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PART I

SQL

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Table rakjay

Eno Ename Job Mgr Hierdate Sal Comm. Dept

7369 Sunita Clerk 7902 17-dec-80 2800 207499 Ashok Salesman 7698 20-feb-81 3600 300 30

7521 Rohit Salesman 7698 22-feb-81 5250 500 30

7566 Jyoti Manager 7839 02-apr-81 4975 20

7654 Martin salesman 7698 28-sep-81 6250 1400 30

7698 Binod Manager 7839 01-may-81 5850 30

7782 Chetan Manager 7839 09-jun-81 2450 10

7782 Sudhir Analyst 7566 19-apr-87 5000 20

7902 Sumit vats Analyst 7566 03-dec-81 3500 3600 20

1. Create the above table and insert the same values.SQL> create table rakjay(ename varchar(10), job varchar(10), eno number(5), mgr number(5), hierdate

date, sal number(8), comm number(5), dept number(5));

Table created.

SQL> desc rakjay;

Name Null? Type

----------------------------------------- -------- ----------------------------

ENAME VARCHAR2(10)

JOB VARCHAR2(10)ENO NUMBER(5)

MGR NUMBER(5)

HIERDATE DATE

SAL NUMBER(8)

COMM NUMBER(5)

DEPT NUMBER(5)

SQL>insert into rakjay values ('&ename','&job','&eno','&mgr','&hierdate','&sal','&comm','&dept');

Enter value for ename: Sunita

Enter value for job: clerk

Enter value for eno: 7369Enter value for mgr: 7902

Enter value for hierdate: 17-dec-80

Enter value for sal: 2800

Enter value for comm:

Enter value for dept: 20

old 1: insert into rakjay values('&ename','&job','&eno','&mgr','&hierdate','&sal','&comm','&dept')

new 1: insert into rakjay values('Sunita','clerk','7369',' 7902',' 17-dec-80','2800','','20')

1 row created.

SQL> /

Enter value for ename: ashokEnter value for job: salesman

Enter value for eno: 7499

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Enter value for mgr: 7698

Enter value for hierdate: 20-feb-81


Enter value for comm: 300



new 1: insert into rakjay values('ashok','salesman','7499','7698','20-feb-81','3600','300','30')

1 row created.

SQL> /

Enter value for ename: rohit

Enter value for job: salesman



Enter value for hierdate: 22-feb-81



Enter value for dept: 30old 1: insert into rakjay values('&ename','&job','&eno','&mgr','&hierdate','&sal','&comm','&dept')

new 1: insert into rakjay values('rohit','salesman','7521','7698','22-feb-81','5250','500','30')

1 row created.

SQL> /

Enter value for ename: jyoti

Enter value for job: manager



Enter value for hierdate: 02-apr-81





new 1: insert into rakjay values('jyoti','manager','7566','7839','02-apr-81','4975','','20')

1 row created.

SQL> /

Enter value for ename: martinEnter value for job: salesman



Enter value for hierdate: 28-sep-81





new 1: insert into rakjay values('martin','salesman','7654','7698','28-sep-81','6250','1400','30')

1 row created.

SQL> /

Enter value for ename: binod

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Enter value for hierdate: 01-may-81




old 1: insert into rakjay values('&ename','&job','&eno','&mgr','&hierdate','&sal','&comm','&dept')new 1: insert into rakjay values('binod','manager','7698','7839','01-may-81','5850','','30')

1 row created.

SQL> /

Enter value for ename: chetan




Enter value for hierdate: 09-jun-81

Enter value for sal: 2450Enter value for comm:



new 1: insert into rakjay values('chetan','manager','7782','7839','09-jun-81','2450','','10')

1 row created.

SQL> /

Enter value for ename: sudhir

Enter value for job: analyst



Enter value for hierdate: 19-apr-87





new 1: insert into rakjay values('sudhir','analyst','7782','7566','19-apr-87','5000','','20')

1 row created.

SQL> /

Enter value for ename: sumit vats

Enter value for job: analyst



Enter value for hierdate: 03-dec-81





new 1: insert into rakjay values('sumit vats','analyst','7902','7566','03-dec-81','3500','3600','2

1 row created.

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2. Select all the columns of the above table.

SQL> select * from rakjay;

ENAME JOB ENO MGR HIERDATE SAL COMM---------- ---------- ---------- ---------- --------- ---------- ----------

DEPT

----------

Sunita clerk 7369 7902 17-DEC-80 2800

20

ashok salesman 7499 7698 20-FEB-81 3600 300

30

rohit salesman 7521 7698 22-FEB-81 5250 500

30

ENAME JOB ENO MGR HIERDATE SAL COMM---------- ---------- ---------- ---------- --------- ---------- ----------

DEPT

----------

jyoti manager 7566 7839 02-APR-81 4975

20

martin salesman 7654 7698 28-SEP-81 6250 1400

30

binod manager 7698 7839 01-MAY-81 5850

30

ENAME JOB ENO MGR HIERDATE SAL COMM

---------- ---------- ---------- ---------- --------- ---------- ----------

DEPT

----------

chetan manager 7782 7839 09-JUN-81 2450

10

sudhir analyst 7781 7566 19-APR-87 5000

20

sumit vats analyst 7902 7566 03-DEC-81 3500 3600

20

9 rows selected.

