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CRANK NICHLSON
0.05568
Delta t = 300 seg
Delta Z = 10 cm
Beta = 0.08352
CONDICIO LIMITE
X( z, 0 ) = 0
X( 0, t ) = 0.01375
X( L, t ) = 0
i 0 1 2 3 4 5 MATRIZ Aj TIEMPO DISTANCIA cm 1.16704 -0.08352
seg 0 10 20 30 40 50 -0.08352 1.167040 0 0.01375 0 0 0 0 0 0 -0.083521 300 0.01375 0.001978 0.000142 0.000010 0.000001 0 0 02 600 0.01375 0.003425 0.000493 0.000053 0.000005 0
3 900 0.01375 0.004515 0.000934 0.000142 0.000018 0 j = 04 1200 0.01375 0.005358 0.001403 0.000273 0.000042 0 T(i,j) C5 1500 0.01375 0.006026 0.001867 0.000437 0.000081 0 I = 0 0.013756 1800 0.01375 0.006568 0.002310 0.000626 0.000134 0 I = 1 0 0.00229687 2100 0.01375 0.007016 0.002725 0.000831 0.000200 0 I = 2 0 08 2400 0.01375 0.007393 0.003111 0.001045 0.000277 0 I = 3 0 09 2700 0.01375 0.007716 0.003467 0.001262 0.000363 0 I = 4 0 0
10 3000 0.01375 0.007995 0.003795 0.001479 0.000455 0 I = 5 011 3300 0.01375 0.008239 0.004097 0.001693 0.000552 0 T(0,J+1) 0.0137512 3600 0.01375 0.008455 0.004376 0.001901 0.000651 0 T(5,J+1) 013 3900 0.01375 0.008647 0.004634 0.002102 0.000751 0
DAB = cm2/seg
PROBLEMA 9.2
Se tiene n-octano líquido a 20 C y 1 atm. que se evapora y difunde a través de N2. El nivel del n-octano se mantiene constante. La concentración de en la interfase líquido-gas es xA0 = PAvap/P, siendo la presión de vapor a 20 C 10.45 mm Hg.
Asumir que la solubilidad de N2 en n-octano es despreciable, que la temperatura y presión son constantes y que los gases se comportan idealmente.
Graficar el perfil de concentración.
0 10 20 30 40 50 600
0.002
0.004
0.006
0.008
0.01
0.012
0.014
0.016 300 seg
600 seg
900 seg
1200 seg
1500 seg
2100 seg
2400 seg
2700 seg
3000
3300 seg
3600 seg
3900 seg
4200 segZ (cm)
XA
0 10 20 30 40 50 600
0.002
0.004
0.006
0.008
0.01
0.012
0.014
0.016 300 seg
600 seg
900 seg
1200 seg
1500 seg
2100 seg
2400 seg
2700 seg
3000
3300 seg
3600 seg
3900 seg
4200 segZ (cm)
XA
MATRIZ A INVERSA DE A0 0 0.861302773 0.06195867 0.00445694 0.000319
-0.08352 0 0.061958674 0.86575971 0.06227764 0.00445691.16704 -0.08352 0.004456941 0.06227764 0.86575971 0.0619587
-0.08352 1.16704 0.000318964 0.00445694 0.06195867 0.8613028
J = 1 J=2 J =3 J=4T(i,j) C T(i,j) C T(i,j) C T(i,j) C0.01375 0.01375 0.01375 0.01375
0.00197824 0.0039565 0.0034255 0.005191227 0.00451504 0.00613565 0.0053578 0.006876830.00014231 0.0002846 0.0004928 0.00070104 0.00093396 0.00116688 0.0014028 0.001638741.0237E-05 2.047E-05 5.3175E-05 8.5876E-05 0.00014168 0.00019748 0.0002726 0.00034778
7.326E-07 1.465E-06 5.061E-06 8.65673E-06 1.7557E-05 2.6458E-05 4.218E-05 5.7906E-050 0 0 0
0.01375 0.01375 0.01375 0.013750 0 0 0
PROBLEMA 9.2
Se tiene n-octano líquido a 20 C y 1 atm. que se evapora y difunde a través de N2. El nivel del n-octano se mantiene constante. La concentración de en la interfase líquido-gas es xA0 = PAvap/P, siendo la presión de vapor a 20 C 10.45 mm Hg.
Asumir que la solubilidad de N2 en n-octano es despreciable, que la temperatura y presión son constantes y que los gases se comportan idealmente.
Graficar el perfil de concentración.
0 10 20 30 40 50 600
0.002
0.004
0.006
0.008
0.01
0.012
0.014
0.016 300 seg
600 seg
900 seg
1200 seg
1500 seg
2100 seg
2400 seg
2700 seg
3000
3300 seg
3600 seg
3900 seg
4200 segZ (cm)
XA
0 10 20 30 40 50 600
0.002
0.004
0.006
0.008
0.01
0.012
0.014
0.016 300 seg
600 seg
900 seg
1200 seg
1500 seg
2100 seg
2400 seg
2700 seg
3000
3300 seg
3600 seg
3900 seg
4200 segZ (cm)
XA
J=5 J=6 J=7 J=8T(i,j) C T(i,j) C T(i,j) C T(i,j)
0.01375 0.01375 0.01375 0.013750.0060261352 0.00747224 0.0065680326 0.00796062 0.0070162328 0.00836864 0.00739343360.0018667539 0.00209476 0.002309816 0.00252487 0.0027250963 0.00292533 0.00311052940.0004373851 0.00052699 0.00062645 0.00072591 0.0008313347 0.00093676 0.00104511098.091933E-05 0.00010393 0.0001338892 0.00016385 0.0001998891 0.00023593 0.0002769574
0 0 0 00.01375 0.01375 0.01375 0.01375
0 0 0 0
J=9 J=10 J=11 J=12C T(i,j) C T(i,j) C T(i,j) C T(i,j)
0.01375 0.01375 0.01375 0.013750.00871503 0.00771572 0.00901321 0.00799471 0.00927301 0.00823897 0.00950173 0.008454920.00329573 0.00346654 0.00363734 0.00379473 0.00395212 0.00409721 0.0042423 0.004376190.00115346 0.00126241 0.00137137 0.00147923 0.00158709 0.00169264 0.00179819 0.001900590.00031798 0.00036281 0.00040765 0.00045516 0.00050268 0.00055186 0.00060105 0.00065104
0 0 0 00.01375 0.01375 0.01375 0.01375
0 0 0 0
J=13C T(i,j)
0.013750.00970491 0.00864745690.00451009 0.00463382180.00200299 0.00210167580.00070103 0.0007510943
00.01375
0
