69
Quantization C.M. Liu Perceptual Signal Processing Lab College of Computer Science National Chiao-Tung University Office: EC538 (03)5731877 [email protected] http://www.csie.nctu.edu.tw/~cmliu/Courses/Compression/

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Page 1: [CSCI 6990-DC] 09: Scalar Quantizationcmliu/Courses/Compression/... · 2009-04-27 · Vector Quantization (c.1) Vector quantization the vector quantization of x may be viewed as a

Quantization

C.M. LiuPerceptual Signal Processing Lab College of Computer ScienceNational Chiao-Tung University

Office: EC538(03)5731877

[email protected]

http://www.csie.nctu.edu.tw/~cmliu/Courses/Compression/

Page 2: [CSCI 6990-DC] 09: Scalar Quantizationcmliu/Courses/Compression/... · 2009-04-27 · Vector Quantization (c.1) Vector quantization the vector quantization of x may be viewed as a

Contents

Quantization Problem

Uniform Quantization

Adaptive Quantization

Nonuniform Quantization

Entropy-Coded Quantization

Vector Quantization

Rate-Distortion Function

2

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Quantization

Definition:

The process of representing a large—possibly infinite—set of values with a smaller set.

Example:Source:

Real numbers in the [-10.0, 10.0]

Quantization

Q(x) = ⎣x+0.5⎦[-10.0, -10.0] {-10, -9, …, -1, 0, 1, 2, …, 9, 10}

Scalar vs. vector quantizationScalar: applied to scalars

Vector: applied to vectors

3

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The Quantization Process

Two aspectsEncoder mapping

Map a range of values to a codewordIf source is analog A/D converterKnowledge of the source can help pick more appropriate ranges

Decoder mappingMap the codeword to a value in the rangeIf output is analog D/A converterKnowledge of the source distribution can help pick better approximations

Quantizer = encoder + decoder

4

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Quantization Example 5

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Quantizer Input-Output Map6

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Quantization Problem Formulation

Input:X – random variablefX(x) – probability density function (pdf)

Output:{bi}i=0..M decision boundaries

{yi}i=1..M reconstruction levels

Discrete processes are often approximated by continuous distributions

E.g.: Laplacian model of pixel differenceIf source is unbounded, then first/last decision boundaries = ±∞

7

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Quantization Error

Mean squared quantization error

8

( )

( ) dxfyx

dxfxQx

X

M

i

b

b i

Xq

i

i∑∫

=

∞−

−=

−=

1

2

22

1

)(σ

iii bxbyxQ ≤<= −1iff)(

Quantization error is a.k.a.Quantization noiseQuantizer distortion

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Quantization Problem Formulation (2)

Bit rates w/ fixed-length codewordsR = ⎡log2M⎤E.g.: M = 8 R = 3

Quantizer design problemGiven:

input pdf fX(x) & MFind:

decision boundaries {bi} and Reconstruction levels {yi}

Such that: MSQE is minimized

9

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Quantization Problem Formulation (3)

Bit rates w/ variable-length codewordsR depends on boundary selectionExample

10

∑ ==

M

i ii yPlR1

)(

∫−

=i

i

b

b Xi dxxfyP1

)()(

∑ ∫=−

=M

i

b

b Xii

i

dxxflR1

1

)(

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Quantization Problem Formulation (4)

Rate-optimization formulation

Given:

Distortion constraint σq2 ≤ D*

Find:{bi}, {yi}, binary codes

Such that:R is minimized

Distortion-optimization formulation

Given:Rate constraint R ≤ R*

Find:{bi}, {yi}, binary codes

Such that:

σq2 is minimized

11

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Uniform Quantizer

All intervals of the same sizei.e., boundaries are evenly spaced (Δ)Outer intervals may be an exception

ReconstructionUsually the midpoint is selected

Midrise quantizerZero is not an output level

Midtread quantizerZero is an output level

12

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Midrise vs. Midtread Quantizer13

Midrise Midtread

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Uniform Quantization of Uniform Source

InputUniform [-Xmax, Xmax]

OutputM-level uniform quantizer

14

MX max2

1221

2122

22

1)1(

max

22 Δ

=⎟⎠⎞

⎜⎝⎛ Δ

−−= ∑∫

=

Δ

Δ−

M

i

i

iq dxX

ixσ

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Alternative MSQE Derivation

Consider quantization error instead:q = x – Q(x)

q ∈ [-Δ/2, Δ/2]

