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8/4/2019 Cooling Tower Info
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IndirectEvaporative
Cooling SystemsUsing Cooling
TowersRev.1 01/16/06
Reinhard Seidl, P.E.Taylor Engineering
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1
Overview
Goals for today
Why use systems without compressors?
3 Strategies for multi-stage cooling usingcooling towers
Where are these applicable?
How does it work?
Energy and initial cost considerations
Wrap up
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Overview
Why use cooling towersinstead of refrigeration?
Compare 3 modelsannual energy use
Compare 3 modelslife cycle cost
Compare 3 models ofcooling tower use @
Design
Annual Analysis
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3
Overview
Why use cooling towersinstead of refrigeration?
Compare 3 modelsannual energy use
Compare 3 modelslife cycle cost
Compare 3 models ofcooling tower use @
Design
Annual Analysis
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Why use systems w ithoutcompressors?
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Cooling Without Compressors?
Energy consumption can be greatly reduced
Air-cooled chiller consumes about 1.2 kW/ton
Water-cooled chiller & tower consumes about
0.8 kW/ton.
Cooling tower consumes about 0.1 kW/ton.
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Where is this applicable?
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Applications
Low temperatures cant be achieved
Only useful for systems with relatively warm airsupply (65F)
Wont work in wet climates like Florida, but
will work in dry climates like bay area, Arizonaand the like
Underfloor (UFAD)
Systems that move a lot of air by design (Labs,Hospitals)
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Air cooled chiller-design values
Chiller: 1.2 kW/ton
CHW pump:0.05 kW/ton
Total: 1.25 kW/ton
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Water cooled chiller-design values
Towers: 0.1 kW/ton
CW pump: 0.05 kW/ton
Chillers: 0.6 kW/ton
CHW pump:0.05 kW/ton
Total: 0.8 kW/ton
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Cooling tow er-design values
Towers: 0.1 kW/ton
Note: using an oversized tower dramatically reduces tower energy use. Forexample, using a tower with twice the surface area results in a reduction of50% in airflow, which in turn reduces fan energy to ()3 or about 1/8th of theoriginal fan energy.
In this sense, any discussion about tower energy is only meaningful whenpart-load energy consumption values and initial investment are consideredalong with energy use.
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Cooling tower basic operation
Closed towers (indirect system)and open towers (direct system)
Open tower: water falls down andair passing over water evaporatessome of it, cooling both air and
water.
Imagine taking a shower in astrong wind -> evaporation
provides cooling effectOpen tower: cooling water isexposed to outside air
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Cooling tower basic operation
The ambient wet-bulb is ameasure of the humidity. The
higher the wet-bulb, the morehumid the air.
Wet-bulb temperature can never
exceed dry-bulb temperature.
Dry-bulb temperature is what wecommonly refer to as just
temperatureThe leaving water temperature ofthe cooling tower can never be
less than the wet-bulbtemperature of the entering air.
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Cooling tower basic operation
RANGE: entering watertemperature leaving water
temperature. In this example:90F - 80F = 10F
APPROACH: difference between
leaving water temperature andambient wet-bulb temperature. Inthis example: 80F 62F = 18F
The closer the approach, the morefan energy the tower will require,and the larger its surface will haveto be
Tr (10F
Ta (18F)
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Cooling tower basic operation
Closed tower: a closed coil isolatesthe cooling water from the water,
circulated through the tower.
