Upload
lydat
View
218
Download
0
Embed Size (px)
Citation preview
Welcome to 18.05 Introduction to Probability and Statistics
Spring 2014
http://xkcd.com/904/ January 1, 2017 1 / 23
R
Free open source package.
Very easy to use and install.
Instructions and a link for this are on MITx/18.05r.
January 1, 2017 2 / 23
Platonic Dice
January 1, 2017 3 / 23
Probability vs. Statistics
Different subjects: both about random processes
Probability
Logically self-contained
A few rules for computing probabilities
One correct answer
Statistics
Messier and more of an art
Get experimental data and try to draw probabilistic conclusions
No single correct answer
January 1, 2017 4 / 23
Counting: Motivating Examples
What is the probability of getting exactly 1 heads in 3 tosses of a fair coin?
January 1, 2017 5 / 23
Poker Hands
Deck of 52 cards
13 ranks: 2, 3, . . . , 9, 10, J, Q, K, A
4 suits: ♥, ♠, ♦, ♣,
Poker hands
Consists of 5 cards
A one-pair hand consists of two cards having one rank and the remaining three cards having three other rank
Example: {2♥, 2♠, 5♥, 8♣, K♦}
The probability of a one-pair hand is: (1) less than 5% (2) between 5% and 10% (3) between 10% and 20% (4) between 20% and 40% (5) greater than 40%
January 1, 2017 6 / 23
Sets in Words
Old New England rule: don’t eat clams (or any shellfish) in months without an ’r’ in their name.
S = all months
L = the month has 31 days
R = the month has an ‘r’ in its name
S = {Jan, Feb, Mar, Apr, May, Jun, Jul, Aug, Sep, Oct, Nov, Dec}
L = {Jan, Mar, May, Jul, Aug, Oct, Dec}
R = {Jan, Feb, Mar, Apr, Sep, Oct, Nov, Dec}
L ∩ R = {Jan, Mar, Oct, Dec} = months with 31 days and an ‘r’
January 1, 2017 7 / 23
Visualize Set Operations with Venn Diagrams
S L R
L ∪ R L ∩ R Lc L−R
January 1, 2017 8 / 23
Product of Sets
S × T = {(s, t)}
January 1, 2017 9 / 23
Inclusion-Exclusion Principle
S
AB A ∩ B
January 1, 2017 10 / 23
Board Question
A band consists of singers and guitar players.
7 people sing
4 play guitar
2 do both How many people are in the band?
January 1, 2017 11 / 23
Rule of Product
3 shirts, 4 pants = 12 outfits
(More powerful than it seems.)
January 1, 2017 12 / 23
Concept Question: DNA
DNA is made of sequences of nucleotides: A, C, G, T.
How many DNA sequences of length 3 are there?
(i) 12 (ii) 24 (iii) 64 (iv) 81
answer: (iii) 4 × 4 × 4 = 64
How many DNA sequences of length 3 are there with no repeats?
(i) 12 (ii) 24 (iii) 64 (iv) 81
answer: (ii) 4 × 3 × 2 = 24
January 1, 2017 13 / 23
Board Question 1
There are 5 Competitors in 100m final.
How many ways can gold, silver, and bronze be awarded?
answer: 5 × 4 × 3. There are 5 ways to pick the winner. Once the winner is chosen there are 4 ways to pick second place and then 3 ways to pick third place.
January 1, 2017 14 / 23
Board Question 2
I won’t wear green and red together; I think black or denim goes with anything; Here is my wardrobe.
Shirts: 3B, 3R, 2G; sweaters 1B, 2R, 1G; pants 2D,2B.
How many different outfits can I wear?
January 1, 2017 15 / 23
Solution
answer: Suppose we choose shirts first. Depending on whether we choose red compatible or green compatible shirts there are different numbers of sweaters we can choose next. So we split the problem up before using the rule of product. A multiplication tree is an easy way to present the answer.
R B G
R,B R,B,G B,G
B,D B,D B,D
3 3 2
3 4 2
4 4 4
Shirts
Sweaters
Pants
Multiplying down the paths of the tree: Number of outfits = (3 × 3 × 4) + (3 × 4 × 4) + (2 × 2 × 4) = 100
January 1, 2017 16 / 23
Permutations
Lining things up. How many ways can you do it?
‘abc’ and ‘cab’ are different permutations of {a, b, c}
January 1, 2017 17 / 23
Permutations of k from a set of n
Give all permutations of 3 things out of {a, b, c , d}
abc abd acb acd adb adc bac bad bca bcd bda bdc cab cad cba cbd cda cdb dab dac dba dbc dca dcb
Would you want to do this for 7 from a set of 10?
January 1, 2017 18 / 23
Combinations
Choosing subsets – order doesn’t matter.
How many ways can you do it?
January 1, 2017 19 / 23
Combinations of k from a set of n
Give all combinations of 3 things out of {a, b, c , d}
Answer: {a,b,c}, {a,b,d}, {a,c,d}, {b,c,d}
January 1, 2017 20 / 23
Permutations and Combinations
abc abd acd bcd
acb adb adc bdc
bac bad cad cbd
bca bda cda cdb
cab dab dac dbc
cba dba dca dcb
Permutations:
4P3
� 4 3
�
= 4C3 = 4P3
3!
{a, b, c}{a, b, d}{a, c , d}{b, c , d}
Combinations: 4 3 = 4C3
January 1, 2017 21 / 23
Board Question
(a) Count the number of ways to get exactly 3 heads in 10 flips of a coin.
(b) For a fair coin, what is the probability of exactly 3 heads in 10 flips?
10answer: (a) We have to ’choose’ 3 out of 10 flips for heads: 3 .
(b) There are 210 possible outcomes from 10 flips (this is the rule of product). For a fair coin each outcome is equally probable so the probability of exactly 3 heads is
10 1203 = = 0.117
210 1024
( )
January 1, 2017 22 / 23
( )
MIT OpenCourseWarehttps://ocw.mit.edu
18.05 Introduction to Probability and StatisticsSpring 2014
For information about citing these materials or our Terms of Use, visit: https://ocw.mit.edu/terms.