Cooling Tower Info

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    IndirectEvaporative

    Cooling SystemsUsing Cooling

    TowersRev.1 01/16/06

    Reinhard Seidl, P.E.Taylor Engineering

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    1

    Overview

    Goals for today

    Why use systems without compressors?

    3 Strategies for multi-stage cooling usingcooling towers

    Where are these applicable?

    How does it work?

    Energy and initial cost considerations

    Wrap up

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    2

    Overview

    Why use cooling towersinstead of refrigeration?

    Compare 3 modelsannual energy use

    Compare 3 modelslife cycle cost

    Compare 3 models ofcooling tower use @

    Design

    Annual Analysis

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    3

    Overview

    Why use cooling towersinstead of refrigeration?

    Compare 3 modelsannual energy use

    Compare 3 modelslife cycle cost

    Compare 3 models ofcooling tower use @

    Design

    Annual Analysis

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    Why use systems w ithoutcompressors?

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    5

    Cooling Without Compressors?

    Energy consumption can be greatly reduced

    Air-cooled chiller consumes about 1.2 kW/ton

    Water-cooled chiller & tower consumes about

    0.8 kW/ton.

    Cooling tower consumes about 0.1 kW/ton.

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    Where is this applicable?

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    7

    Applications

    Low temperatures cant be achieved

    Only useful for systems with relatively warm airsupply (65F)

    Wont work in wet climates like Florida, but

    will work in dry climates like bay area, Arizonaand the like

    Underfloor (UFAD)

    Systems that move a lot of air by design (Labs,Hospitals)

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    8

    Air cooled chiller-design values

    Chiller: 1.2 kW/ton

    CHW pump:0.05 kW/ton

    Total: 1.25 kW/ton

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    9

    Water cooled chiller-design values

    Towers: 0.1 kW/ton

    CW pump: 0.05 kW/ton

    Chillers: 0.6 kW/ton

    CHW pump:0.05 kW/ton

    Total: 0.8 kW/ton

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    10

    Cooling tow er-design values

    Towers: 0.1 kW/ton

    Note: using an oversized tower dramatically reduces tower energy use. Forexample, using a tower with twice the surface area results in a reduction of50% in airflow, which in turn reduces fan energy to ()3 or about 1/8th of theoriginal fan energy.

    In this sense, any discussion about tower energy is only meaningful whenpart-load energy consumption values and initial investment are consideredalong with energy use.

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    11

    Cooling tower basic operation

    Closed towers (indirect system)and open towers (direct system)

    Open tower: water falls down andair passing over water evaporatessome of it, cooling both air and

    water.

    Imagine taking a shower in astrong wind -> evaporation

    provides cooling effectOpen tower: cooling water isexposed to outside air

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    12

    Cooling tower basic operation

    The ambient wet-bulb is ameasure of the humidity. The

    higher the wet-bulb, the morehumid the air.

    Wet-bulb temperature can never

    exceed dry-bulb temperature.

    Dry-bulb temperature is what wecommonly refer to as just

    temperatureThe leaving water temperature ofthe cooling tower can never be

    less than the wet-bulbtemperature of the entering air.

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    13

    Cooling tower basic operation

    RANGE: entering watertemperature leaving water

    temperature. In this example:90F - 80F = 10F

    APPROACH: difference between

    leaving water temperature andambient wet-bulb temperature. Inthis example: 80F 62F = 18F

    The closer the approach, the morefan energy the tower will require,and the larger its surface will haveto be

    Tr (10F

    Ta (18F)

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    14

    Cooling tower basic operation

    Closed tower: a closed coil isolatesthe cooling water from the water,

    circulated through the tower.

    This means less problems withwater treatment for coils served by

    cooling water

    Range and approach definitionsremain the same

    A closed circuit tower will be lesseffective (greater fan energy perunit of cooling) than an open

    tower at the same size

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    15

    Cooling tower basic operation

    Cooling towers work better in dryclimates like Arizona, because the

    ambient wet-bulb there is lower

    That means colder water leavingthe tower, for the same fan energy

    It also means more water isevaporated

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    16

    Psychrometric diagram

    More detail onpsychrometrics

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    17

    120 tons capacity, low airflow

    h

    h * tower airflow (lbs/h) = cooling tower capacity (Btu/h)

    Example:

    Flow = 160 gpmRange = 18F

    Capacity =160*18*500/12000 =

    = 120 tons

    Airside flow has to be:

    h1=(62 wb) = 27.7 Btu/lb

    h2=(70 wb) = 34.1 Btu/lb

    =120 tons/h = 3,756 lbs/min

    Density @ Ta,in = 0.0728 lb/ft3

    Airflow = / = 51,590 cfm

    Tw,in=84FTw,out=66F

    Range=18F

    Approach=4F

    Ta,in=83/62F

    Ta,out=70/70F

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    18

    120 tons capacity, higher airflow

    h

    h * tower airflow (lbs/h) = cooling tower capacity (Btu/h)

