: Do mu s c o hm l 2x 3 nn ta s phn tch t s c cha o hm ca mu nh sau:

    ( )23 2 2 2 2 2

    3 42 3 2 3 6 (2 3) 6 6 ( 1)( 4)3 4 3 4 3 4 3 4 3 4d x xx x x dx dx dxI dx dx

    x xx x x x x x x x x x

    + + = = = + = +

    +

    2 2 26 ( 1) ( 4) 6 6 4ln 3 4 ln 3 4 ln 3 4 ln .5 ( 1)( 4) 5 4 1 5 1

    x x dx dx xx x dx x x x x C

    x x x x x

    + = + = + = + + + + +

    Nhn xt: Nhn hai cch gii, thot nhn chng ta lm tng l bi ton ra hai p s. Nhng, ch bng mt vi php bin i logarith n gin ta c ngay cng kt qu. Tht vy, theo cch 2 ta c:

    2 6 4 6 6 1 11ln 3 4 ln ln 4 ln 1 ln 4 ln 1 ln 1 ln 4 .5 1 5 5 5 5

    xx x x x x x C x x

    x

    + = + + + + + = + + +

    R rng, chng ta thy ngay u im ca cch 2 l khng phi ng nht, v cng khng cn dng n giy nhp ta c th gii quyt nhanh gn bi ton, v l iu m ti mong mun cc bn thc hin c!

    d) 4 23 4 3 4

    5 6 1 ( 1)(5 1)x xI dx dx

    x x x x

    + += =

    + + + +

    Cch 1:

    Ta c

    13 53 4 43 4 (5 1) ( 1)4 17( 1)(5 1) 1 5 1

    4

    AA Bx A Bx A x B x

    A Bx x x x B

    = = ++

    = + + + + + = ++ + + +

    =

    T 43 4 1 17 1 17

    ( 1)(5 6) 4( 1) 4(5 1) 4 1 4 5 1x dx dxI dx dx

    x x x x x x

    += = + = +

    + + + + + +

    41 17ln 1 ln 5 1 .4 20

    I x x C = + + + +

    Cch 2: Do mu s c o hm l 10x + 6 nn ta s phn tch t s c cha o hm ca mu nh sau:

    ( ) ( )4 2 2 2 2

    3 2210 6 10 63 4 3 2210 105 6 1 5 6 1 10 5 6 1 10 5 6 1

    x xx dxI dx dx dxx x x x x x x x

    + + ++= = = +

    + + + + + + + +

    ( )2 22

    5 6 13 22 3 22 (5 1) 5( 1)ln 5 6 110 5 6 1 10 (5 1)( 1) 10 40 (5 1)( 1)

    d x x dx x xx x dx

    x x x x x x

    + + + += + = + +

    + + + + + +

    2 23 22 5 3 11 1ln 5 6 1 ln 5 6 1 ln .10 40 1 5 1 10 20 5 1

    dx dx xx x x x C

    x x x

    + = + + = + + + + + +

    V d 2. Tm nguyn hm ca cc hm s sau:

    a) 3

    5 24 2 1

    1x xI dx

    x

    + =

    b) 6 25

    3 2xI dx

    x x

    =

    Hng dn gii:

    a) Do t s c bc ln hn mu nn chia a thc ta c 3

    5 2 24 2 1 6 14

    1 1x x xI dx x dx

    x x

    + = = +

    Ta c 2

    766 1 6 1 26 1 ( 1) ( 1)

    1 51 ( 1)( 1) 1 12

    AA Bx x A Bx A x B x

    A Bx x x x x B

    == +

    = = + + + = + + +

    =

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    ( ) ( )2

    57 5 7 54 2 ln 1 ln 1 .

    2 1 2 1 2 2I x dx x x x C

    x x

    = + + = + + + + +

    b) Ta c 2 25 5 5 5 ( 3) ( 1)

    3 2 2 3 ( 1)( 3) 1 3x x x A B

    x A x B xx x x x x x x x

    = = = + + + + + +

    6 2

    1 1 5 1 2 25 3 2 1 3 1 33 2

    A B A x dx dxI dx dxA B B x x x xx x

    = + = = = + = +

    = = + +

    ( ) ( )2 26

    3 3ln 1 2ln 3 ln ln .