15

∫Δ

Δ−

Δ=

Δ=

2

2

222

121 dqqqσ

( ) ( )

dB02.6)2(log20)(log10

212

122log1012

122log10log10)dB(SNR

102

10

2max

2max

102

2max

102

2

10

nM

MX

XX

n

q

s

===

⎟⎟⎟⎟⎟

⎜⎜⎜⎜⎜

⎟⎠⎞

⎜⎝⎛

=⎟⎟⎠

⎞⎜⎜⎝

⎛Δ

=⎟⎟⎠

⎞⎜⎜⎝

⎛=

σσ

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Examples (8 1, 2, 3 bits/pixel)16

Darkening, contouring & dithering

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Uniform Quantization of Nonuniform Sources

Example nonuniform source:x ∈ [-100, 100], P(x ∈ [-1, 1]) = 0.95

ProblemDesign an 8-level quantizer

The naïve approach leads to95% of samples values represented by two numbers:

-12.5 and 12.5

Max quantization error (QE)= 12.5

Min QE = 11.5 (!)

Consider an alternativeStep = 0.3

Max QE = 98.5, however 95% of the time QE < 0.15

17

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Optimizing MSQE18

Numerically solvable for specific PDF

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Example Optimum Step Sizes19

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QE for 3-bit Midrise Quantizer20

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Overload/Granular Regions21

"4"4,stdev

valuegranularmax11 loadingff σ→==

The step selectionTradeoff between overload noise and granular noise.

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Variance Mismatch Effects22

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Variance Mismatch Effects (2)23

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Distribution Mismatch Effects

8-level quantizers, SNR

24

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Adaptive Quantization

IdeaInstead of a static scheme, adapt to the actual data:

Mean, variance, pdf

Forward adaptive (off-line)Divide source in blocksAnalyze block statisticsSet quantization scheme

Side channel

Backward adaptive (on-line)Adaptation based on quantizer outputNo side channel necessary

25

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Forward Adaptive Quantization (FAQ)

Choosing block sizeToo large

Not enough resolutionIncreased latency

Too smallMore side channel information

Assuming a mean of zeroVariance estimate:

26

∑ −

= +=1

022 1ˆ N

i inq xN

σ

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Speech Quantization Example

16-bit speech 3-bit fixed

27

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Speech Quantization Example (2)

16-bit speech 3-bit FAQBlock = 128 samples

8-bit variance quantization

28

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FAQ Refinement

So far we assumed uniform pdf

RefinementAssume uniform pdf butRecord min/max values for each block

Example:Sena image8x8 blocks3-bit quantizationOverhead = 16/8x8 = 0.25 bits/pixel

29

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FAQ Refinement Example30

Original: 8 bits/pixel Quantized: 3.25 bits/pixel

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Backward Adaptive Quantization (BAQ)

ObservationOnly encoder sees inputAdaptation can only be based on quantized output

ProblemHow do we deduce mismatch information from output only?It is possible, if we know the pdf …… and we are very patient

31

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Jayant Quantizer

IdeaIf input falls in the outer levels

Expand step size

If input falls in the inner levelsContract step size

The product of expansions & contraction should be 1

Multipliers: Mk

If input Sn-1 falls in the kth interval, thenstep is multiplied by Mk

Inner Mk < 1, outer Mk > 1

32

1)1( −− Δ=Δ nnln M

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3-bit Jayant Quantizer Output Levels33

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Jayant Example

M0 = M4 = 0.8, M1 = M5 = 0.9

M2 = M6 = 1.0, M3 = M7 = 1.2, Δ0 = 0.5

Input: 0.1 -0.2 0.2 0.1 -0.3 0.1 0.2 0.5 0.9 1.5

34

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Picking Jayant Multipliers

Δmin / Δmax to prevent under/overflow.

Adaption speed affected by γ.

35

⎣ ⎦

∑∏

==

=

=

=

=⇒=

=>=

==

=

=

M

kkk

M

k

Pl

kkl

k

M

k

kk

P

M

k

Nn

M

k

n

Pl

llMLetNnPM

M

M

kk

k

k

k

k

k

k

k

00

0

0

0

01

,1where,

where,1

1

1

γ

γγ

Page 36: [CSCI 6990-DC] 09: Scalar Quantizationcmliu/Courses/Compression/... · 2009-04-27 · Vector Quantization (c.1) Vector quantization the vector quantization of x may be viewed as a

Jayant Example36

“Ringing”

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Jayant Performance37

Expands more rapidly than contracts to avoid overload errors.Robustness over changing input statistics.