This means less problems withwater treatment for coils served by
cooling water
Range and approach definitionsremain the same
A closed circuit tower will be lesseffective (greater fan energy perunit of cooling) than an open
tower at the same size
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Cooling tower basic operation
Cooling towers work better in dryclimates like Arizona, because the
ambient wet-bulb there is lower
That means colder water leavingthe tower, for the same fan energy
It also means more water isevaporated
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Psychrometric diagram
More detail onpsychrometrics
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120 tons capacity, low airflow
h
h * tower airflow (lbs/h) = cooling tower capacity (Btu/h)
Example:
Flow = 160 gpmRange = 18F
Capacity =160*18*500/12000 =
= 120 tons
Airside flow has to be:
h1=(62 wb) = 27.7 Btu/lb
h2=(70 wb) = 34.1 Btu/lb
=120 tons/h = 3,756 lbs/min
Density @ Ta,in = 0.0728 lb/ft3
Airflow = / = 51,590 cfm
Tw,in=84FTw,out=66F
Range=18F
Approach=4F
Ta,in=83/62F
Ta,out=70/70F
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120 tons capacity, higher airflow
h
h * tower airflow (lbs/h) = cooling tower capacity (Btu/h)
Example:
Flow = 160 gpmRange = 18F
Capacity =160*18*500/12000 =
= 120 tons
Airside flow has to be:
h1=(62 wb) = 27.7 Btu/lb
h2=(68 wb) = 32.4 Btu/lb
=120 tons/h = 5,085 lbs/min
Density @ Ta,in = 0.0728 lb/ft3
Airflow = / = 69,845 cfm
Tw,in=84FTw,out=66F
Range=18F
Approach=4F
Ta,in=83/62F
Ta,out=68/68F
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Pre-cooling effect
h
h * tower airflow (lbs/h) = cooling tower capacity (Btu/h)
Example: When pre-cooling isnot applied, the tower operates
at roughly 70,000 cfm and 120tons capacity to bring waterwithin 4F of entering air wet-bulb temperature (4Fapproach).
Note that the physical size ofthe tower determines theapproach. A smaller tower,operating with the same airflow,would produce a higherapproach (a higher leaving
water temperature, less range)and would require a higherwater flow rate for the samecapacity.
Tw,in=84FTw,out=66F
Range=18F
Approach=4F
Outside air
Leaving air, no pre-cooling
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Pre-cooling effect
h
h * tower airflow (lbs/h) = cooling tower capacity (Btu/h)
With pre-cooling, the enteringair wet-bulb is reduced. The
same tower can now producecolder leaving watertemperatures. This also means alarger range, and less waterflow for the same capacity.
Note that, as the pre-coolingeffect pushes the condition ofair entering the tower closer tothe saturation line, thesensible/total heat ratio of airpassing through the tower
changes, to maintain the sameh and tower capacity.
Tw,in=84FTw,out=61F
Range=23F
Approach=4F
Outside air
Leaving air, no pre-cooling
Pre-cooled air
h
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Overview
Why use cooling towersinstead of refrigeration?
Compare 3 modelsannual energy use
Compare 3 modelslife cycle cost
Compare 3 models ofcooling tower use @
Design
Annual Analysis
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Overview
2-Stage model(Shlomo Rosenfeld)
Why use cooling towersinstead of refrigeration?
Compare 3 modelsannual energy use
Compare 3 modelslife cycle cost
Compare 3 models ofcooling tower use @
Design
Annual Analysis
Direct 1-Stage model(Loek Vaneveld)
Indirect 1-Stage model(Mark Hydeman)
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3 Strategies for multi-stagecooling using cooling towers
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Direct 1-Stage Design
Note this is an open towerdesign. This may not beacceptable in some caseswhere concerns over water
treatment and fouling of coilsexist. In such a case, the useof a plate heat exchanger(typically employed on opentowers) will not work, sincethe temperature losses
inherent in such an approachmake the design impractical.
?
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Pre-cooling effect-special case
hNote this slide shows the principle.The actual values for the tower underconsideration are different (next
slide)Note that tower pre-cooling energyextracted from the air is re-introduced into the tower through thewater, and has to be cooled withinthe tower.
Leaving air temperature is the same
with or without pre-cooling, for thesame airflow through the tower.
h = Building or Process Load
hp = Pre-cooling Load
Tw,in=84FTw,out=61F
Range=23F
Approach=4F
Outside air
Leaving air
h
hp
Pre-cooled air
hp Dashed line = towerwithout pre-cooling, forsame process load withsame tower airflow
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Direct 1-Stage Design
Actual Values
Note this is an open towerdesign. This may not be
acceptable in some caseswhere concerns over watertreatment and fouling of coilsexist. In such a case, the useof a plate heat exchanger(typically employed on opentowers) will not work, since
the temperature lossesinherent in such an approachmake the design impractical.
?