    1 1x x

    x x C C I Cx x

    = + + + = + = +

    BI TP LUYN TP:

    1) 1 22 1

    3 2xI dx

    x x

    =

    + + 2) 2 2

    3 45 6 1

    xI dxx x

    +=

    + + 3)

    2

    3 23 1

    2 3 1xI dx

    x x

    +=

    + +

    4) 4 25 4

    3 2xI dx

    x x

    +=

    5) 5 25 3

    2 1xI dx

    x x

    +=

    6) 6 21 5

    4 5 1xI dx

    x x

    =

    + +

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    Xt nguyn hm ca hm phn thc hu t ( )( )P xI dxQ x=

    Nguyn tc gii: Khi bc ca t s P(x) ln hn Q(x) th ta phi chia a thc quy v nguyn hm c bc ca t s nh hn mu s. II. MU S L TAM THC BC HAI (tip theo)

    Khi Q(x) = ax2 + bx + c. Ta c ba kh nng xy ra vi Q(x). TH1: Q(x) = 0 c 2 nghim phn bit x1 v x2 TH2: Q(x) = 0 c nghim kp

    Khi Q(x) c biu din di dng ( ) ( )2

    2( )( ) = + =+

    P xQ x ax b I dx

    ax b

    Nu P(x) l hng s th ta s dng cc bin i sau ( )

    2

    1

    1

    = +

    = +

    dx d ax ba

    du Cuu

    Nu ( )( )

    ( ) ( )2 2 2( )+ +

    + = + = = = + + + + +

    m bmax b n

    mx n m dx bm dxa aP x mx n I dx dx na ax b aax b ax b ax b

    ( ) ( )( )2 2 2 2

    1ln .+ +

    = + = + + + + +

    bmnd ax b d ax bm m na bma ax b C

    ax b a ax ba a aax b

    Nu P(x) c bc ln hn hoc bng 2 th ta chia a thc, quy bi ton v hai trng hp c bc ca P(x) nh trn gii. Ch :

    Ngoi cch gii nu trn, dng nguyn hm ny c cch gii tng qut l t t b

    xt ax b a

    dt adx

    =

    = + =

    V d 1. Tm nguyn hm ca cc hm s sau:

    a) 1 22

    2 1dxI

    x x=

    + b) 2 26 9 1dxI

    x x=

    + + c) 3 225 10 1

    dxIx x

    =

    +

    Hng dn gii:

    a) 1 12 2 22 ( 1) 2 22 2 .

    1 12 1 ( 1) ( 1)dx dx d xI C I C

    x xx x x x

    = = = = + = + +

    b) 2 22 2 21 (3 1) 1 1

    .

    6 9 1 (3 1) 3 (3 1) 3(3 1) 3(3 1)dx dx d xI C I C

    x x x x x x

    += = = = + = +

    + + + + + +

    c) 3 32 2 21 (5 1) 1 1

    .

    25 10 1 (5 1) 5 (5 1) 5(5 1) 5(5 1)

    = = = = + = + + dx dx d xI C I C

    x x x x x x

    V d 2. Tm nguyn hm ca cc hm s sau:

    a) 4 22 1

    4 4 1xI dx

    x x

    =

    + + b) 2

    5 24 3

    4 12 9xI dx

    x x

    =

    + + c) 6 2

    1 59 24 16

    xI dxx x

    =

    +

    Hng dn gii:

    a) ( )4 2 22 1 2 1

    4 4 1 2 1x xI dx dx

    x x x

    = =

    + + +

    Ti liu bi ging:

    04. NGUYN HM CA HM HU T - P2 Thy ng Vit Hng

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    Cch 1:

    t ( )4 2 2 22 1 2 1 2 1 2 1 12 1 ln

    2 2 2 22 1

    x t x t dt dt dtt x I dx t C

    dt dx t tt tx=

    = + = = = = + + = +

    41 1ln 2 1 .2 2 1

    I x Cx

    = + + ++

    Cch 2:

    ( ) ( )( )

    ( ) ( )( )

    2

    4 2 2 2 2 2 2

    1 8 4 2 4 4 18 4 2 12 1 1 14 24 44 4 1 4 4 1 4 4 1 4 4 12 1 2 1

    x d x xx d xx dxI dx dx dxx x x x x x x xx x

    + + ++ +

    = = = =

    + + + + + + + ++ +

    ( ) ( )( )