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Non-uniform Quantization

Idea: Pick the boundaries such that error is minimized

i.e., smaller/bigger step for smaller/bigger values

e.g.:

38

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Non-uniform Quantization-- pdf-optimized Quantization

Problem: Given fX, minimize MSQE:

39

( ) dxfyx X

M

i

b

b iqi

i∑∫

= −

−=1

22

1

σ

Set derivative w.r.t. yj to zero and solve for yj:

( )

( )dxxf

dxxfxy

j

j

j

j

b

b X

b

b X

j

∫∫

−=

1

1

Set derivative w.r.t. bj to zero and solve for bj:( ) 21 jjj yyb += +

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Non-uniform Quantization-- Lloyd-Max Algorithm

Observation:Circular dependency b/w bj and yj

Lloyd/Max/Lukaszewics/Steinhaus approach:Solve the two iteratively until an acceptable solution is found

Example:

40

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Non-uniform Quantization-- Lloyd-Max Algorithm (2)

Boundaries: { b1, b2, …, bM/2-1}b0 = 0, bM/2-1 = MAX_INPUT

Reconstruction levels: { y1, y2, …, yM/2-1}

41

( ) ( )dxxfdxxfxyb

b X

b

b X ∫∫=1

0

1

01

One equation, two unknowns: b1, y1Pick a value for b1 (e.g. b1 = 1), solve for y1 and continue:

112 2 yby += ( ) ( )dxxfdxxfxyb

b X

b

b X ∫∫=2

1

2

12

… and so on until all { bn} and { ym} are found

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Non-uniform Quantization-- Lloyd-Max Algorithm (3)Terminating condition:

42

12122 2ˆ −− += MMM yby

( ) ( )dxxfdxxfxy M

M

M

M

b

b X

b

b XM ∫∫−−

=2/

12/

2/

12/2

ε≤− 22 ˆMM yy

Else: pick a different b1 & repeat

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Non-uniform Quantization— Example: pdf-Optimized Quantizers

43

Significant improvement over the uniform quantizer.

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Lloyd-Max Quantizer Properties

1. MeanOUTPUT = MeanINPUT

2. VarianceOUTPUT ≤ VarianceINPUT

3. MSQE:

44

[ ]jj

M

jjxq bxbPy ≤≤−= −

=∑ 1

1

222 σσ

4. If N is a random variable representing QE

[ ] 2qXNE σ−=

5. Quantizer output and QE are orthogonal (uncorrelated)

[ ] 0,,,|)( 10 =MbbbNXQE K

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Mismatch Effects45

4-bit Laplacian pdf-optimized quantizer

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Companded Quantization (CQ)46

Compressor Uniform quantizer Expander

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CQ Example: Compressor47

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CQ Example: Uniform Quantizer48

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CQ Example: Expander49

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CQ Example: Equivalent Non-uniform Quantizer50

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Vector Quantization

Definition

in alues vector v) stic(determini L of one only takemay it in that

on distributi special a has y vector e vector thrandom ldimensiona -N : ,

variablesrandom real : 1 , )( , )(

)]( .......... )2( )1([ )]( .......... )2( )1([

NR

yx

Niiyix

NyyyyNxxxx

≤≤

==

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Vector Quantization (c.1)

Vector quantization

the vector quantization of x may be viewed as a pattern recognition problem involving the classification of the outcomes of the random variable x into a discrete number of categories or cell in N-space in a way that optimizes some fidelity criterion, such as mean square distortion.

y Q x= ( )

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Vector Quantization (c.2)

VQ Distortion

VQ Optimizationminimize the average distortion D.

D P x C E d x y x C

d x yR l l l

k k kk

L

kN

= ∈ ∈=

∑ ( ) { ( , )| }

( , )1

1 2

are typically the distance measures in , including , , norm

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Vector Quantization (c.3)

Two conditions for optimalityNearest Neighbor Selection

minimize average distortion

=> applied to partition the N-dimensional space into cell when the joint pdf is known.

.1,for ),( ),( , )(

LjjkyxdyxdiffCxyxQ

jk

kk

≤≤≠≤∈=

NnxCxy

ky

ky

k

ddfyxd

CxyxdEDy

kξξξξ .....)....(),(....=

}|),({

11minarg

minargminarg

∈∫∫

∈===

{ , }C k Lk 1≤ ≤ fx( )•

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55

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Appendix C: Rate-Distortion Functions

Introduction

Rate-Distortion Function for a Gaussian Source

Rate-Distortion Bounds

Distortion Measure Methods

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1. Introduction

Considering questionGiven a source-user pair and a channel, under what conditions is it possible to design a communication system that reproduces the source output for the user with an average distortion that does not exceed some specified upper limit D?

The capacity (C) of a communication channel. The rate distortion function ( R(D) )of a source-user pair.

Rate-distortion function R(D)A communication system can be designed that achieves fidelity D if and only if the capacity of the channel that connects the source to user exceeds R(D).

The lower limit for data compression to achieve a certain fidelity subject to a predetermined distortion measure D.

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1. Introduction (cont.)