    Example:

    Flow = 160 gpmRange = 18F

    Capacity =160*18*500/12000 =

    = 120 tons

    Airside flow has to be:

    h1=(62 wb) = 27.7 Btu/lb

    h2=(68 wb) = 32.4 Btu/lb

    =120 tons/h = 5,085 lbs/min

    Density @ Ta,in = 0.0728 lb/ft3

    Airflow = / = 69,845 cfm

    Tw,in=84FTw,out=66F

    Range=18F

    Approach=4F

    Ta,in=83/62F

    Ta,out=68/68F

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    19

    Pre-cooling effect

    h

    h * tower airflow (lbs/h) = cooling tower capacity (Btu/h)

    Example: When pre-cooling isnot applied, the tower operates

    at roughly 70,000 cfm and 120tons capacity to bring waterwithin 4F of entering air wet-bulb temperature (4Fapproach).

    Note that the physical size ofthe tower determines theapproach. A smaller tower,operating with the same airflow,would produce a higherapproach (a higher leaving

    water temperature, less range)and would require a higherwater flow rate for the samecapacity.

    Tw,in=84FTw,out=66F

    Range=18F

    Approach=4F

    Outside air

    Leaving air, no pre-cooling

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    20

    Pre-cooling effect

    h

    h * tower airflow (lbs/h) = cooling tower capacity (Btu/h)

    With pre-cooling, the enteringair wet-bulb is reduced. The

    same tower can now producecolder leaving watertemperatures. This also means alarger range, and less waterflow for the same capacity.

    Note that, as the pre-coolingeffect pushes the condition ofair entering the tower closer tothe saturation line, thesensible/total heat ratio of airpassing through the tower

    changes, to maintain the sameh and tower capacity.

    Tw,in=84FTw,out=61F

    Range=23F

    Approach=4F

    Outside air

    Leaving air, no pre-cooling

    Pre-cooled air

    h

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    21

    Overview

    Why use cooling towersinstead of refrigeration?

    Compare 3 modelsannual energy use

    Compare 3 modelslife cycle cost

    Compare 3 models ofcooling tower use @

    Design

    Annual Analysis

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    22

    Overview

    2-Stage model(Shlomo Rosenfeld)

    Why use cooling towersinstead of refrigeration?

    Compare 3 modelsannual energy use

    Compare 3 modelslife cycle cost

    Compare 3 models ofcooling tower use @

    Design

    Annual Analysis

    Direct 1-Stage model(Loek Vaneveld)

    Indirect 1-Stage model(Mark Hydeman)

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    3 Strategies for multi-stagecooling using cooling towers

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    Direct 1-Stage Design

    Note this is an open towerdesign. This may not beacceptable in some caseswhere concerns over water

    treatment and fouling of coilsexist. In such a case, the useof a plate heat exchanger(typically employed on opentowers) will not work, sincethe temperature losses

    inherent in such an approachmake the design impractical.

    ?

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    25

    Pre-cooling effect-special case

    hNote this slide shows the principle.The actual values for the tower underconsideration are different (next

    slide)Note that tower pre-cooling energyextracted from the air is re-introduced into the tower through thewater, and has to be cooled withinthe tower.

    Leaving air temperature is the same

    with or without pre-cooling, for thesame airflow through the tower.

    h = Building or Process Load

    hp = Pre-cooling Load

    Tw,in=84FTw,out=61F

    Range=23F

    Approach=4F

    Outside air

    Leaving air

    h

    hp

    Pre-cooled air

    hp Dashed line = towerwithout pre-cooling, forsame process load withsame tower airflow

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    26

    Direct 1-Stage Design

    Actual Values

    Note this is an open towerdesign. This may not be

    acceptable in some caseswhere concerns over watertreatment and fouling of coilsexist. In such a case, the useof a plate heat exchanger(typically employed on opentowers) will not work, since

    the temperature lossesinherent in such an approachmake the design impractical.

    ?

