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Copyright © 2001 by Harcourt, Inc. All rights reserved.
Chapter 13
Acids and Bases
Copyright © 2001 by Harcourt, Inc.All rights reserved. Requests for permission to make copies of any part of the work should be mailed to the following address: Permissions Department, Harcourt, Inc. 6277 Sea Harbor Drive, Orlando, Florida 32887-6777
Bronsted-Lowry Acid-Base ModelThe Ion Product of WaterpH and pOHWeak Acids and Their Equilibrium ConstantsWeak Bases and Their Equilibrium ConstantsAcid-Base Properties of Salt Solutions
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The Arrhenius Theory:A Brief Review
HCl(g) → H+(aq) + Cl-(aq)
NaOH(s) → Na+(aq) + OH-(aq)H2O
H2O
Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) → H2O(l) + Na+(aq) + Cl-(aq)
H+(aq) + OH-(aq) → H2O(l)
Arrhenius theory did not handle non OH- bases such as ammonia very well.
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Brønsted-Lowry Acid-Base Model
Acid : a proton donor, base : a proton acceptor
HB(aq)+A-(aq) HA(aq)+B-(aq)
amphiprotic: H2O, HCO3-….
OHOHOH HH32
acid base
conj
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id
conj
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Brønsted-Lowry Model of Acids and Bases
Acid is proton donor, base is proton acceptor
HB(aq)+A-(aq) HA(aq)+B-(aq)
HB, HA are acids; A-, B- are bases. HB – B- and HA – A- are conjugate acid-base pairs.
Amphiprotic
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Acidic and Basic Water Solutions
Aqueous solution : acidic and basic properties of aqueous solutions are dependent on an equilibrium that involves
the solvent, water
pH : power of the hydrogen ion
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Aqueous solution
In any aqueous solution, there is an equilibrium between H30+ (
H+) ions and OH– ions: ion product constant of waterH2O H+(aq) + OH–(aq)
KW = [H+] [OH–] = 1.0 10-14 at 25C
1. Pure water: [H+] = [OH–] = 1.0 10–7 M; neutral solution
2. Acidic solution: [H+] > 1.0 10–7 M > [OH–]
3. Basic solution: [OH–] > 1.0 10–7 M > [H+]In seawater, [H+] = 5 10-9 M; [OH–] = ?[OH–] = (1.0 10-14) / (5 10-9) = 2 10-6 M
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pH
pH = –1og10[H+]
Neutral solution: pH = 7.0
Acidic solution: pH < 7.0
Basic solution: pH > 7.0Suppose [H+] = 2.4 10-6 M; calculate pH
pH = –1og10(2.4 10–6) = 5.62
Suppose pH = 8.68; calculate [H+]
[H+] = 10–8.68 = 2.1 10–9 MpOH = –1og10[OH–]; pH + pOH = 14.00 at 25C
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Ionization of aqueous HCl
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Relationship between pH and [H+]
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Relationship between pH and [H+]
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Strong AcidsHCl, HBr, HI, HClO4, HNO3, H2SO4
Strong BasesLiOH, NaOH, KOH, Ca(OH)2, Sr(OH)2, Ba(OH)2
HCl solution
Strong Acids & Bases
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Weak Acid and Their Eqilibrium Consts.
Acetic Acid HC2H3O2 or CH3CO2H
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Weak Acids
Molecules : molecules containing an ionizable hydrogen atom
Cations
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Molecules
HF(aq) + H2O H3O+(aq) + F –(aq)
There are literally thousands of molecular weak acids, most of them organic in nature.
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Cations
NH4+(aq) + H2O H3O+(aq) + NH3(aq)
Zn(H2O)42+(aq) + H2O H3O+(aq) + Zn(H2O)3(OH)+(aq)
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Weak Acids
Equilibrium constantsCalculation of Ka : the weaker the acid, the smaller the value of Ka
Calculation of [H+] in solution : by known amount of the weakacid to form a given volume of solution
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Weak Acids
Equilibrium constants
HB(aq) H+(aq) + B–(aq)
Ka [H+][B- ]
[HB]
pKa = -log10Ka
Weak acida : pKa HNO2 pKa = 3.22, HCN pKa=9.24
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Percent Ionization
HA + H2O H3O+ + A-
Degree of ionization =[H3O+] from HA
[HA] originally
Percent ionization =[H3O+] from HA
[HA] originally X 100%
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Polyprotic Weak Acid
H3PO4 H+ + H2PO4- Ka1 = 7.1 10-3
H2PO4- H+ + HPO4
2- Ka2 = 6.2 10-8
HPO42- H+ + PO4
3- Ka3 = 4.5 10-13
Ka1 >> Ka2 >> Ka3
All H3O+ is formed in the first ionization step.