Equations representations :D is to r t io n D :

M u tu a l in fo rm a tio n :

R a te d is to r t io n fu n c t io n R (D ) :

d is to r t io n m e a su re fo r th e s o u rc e w o rd

= (

D d q p x q y x x y d x d y

I q p x q y xq y x

q yd x d y

R D I q Q q y x d q D

x y

x x

q Qd

n

D

= =

=

= = =

∫ ∫

∫ ∫

( ) ( ) ( | ) ( , )

( ) ( ) ( | ) lo g( | )

( )

( ) in f ( ) , { ( | ) : ( ) }

( , ) :

, . . . , )

ρ

ρx 1 r e p ro d u c e d a s = (y

T h e fa m ily is c a l le d th e

s in g le - le t te r f id e li ty c r i te r io n g e n e ra te d b y .

1

n

y

x ,y

,. . . , )

( ) ( , )

{ , }

y

n x y

F n

n

t t

t

n

n

ρ ρ

ρ

ρρ

=

= ≤ < ∞

=∑1

1

1

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2. Rate-Distortion Bounds

Introduction

Rate-Distortion Function for A Gaussian Source R(D) for a memoryless Gaussian sourceSource coding with a distortion measure

Rate-Distortion Bounds

Conclusions

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3. Rate-Distortion Function for A Gaussian Source

Rate-Distortion for a memoryless Gaussian source

The minimum information rate (bpn) necessary to represent the output of a discrete-time, continuous-amplitude, memorylessstationary Gaussian source based on an MSE distortion measure per symbol.

R DD D

Dg

x x

x

( )log ( ),

,=

≤ ≤

⎧⎨⎪

⎩⎪

12 2

2 2

20

σ σ

σ

0

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3. Rate-Distortion Function for A Gaussian Source (c.1)

Source coding with a distortion measure (Shannon, 1959)

There exists a coding scheme that maps the source output into codewords such that for any given distortion D, the minimum rate R(D) bpn is sufficient to reconstruct the source output with an average distortion that is arbitrarily close to D.

Transform the R(D) to distortion-rate function D(R)

21010

22

log106)(log10dBin Express

2)(

xg

xR

g

RRD

RD

σ

σ

+−=

= −

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Comparison between different quantizations

3. Rate-Distortion Function for A Gaussian Source (c.2)

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4. Rate-Distortion Bounds

Source:Memoryless, continuous-amplitude source with zero mean and finite variance with respect to the MSE distortion measure.

Upper boundAccording to the theorem of Berger (1971), it implies that the Gaussian source requires the maximum rate among all other sources for a specified level of mean square distortion.

R DD

R D D

D R D R

xg x

gR

x

( ) log ( ),

( ) ( )

≤ = ≤ ≤

≤ = −

12

0

2

2

22

2 2

σσ

σ

σx2

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Lower bound (Shannon lower bound)

where

4. Rate-Distortion Bounds (c.1)

)(2*

2*

22

1)(

2log21)()(

xHR

eRD

eDxHDR

−−=

−=

π

π

DeDeDR

exH

exf

xx

xg

x

xx

x

2

222

2*

22

2

log212log

212log

21)(

2log21)(

21)(

:sourceGaussian For 22

σπσπ

σπ

σπσ

=−=⇒

=

= −

∫∞

∞−−= ξξξ dffxH

xH

nxnx

def)(log)()(

entropy aldifferenti :)(

)(2)(

)()()(

)()()(*

*

RDRDRD

DRDRDR

g

g

≤≤

≤≤

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For Gaussian source, the rate-distortion, upper bound and lower bound are all identical to each other.The bound of differential entropy

4. Rate-Distortion Bounds (c.2)

)(by boundedupper isentropy aldifferenti The

)]()([6

)]()([6)()(

log10

)]()([66)(log10

*

*10

*10

xH

DRDR

xHxHRDRD

xHxHRRD

g

g

gg

g

−=

−=

−−−=

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Rate-distortion R(D) to channel capacity CFor C > Rg(D)

The fidelity (D) can be achieved.

For R(D)<C< Rg(D) Achieve fidelity for stationary sourceMay not achieve fidelity for random source

For C<R(D)Can not be sure to achieve fidelity

4. Rate-Distortion Bounds (c.3)

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4. Rate-Distortion Bounds (c.4)

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5. Distortion Measure Methods

{ }GG m r k c x m

k rcr

c rr

rrrrr

r( , , ) exp ( )

( / )( / )

( / ):

σ

σ

= − −

= =

= →= →= →= ∞ →

and

For different Laplacian pdf Gaussian pdf constant pdf uniform pdf

2 13

1

120

2ΓΓ

Γ

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Problems

Homeworks (Sayood 3rd, pp. 270-271)

3, 6.

Referenceshttp://en.wikipedia.org/wiki/Rate_distortion_theory.J.R. Deller, J.G. Proakis, and J.H.L. Hansen, “Discrete-Time Processing of Speech Signals,” IEEE Press

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