    79.7 tons pre-cooling

    200 tons towercapacity

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    27

    Indirect 1-Stage Design

    CT1/2: 180 gpm 78F - 62F = 120 tons @ 50 Hp 0.311 kW/ton CT3/4: 172 gpm 81F 66F at 15 Hp, relate to orig.120 tons 0.093 kW/ton

    requires 7.5 Hp and 3.0 Hp spray pumps 0.065 kW/tonTotal 0.469 kW/ton

    Evaporation water usage 0.037 gpm/ton

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    28

    Indirect 1-Stage Design

    CT1/2: 180 gpm 78F - 62F = 120 tons @ 50 Hp 0.311 kW/ton CT3/4: 172 gpm 81F 66F at 15 Hp, relate to orig.120 tons 0.093 kW/ton

    requires 7.5 Hp and 3.0 Hp spray pumps 0.065 kW/tonTotal 0.469 kW/ton

    Evaporation water usage 0.037 gpm/ton

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    29

    2-Stage Design

    CCT1/2 each: 180 gpm 78F - 67F = 82.5 tons @ 25 Hp 0.155 kW/ton*

    CCT3/4 each: 180 gpm 67F - 62F = 37.5 tons @ 50 Hp 0.311 kW/tonrequires 5 Hp, 5 Hp, 2 Hp spray pumps 0.075 kW/tonTotal 0.541 kW/ton

    Evaporation water usage 0.027 gpm/ton

    Note: all kW/ton calculations are basedon the total output (120 tons) of thesystem, not on the individual capacity

    of each tower

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    30

    2-Stage Design

    CCT1/2 each: 180 gpm 78F - 67F = 82.5 tons @ 25 Hp 0.155 kW/ton*

    CCT3/4 each: 180 gpm 67F - 62F = 37.5 tons @ 50 Hp 0.311 kW/tonrequires 5 Hp, 5 Hp, 2 Hp spray pumps 0.075 kW/tonTotal 0.541 kW/ton

    Evaporation water usage 0.027 gpm/ton

    73.4 tons pre-cooling

    111 tons towercapacity

    73.4 tons heat re-gain

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    31

    Energy and Water Usage

    at Design Conditions

    Direct 1-Stage 0.167 kW/ton 0.032 gpm/ton

    Indirect 1-Stage 0.469 kW/ton 0.037 gpm/ton

    2-Stage 0.541 kW/ton 0.027 gpm/ton

    Note that these values are fairly easily derived, butdont show the whole picture.

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    32

    Coil Calculations

    Why use cooling towersinstead of refrigeration?

    Compare 3 modelsannual energy use

    Compare 3 modelslife cycle cost

    Compare 3 models ofcooling tower use @

    Design

    Annual Analysis

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    33

    Annual Simulation

    Could use a spreadsheet, maybe DOE2.

    Spreadsheet offers more flexibility

    Look at bin weather data file to run a simulation

    Use approximation of coil performance to arriveat results for varying airflows and air enteringtemperatures. Use LMTD and -NTU methods.

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    34

    Bin Data and Building Load

    Match each temperature bin with a building

    load. This building load doesnt necessarily haveto be exact a rough approximation is sufficientsince were trying to find a comparison betweenmodels rather than an absolute number.

    Use the dry-bulb and coincident wet-bulb topredict how coil performance at tower inlets will

    vary.

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    36

    Sample Bin Data

    Temperaturevalues below the

    65F mark can beignored for thesimulation, sincethe system will bein economizer.

