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Unit II - Lecture 7 Chemistry The Molecular Nature of Matter and Change Fifth Edition Martin S. Silberberg Copyright ! The McGraw-Hill Companies, Inc. Permission required for reproduction or display. Sample Problem 7.5 SOLUTION: PLAN: Applying the Uncertainty Principle PROBLEM: An electron moving near an atomic nucleus has a speed 6x10 6 ± 1%. What is the uncertainty in its position ("x)? The uncertainty ("x) is given as ±1% (0.01) of 6x10 6 m/s. Once we calculate this, plug it into the uncertainty equation. "u = (0.01)(6x10 6 m/s) = 6x10 4 m/s " x * m " u ! h 4# "x ! 4# (9.11x10 -31 kg)(6x10 4 m/s) 6.626x10 -34 kg*m 2 /s ! 1 x 10 -9 m The Schrödinger Equation H$ = E$ d 2 $ dy 2 d 2 $ dx 2 d 2 $ dz 2 + + 8# 2 m % h 2 (E-V(x,y,z)$(x,y,z) = 0 + how & changes in space mass of electron total quantized energy of the atomic system potential energy at x,y,z wave function Figure 7.16 Electron probability density in the ground-state H atom. Quantum Numbers and Atomic Orbitals An atomic orbital is specified by three quantum numbers. n the principal quantum number - a positive integer l the angular momentum quantum number - an integer from 0 to n-1 m l the magnetic moment quantum number - an integer from -l to +l Table 7.2 The Hierarchy of Quantum Numbers for Atomic Orbitals Name, Symbol (Property) Allowed Values Quantum Numbers Principal, n (size, energy) Angular momentum, l (shape) Magnetic, m l (orientation) Positive integer (1, 2, 3, ...) 0 to n-1 -l,…,0,…,+l 1 0 0 2 0 1 0 3 0 1 2 0 0 -1 +1 -1 0 +1 0 +1 +2 -1 -2

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Page 1: Copyright The McGraw-Hill Companies, Inc. Permission

Unit II - Lecture 7

ChemistryThe Molecular Nature of

Matter and Change

Fifth Edition

Martin S. Silberberg

Copyright ! The McGraw-Hill Companies, Inc. Permission required for reproduction or display.

Sample Problem 7.5

SOLUTION:

PLAN:

Applying the Uncertainty Principle

PROBLEM: An electron moving near an atomic nucleus has a speed 6x106 ± 1%.

What is the uncertainty in its position ("x)?

The uncertainty ("x) is given as ±1% (0.01) of 6x106 m/s. Once we

calculate this, plug it into the uncertainty equation.

"u = (0.01)(6x106 m/s) = 6x104 m/s

" x * m " u ! h

4#

"x !

4# (9.11x10-31 kg)(6x104 m/s)

6.626x10-34 kg*m2/s! 1 x 10-9 m

The Schrödinger Equation

H$ = E$

d2$

dy2

d2$

dx2

d2$

dz2+ +

8#2m%

h2(E-V(x,y,z)$(x,y,z) = 0+

how & changes in space

mass of electron

total quantized energy of the atomic system

potential energy at x,y,zwave function

Figure 7.16

Electron probability density in the ground-state H atom.

Quantum Numbers and Atomic Orbitals

An atomic orbital is specified by three quantum numbers.

n the principal quantum number - a positive integer

l the angular momentum quantum number - an integer from 0 to n-1

ml the magnetic moment quantum number - an integer from -l to +l

Table 7.2 The Hierarchy of Quantum Numbers for Atomic Orbitals

Name, Symbol(Property) Allowed Values Quantum Numbers

Principal, n(size, energy)

Angular momentum, l

(shape)

Magnetic, ml

(orientation)

Positive integer(1, 2, 3, ...)

0 to n-1

-l,…,0,…,+l

1

0

0

2

0 1

0

3

0 1 2

0

0-1 +1 -1 0 +1

0 +1 +2-1-2

Page 2: Copyright The McGraw-Hill Companies, Inc. Permission

Sample Problem 7.6

SOLUTION:

PLAN:

Determining Quantum Numbers for an Energy Level

PROBLEM: What values of the angular momentum (l) and magnetic (ml)

quantum numbers are allowed for a principal quantum number (n) of 3? How many orbitals are allowed for n = 3?

Follow the rules for allowable quantum numbers found in the text.

l values can be integers from 0 to n-1; ml can be integers from -l

through 0 to + l.

For n = 3, l = 0, 1, 2

For l = 0 ml = 0

For l = 1 ml = -1, 0, or +1

For l = 2 ml = -2, -1, 0, +1, or +2

There are 9 ml values and therefore 9 orbitals with n = 3.

Sample Problem 7.7

SOLUTION:

PLAN:

Determining Sublevel Names and Orbital Quantum Numbers

PROBLEM: Give the name, magnetic quantum numbers, and number of orbitals for each sublevel with the following quantum numbers:

(a) n = 3, l = 2 (b) n = 2, l = 0 (c) n = 5, l = 1 (d) n = 4, l = 3

Combine the n value and l designation to name the sublevel. Knowing l, we can find ml and the number of orbitals.

n l sublevel name possible ml values # of orbitals

(a)

(b)

(c)

(d)

3

2

5

4

2

0

1

3

3d

2s

5p

4f

-2, -1, 0, 1, 2

0

-1, 0, 1

-3, -2, -1, 0, 1, 2, 3

5

1

3

7

Sample Problem 7.8

SOLUTION:

Identifying Incorrect Quantum Numbers

PROBLEM: What is wrong with each of the following quantum numbers designations and/or sublevel names?

(a) n = 1 only l = 0. Name 1s.

(b) l = 3 is an f sublevel. Name 4f.

(c) l = 1 can only have ml of -1, 0, +1.

n l mlName

(a)

(b)

(c)

1

4

3

1

3

1

0

+1

-2

1p

4d

3p

Figure 7.17

Figure 7.18

The 2p orbitals.

Figure 7.19 The 3d orbitals.

Page 3: Copyright The McGraw-Hill Companies, Inc. Permission

Figure 7.19 continuedFigure 7.20 One of the seven

possible 4f orbitals.

Figure 7.21 The energy levels in the H atom.