    22

    2 2

    4 4 1 2 11 1 1 1 1ln 4 4 1 ln 2 1 .4 4 2 1 2 2 14 4 1 2 1

    d x x d xx x C x C

    x xx x x

    + + += = + + + + = + + +

    + ++ + +

    b) ( )( )

    ( )2

    5 2 22 2

    2 34 3 12 12 61 12 6 .4 12 9 4 12 9 2 32 3 2 3

    d xx x dxI dx dx dx x x Cx x x x xx x

    + +

    = = = = = + + + + + + + + +

    c) ( )6 2 21 5 1 5

    9 24 16 3 4x xI dx dx

    x x x

    = =

    +

    Cch 1:

    t ( )6 2 2 25( 4)4 11 5 1 5 1733 4 3

    3 93 43

    ttx x dt t

    t x I dx dtt txdt dx

    ++

    = +

    = = = = =

    61 17 1 17 5 175ln 5ln 3 4 ln 3 4 .9 9 3 4 9 9(3 4)t C I x C x Ct x x

    = + = + = + +

    Cch 2:

    ( )( )( ) ( )

    ( ) ( )( )6 2 2 2 2

    5 173 4 3 4 3 41 5 5 17 5 173 33 3 4 3 9 3 4 93 4 3 4 3 4 3 4

    x d x d xx dx dxI dx dxx xx x x x

    = = = =

    ( )65 17 1 5 17ln 3 4 . ln 3 4 .9 9 3 4 9 9 3 4

    x C I x Cx x

    = + + = + +

    TH3: Q(x) = 0 v nghim

    Khi , Q(x) c biu din di dng ( )2 2

    22 24( )2 4

    = + + = + + + +

    b ac bQ x ax b c a x mx n ka a

    Nu P(x) l hng s th ta s dng cc bin i sau ( )

    2 2

    1

    1arctan

    = +

    = + +

    dx d ax ba

    du u Ca au a

    Nu P(x) = x + th ta c phn tch sau: ( ) ( )

    2 2 2 2

    2 2 2 2 2 2

    + + ++ = = = +

    + + + + + + + +

    bax b ax b dxx b dxa aI dx dx dx

    a aax bx c ax bx c ax bx c ax bx c

    ( )2 22 2 22 2

    2

    2 ln

    2 2 24 42 4 2 4

    + + = + = + + +

    + + + + + +

    bd ax bx c b dx dxadx ax bx c

    a a a aax bx c b ac b b ac ba x x

    a a a a

    2 22 2 2 2

    2

    2 22 22ln ln arctan .2 24 4 4

    2 4

    b bb d xax ba aaax bx c ax bx c C

    a a ab ac b ac b ac bx

    a a

    +

    + = + + + = + + + +

    + +

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    Nu P(x) c bc ln hn hoc bng 2 th ta chia a thc, quy bi ton v hai trng hp c bc ca P(x) nh trn gii. Nhn xt: Nhn vo biu thc ca bi ton tng qut trn c th ban u lm cho cc bn pht hong, nhng ng qu bn tm n n, bn ch cn nm c tng thc hin ca n l phn tch t s c cha o hm ca mu s, ri tch thnh hai bi ton nh hn u thuc dng n gin hc.

    V d 1. Tm nguyn hm ca cc hm s sau:

    a) 1 2 2 3dxI

    x x=

    + + b) 2 24 4 2dxI

    x x=

    + + c) 3 29 24 20

    dxIx x

    =

    + +

    Hng dn gii:

    a) ( )( )

    ( ) ( )1 2 2 221 1 1

    arctan .2 3 2 21 2 1 2

    d xdx dx xI Cx x x x

    + + = = = = +

    + + + + + +

    b) ( )( )

    ( ) ( )2 2 22 22 11 1

    arctan 2 1 .4 4 2 2 22 1 1 2 1 1

    d xdx dxI x Cx x x x

    += = = = + +

    + + + + + +

    c) ( )( )

    ( )3 2 2 2 23 4 1 3 4

    arctan .2 29 24 20 3 4 4 3 4 2

    d xdx dx xI Cx x x x

    + + = = = = +

    + + + + + +

    V d 2. Tm nguyn hm ca cc hm s sau:

    a) 4 23 5

    2 10xI dx

    x x

    +=

    + + b) 5 24 1

    6 9 4xI dx

    x x

    =

    + + c)