79.7 tons pre-cooling
200 tons towercapacity
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Indirect 1-Stage Design
CT1/2: 180 gpm 78F - 62F = 120 tons @ 50 Hp 0.311 kW/ton CT3/4: 172 gpm 81F 66F at 15 Hp, relate to orig.120 tons 0.093 kW/ton
requires 7.5 Hp and 3.0 Hp spray pumps 0.065 kW/tonTotal 0.469 kW/ton
Evaporation water usage 0.037 gpm/ton
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Indirect 1-Stage Design
CT1/2: 180 gpm 78F - 62F = 120 tons @ 50 Hp 0.311 kW/ton CT3/4: 172 gpm 81F 66F at 15 Hp, relate to orig.120 tons 0.093 kW/ton
requires 7.5 Hp and 3.0 Hp spray pumps 0.065 kW/tonTotal 0.469 kW/ton
Evaporation water usage 0.037 gpm/ton
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2-Stage Design
CCT1/2 each: 180 gpm 78F - 67F = 82.5 tons @ 25 Hp 0.155 kW/ton*
CCT3/4 each: 180 gpm 67F - 62F = 37.5 tons @ 50 Hp 0.311 kW/tonrequires 5 Hp, 5 Hp, 2 Hp spray pumps 0.075 kW/tonTotal 0.541 kW/ton
Evaporation water usage 0.027 gpm/ton
Note: all kW/ton calculations are basedon the total output (120 tons) of thesystem, not on the individual capacity
of each tower
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2-Stage Design
CCT1/2 each: 180 gpm 78F - 67F = 82.5 tons @ 25 Hp 0.155 kW/ton*
CCT3/4 each: 180 gpm 67F - 62F = 37.5 tons @ 50 Hp 0.311 kW/tonrequires 5 Hp, 5 Hp, 2 Hp spray pumps 0.075 kW/tonTotal 0.541 kW/ton
Evaporation water usage 0.027 gpm/ton
73.4 tons pre-cooling
111 tons towercapacity
73.4 tons heat re-gain
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Energy and Water Usage
at Design Conditions
Direct 1-Stage 0.167 kW/ton 0.032 gpm/ton
Indirect 1-Stage 0.469 kW/ton 0.037 gpm/ton
2-Stage 0.541 kW/ton 0.027 gpm/ton
Note that these values are fairly easily derived, butdont show the whole picture.
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Coil Calculations
Why use cooling towersinstead of refrigeration?
Compare 3 modelsannual energy use
Compare 3 modelslife cycle cost
Compare 3 models ofcooling tower use @
Design
Annual Analysis
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Annual Simulation
Could use a spreadsheet, maybe DOE2.
Spreadsheet offers more flexibility
Look at bin weather data file to run a simulation
Use approximation of coil performance to arriveat results for varying airflows and air enteringtemperatures. Use LMTD and -NTU methods.
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Bin Data and Building Load
Match each temperature bin with a building
load. This building load doesnt necessarily haveto be exact a rough approximation is sufficientsince were trying to find a comparison betweenmodels rather than an absolute number.
Use the dry-bulb and coincident wet-bulb topredict how coil performance at tower inlets will
vary.
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Sample Bin Data
Temperaturevalues below the
65F mark can beignored for thesimulation, sincethe system will bein economizer.
ANNUAL TOTAL
Obsn Hours Total M
TEMP
RANGE
01
to
08
09
to
16
17
to
24
Obsn
Hrs
C
W
B
115/119 0 0 0 0 0
110/114 0 0 0 0 73
105/109 0 0 0 0 71
100/104 0 0.5 0 0.5 70
95/99 0 0.5 0 0.5 68
90/94 0 6.8 0.1 6.9 66
85/89 0 18.6 1.1 19.7 65
80/84 0 43.8 4.3 48.1 6375/79 0.8 94.3 13.3 108 61
70/74 5.2 269 37.4 312 58
65/69 32.1 555 126 714 56
60/64 214 668 421 1303 54
55/59 748 667 927 2341 51
50/54 962 400 892 2255 48
45/49 563 159 384 1107 4440/44 297 35.3 102 435 40
35/39 90.9 3.2 11.5 106 36
30/34 9.2 0.4 0.6 10.2 31
25/29 0 0 0 0 26
20/24 0 0 0 0 23
15/19 0 0 0 0 0
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Calculat ion for Off-Design Values
Successively enter
db/wbcombinations intotower selection tosimulate operation
ANNUAL TOTAL
Obsn Hours Total M
TEMP
RANGE
01
to
08
09
to
16
17
to
24
Obsn
Hrs
C
W
B
115/119 0 0 0 0 0
110/114 0 0 0 0 73
105/109 0 0 0 0 71
100/104 0 0.5 0 0.5 70
95/99 0 0.5 0 0.5 68
90/94 0 6.8 0.1 6.9 66
85/89 0 18.6 1.1 19.7 65
80/84 0 43.8 4.3 48.1 63
75/79 0.8 94.3 13.3 108 61
70/74 5.2 269 37.4 312 58
65/69 32.1 555 126 714 56
60/64 214 668 421 1303 54
55/59 748 667 927 2341 51
50/54 962 400 892 2255 48
45/49 563 159 384 1107 4440/44 297 35.3 102 435 40
35/39 90.9 3.2 11.5 106 36
30/34 9.2 0.4 0.6 10.2 31
25/29 0 0 0 0 26
20/24 0 0 0 0 23
15/19 0 0 0 0 0
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Calculat ion for Off-Design Values
Successively enter
db/wbcombinations intotower selection tosimulate operation
92 ?