H2PO4- essentially does not ionize further.
Assume [H2PO4-] = [H3O+].
ex2) H2CO3 , H2SO3, H2S
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Strengths of Binary Acids
HI HBr HCl HF
160.9 > 141.4 > 127.4 > 91.7 pm
297 < 368 < 431 < 569 kJ/mol
Bond length
Bond energy
109 > 108 > 1.3x106 >> 6.6x10-4 Acid strength
HF + H2O → [F-·····H3O+] F- + H3O+
ion pairH-bonding
free ions
Tips )Structure & AcidityTips )Structure & Acidity
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Strengths of Oxoacids
Factors promoting electron withdrawal from the OH bond to the oxygen atom:
High electronegativity (EN) of the central atom.A large number of terminal O atoms in the molecule.
H-O-Cl H-O-Br
ENCl = 3.0 ENBr= 2.8
Ka = 2.9x10-8 Ka = 2.1x10-9
Tips1)Structure & AcidityTips1)Structure & Acidity
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Calculation of Ka example
pH of 0.100 M HC2H3O2 solution is 2.87; Ka=?
[H+] = [C2H3O2–]=1.3 10–3 M
[HC2H3O2] = 0.100 M – 0.0013 M = 0.099 M
Ka = = 1.7 10–5(1.3 10–3)2
0.099
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Calculation of [H+] in solution example
Find [H+] in 0.200 M HC2H3O2, Ka=1.8 10–5
Let [H+] = x, then [C2H3O2–] = x,
[HC2H3O2] = 0.200 – x
= 1.8 10–5
Assume 0.200 - x 0.200 ; x = 1.9 10–3 M
In this case, % ionization = 100 = 1.0%
x2
0.200 – x
1.9 10–3
0.200
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Calculation of [H+] in solution example
Find [H+] in 0.100 M HF (Ka= 6.9 10–4)
= 6.9 10–4
Set 0.100 – x = 0.100, solve: x = 8.3 10–3 > 5%
Make second approximation:
= 6.9 10–4; x = 8.0 10–3
x2
0.100 – x
x2
0.100 – 0.008
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Weak Bases
Molecules : there are many molecular weak bases, including
the organic compounds known as amines
Anions derived from weak acids
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Molecules
NH3(aq) + H2O OH– (aq) + NH4+(aq)
The simplest weak base is ammonia.
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Anions derived from weak acids
F– (aq) + H2O HF(aq) + OH– (aq)
F- is conjugate base of the weak acid HF.
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Weak Bases
Equilibrium constant
•Expression for Kb : omitting the term for solvent water
•Relation between Ka and Kb : the larger the value of Ka, theSmaller the value of Kb and vise versa
•Calculation of [OH–] in solution of weak base
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Expression for Kb
NH3: Kb =[NH4
+] [OH–][NH3]
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Relation between Ka and Kb
Ka Kb = KW = 1.0 10–14
Ka Kb
HF 6.9 10–4 F– 1.4 10–11
HAc 1.8 10–5 Ac– 5.6 10–10
NH4+ 5.6 10–10 NH3 1.8 10–5
Strength of base is inversely related to that of conjugate weak acid.
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Calculation of [OH–] in solution of weak base
= 1.4 10–11 ; = 1.4 10–11
[OH–] = 1.2 10–6 M ; pH = 8.08
[HF][OH–][F–]
[OH–]2
0.10
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Acid-Base Properties of Salt Solutions
Cations : weak acids or spectator ions
Anions : weak bases or spectator ions
Overall Results
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Cations
Spectator: derived from strong bases
Li+, Na+, K+; Ca2+, Sr2+, Ba2+
Acidic: all other cations, including those of the transition metals.
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Anions
Spectator: derived from strong acids
C1–, Br–, I–, NO3–, SO4
2–
Basic: anions derived from weak acids, such as F–, NO2–
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Overall Results
Salt Cation AnionNaNO3 Na+(Sp.) NO3
–(Sp.) neutral
KF K+(Sp.) F–(Ba.) basicFeCl2 Fe2+(Ac.) Cl–(Sp.) acidic
If cation is acidic, anion basic, compare Ka, Kb values
NH4F: Ka = 5.6 10–10, Kb = 1.4 10–11; acidic
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