    ANNUAL TOTAL

    Obsn Hours Total M

    TEMP

    RANGE

    01

    to

    08

    09

    to

    16

    17

    to

    24

    Obsn

    Hrs

    C

    W

    B

    115/119 0 0 0 0 0

    110/114 0 0 0 0 73

    105/109 0 0 0 0 71

    100/104 0 0.5 0 0.5 70

    95/99 0 0.5 0 0.5 68

    90/94 0 6.8 0.1 6.9 66

    85/89 0 18.6 1.1 19.7 65

    80/84 0 43.8 4.3 48.1 6375/79 0.8 94.3 13.3 108 61

    70/74 5.2 269 37.4 312 58

    65/69 32.1 555 126 714 56

    60/64 214 668 421 1303 54

    55/59 748 667 927 2341 51

    50/54 962 400 892 2255 48

    45/49 563 159 384 1107 4440/44 297 35.3 102 435 40

    35/39 90.9 3.2 11.5 106 36

    30/34 9.2 0.4 0.6 10.2 31

    25/29 0 0 0 0 26

    20/24 0 0 0 0 23

    15/19 0 0 0 0 0

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    37

    Calculat ion for Off-Design Values

    Successively enter

    db/wbcombinations intotower selection tosimulate operation

    ANNUAL TOTAL

    Obsn Hours Total M

    TEMP

    RANGE

    01

    to

    08

    09

    to

    16

    17

    to

    24

    Obsn

    Hrs

    C

    W

    B

    115/119 0 0 0 0 0

    110/114 0 0 0 0 73

    105/109 0 0 0 0 71

    100/104 0 0.5 0 0.5 70

    95/99 0 0.5 0 0.5 68

    90/94 0 6.8 0.1 6.9 66

    85/89 0 18.6 1.1 19.7 65

    80/84 0 43.8 4.3 48.1 63

    75/79 0.8 94.3 13.3 108 61

    70/74 5.2 269 37.4 312 58

    65/69 32.1 555 126 714 56

    60/64 214 668 421 1303 54

    55/59 748 667 927 2341 51

    50/54 962 400 892 2255 48

    45/49 563 159 384 1107 4440/44 297 35.3 102 435 40

    35/39 90.9 3.2 11.5 106 36

    30/34 9.2 0.4 0.6 10.2 31

    25/29 0 0 0 0 26

    20/24 0 0 0 0 23

    15/19 0 0 0 0 0

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    Calculat ion for Off-Design Values

    Successively enter

    db/wbcombinations intotower selection tosimulate operation

    92 ?

    ?

    ?

    ?

    ANNUAL TOTAL

    Obsn Hours Total M

    TEMP

    RANGE

    01

    to

    08

    09

    to

    16

    17

    to

    24

    Obsn

    Hrs

    C

    W

    B

    115/119 0 0 0 0 0

    110/114 0 0 0 0 73

    105/109 0 0 0 0 71

    100/104 0 0.5 0 0.5 70

    95/99 0 0.5 0 0.5 68

    90/94 0 6.8 0.1 6.9 66

    85/89 0 18.6 1.1 19.7 65

    80/84 0 43.8 4.3 48.1 63

    75/79 0.8 94.3 13.3 108 61

    70/74 5.2 269 37.4 312 58

    65/69 32.1 555 126 714 56

    60/64 214 668 421 1303 54

    55/59 748 667 927 2341 51

    50/54 962 400 892 2255 48

    45/49 563 159 384 1107 4440/44 297 35.3 102 435 40

    35/39 90.9 3.2 11.5 106 36

    30/34 9.2 0.4 0.6 10.2 31

    25/29 0 0 0 0 26

    20/24 0 0 0 0 23

    15/19 0 0 0 0 0

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    39

    Calculat ion for Off-Design Values

    Successively enter

    db/wbcombinations intotower selection tosimulate operation

    87 ?

    ?

    ?

    ?

    ANNUAL TOTAL

    Obsn Hours Total M

    TEMP

    RANGE

    01

    to

    08

    09

    to

    16

    17

    to

    24

    Obsn

    Hrs

    C

    W

    B

    115/119 0 0 0 0 0

    110/114 0 0 0 0 73

    105/109 0 0 0 0 71

    100/104 0 0.5 0 0.5 70

    95/99 0 0.5 0 0.5 68

    90/94 0 6.8 0.1 6.9 66

    85/89 0 18.6 1.1 19.7 65

    80/84 0 43.8 4.3 48.1 6375/79 0.8 94.3 13.3 108 61

    70/74 5.2 269 37.4 312 58

    65/69 32.1 555 126 714 56

    60/64 214 668 421 1303 54

    55/59 748 667 927 2341 51

    50/54 962 400 892 2255 48

    45/49 563 159 384 1107 4440/44 297 35.3 102 435 40

    35/39 90.9 3.2 11.5 106 36

    30/34 9.2 0.4 0.6 10.2 31

    25/29 0 0 0 0 26

    20/24 0 0 0 0 23

    15/19 0 0 0 0 0

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    40

    Calculat ion for Off-Design Values

    Successively enter

    db/wbcombinations intotower selection tosimulate operation

    82 ?

    ?

    ?

    ?

    ANNUAL TOTAL

    Obsn Hours Total M

    TEMP

    RANGE

    01

    to

    08

    09

    to

    16

    17

    to

    24

    Obsn

    Hrs

    C

    W

    B

    115/119 0 0 0 0 0

    110/114 0 0 0 0 73

    105/109 0 0 0 0 71

    100/104 0 0.5 0 0.5 70

    95/99 0 0.5 0 0.5 68

    90/94 0 6.8 0.1 6.9 66

    85/89 0 18.6 1.1 19.7 65

    80/84 0 43.8 4.3 48.1 6375/79 0.8 94.3 13.3 108 61

    70/74 5.2 269 37.4 312 58

    65/69 32.1 555 126 714 56

    60/64 214 668 421 1303 54

    55/59 748 667 927 2341 51

    50/54 962 400 892 2255 48

    45/49 563 159 384 1107 4440/44 297 35.3 102 435 40

    35/39 90.9 3.2 11.5 106 36

    30/34 9.2 0.4 0.6 10.2 31

    25/29 0 0 0 0 26

    20/24 0 0 0 0 23

    15/19 0 0 0 0 0

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    41

    Calculat ion for Off-Design Values

    Successively enter

    db/wbcombinations intotower selection tosimulate operation

    77 ?