?
?
?
ANNUAL TOTAL
Obsn Hours Total M
TEMP
RANGE
01
to
08
09
to
16
17
to
24
Obsn
Hrs
C
W
B
115/119 0 0 0 0 0
110/114 0 0 0 0 73
105/109 0 0 0 0 71
100/104 0 0.5 0 0.5 70
95/99 0 0.5 0 0.5 68
90/94 0 6.8 0.1 6.9 66
85/89 0 18.6 1.1 19.7 65
80/84 0 43.8 4.3 48.1 63
75/79 0.8 94.3 13.3 108 61
70/74 5.2 269 37.4 312 58
65/69 32.1 555 126 714 56
60/64 214 668 421 1303 54
55/59 748 667 927 2341 51
50/54 962 400 892 2255 48
45/49 563 159 384 1107 4440/44 297 35.3 102 435 40
35/39 90.9 3.2 11.5 106 36
30/34 9.2 0.4 0.6 10.2 31
25/29 0 0 0 0 26
20/24 0 0 0 0 23
15/19 0 0 0 0 0
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Calculat ion for Off-Design Values
Successively enter
db/wbcombinations intotower selection tosimulate operation
87 ?
?
?
?
ANNUAL TOTAL
Obsn Hours Total M
TEMP
RANGE
01
to
08
09
to
16
17
to
24
Obsn
Hrs
C
W
B
115/119 0 0 0 0 0
110/114 0 0 0 0 73
105/109 0 0 0 0 71
100/104 0 0.5 0 0.5 70
95/99 0 0.5 0 0.5 68
90/94 0 6.8 0.1 6.9 66
85/89 0 18.6 1.1 19.7 65
80/84 0 43.8 4.3 48.1 6375/79 0.8 94.3 13.3 108 61
70/74 5.2 269 37.4 312 58
65/69 32.1 555 126 714 56
60/64 214 668 421 1303 54
55/59 748 667 927 2341 51
50/54 962 400 892 2255 48
45/49 563 159 384 1107 4440/44 297 35.3 102 435 40
35/39 90.9 3.2 11.5 106 36
30/34 9.2 0.4 0.6 10.2 31
25/29 0 0 0 0 26
20/24 0 0 0 0 23
15/19 0 0 0 0 0
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Calculat ion for Off-Design Values
Successively enter
db/wbcombinations intotower selection tosimulate operation
82 ?
?
?
?
ANNUAL TOTAL
Obsn Hours Total M
TEMP
RANGE
01
to
08
09
to
16
17
to
24
Obsn
Hrs
C
W
B
115/119 0 0 0 0 0
110/114 0 0 0 0 73
105/109 0 0 0 0 71
100/104 0 0.5 0 0.5 70
95/99 0 0.5 0 0.5 68
90/94 0 6.8 0.1 6.9 66
85/89 0 18.6 1.1 19.7 65
80/84 0 43.8 4.3 48.1 6375/79 0.8 94.3 13.3 108 61
70/74 5.2 269 37.4 312 58
65/69 32.1 555 126 714 56
60/64 214 668 421 1303 54
55/59 748 667 927 2341 51
50/54 962 400 892 2255 48
45/49 563 159 384 1107 4440/44 297 35.3 102 435 40
35/39 90.9 3.2 11.5 106 36
30/34 9.2 0.4 0.6 10.2 31
25/29 0 0 0 0 26
20/24 0 0 0 0 23
15/19 0 0 0 0 0
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Calculat ion for Off-Design Values
Successively enter
db/wbcombinations intotower selection tosimulate operation
77 ?