    4

    6 22

    2 7x xI dx

    x x

    =

    + +

    Hng dn gii:

    a) ( ) ( )

    4 2 2 2 2

    3 174 1 4 13 5 3 174 44 42 10 2 10 2 10 2 10

    x x dxx dxI dx dxx x x x x x x x

    + + ++= = = +

    + + + + + + + +

    ( ) ( )2

    22 2

    2

    2 103 17 3 17ln 2 104 8 4 82 10 1 795

    2 4 16

    d x x dx dxx x

    xx x x x

    + += + = + + +

    + + + + + +

    ( ) ( )2 2221

    3 17 3 17 4 4 14ln 2 10 ln 2 10 . arctan .4 8 4 8 79 791 79

    4 4

    d xx

    x x x x C

    x

    + +

    = + + + = + + + +

    + +

    Vy ( )24 3 17 4 1ln 2 10 arctan .4 2 79 79xI x x C += + + + +

    b) ( ) ( )

    5 2 2 2 2

    1 12 9 4 12 94 1 13 46 9 4 6 9 4 3 6 9 4 6 9 4

    x x dxx dxI dx dx dxx x x x x x x x

    + +

    = = =

    + + + + + + + +

    ( )( ) ( )

    ( )( ) ( )

    22

    2 22 2

    6 9 4 3 11 1 44 ln 6 9 43 6 9 4 3 33 1 3 3 1 3

    d x x d xdxdx x xx x x x

    + + += = + +

    + + + + + +

    ( ) ( )2 251 4 1 3 1 1 4 3 1ln 6 9 4 . arctan ln 6 9 4 arctan .3 3 33 3 3 3 3x x

    x x C I x x C+ + = + + + = + + +

    c) 4 3

    2 26 2 2 2

    2 25 7 2 25 72 4 1 232 7 2 7 2 7

    x x x x xI dx x x dx x x dxx x x x x x

    = = + + = + +

    + + + + + +

    t ( ) ( )

    2 2 2 2

    25 2 2 32 2 225 7 252 3222 7 2 7 2 7 2 7

    x x dxx dxJ dx dx dxx x x x x x x x

    + +

    = = =

    + + + + + + + +

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    ( )( ) ( )

    ( )( ) ( )

    22

    2 2 22

    2 7 125 2532 ln 2 7 322 22 7 1 6 1 6

    d x x d xdxdx x xx x x x

    + + += = + +

    + + + + + +

    ( ) ( )32 2 2625 32 1 2 25 32 1ln 2 7 arctan 2 ln 2 7 arctan .2 3 26 6 6 6x x x

    x x I x x x x C + ++ + = + + + + +

    Tng kt: Qua ba phn trnh by v hm phn thc c mu s l bc hai, chng ta nhn thy im mu cht gii quyt bi ton l x l mu s.

    Nu

    ( )( )

    ( )( )

    21 2 2

    1 2

    22 22 2 2

    222

    ( ) 1

    ( ) 1arctan

    1

    + + = = +

    + +

    + + = + + = ++ + +

    + + = + = +

    P x A Bax bx c a x x x x

    a x x x xax bx cP x du u

    ax bx c mx n k Cax bx c u

    duax bx c mx n C

    uu

    BI TP LUYN TP:

    7) 7 24 1

    2 1xI dx

    x x

    =

    + + 8) 8 2

    3 74 4 1

    xI dxx x

    +=

    + + 9)

    2

    9 23 1

    9 6 1xI dx

    x x

    +=

    + +

    10) 2

    10 24 3 14 4 1

    x xI dxx x

    +=

    + 11)

    2

    11 22 3 2

    4 4x xI dx

    x x

    + +=

    + 12) 12 2

    3 26 9

    xI dxx x

    =

    +

    13) 13 22 3

    4 5xI dx

    x x

    =

    + 14) 14 2

    3 12

    xI dxx x

    +=

    + + 15) 15 22 1

    dxIx x

    =

    +

    16) 16 22 1

    4xI dx

    x x

    =

    + 17) 17 2

    14 1

    xI dxx x

    +=

    + + 18) 18 2

    4 11

    xI dxx x

    +=

    +

    III. MU S L A THC BC BA

    Khi Q(x) = ax3 + bx2 + cx + d. Ta c bn kh nng xy ra vi Q(x). TH1: Q(x) = 0 c 3 nghim phn bit x1; x2; x3 Tng t nh trng hp mu s l bc hai c hai nghim phn bit. Ta c cch gii truyn thng l phn tch v ng nht h s. Ngoi ra ta cn c th s dng phng php bin i t s cha o hm ca mu (ty thuc vo biu thc ca t s l bc my) Ta c ( )( )( )3 2 1 2 3