    ?

    ?

    ?

    ANNUAL TOTAL

    Obsn Hours Total M

    TEMP

    RANGE

    01

    to

    08

    09

    to

    16

    17

    to

    24

    Obsn

    Hrs

    C

    W

    B

    115/119 0 0 0 0 0

    110/114 0 0 0 0 73

    105/109 0 0 0 0 71

    100/104 0 0.5 0 0.5 70

    95/99 0 0.5 0 0.5 68

    90/94 0 6.8 0.1 6.9 66

    85/89 0 18.6 1.1 19.7 65

    80/84 0 43.8 4.3 48.1 6375/79 0.8 94.3 13.3 108 61

    70/74 5.2 269 37.4 312 58

    65/69 32.1 555 126 714 56

    60/64 214 668 421 1303 54

    55/59 748 667 927 2341 51

    50/54 962 400 892 2255 48

    45/49 563 159 384 1107 4440/44 297 35.3 102 435 40

    35/39 90.9 3.2 11.5 106 36

    30/34 9.2 0.4 0.6 10.2 31

    25/29 0 0 0 0 26

    20/24 0 0 0 0 23

    15/19 0 0 0 0 0

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    42

    Calculat ion for Off-Design Values

    Successively enter

    db/wbcombinations intotower selection tosimulate operation

    72 ?

    ?

    ?

    ?

    ANNUAL TOTAL

    Obsn Hours Total M

    TEMP

    RANGE

    01

    to

    08

    09

    to

    16

    17

    to

    24

    Obsn

    Hrs

    C

    W

    B

    115/119 0 0 0 0 0

    110/114 0 0 0 0 73

    105/109 0 0 0 0 71

    100/104 0 0.5 0 0.5 70

    95/99 0 0.5 0 0.5 68

    90/94 0 6.8 0.1 6.9 66

    85/89 0 18.6 1.1 19.7 65

    80/84 0 43.8 4.3 48.1 6375/79 0.8 94.3 13.3 108 61

    70/74 5.2 269 37.4 312 58

    65/69 32.1 555 126 714 56

    60/64 214 668 421 1303 54

    55/59 748 667 927 2341 51

    50/54 962 400 892 2255 48

    45/49 563 159 384 1107 4440/44 297 35.3 102 435 40

    35/39 90.9 3.2 11.5 106 36

    30/34 9.2 0.4 0.6 10.2 31

    25/29 0 0 0 0 26

    20/24 0 0 0 0 23

    15/19 0 0 0 0 0

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    43

    Calculat ion for Off-Design Values

    Lower wb means: Tower fancan run at less than 100%.How will coil react to lessairflow, and what will pre-cooling effect be?

    67 ?

    ?

    ?

    ?

    ANNUAL TOTAL

    Obsn Hours Total M

    TEMP

    RANGE

    01

    to

    08

    09

    to

    16

    17

    to

    24

    Obsn

    Hrs

    C

    W

    B

    115/119 0 0 0 0 0

    110/114 0 0 0 0 73

    105/109 0 0 0 0 71

    100/104 0 0.5 0 0.5 70

    95/99 0 0.5 0 0.5 68

    90/94 0 6.8 0.1 6.9 66

    85/89 0 18.6 1.1 19.7 65

    80/84 0 43.8 4.3 48.1 6375/79 0.8 94.3 13.3 108 61

    70/74 5.2 269 37.4 312 58

    65/69 32.1 555 126 714 56

    60/64 214 668 421 1303 54

    55/59 748 667 927 2341 51

    50/54 962 400 892 2255 48

    45/49 563 159 384 1107 4440/44 297 35.3 102 435 40

    35/39 90.9 3.2 11.5 106 36

    30/34 9.2 0.4 0.6 10.2 31

    25/29 0 0 0 0 26

    20/24 0 0 0 0 23

    15/19 0 0 0 0 0

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    Coil Calculations

    Why use cooling towersinstead of refrigeration?

    Compare 3 modelsannual energy use

    Compare 3 modelslife cycle cost

    Compare 3 models ofcooling tower use @

    Design

    Annual Analysis

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    45

    Coil Calculations

    Take desired designvalues and calculatewhat coil overall heattransfer needs to be

    LMTD method

    Verify design conditionwith calculated coil heat

    transfer

    -NTU method

    Verify other conditionwith calculated coil heat

    transfer

    -NTU method

    Explanation of-NTU method

    Why use cooling towersinstead of refrigeration?