?
?
?
ANNUAL TOTAL
Obsn Hours Total M
TEMP
RANGE
01
to
08
09
to
16
17
to
24
Obsn
Hrs
C
W
B
115/119 0 0 0 0 0
110/114 0 0 0 0 73
105/109 0 0 0 0 71
100/104 0 0.5 0 0.5 70
95/99 0 0.5 0 0.5 68
90/94 0 6.8 0.1 6.9 66
85/89 0 18.6 1.1 19.7 65
80/84 0 43.8 4.3 48.1 6375/79 0.8 94.3 13.3 108 61
70/74 5.2 269 37.4 312 58
65/69 32.1 555 126 714 56
60/64 214 668 421 1303 54
55/59 748 667 927 2341 51
50/54 962 400 892 2255 48
45/49 563 159 384 1107 4440/44 297 35.3 102 435 40
35/39 90.9 3.2 11.5 106 36
30/34 9.2 0.4 0.6 10.2 31
25/29 0 0 0 0 26
20/24 0 0 0 0 23
15/19 0 0 0 0 0
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Calculat ion for Off-Design Values
Successively enter
db/wbcombinations intotower selection tosimulate operation
72 ?
?
?
?
ANNUAL TOTAL
Obsn Hours Total M
TEMP
RANGE
01
to
08
09
to
16
17
to
24
Obsn
Hrs
C
W
B
115/119 0 0 0 0 0
110/114 0 0 0 0 73
105/109 0 0 0 0 71
100/104 0 0.5 0 0.5 70
95/99 0 0.5 0 0.5 68
90/94 0 6.8 0.1 6.9 66
85/89 0 18.6 1.1 19.7 65
80/84 0 43.8 4.3 48.1 6375/79 0.8 94.3 13.3 108 61
70/74 5.2 269 37.4 312 58
65/69 32.1 555 126 714 56
60/64 214 668 421 1303 54
55/59 748 667 927 2341 51
50/54 962 400 892 2255 48
45/49 563 159 384 1107 4440/44 297 35.3 102 435 40
35/39 90.9 3.2 11.5 106 36
30/34 9.2 0.4 0.6 10.2 31
25/29 0 0 0 0 26
20/24 0 0 0 0 23
15/19 0 0 0 0 0
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Calculat ion for Off-Design Values
Lower wb means: Tower fancan run at less than 100%.How will coil react to lessairflow, and what will pre-cooling effect be?
67 ?
?
?
?
ANNUAL TOTAL
Obsn Hours Total M
TEMP
RANGE
01
to
08
09
to
16
17
to
24
Obsn
Hrs
C
W
B
115/119 0 0 0 0 0
110/114 0 0 0 0 73
105/109 0 0 0 0 71
100/104 0 0.5 0 0.5 70
95/99 0 0.5 0 0.5 68
90/94 0 6.8 0.1 6.9 66
85/89 0 18.6 1.1 19.7 65
80/84 0 43.8 4.3 48.1 6375/79 0.8 94.3 13.3 108 61
70/74 5.2 269 37.4 312 58
65/69 32.1 555 126 714 56
60/64 214 668 421 1303 54
55/59 748 667 927 2341 51
50/54 962 400 892 2255 48
45/49 563 159 384 1107 4440/44 297 35.3 102 435 40
35/39 90.9 3.2 11.5 106 36
30/34 9.2 0.4 0.6 10.2 31
25/29 0 0 0 0 26
20/24 0 0 0 0 23
15/19 0 0 0 0 0
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Coil Calculations
Why use cooling towersinstead of refrigeration?
Compare 3 modelsannual energy use
Compare 3 modelslife cycle cost
Compare 3 models ofcooling tower use @
Design
Annual Analysis
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Coil Calculations
Take desired designvalues and calculatewhat coil overall heattransfer needs to be
LMTD method
Verify design conditionwith calculated coil heat
transfer
-NTU method
Verify other conditionwith calculated coil heat
transfer
-NTU method
Explanation of-NTU method
Why use cooling towersinstead of refrigeration?