3. List the name & eno from the above table.SQL> select ename, eno from rakjay;

ENAME ENO

---------- ----------

Sunita 7369

ashok 7499

rohit 7521

jyoti 7566martin 7654

binod 7698

chetan 7782

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sudhir 7781

sumit vats 7902

4. Display the ename and the incremented value of sal as sal+300.

SQL> Select ename, sal+300 from rakjay;

E_NAME increment

--------------- ----------

sunita 3100

ashok 3900

rohit 5550

jyoti 5275

martin 6550

binod 6150

chetan 2750

sudhir 5300

sumit vats 3800

9 rows selected

5. Display the ename & sal where comm. Is null.

SQL> select e_name, sal from rakjay where comm is NULL;

E_NAME SAL

--------------- ----------

sunita 2800

jyoti 4975

binod 5850

chetan 2450

sudhir 5000

6. List the distinct deptno from the table.

SQL> select distinct (deptno) from rakjay;

DEPTNO

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----------

10

20

30

7. List the unique jobs from the table.

SQL> select distinct (job) from rakjay;

JOB

--------------------

analyst

clerk

manager

salesman

8. List the sal where sal is less than the commission.

SQL> select sal from rakjay where sal select e_name, mgr from rakjay where mgr in (7902,7566,7788);

E_NAME MGR

--------------- ----------

sunita 7902

sudhir 7566

sumit vats 7566

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10. List the ename starting with sSQL> select e_name from rakjay where e_name like 's%';

E_NAME

---------------

sunita

sudhir

sumit vats

11.List all the columns where salary is greater than 4100.SQL> select * from rakjay where sal>4100;

E_NO E_NAME JOB MGR HIREDATE SAL

---------- --------------- -------------------- ---------- --------- ----------

COMM DEPTNO

---------- ----------

7521 rohit salesman 7698 22-FEB-81 5250

500 30

7566 jyoti manager 7839 02-APR-81 4975

20

7654 martin salesman 7698 28-SEP-81 6250

1400 30


---------- --------------- -------------------- ---------- --------- ----------

COMM DEPTNO

---------- ----------

7698 binod manager 7839 01-MAY-81 5850

30

7781 hir analyst 7566 19-APR-87 5000

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12. List all the columns in the ascending order of hiredate.SQL> select * from rakjay order by hiredate;


---------- --------------- -------------------- ---------- --------- ----------

COMM DEPTNO

---------- ----------

7369 sunita clerk 7902 17-DEC-80 2800

20

7499 ashok salesman 7698 20-FEB-81 3600

300 30

7521 rohit salesman 7698 22-FEB-81 5250

500 30


---------- --------------- -------------------- ---------- --------- ----------

COMM DEPTNO

---------- ----------

7566 jyoti manager 7839 02-APR-81 4975

20

7698 binod manager 7839 01-MAY-81 5850

30

7782 chetan manager 7839 09-JUN-81 2450

10


---------- --------------- -------------------- ---------- --------- ----------

COMM DEPTNO

---------- ----------

7654 martin salesman 7698 28-SEP-81 6250

1400 30

7902 sumit vats analyst 7566 03-DEC-81 3500

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3600 20

7781 sudhir analyst 7566 19-APR-87 5000

20

9 rows selected.

13. List all the details in the ascending order of deptno & descending order of

salary.

SQL> select * from rakjay order by deptno,sal desc;

E_NO E_NAME JOB MGR HIREDATE

---------- -------------------- -------------------- ---------- ---------

SAL COMM DEPTNO GRAD

---------- ---------- ---------- ----

7782 chetan manager 7839 09-JUN-81

2450 10

7781 sudhir analyst 7566 19-APR-87

5000 20

7566 jyoti manager 7839 02-APR-81

4975 20


---------- -------------------- -------------------- ---------- ---------


---------- ---------- ---------- ----

7902 sumit vats analyst 7566 03-DEC-81

3500 3600 20

7369 sunita clerk 7902 17-DEC-80

2800 20

7654 martin salesman 7698 28-SEP-81

6250 1400 30


---------- -------------------- -------------------- ---------- ---------

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---------- ---------- ---------- ----

7698 binod manager 7839 01-MAY-81

5850 30

7521 rohit salesman 7698 22-FEB-81

5250 500 30

7499 ashok salesman 7698 20-FEB-81

3600 300 30

9 rows selected.

14. Display the ename & deptno of all employees in dept 20 &30 in alphabetical

order by name.

