Embed Size (px)
Citation preview
Page 1 of 18
Course Highlights
150+ Hours Live Classes
58 Online Live Classes of 2-2.30 hours each and 12 Online Workshops (Practice Sessions) of 3-4 hours each
100+ Pre Recorded Videos
Lectures covering all topics with smart tips & tricks
E-Books
Understand concepts better through downloadable e-books
Assignments
Daily Practice assignments to keep you well prepared
Doubt Clearing Sessions
Discussion board and live doubt clearing sessions to resolve every single doubt you may have
150+ Mock Tests
40 Full Lengths, 30 Sectional, 80+ Topic Tests
Personalized Mentoring
1-to-1 regular interaction sessions with our expert mentors offer unparalleled test preparedness
Other Benefits
Current Affairs E-Books, Questions Box, Interview Process Guide and more
Page 2 of 18
Meet Yours Mentors
Abhishek Shrivastava (Quantitative Aptitude/ Data Interpretation/ Logical Reasoning)
Ajit Chautrani (Quantitative Aptitude/ Data Interpretation/ Logical Reasoning)
Sneha Batham(Language Skills)
Page 3 of 18
IBPS PO Prelims 2018 - Memory Based Paper
(Logical Reasoning)
Answer Key 1 (c) 2 (b) 3 (c) 4 (c) 5 (c) 6 (c) 7 (d) 8 (b) 9 (b) 10 (c)
11 (a) 12 (c) 13 (d) 14 (b) 15 (e) 16 (d) 17 (e) 18 (b) 19 (a) 20 (b)
21 (d) 22 (c) 23 (c) 24 (d) 25 (c) 26 (c) 27 (b) 28 (b) 29 (a) 30 (e)
31 (d) 32 (c) 33 (b) 34 (b) 35 (d)
Solution Details 1. Ans: (c)
Box J kept at fifth position from the top. Two boxes kept between G and J. there are two positions. Box D
is kept just above box G.
There are as many boxes above box D as below box A. This condition possible only in case (i)
Five boxes are kept between box E and box C, which is kept at one of the positions below box J. if . Box I
is kept at one of the positions above box E. Only one box is kept between Box J and Box H. Thus
E = 4th position from Top
I = 3rd
position from Top
C= 2nd
position from Bottom.
H= 7th position from Top.
B kept above box F but not just above. Box F is not kept immediately above or immediately below box H.
Thus
Page 4 of 18
F = 9th position from Top
B = 6th position from Top
Reaming Box K kept between H and F.
2. Ans: (b)
Box J kept at fifth position from the top. Two boxes kept between G and J. there are two positions. Box D
is kept just above box G.
There are as many boxes above box D as below box A. This condition possible only in case (i)
Five boxes are kept between box E and box C, which is kept at one of the positions below box J. if . Box I
is kept at one of the positions above box E. Only one box is kept between Box J and Box H. Thus
E = 4th position from Top
I = 3rd
position from Top
C= 2nd
position from Bottom.
H= 7th position from Top.
B kept above box F but not just above. Box F is not kept immediately above or immediately below box H.
Thus
F = 9th position from Top
Page 5 of 18
B = 6th position from Top
Reaming Box K kept between H and F.
3. Ans: (c)
Box J kept at fifth position from the top. Two boxes kept between G and J. there are two positions. Box D
is kept just above box G.
There are as many boxes above box D as below box A. This condition possible only in case (i)
Five boxes are kept between box E and box C, which is kept at one of the positions below box J. if . Box I
is kept at one of the positions above box E. Only one box is kept between Box J and Box H. Thus
E = 4th position from Top
I = 3rd
position from Top
C= 2nd
position from Bottom.
H= 7th position from Top.
B kept above box F but not just above. Box F is not kept immediately above or immediately below box H.
Thus
F = 9th position from Top
B = 6th position from Top
Page 6 of 18
Reaming Box K kept between H and F.
4. Ans: (c)
Box J kept at fifth position from the top. Two boxes kept between G and J. there are two positions. Box D
is kept just above box G.
There are as many boxes above box D as below box A. This condition possible only in case (i)
Five boxes are kept between box E and box C, which is kept at one of the positions below box J. if . Box I
is kept at one of the positions above box E. Only one box is kept between Box J and Box H. Thus
E = 4th position from Top
I = 3rd
position from Top
C= 2nd
position from Bottom.
H= 7th position from Top.
B kept above box F but not just above. Box F is not kept immediately above or immediately below box H.
Thus
F = 9th position from Top
B = 6th position from Top
Reaming Box K kept between H and F.
Page 7 of 18
5. Ans: (c)
Box J kept at fifth position from the top. Two boxes kept between G and J. there are two positions. Box D
is kept just above box G.
There are as many boxes above box D as below box A. This condition possible only in case (i)
Five boxes are kept between box E and box C, which is kept at one of the positions below box J. if . Box I
is kept at one of the positions above box E. Only one box is kept between Box J and Box H. Thus
E = 4th position from Top
I = 3rd
position from Top
C= 2nd
position from Bottom.
H= 7th position from Top.
B kept above box F but not just above. Box F is not kept immediately above or immediately below box H.
Thus
F = 9th position from Top
B = 6th position from Top
Reaming Box K kept between H and F.