Compare 3 modelsannual energy use
Compare 3 modelslife cycle cost
Compare 3 models ofcooling tower use @
Design
Annual Analysis
Skip coilcalculations
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Coil Calculations-Step 1
Take desired designvalues and calculatewhat coil overall heattransfer needs to be
LMTD method
Verify design conditionwith calculated coil heat
transfer
-NTU method
Verify other conditionwith calculated coil heat
transfer
-NTU method
Explanation of-NTU method
Why use cooling towersinstead of refrigeration?
Compare 3 modelsannual energy use
Compare 3 modelslife cycle cost
Compare 3 models ofcooling tower use @
Design
Annual Analysis
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Coil Calculation - LMTD
LMTD method:
T1= Thot,in Tcold,out and T2= Thot,out Tcold,in
T2 T1Tlmtd = -----------------
ln (T2/ T1)
Q = UATlmtd
Use this method to determine UA, based on the temperatures weexpect from design. In other words, we dont care exactly how the
U and A are derived (fin spacing, number of rows etc). Well justassume that for the given problem, a coil can be purchased withthe right UA. We will then use this number to simulate how thatcoil will operate under different conditions.
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Coil Calculation LMTD Example
LMTD method:
T1= 83 80 and T2= 68.2 65
3.2-3.0Tlmtd = ----------------- = 3.1
ln (3.2/ 3.0)
Q = UA * 3.1 = 125 gpm * 15= 937.5 MBH
UA = 302,524 Btu/ hF
This number UA, which represents the overall heat transfercoefficient of the coil, can now be used to calculateperformance under different conditions.
l l l
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Coil Calculations-Step 2
Take desired designvalues and calculatewhat coil overall heattransfer needs to be
LMTD method
Verify design conditionwith calculated coil heat
transfer
-NTU method
Verify other conditionwith calculated coil heat
transfer
-NTU method
Explanation of-NTU method
Why use cooling towersinstead of refrigeration?
Compare 3 modelsannual energy use
Compare 3 modelslife cycle cost
Compare 3 models ofcooling tower use @
Design
Annual Analysis
C il Si l t i NTU
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Coil Simulation -NTU -NTU method:
By taking the UA we calculated earlier, and using the mass flow
rates for each medium and the specific heat, we can determinewhat the leaving temperatures will be, based on the calculatedeffectiveness
=
max
min
minmax
min
max
min
min
C
C1
C
UAexp
C
C1
C
C1
C
UAexp1
Hot
actinHotoutHot
CQTT = ,,
Cold
act
in,Coldout,Cold C
QTT +=
Maxact
inColdinHotMinMax
QQTTCQ
== )( ,,
C il Si l t i NTU
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Coil Simulation -NTU -NTU method:
Note that the formula shown below for only holds for a perfectcounterflow heat exchanger.
For other types (most real heat exchangers are somewherebetween a counter flow and parallel-flow exchanger).
For such a case, the NTU is calculated, and is read off a chart
Perfect Counter-flow Parallel flow Counter-flow
=
max
min
minmax
min
max
min
min
CC1
CUAexp
CC1
C
C1
C
UAexp1
minC
UANTU =
1C
C
max
min =
0CC
max
min =
C il i l t i NTU
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Coil simulation -NTU -NTU method:
Note that the formula shown below for only holds for a perfectcounterflow heat exchanger.
For other types (most real heat exchangers are somewherebetween a counter flow and parallel-flow exchanger).
For such a case, the NTU is calculated, and is read off a chart
Perfect Counter-flow Parallel flow Counter-flow
=
max
min
minmax
min
max
min
min
CC1
CUAexp
CC1
C
C1
C
UAexp1
minC
UANTU =
1C
C
max
min =
0CC
max
min =
We will use onlythis method
C il Si l t i NTU E l
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Coil Simulation -NTU Example -NTU method:
Design at 83 / 68.2F for 57,700 cfm of airand 65 / 80F for 125 gpm of water
(78.3 tons or 937 MBH)
Reduce fan speed, use 40,000 cfm andAmbient reduced to 67F
Performance now:Air at 67 / 65.1F for 40,000 cfmand 65 / 66.3F for 125 gpm of water(7 tons or 84 MBH)
Coil Simulation NTU Example
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Coil Simulation -NTU Example -NTU method:
Design at 83 / 68.2F for 57,700 cfm of air =0.83and 65 / 80F for 125 gpm of water Qmax = 1,126 MBH(78.3 tons or 937 MBH)
Reduce fan speed, use 40,000 cfm andAmbient reduced to 67F
Performance now:Air at 67 / 65.1F for 40,000 cfm =0.96and 65 / 66.3F for 125 gpm of water Qmax = 88 MBH(7 tons or 84 MBH)
Note that Qmax is the amount of heat that could be exchanged with aninfinitely large (or perfect) heat exchanger. is a measure of how wellthe actual exchanger under consideration approximates this idealexchanger, and varies with selected temperatures and flows.
