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ConcepTest • Section 4.7 • Question 1
True or false?
xgxfxgxfxg af
xQxQxgxfxQagaf
ag
af
ag
afagaf
axax
ax
axax
).(')('lim)()(limThen .)(limand 0)( Suppose (c)
).('lim)(limThen ).(/)()(Let .0)()( Suppose (b)
.)('
)('
)(
)( rule,
sHopital'l' toAccording .0)()( Suppose (a)
ConcepTest • Section 4.7 • Answer 1
ANSWER
COMMENT:Follow-up Question. What does l’Hopital’s rule say?Answer. If f and g are differentiable, f (a) = g(a) = 0, and g’(a) ≠ 0, then
(a) False. l’Hopital’s rule concerns the equality of limits, not the equality of functions.
(b) False. In applying l’Hopital’s rule, the numerator and the denominator are differentiated separately.
(c) False. To apply l’Hopital’s rule to a product, the expression must first be rewritten as a ratio.
.)('
)('
)(
)(lim
ag
af
xg
xfax
Consider 3 limits:
Which is the correct ranking?(a)p < q < r(b)p < r < q(c) q < p < r(d)q < r < p(e)r < p < q(f) r < q < p
ConcepTest • Section 4.7 • Question 2
44
122lim
23
23
1
xxx
xxxp
x 26
7lim
3
3
1
xx
xxq
x 45
sinlim
21
xx
xr
x
ConcepTest • Section 4.7 • Answer 2
119
9
26
7lim
3
3
1
xx
xxq
x
ANSWER(a) Since p is a limit of the form 0/0 it can be
evaluated by l’Hopital’s rule.
The limit for q is the limit of a function that is continuous
at x = 1, so l’Hopital’s rule does not apply. To compute the
limit, evaluate the function.
2
1
10
5
183
243lim
44
122lim
2
2
123
23
1
xx
xx
xxx
xxxp
xx
Since r is a limit of the form 0/0 it can be evaluated by l’Hopital’s rule.
We have
COMMENT:Students may attempt to evaluate q with l’Hopital’s
rule. Remindthem that l’Hopital’s rule usually gives the wrong
answer when it does not apply.ConcepTest • Section 4.7 • Answer 2
.3352
coslim
45
sinlim
121
x
x
xx
xr
xx
ANSWER (cont’d)
31
2
1 rqp
ConcepTest • Section 4.7 • Question 3
For which of the following can you use l’Hopital’s rule to evaluate the limit?
2
0x
2
x
0x
0x
lim (d)
lim (c)
sinlim (b)
coslim (a)
xe
xex
xx
x
x
x
ConcepTest • Section 4.7 • Answer 3
ANSWER
COMMENT:Follow-up Question. Compute the limits.Answer. For (a) the limit does not exist; for (b) the limit is 1; for (c) and (d) the limit is zero.
.lim asit rewritingafter (c) (b),2
x xe
x
Consider 3 limits:
Which is the correct ranking?(a)p < q < r(b)p < r < q(c) q < p < r(d)q < r < p(e)r < p < q(f) r < q < p
ConcepTest • Section 4.7 • Question 4
20
cos1lim
x
xp
x
x
xq
x
lnlim
.)(lim 22 xx
xeexr
(c) Since p is a limit of the form 0/0 it can be evaluated by l’Hopital’s rule. The first application of the rule leads to another limit of the form 0/0, so l’Hopital’s rule must be applied a second time.
Since q is a limit of the form ∞/∞ it can be evaluated by
l’Hopital’s rule.
ConcepTest • Section 4.7 • Answer 4
02
lim)2/1(
/1lim
lnlim
2/1
xx
x
x
xq
xxx
ANSWER
.2
1
2
coslim
2
sinlim
cos1lim
0020
x
x
x
x
xp
xxx
Since r is a limit of the form ∞*0 it can be rewritten in the form
∞/∞, and then l’Hopital’s rule can be applied.
We have
COMMENT:The limits for q and r could be the starting point for a
discussion of dominance relations among logarithmic, power, and
exponential functions.ConcepTest • Section 4.7 • Answer 4
.11012
1lim
2
21limlim)(lim
22
2
2
222
xxx
x
xx
x
x
xx
x ee
e
e
exeexr
ANSWER (cont’d)
12
10 rpq
ConcepTest • Section 4.7 • Question 5
Arrange in order by dominance as x ∞, from least to most dominant.
xexx
exx
x
x
x
ln (e) (d)
(c)
)(ln (b) (a)
2
2
2
100
ConcepTest • Section 4.7 • Answer 5
ANSWER
(b), (d), (a), (e), (c). As x ∞, in increasing order of dominance, we have
x(ln x)2 < x2 < x100 < ex lnx < e2x / x.
COMMENT:Do the students know the answer without using l’Hopital’s Rule?