    1 2 3

    ( )( ) ax ( )P x A B CQ x bx cx d a x x x x x x Q x x x x x x x= + + + = = + +

    ng nht h s hai v ta c A, B, C. Bi ton quy v nguyn hm c mu s l bc nht xt trn. Ch : vic ng nht c, th ta vn phi tun th nguyn tc l bin i sao cho bc ca t s phi nh hn bc ca mu s. V d 1. Tm nguyn hm ca cc hm s sau:

    a) ( )( )1 22 9dxI

    x x=

    b) ( )2

    2 2

    6 21

    x xI dxx x

    + =

    c) ( )4 2

    3 2

    3 3 72

    x x xI dxx x x

    + =

    +

    Hng dn gii:

    a) ( )( ) ( )( )( )1 2 2 3 32 9dx dxI

    x x xx x= =

    +

    Ta c ( )( )( )21 1 ( 9) ( 2)( 3) ( 2)( 3)

    2 3 3 2 3 3A B C A x B x x C x x

    x x x x x x= + + + + +

    + +

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    150

    10 530

    1 9 6 6 16

    AA B C

    B C BA B C

    C

    =

    = + +

    = + =

    = + =

    Nhn xt: Ngoi cch gii truyn thng trn, chng ta c th bin i cch khc nh sau m khng mt nhiu thi gian cho vic tnh ton, suy ngh:

    ( )( )( ) ( )( )( ) ( )( ) ( )( )11 ( 3) ( 3) 1 1

    2 3 3 6 2 3 3 6 2 3 6 2 3+

    = = =

    + + + dx x x dx dxI dx dx

    x x x x x x x x x x

    n y, bi ton tr v cc dng bin i n gin xt n!

    b) ( ) ( )( )2 2

    2 2

    6 2 6 21 11

    x x x xI dx dxx x xx x

    + + = =

    +

    Cch 1: Ta c ( )( )2

    2 26 2 6 2 ( 1) ( 1) ( 1)1 1 1 1

    x x A B Cx x A x Bx x Cx x

    x x x x x x

    + = + + + + + +

    + +

    2

    2 3 563 2 3 52 21 2ln ln 1 ln 1 .2 1 1 2 2

    2 52

    AA B CB C B I dx x x x C

    x x xA

    C

    = = + +

    = + = = + + = + + + + +

    = =

    Cch 2: ( )( ) ( ) ( ) ( )2 22

    2 3 3 3 32

    2 3 1 1 1 3 1 16 2 21

    x x x dx x dxx x dxI dx dx dxx x x x x x x xx x

    + + +

    = = = + + =

    ( )3 332 2ln( 1) ( 1)( 1)

    d x x dx dxdx x x J Kx x x x xx x

    = + + = + ++ +

    Vi ( 1) 1 1 ln ln 1 ln( 1) ( 1) 1 1dx x x xJ dx dx x x

    x x x x x x x

    + = = = = + = + + + +

    ( 1) ( 1) 1 ( 1) ( 1)( 1)( 1) ( 1)( 1) ( 1) ( 1)( 1) ( 1) 2 ( 1)( 1)

    dx x x dx dx x x x xK dx dx dxx x x x x x x x x x x x x x

    + + = = = = =

    + + + +

    ( 1) 1 ( 1) ( 1) 1 1 1 1 1 1 1 1ln ln( 1) 2 ( 1)( 1) 1 2 1 1 2 1x x x x x xdx dx dx dxx x x x x x x x x x

    + = = =

    + + +

    T ta c 321 1 12ln ln ln ln .