Coil Calculations Step 3
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Coil Calculations-Step 3
Take desired designvalues and calculatewhat coil overall heattransfer needs to be
LMTD method
Verify design conditionwith calculated coil heat
transfer
-NTU method
Verify other conditionwith calculated coil heat
transfer
-NTU method
Explanation of-NTU method
Why use cooling towersinstead of refrigeration?
Compare 3 modelsannual energy use
Compare 3 modelslife cycle cost
Compare 3 models ofcooling tower use @
Design
Annual Analysis
Coil Simulation NTU Example
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Coil Simulation -NTU Example -NTU method:
Design at 83 / 68.2F for 57,700 cfm of air =0.83and 65 / 80F for 125 gpm of water Qmax = 1,126 MBH
(78.3 tons or 937 MBH)
Fh
Btu396,63
h
min60*
cuft
lb0763.0*cfm700,57*
Flb
Btu24.0cC 111
=
==
Fh
Btu550,62
h
min60*
gal
lb34.8*gpm125*
Flb
Btu0.1cC 222
=
==
Coil Simulation NTU Example
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Coil Simulation -NTU Example-NTU method:Design at 83 / 68.2F for 57,700 cfm of air =0.83and 65 / 80F for 125 gpm of water Qmax = 1,126 MBH
(78.3 tons or 937 MBH)
=
63,396
62,550162,550
302,524exp63,396
62,5501
63,396
62,5501
62,550
302,524exp1
396,63
126,938
832.68
C
QTT
Hot
actin,Hotout,Hot
=
=
550,62
126,9386580
C
QTT
Cold
actin,Coldout,Cold
=
+=
MBH938126,1*83.0QQ
MBH126,1)6583(550,62Q
Maxact
Max
===
==
Coil Calculations-Step 4
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Coil Calculations-Step 4
Take desired designvalues and calculatewhat coil overall heattransfer needs to be
LMTD method
Verify design conditionwith calculated coil heat
transfer
-NTU method
Verify other conditionwith calculated coil heat
transfer
-NTU method
Explanation of-NTU method
Why use cooling towersinstead of refrigeration?
Compare 3 modelsannual energy use
Compare 3 modelslife cycle cost
Compare 3 models ofcooling tower use @
Design
Annual Analysis
Coil simulation -NTU example
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Coil simulation -NTU example -NTU method:
Design at 67 / 65.1F for 40,000 cfm of air =0.96and 65 / 66.3F for 125 gpm of water Qmax = 88 MBH
(7.0 tons or 84 MBH)
Fh
Btu949,43
h
min60*
cuft
lb0763.0*cfm000,40*
Flb
Btu24.0cC 111
=
==
Fh
Btu550,62
h
min60*
gal
lb34.8*gpm125*
Flb
Btu0.1cC 222
=
==
Coil simulation -NTU example
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Coil simulation NTU example -NTU method:
Design at 67 / 65.1F for 40,000 cfm of air =0.96and 65 / 66.3F for 125 gpm of water Qmax = 88 MBH
(7.0 tons or 84 MBH)
=
62,550
43,949143,949
302,524exp62,550
43,9491
62,550
43,9491
43,949
302,524exp1
949,43
186,84671.65
C
QTT
Hot
actin,Hotout,Hot
=
=
550,62
186,84653.66
C
QTT
Cold
actin,Coldout,Cold
=
+=MBH2.848.87*96.0QQ
MBH8.87)6567(949,43Q
Maxact
Max
===
==
Annual Energy Use
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Annual Energy Use
Why use cooling towersinstead of refrigeration?