    Compare 3 modelsannual energy use

    Compare 3 modelslife cycle cost

    Compare 3 models ofcooling tower use @

    Design

    Annual Analysis

    Skip coilcalculations

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    46

    Coil Calculations-Step 1

    Take desired designvalues and calculatewhat coil overall heattransfer needs to be

    LMTD method

    Verify design conditionwith calculated coil heat

    transfer

    -NTU method

    Verify other conditionwith calculated coil heat

    transfer

    -NTU method

    Explanation of-NTU method

    Why use cooling towersinstead of refrigeration?

    Compare 3 modelsannual energy use

    Compare 3 modelslife cycle cost

    Compare 3 models ofcooling tower use @

    Design

    Annual Analysis

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    Coil Calculation - LMTD

    LMTD method:

    T1= Thot,in Tcold,out and T2= Thot,out Tcold,in

    T2 T1Tlmtd = -----------------

    ln (T2/ T1)

    Q = UATlmtd

    Use this method to determine UA, based on the temperatures weexpect from design. In other words, we dont care exactly how the

    U and A are derived (fin spacing, number of rows etc). Well justassume that for the given problem, a coil can be purchased withthe right UA. We will then use this number to simulate how thatcoil will operate under different conditions.

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    Coil Calculation LMTD Example

    LMTD method:

    T1= 83 80 and T2= 68.2 65

    3.2-3.0Tlmtd = ----------------- = 3.1

    ln (3.2/ 3.0)

    Q = UA * 3.1 = 125 gpm * 15= 937.5 MBH

    UA = 302,524 Btu/ hF

    This number UA, which represents the overall heat transfercoefficient of the coil, can now be used to calculateperformance under different conditions.

    l l l

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    Coil Calculations-Step 2

    Take desired designvalues and calculatewhat coil overall heattransfer needs to be

    LMTD method

    Verify design conditionwith calculated coil heat

    transfer

    -NTU method

    Verify other conditionwith calculated coil heat

    transfer

    -NTU method

    Explanation of-NTU method

    Why use cooling towersinstead of refrigeration?

    Compare 3 modelsannual energy use

    Compare 3 modelslife cycle cost

    Compare 3 models ofcooling tower use @

    Design

    Annual Analysis

    C il Si l t i NTU

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    Coil Simulation -NTU -NTU method:

    By taking the UA we calculated earlier, and using the mass flow

    rates for each medium and the specific heat, we can determinewhat the leaving temperatures will be, based on the calculatedeffectiveness

    =

    max

    min

    minmax

    min

    max

    min

    min

    C

    C1

    C

    UAexp

    C

    C1

    C

    C1

    C

    UAexp1

    Hot

    actinHotoutHot

    CQTT = ,,

    Cold

    act

    in,Coldout,Cold C

    QTT +=

    Maxact

    inColdinHotMinMax

    QQTTCQ

    == )( ,,

    C il Si l t i NTU

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    Coil Simulation -NTU -NTU method:

    Note that the formula shown below for only holds for a perfectcounterflow heat exchanger.

    For other types (most real heat exchangers are somewherebetween a counter flow and parallel-flow exchanger).

    For such a case, the NTU is calculated, and is read off a chart

    Perfect Counter-flow Parallel flow Counter-flow

    =

    max

    min

    minmax

    min

    max

    min

    min

    CC1

    CUAexp

    CC1

    C

    C1

    C

    UAexp1

    minC

    UANTU =

    1C

    C

    max

    min =

    0CC

    max

    min =

    C il i l t i NTU

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    52

    Coil simulation -NTU -NTU method:

    Note that the formula shown below for only holds for a perfectcounterflow heat exchanger.

    For other types (most real heat exchangers are somewherebetween a counter flow and parallel-flow exchanger).

    For such a case, the NTU is calculated, and is read off a chart

    Perfect Counter-flow Parallel flow Counter-flow

    =

    max

    min

    minmax

    min

    max

    min

    min

    CC1

    CUAexp

    CC1

    C

    C1

    C

    UAexp1

    minC

    UANTU =

    1C

    C

    max

    min =

    0CC

    max

    min =

    We will use onlythis method

    C il Si l t i NTU E l

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    Coil Simulation -NTU Example -NTU method:

    Design at 83 / 68.2F for 57,700 cfm of airand 65 / 80F for 125 gpm of water

    (78.3 tons or 937 MBH)

    Reduce fan speed, use 40,000 cfm andAmbient reduced to 67F

    Performance now:Air at 67 / 65.1F for 40,000 cfmand 65 / 66.3F for 125 gpm of water(7 tons or 84 MBH)

    Coil Simulation NTU Example

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    Coil Simulation -NTU Example -NTU method:

    Design at 83 / 68.2F for 57,700 cfm of air =0.83and 65 / 80F for 125 gpm of water Qmax = 1,126 MBH(78.3 tons or 937 MBH)

    Reduce fan speed, use 40,000 cfm andAmbient reduced to 67F

    Performance now:Air at 67 / 65.1F for 40,000 cfm =0.96and 65 / 66.3F for 125 gpm of water Qmax = 88 MBH(7 tons or 84 MBH)

    Note that Qmax is the amount of heat that could be exchanged with aninfinitely large (or perfect) heat exchanger. is a measure of how wellthe actual exchanger under consideration approximates this idealexchanger, and varies with selected temperatures and flows.