    1 2 1x x xI x x C

    x x x

    = + + ++ +

    Nhn xt: Cch phn tch nh trn vn cha thc s ti u, cc em hy tm li gii khc thng minh hn nh!

    c) ( ) ( )4 2 2 2

    3 2 2

    3 3 7 8 3 7 33 3 322 2

    x x x x x xI dx x dx x Jx x x x x x

    + + = = + = +

    + +

    Vi ( ) ( )( )2 2

    2

    8 3 7 8 3 71 22

    x x x xJ dx dxx x xx x x

    + += =

    ++

    Ta c ( )( )2

    28 3 7 8 3 7 ( 1)( 2) ( 2) ( 1)1 2 1 2

    x x A B Cx x A x x Bx x Cx x

    x x x x x x

    += + + + + + + +

    + +

    77 158 2 4 7 152 23 2 4 ln 4ln 1 ln 2 .

    1 2 2 27 2 15

    2

    AA B CA B C B J dx x x x C

    x x xA C

    = = + +

    = + = = + + = + + + +

    + = =

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    Vy 2

    33 7 153 ln 4ln 1 ln 2 .2 2 2xI x x x x C= + + + +

    BI TP LUYN TP:

    1) 1 2( 1)dxI

    x x=

    2) 2 22 1

    ( 1)( 9)xI dx

    x x

    +=

    + 3)

    2

    3 21

    ( 2)( 4 3)x xI dx

    x x x

    + +=

    + + +

    4) 4 25 2

    (1 )(4 )xI dx

    x x

    +=

    + 5) 5 2

    1( 4)xI dx

    x x

    +=

    6) 2

    6 2( 1)( 2)xI dx

    x x=

    +

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  • LUYN THI I HC MN TON Thy Hng Chuyn Nguyn hm Tch phn

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    Xt nguyn hm ca hm phn thc hu t ( )( )P xI dxQ x=

    Nguyn tc gii: Khi bc ca t s P(x) ln hn Q(x) th ta phi chia a thc quy v nguyn hm c bc ca t s nh hn mu s. III. MU S L A THC BC BA

    Khi Q(x) = ax3 + bx2 + cx + d. Ta c bn kh nng xy ra vi Q(x). TH1: Q(x) = 0 c 3 nghim phn bit x1; x2; x3 TH2: Q(x) = 0 c 2 nghim: mt nghim n, mt nghim kp Khi ta c ( )( )23 2 1 2( ) = + + + = Q x ax bx cx d a x x x x ng nht c, ta phi phn tch theo quy tc: ( )( ) ( )2 211 2 2

    ( ) ( )( )

    P x P x A Bx CQ x x xa x x x x x x

    += = +

    ng nht h s hai v ta c A, B, C. Bi ton tr v cc dng c bn xt n. Ch : Ngoi vic s dng ng nht, ta cng c th phn tch t s theo o hm ca mu gii. V d 1. Tm nguyn hm ca cc hm s sau:

    a) ( )1 2 2dxI

    x x=

    + b) ( ) ( )2 21

    1 2 3xI dx

    x x

    =

    + c) ( )

    2

    3 22 4

    2 1x xI dx

    x x

    + +=

    Hng dn gii:

    a) Xt ( )1 2 2dxI

    x x=

    +

    Cch 1: (ng nht hai v)

    Ta c ( ) ( )( )2

    2 2

    140

    1 11 Ax 2 0 22 42

    1 2 12

    AA B

    A Bx C Bx C x B C Bxx x x C

    C

    =

    = + +

    = + + + + = + = ++

    = =

    Khi , ( )1 2 2 21 1 1

    1 1 1 1 2 14 4 2 ln .2 4 2 4 2 4 22

    xdx dx dx dx xI dx Cx x x x xx x x x

    + +

    = = + = + = + + ++

    Cch 2: (S dng k thut phn tch nhy tng lu ta c)

    ( )

    ( )( )

    2 2

    2 3 2 3 2 3 2 3 2 3 2

    2 2

    13 2 2 2 3 2 2

    3 2

    3 2

    1 1 1 3 4 3 ( 2) 2 4 1 3 4 3 ( 2) 2 4.