Compare 3 modelsannual energy use
Compare 3 modelslife cycle cost
Compare 3 models ofcooling tower use @
Design
Annual Analysis
Back to coilcalculations
Energy Usage from Annual Simulation
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Energy Usage from Annual Simulation
Direct 1-Stage 1.7 MWh per year
Indirect 1-Stage 20.4 MWh per year
2-Stage 17.5 MWh per year
Life Cycle Cost
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Life Cycle Cost
Why use cooling towersinstead of refrigeration?
Compare 3 modelsannual energy use
Compare 3 modelslife cycle cost
Compare 3 models ofcooling tower use @
Design
Annual Analysis
Initial Cost
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Initial Cost
Direct 1-Stage CT1/2 $ 36,000Coils (59,320 cfm)x2 $ 72,000Total $ 108,000
Indirect 1-Stage CT1/2 $ 40,000CT3/4 $ 120,000Coils (78,500 cfm)x2 $ 92,000Total $ 252,000
2-Stage CCT1/2 $ 125,000CCT3/4 $ 105,000Coils (114,000 cfm)x2 $ 145,000Total $ 375,000
Note: pricing is for towers, and estimated coil + custom coilinstallation. Pricing does not include piping, valves and associatedcontrols.
Simplified Life-Cycle Cost
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Simplified Life Cycle Cost
Direct 1-Stage first cost $ 108,000Energy cost, 20 years $ 4,100 (1.7 MWh/a)Total $ 112,100
Indirect 1-Stage first cost $ 252,000Energy cost, 20 years $ 49,000 (20.4 MWh/a)Total $ 301,000
2-Stage CCT1/2 $ 375,000
Energy cost, 20 years $ 42,000 (17.5 MWh/a)Total $ 417,000
Note: pricing is for equipment only. This includes towers, andestimated coil + installation of coil on tower. Pricing does not include
piping, valves, rigging, setting, startup or associated controls.
Direct 1-Stage also has lower water usage and maintenance costs (notincluded in this simple analysis)
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20-year life cycle cost
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y y
20-year Life cycle cost
$0
$100,000
$200,000
$300,000
$400,000
$500,000
$600,000
$700,000
0.06 0.08 0.1 0.12 0.14 0.16 0.18 0.2 0.22 0.24 0.26 0.28 0.3 0.32
Cost $ / kWh
Life
cyc
le
cost
Direct
Indirect2-Stage
Chiller
Break-even at around $ 0.10/kWh
Break-even at around $ 0.19/kWh
Note: For amore realisticcalculation,piping materials& labor have tobe added to thecalculation. Thismakes thechiller modellook evenbetter, andbreak-evenoccurs at higherelectricityprices.
15-year life cycle cost
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15-year Life cycle cost
$0
$100,000
$200,000
$300,000
$400,000
$500,000
$600,000
$700,000
0.06 0.08 0.1 0.12 0.14 0.16 0.18 0.2 0.22 0.24 0.26 0.28 0.3 0.32
Cost $ / kWh
Lifec
ycle
cost Direct
Indirect
2-StageChiller
y y
Break-even at around $ 0.13/kWh
Break-even at around $ 0.25/kWh
Note: For amore realisticcalculation,piping materials& labor have tobe added to thecalculation. Thismakes thechiller modellook evenbetter, andbreak-evenoccurs at higherelectricityprices.
Questions
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Q
?
Psychrometric diagram
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y g
Back to coolingtower principles
WET
DRY
Psychrometric diagram
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y g
Back to coolingtower principles
COLD HOT
Psychrometric diagram
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Back to coolingtower principles
San
Francisco
F
lorida
Las Vegas
Psychrometric diagram
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Back to coolingtower principles
Ab
solute
Humid
ity
Temperature
50
70
90
Psychrometric diagram
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Temperature
0.45 lbs water/100 lb air
1.6 lb water/100 lb air
2.7 lb water/100 lb air
AbsoluteHumidity
Psychrometric diagram
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Back to coolingtower principles
20% RH
50% RH
AbsoluteH
umidity
Temperature
FOG
90% RH
Psychrometric diagram
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Back to coolingtower principles
AbsoluteH
umidity
Temperature
FOG
For the same moisture content,
warmer air has a lower relative
humidity or a lower saturation
rate because hot air can absorbmore moisture
20% RH50% RH90% RH
1.08 lbs water/100 lb air
Psychrometric diagram
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Back to coolingtower principles
Temperature
90/90%
90/33%Abs
oluteH
umidi
ty
68 wb
87 wbWet bulb temp.