    Coil Calculations Step 3

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    Coil Calculations-Step 3

    Take desired designvalues and calculatewhat coil overall heattransfer needs to be

    LMTD method

    Verify design conditionwith calculated coil heat

    transfer

    -NTU method

    Verify other conditionwith calculated coil heat

    transfer

    -NTU method

    Explanation of-NTU method

    Why use cooling towersinstead of refrigeration?

    Compare 3 modelsannual energy use

    Compare 3 modelslife cycle cost

    Compare 3 models ofcooling tower use @

    Design

    Annual Analysis

    Coil Simulation NTU Example

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    Coil Simulation -NTU Example -NTU method:

    Design at 83 / 68.2F for 57,700 cfm of air =0.83and 65 / 80F for 125 gpm of water Qmax = 1,126 MBH

    (78.3 tons or 937 MBH)

    Fh

    Btu396,63

    h

    min60*

    cuft

    lb0763.0*cfm700,57*

    Flb

    Btu24.0cC 111

    =

    ==

    Fh

    Btu550,62

    h

    min60*

    gal

    lb34.8*gpm125*

    Flb

    Btu0.1cC 222

    =

    ==

    Coil Simulation NTU Example

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    Coil Simulation -NTU Example-NTU method:Design at 83 / 68.2F for 57,700 cfm of air =0.83and 65 / 80F for 125 gpm of water Qmax = 1,126 MBH

    (78.3 tons or 937 MBH)

    =

    63,396

    62,550162,550

    302,524exp63,396

    62,5501

    63,396

    62,5501

    62,550

    302,524exp1

    396,63

    126,938

    832.68

    C

    QTT

    Hot

    actin,Hotout,Hot

    =

    =

    550,62

    126,9386580

    C

    QTT

    Cold

    actin,Coldout,Cold

    =

    +=

    MBH938126,1*83.0QQ

    MBH126,1)6583(550,62Q

    Maxact

    Max

    ===

    ==

    Coil Calculations-Step 4

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    Coil Calculations-Step 4

    Take desired designvalues and calculatewhat coil overall heattransfer needs to be

    LMTD method

    Verify design conditionwith calculated coil heat

    transfer

    -NTU method

    Verify other conditionwith calculated coil heat

    transfer

    -NTU method

    Explanation of-NTU method

    Why use cooling towersinstead of refrigeration?

    Compare 3 modelsannual energy use

    Compare 3 modelslife cycle cost

    Compare 3 models ofcooling tower use @

    Design

    Annual Analysis

    Coil simulation -NTU example

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    Coil simulation -NTU example -NTU method:

    Design at 67 / 65.1F for 40,000 cfm of air =0.96and 65 / 66.3F for 125 gpm of water Qmax = 88 MBH

    (7.0 tons or 84 MBH)

    Fh

    Btu949,43

    h

    min60*

    cuft

    lb0763.0*cfm000,40*

    Flb

    Btu24.0cC 111

    =

    ==

    Fh

    Btu550,62

    h

    min60*

    gal

    lb34.8*gpm125*

    Flb

    Btu0.1cC 222

    =

    ==

    Coil simulation -NTU example

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    Coil simulation NTU example -NTU method:

    Design at 67 / 65.1F for 40,000 cfm of air =0.96and 65 / 66.3F for 125 gpm of water Qmax = 88 MBH

    (7.0 tons or 84 MBH)

    =

    62,550

    43,949143,949

    302,524exp62,550

    43,9491

    62,550

    43,9491

    43,949

    302,524exp1

    949,43

    186,84671.65

    C

    QTT

    Hot

    actin,Hotout,Hot

    =

    =

    550,62

    186,84653.66

    C

    QTT

    Cold

    actin,Coldout,Cold

    =

    +=MBH2.848.87*96.0QQ

    MBH8.87)6567(949,43Q

    Maxact

    Max

    ===

    ==

    Annual Energy Use

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    Annual Energy Use

    Why use cooling towersinstead of refrigeration?