    4 42 2 2 2 2 2

    1 3 4 3 2 1 3 4 3 14 4 4 22 2 2

    21 3 1 1ln ln4 4 2 42

    x x x x x x x x x x

    x x x x x x x x x x x x

    x x dx x x dx dxI dxx xx x x x x x x x

    d x xdx x

    xx x

    + + + + + + += = = + =

    + + + + + +

    + += + = = + =

    + + +

    += =

    +

    3 2 3 2

    13 1 1 3 12 ln ln 2 ln .4 2 4 4 2

    x x x C I x x x Cx x

    + + = + +

    b) ( )( ) ( ) ( ) ( )2 2 21 2 21

    2 51 2 1 5x tI d x dt

    t tx x

    +

    = + = + +

    , vi t = x + 1.

    Cch 1: (ng nht hai v)

    Ti liu bi ging:

    04. NGUYN HM CA HM HU T - P3 Thy ng Vit Hng

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  • LUYN THI I HC MN TON Thy Hng Chuyn Nguyn hm Tch phn

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    Ta c ( ) ( )( )2

    2 2

    1250 2

    2 22 2 5 1 2 52 5 52 5

    2 5 225

    AA C

    t At B Ct At B t Ct B A B

    tt t tB

    C

    =

    = + +

    = + + + = =

    = =

    T ta c ( )( )

    2 2 2 2

    1 2 22 52 1 2 125 5 25

    2 5 25 5 25 2 52 5

    t d tt dt dtI dt dtt t tt t t t

    +

    = = + = + + =

    1 2 1 1 2 5 2 1 2 3 2ln ln 2 5 ln ln .25 5 25 25 5 25 1 5( 1)

    t xt t C C C

    t t t x x

    = + + = + = ++ +

    Cch 2: (S dng k thut phn tch nhy tng lu ta c)

    ( ) ( ) ( )( )

    ( )( ) ( ) ( )

    ( )2

    2 2 2

    2

    3 2 2

    56 10 3 2 5 2 52 5 22 1 2 1 4 2. .

    2 5 5 2 5 252 5 2 5 2 5

    1 1 2 4 6 10 3 5. .

    5 2 5 25 2 5 2

    t t t t tt tt

    t t t tt t t t t t

    t t

    t t tt t t

    = = =

    =

    ( ) ( ) ( )3 222 3 2 2 3 2 2

    2 52 5 2 51 1 4 6 10 12 2 7 1 4 25 5 2 5 25 25 5 25 5 2 5 25 52 5 2 5

    d t td t d tdt t t dt dt dt dtI dtt t t t tt t t t t t

    = + + + = + + =

    3 22

    7 1 4 2 1 1 2 1 2 5 2ln ln 2 5 ln 2 5 ln ln 2 5 ln .25 5 25 5 25 25 5 25 5

    tt t t t C I t t C C

    t t t t

    = + + = + + = +

    Thay li t = x + 1 ta c 21 2 3 2ln .25 1 5( 1)

    xI Cx x

    = ++ +

    c) ( )2

    3 22 4

    2 1x xI dx

    x x

    + +=

    Cch 1: (ng nht hai v)

    Ta c ( ) ( )( )2

    2 22 2

    2 2 92 4 Ax 2 4 Ax 2 1 1 2 4

    2 12 1 4 20

    A C Ax x B C

    x x B x Cx A B Bxx x x

    B C

    = + = + + +

    = + + + + + = + =

    = =

    ( )2

    3 2 2 22 4 9 4 20 20 49 4 9ln 10ln 2 1 .

    2 1 2 12 1x x x dx dxI dx dx dx x x C

    x x x xx x x x

    + + = = + = + = + + +

    Cch 2: (S dng k thut phn tch nhy tng lu ta c)

    Ta c ( ) ( ) ( )( )

    ( )( ) ( )

    ( )2 22

    2 2 2

    6 2 6 2 12 1 22 4 2 1 4 2 4.2 1 2 1 2 1 2 12 1 2 1 2 1

    x x x xx xx x

    x x x x x xx x x x x x

    + + +

    = + + = =

    ( ) ( )( )

    2 2

    33 2 2 2 2

    3 2

    6 2 6 22 1 2 24 4 1 28 44. 4.2 1 2 1 2 1 2 12 2 1

    4 4ln 4ln 2 14ln 2 1 9ln 10ln 2 1 .

    x x x xI dx

    x x x x x xx x x x x x

    x x x x C x x Cx x

    = + + = + =

    = + + + = + + +

    TH3: Q(x) = 0 c 1 nghim n Khi ta c ( )( )3 2 21( ) = + + + = + +Q x ax bx cx d x x mx nx p , trong 2 0mx nx p+ + = v nghim. ng nht c, ta phi phn tch theo quy tc: ( )( ) 22 11