Page 8 of 18
6. Ans: (c)
C
7. Ans: (d)
Fourth to the left
8. Ans: (b)
The Golfer and the Swimmer sit opposite to each other.
9. Ans: (b)
DB
Page 9 of 18
10. Ans: (c)
B and F, when counted clockwise.
11. Ans: (a)
12. Ans: (c)
Page 10 of 18
13. Ans: (d)
14. Ans: (b)
Page 11 of 18
15. Ans: (e)
16. Ans: (d)
From (i) and (ii), very ⇒ gi
From (i), (ii) and (iv), risk ⇒ nu
From (i) and (iii), occurred ⇒ ta
From (iii) and (iv), also ⇒ fu
From (i), huge ⇒ ro
From (ii), low ⇒ se
From (ii) and (iii), is ⇒ ml
From (iii), that ⇒ po
From (iv), inherent ⇒ di/yu
damaging ⇒ di/yu
risk also huge ⟶ nu fu ro
17. Ans: (e)
Page 12 of 18
From (i) and (ii), very ⇒ gi
From (i), (ii) and (iv), risk ⇒ nu
From (i) and (iii), occurred ⇒ ta
From (iii) and (iv), also ⇒ fu
From (i), huge ⇒ ro
From (ii), low ⇒ se
From (ii) and (iii), is ⇒ ml
From (iii), that ⇒ po
From (iv), inherent ⇒ di/yu
damaging ⇒ di/yu
very ⟶ gi
18. Ans: (b)
From (i) and (ii), very ⇒ gi
From (i), (ii) and (iv), risk ⇒ nu
From (i) and (iii), occurred ⇒ ta
From (iii) and (iv), also ⇒ fu
From (i), huge ⇒ ro
From (ii), low ⇒ se
From (ii) and (iii), is ⇒ ml
From (iii), that ⇒ po
From (iv), inherent ⇒ di/yu
damaging ⇒ di/yu
occurred ⟶ ta
19. Ans: (a)
From (i) and (ii), very ⇒ gi
From (i), (ii) and (iv), risk ⇒ nu
From (i) and (iii), occurred ⇒ ta
From (iii) and (iv), also ⇒ fu
From (i), huge ⇒ ro
From (ii), low ⇒ se
From (ii) and (iii), is ⇒ ml
From (iii), that ⇒ po
From (iv), inherent ⇒ di/yu
damaging ⇒ di/yu
‘di’ stands for either ‘damaging’ or ‘inherent’
20. Ans: (b)
From (i) and (ii), very ⇒ gi
From (i), (ii) and (iv), risk ⇒ nu
From (i) and (iii), occurred ⇒ ta
From (iii) and (iv), also ⇒ fu
From (i), huge ⇒ ro
From (ii), low ⇒ se
From (ii) and (iii), is ⇒ ml
From (iii), that ⇒ po
From (iv), inherent ⇒ di/yu
damaging ⇒ di/yu
that is low ⟶ po ml se
Page 13 of 18
21. Ans: (d) The given information can be represented in the following diagram:
Point H is in northwest direction with respect to point F. 22. Ans: (c) The given information can be represented in the following diagram:
Point C, 6 meter far from point E
Page 14 of 18
23. Ans: (c) The given information can be represented in the following diagram:
Point F, 8 meter far from point D in south-east direction 24. Ans (d) The sequence series: ZA 25 / YB 23/XC 21 /WD 19/ VE 17. 25. Ans (c) The sequence is:
2 → B 3 → C 6 → F 7 → G 4 → D 5 → E 8 → H 9 → I
So, the missing terms are: C, 7, 4, E, 9. 26. Ans: (c)
Only III follows. 27. Ans: (b)
28. Ans: (b) Conclusion II does not follow.
Page 15 of 18
29. Ans: (a) In the statements,
M > A ≥ B = Q ≤ P < J ≤ Y …. (i)
Z ≥ A > X …. (ii)
In conclusion I, B < Y
From, (i), we get
Y ≥J > P ≥ Q = B
or Y ≥ J > P ≥ B
Here, Y > B
So, conclusion I is true.
In conclusion II,
X ≥ J
From Eq. (i) and (ii), we get
X < A ≥ B = Q ≤ P < J
We cannot compare X and J here.
So, conclusion II is not true.
Hence, only conclusion I is true.
Page 16 of 18
30. Ans: (e) In the statements,
M > A ≥ B = Q ≤ P < J ≤ Y ….. (i)
Z ≥ A > X
In conclusion I, Z = Q
From, (i) and (ii), we get
Z ≥ A ≥ B = Q
or Z ≥ A ≥ Q
Here, Z = Q and Z = Q
So, Z ≥ Q
In conclusion II, Z > Q
From Eq. (i) and (ii), we get Z ≥ Q
Hence, either conclusion I or II is true.
31. Ans: (d) In the statements,
G < R = A ≤ S ……(i)
T < R ……(ii)
In conclusion I,
G < S From, (i), we get
G < R = A ≤ S
Or G < R ≤ S
Here, G < S
So, conclusion I is true.
In conclusion II, S > T
From Eq. (i) and (ii), we get
S ≥ A = R > T
or S ≥ R > T
Here, S > T
So, conclusion II is true.
Hence, both conclusions I and II are true.
32. Ans: (c)
33. Ans: (b)
Page 17 of 18
34. Ans: (b)
35. Ans: (d)
Page 18 of 18