    Compare 3 modelsannual energy use

    Compare 3 modelslife cycle cost

    Compare 3 models ofcooling tower use @

    Design

    Annual Analysis

    Back to coilcalculations

    Energy Usage from Annual Simulation

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    Energy Usage from Annual Simulation

    Direct 1-Stage 1.7 MWh per year

    Indirect 1-Stage 20.4 MWh per year

    2-Stage 17.5 MWh per year

    Life Cycle Cost

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    Life Cycle Cost

    Why use cooling towersinstead of refrigeration?

    Compare 3 modelsannual energy use

    Compare 3 modelslife cycle cost

    Compare 3 models ofcooling tower use @

    Design

    Annual Analysis

    Initial Cost

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    Initial Cost

    Direct 1-Stage CT1/2 $ 36,000Coils (59,320 cfm)x2 $ 72,000Total $ 108,000

    Indirect 1-Stage CT1/2 $ 40,000CT3/4 $ 120,000Coils (78,500 cfm)x2 $ 92,000Total $ 252,000

    2-Stage CCT1/2 $ 125,000CCT3/4 $ 105,000Coils (114,000 cfm)x2 $ 145,000Total $ 375,000

    Note: pricing is for towers, and estimated coil + custom coilinstallation. Pricing does not include piping, valves and associatedcontrols.

    Simplified Life-Cycle Cost

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    Simplified Life Cycle Cost

    Direct 1-Stage first cost $ 108,000Energy cost, 20 years $ 4,100 (1.7 MWh/a)Total $ 112,100

    Indirect 1-Stage first cost $ 252,000Energy cost, 20 years $ 49,000 (20.4 MWh/a)Total $ 301,000

    2-Stage CCT1/2 $ 375,000

    Energy cost, 20 years $ 42,000 (17.5 MWh/a)Total $ 417,000

    Note: pricing is for equipment only. This includes towers, andestimated coil + installation of coil on tower. Pricing does not include

    piping, valves, rigging, setting, startup or associated controls.

    Direct 1-Stage also has lower water usage and maintenance costs (notincluded in this simple analysis)

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    20-year life cycle cost

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    y y

    20-year Life cycle cost

    $0

    $100,000

    $200,000

    $300,000

    $400,000

    $500,000

    $600,000

    $700,000

    0.06 0.08 0.1 0.12 0.14 0.16 0.18 0.2 0.22 0.24 0.26 0.28 0.3 0.32

    Cost $ / kWh

    Life

    cyc

    le

    cost

    Direct

    Indirect2-Stage

    Chiller

    Break-even at around $ 0.10/kWh

    Break-even at around $ 0.19/kWh

    Note: For amore realisticcalculation,piping materials& labor have tobe added to thecalculation. Thismakes thechiller modellook evenbetter, andbreak-evenoccurs at higherelectricityprices.

    15-year life cycle cost

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    15-year Life cycle cost

    $0

    $100,000

    $200,000

    $300,000

    $400,000

    $500,000

    $600,000

    $700,000

    0.06 0.08 0.1 0.12 0.14 0.16 0.18 0.2 0.22 0.24 0.26 0.28 0.3 0.32

    Cost $ / kWh

    Lifec

    ycle

    cost Direct

    Indirect

    2-StageChiller

    y y

    Break-even at around $ 0.13/kWh

    Break-even at around $ 0.25/kWh

    Note: For amore realisticcalculation,piping materials& labor have tobe added to thecalculation. Thismakes thechiller modellook evenbetter, andbreak-evenoccurs at higherelectricityprices.

    Questions

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    Q

    ?

    Psychrometric diagram

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    70

    y g

    Back to coolingtower principles

    WET

    DRY

    Psychrometric diagram

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    y g

    Back to coolingtower principles

    COLD HOT

    Psychrometric diagram

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    Back to coolingtower principles

    San

    Francisco

    F

    lorida

    Las Vegas

    Psychrometric diagram

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    Back to coolingtower principles

    Ab

    solute

    Humid

    ity

    Temperature

    50

    70

    90

    Psychrometric diagram

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    Back to coolingtower principles

    Temperature

    0.45 lbs water/100 lb air

    1.6 lb water/100 lb air

    2.7 lb water/100 lb air

    AbsoluteHumidity

    Psychrometric diagram

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    Back to coolingtower principles

    20% RH

    50% RH

    AbsoluteH

    umidity

    Temperature

    FOG

    90% RH

    Psychrometric diagram

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    Back to coolingtower principles

    AbsoluteH

    umidity

    Temperature

    FOG

    For the same moisture content,

    warmer air has a lower relative

    humidity or a lower saturation

    rate because hot air can absorbmore moisture

    20% RH50% RH90% RH

    1.08 lbs water/100 lb air

    Psychrometric diagram

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    Back to coolingtower principles

    Temperature

    90/90%

    90/33%Abs

    oluteH

    umidi

    ty

    68 wb

    87 wbWet bulb temp.