    ( ) ( )( )

    P x P x A Bx CQ x x x mx nx px x mx nx p

    += = +

    + + + +

    ng nht h s hai v ta c A, B, C. Bi ton tr v cc dng c bn xt n. Ch :

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    - Nguyn hm = + +

    2 2du 1 u

    arctan C.u au a

    - Ngoi vic s dng ng nht, ta cng c th phn tch t s theo o hm ca mu gii. V d 2. Tm nguyn hm ca cc hm s sau:

    a) ( )1 2 1dxI

    x x=

    + b) ( )( )2 2

    2 31 4

    xI dxx x

    +=

    + c) ( )

    2

    3 2

    11

    x xI dxx x x

    +=

    +

    Hng dn gii:

    a) ( )1 2 1dxI

    x x=

    +

    Cch 1: (ng nht hai v)

    ( ) ( ) ( )2

    22

    0 11 1 1 0 1

    11 1 0

    A B AA Bx C A x Bx C x C Bx xx x A C

    = + = +

    = + + + + = = ++

    = =

    Khi , ( )( ) ( )

    22

    1 2 2 22

    11 1 1ln ln ln 1 .2 21 1 11

    d xdx x dx xI dx dx x x x Cx xx x xx x

    +

    = = + = + = = + + + + + +

    Cch 2: (S dng k thut phn tch nhy tng lu ta c)

    ( )( )

    ( ) ( )2 2

    212 22 2

    11 1 1ln ln 1 .21 11 1

    x x x dx xdxI dx x x Cx xx xx x x x

    + = = = = + +

    + ++ +

    b) ( )( )2 22 31 4

    xI dxx x

    +=

    +

    Cch 1: (ng nht hai v)

    ( )( ) ( ) ( )( )2

    22

    350

    2 3 32 3 4 1 21 541 4 3 4 7

    5

    AA B

    x A Bx Cx A x Bx C x B C B

    x xx x A CC

    =

    = + + +

    = + + + + + = + = +

    + =

    =

    Khi ta c ( )( )2 2 2 222 3 3 1 3 7 3 3 7

    . ln 15 1 5 5 5 54 4 41 4

    x dx x x dx dxI dx xx x x xx x

    + += = + = + =

    + + + +

    ( ) ( )2 23 3 7 1 3 3 7ln 1 ln 4 . arctan ln 1 ln 4 arctan .5 10 5 2 2 5 10 10 2x xx x C x x C = + + + = + + + Cch 2: (S dng k thut phn tch nhy tng lu ta c) Ta c ( )( )

    ( )( ) ( ) ( ) ( ) ( )222 2 2

    2 1 32 3 2 3 2 3; 1

    2 51 4 2 5 2 51 1 2 1 5

    xx tt x

    t tx x t t t t t tx x x

    ++ += = = + =

    + + + + + + +

    + +

    M ( )( ) ( )

    ( )2 2 2

    3 2 22 2

    3 4 3 2 5 23 1 1 3 4 3 2 1. . .

    5 5 5 52 5 2 52 5 2 5

    t t t t t t t

    tt t t tt t t t t t

    + + + + += = +

    + + + ++ + + +

    Suy ra

    ( )2 2

    2 3 2 2 2 3 2 22

    2 3 1 3 4 3 2 1 2 1 3 4 3 8 1. . . .

    5 5 5 5 5 52 5 2 5 2 5 2 5 2 5 2 52 5t t t t

    t tt t t t t t t t t t t tt t t

    + ++ = + + = +

    + + + + + + + + + + + ++ +

    Thay vo ta c ( )( ) ( ) ( )2

    2 3 2 22 2

    2 3 2 3 1 3 4 3 8. .

    5 5 52 51 4 2 5 1 4x t t t dt dtI dx dt dt

    tt tx x t t t t

    + + += = = + =

    + + + + + + +

    3 2 3 21 3 8 1 1 1 3 8 1 1ln 2 5 ln . arctan ln 2 5 ln . arctan .5 5 5 2 2 5 5 5 2 2

    t tt t t C t t t C+ + = + + + + = + + + +

    TH4: Q(x) = 0 c 1 nghim