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EC3202 / MC3207Signals and Systems
Jonghyun [email protected]
Slides adapted from Kuk-Jin Yoon
Continuous Time Fourier Transform
Part I
• Signals• Systems• LTI Systems• Con2nuous Time Fourier Series• Discrete Time Fourier Series
What We’ve LearnedBefore the Mid-term
Review: Continuous Time Fourier Series
Review: Continuous Time Fourier Series
Fourier Transform
! " = $%&'(
()% *+%,-.
Fourier Series →)% =
1123
! " *'+%,-.4"Fourier Transform →
)% =112'(
(! " *'+%,-.4"
5 67 where 7 = 879
Inverse Fourier Transform
! " = 12&'()
)* +, -./01,
Continuous Time Fourier Transform (CTFT)
• Aperiodic con+nuous-+me signals can be represented as an infinite-length discrete-frequency signals
• Aperiodic signal !(#) → periodic extension of !(#)• Assuming that !(#) is repeated every %& seconds
and deno+ng it as !'((#)• if we take the limit as %& → ∞, we obtain a precise
model of an aperiodic signal for which all rules that govern periodic signals can be applied
From CTFS to CTFT• By three steps1. Make aperiodic signal !(#) to a fake periodic
signal %!(#) with period &2. Represent %!(#) into a Fourier Series3. Let & go to ∞
Step 1: Fake Periodic Signal• We assume that an aperiodic signal x(t) has finite
dura7on, i.e., !(#) = 0 for |#| > )/2, for some ). Since !(#) is aperiodic, we first construct a periodic signal ,!(#):
,!(#) = !(#),
for −)/2 < # < )/2, and ,!(# + )) = ,!(#)
Step 2: !"($) to CTFS• Since x (̃t) is periodic, we may express x (̃t) using
Fourier Series:
&' ( = *+,-.
./+01+234
where /+ = 56 ∫6 &' ( 0-1+2348(
• We can represent /+ by
/+ =1:;-.
.' ( 0-1+2348(
where
' ( =&' ( , −:2 < ( < :
20, ( > :
2
Step 2: !"($) to CTFS
• We define & '( = ∫+,, - . /+012345., then
61 =18 & '9(:
Consequently, subs2tu2ng this into ;- . =∑1=+,, 61/01234
;- . = >1=+,
, 18 & '9(: /01234
= >1=+,
, 12@ & '9(: /01234(:
(Cont’d)
Step 3: Let ! go to ∞• Note that x ̃(t) is the periodic padded version of x(t). • When the period T → ∞, the periodic signal x ̃(t) approaches
x(t). Therefore #$ % → $(%)
as ! → ∞.• Moreover, when ! → ∞, or equivalently )* → 0, the limit
of the sum becomes an integral as
lim/0→*12345
5 128 9 :;)* <=2/0>)* = @
45
5 128 9 :;)* <=2/0A)*
RewriEng the last equaEon,
$ % = 128@45
59 :;)* <=2/0>A)*
CTFT, a formal version• The Fourier Transform X(jω) of a signal x(t) is given
by
! "# = %&'
'( ) *&+,-.)
and the inverse Fourier Transform is given by
( ) = 121%&'
'! "# *+,-.#
(analysis equa=on)
(synthesis equa=on)
Called Fourier Transform pair.
Next Class• Details about Con.nuous .me Fourier Transform