SQL> select e_name, deptno from rakjay where deptno=20 or deptno=30 order by e_name;

E_NAME DEPTNO

--------------- ----------

ashok 30

binod 30

jyoti 20

martin 30

rohit 30

sudhir 20

sumit vats 20

sunita 20

15. List the name & salary of all the employees who earn more than 1200

and are in dept 10 or 40.SQL> select e_name, sal from rakjay where sal>1200 and (deptno=10 or deptno=40);

E_NAME SAL

--------------- ----------

chetan 2450

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16. List the name of all employees where the second letter of their name is

an a.SQL> select e_name from rakjay where e_name like '_a%';

E_NAME

---------------

Martin

17. Display the difference of highest & lowest salary of each

department having maximum salary >6000SQL> select (max(sal)-min(sal))"difference" from rakjay group by deptno having max(sal)>6000;

difference

----------

2650

18. Display the name of employees whose name contains Mas first alphabet ,L as

third alphabet.SQL> select e_name from rakjay where e_name like 'm_l%';

no rows selected

19. Display ename, sal of those employees who do not have their salary in the range

of 3000 to 6000.SQL> select e_name, sal from rakjay where sal not between 3000 and 6000;

E_NAME SAL

--------------- ----------

sunita 2800

martin 6250

chetan 2450

20. Display the name of employee whose name contain M as firstSQL> select e_name from rakjay where e_name like 'm%';

E_NAME

---------------

Martin

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21. Display total salary of all employees listed in table emp.SQL> select sum(sal)"total salary" from rakjay;

total salary

------------

39675

22.List the maximum salary of employee grouped by their department number.SQL> select max(sal) from rakjay group by deptno;

MAX(SAL)

----------

2450

5000

6250

23. Display the sum, average, highest and lowest salary of the employees grouped by

department number.SQL> select deptno, sum(sal), max(sal), min(sal), avg(sal) from rakjay group by deptno;

DEPTNO SUM(SAL) MAX(SAL) MIN(SAL) AVG(SAL)

---------- ---------- ---------- ---------- ----------

10 2450 2450 2450 2450

20 16275 5000 2800 4068.75

30 20950 6250 3600 5237.5

24. Add a field Grade in above tableSQL> alter table rakjay add(grade char(4));

Table altered.

SQL> desc rakjay;

Name Null? Type

----------------------------------------- -------- ----------------------

ENAME VARCHAR2(10)

JOB VARCHAR2(10)

ENO NUMBER(5)

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MGR NUMBER(5)

HIREDATE DATE

SAL NUMBER(8)

COMM NUMBER(5)

DEPT NUMBER(5)

GRADE CHAR(4)

25. Calcualte the average gross & total gross for employees belonging to E4 grade.SQL> Select avg(sal), sum(sal) from rakjay where grade= E4;

26. To display the jobs where the number of employees is less than 3.SQL> select job from rakjay group by job having count(job) create table rakjay(ID number(4) primary key, First_name varchar2(30) not null, last_name varchar2(30)

not null, user_id varchar2(10) unique, salary number(9,2), check (salary>5000));

Table created.

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SQL> desc rakjay;

Name Null? Type

----------------------------------------- -------- ----------------------------

ID NUMBER(4)

FIRST_NAME NOT NULL VARCHAR2(30)

LAST_NAME NOT NULL VARCHAR2(30)

USER_ID VARCHAR2(10)

SALARY NUMBER(9,2)

28. Delete the employee Record having ename as Jyoti.SQL> delete from rakjay where e_name='jyoti';

1 row deleted.

29. Rename rakjay to vr.SQL> alter table rakjay rename to vr;

Table altered.

SQL> desc rakjay;

ERROR:

ORA-04043: object employee does not exist

SQL> desc vr;

Name Null? Type

----------------------------------------- -------- ----------------------

ENAME VARCHAR2(10)

JOB VARCHAR2(10)

ENO NUMBER(5)

MGR NUMBER(5)

HIREDATE DATE

SAL NUMBER(8)

COMM NUMBER(5)

DEPT NUMBER(5)

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GRADE CHAR(4)

30. Drop table vr.SQL> drop table vr;

Table dropped.

31. Change the data type of column ename to char(20) in the Table employee.SQL> alter table rakjay modify(ename varchar(20));

Table altered.

SQL> desc rakjay;

Name Null? Type

----------------------------------------- -------- ----------------------

ENAME VARCHAR2(20)

JOB VARCHAR2(10)

ENO NUMBER(5)

MGR NUMBER(5)

HIREDATE DATE

SAL NUMBER(8)

COMM NUMBER(5)

DEPT NUMBER(5)

GRADE CHAR(4)

32. Make the changes permanent.SQL> Commit;

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Q1. List the name and salary of the employees whose salary is more than 1000.

SQL> select ename, sal from emp where sal>1000;

ENAME SAL

---------- ----------

ALLEN 1600

WARD 1250

JONES 2975

MARTIN 1250

BLAKE 2850

CLARK 2450

SCOTT 5500

KING 5000

TURNER 1500

ADAMS 1100

FORD 5500

ENAME SAL

---------- ----------

MILLER 1300

12 Rows selected.

Q2. List the employee number and name of manager.

SQL> select empno, ename from emp where job='MANAGER';

EMPNO ENAME

---------- ----------

7566 JONES

7698 BLAKE

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7782 RK

Q3. List the name of Clerks working in Department 20.

SQL> select ename from emp where job='CLERK' and deptno='20';

ENAME

----------

SMITH

ADAMS

Q4. List the employee name and salary, whose salary is between 1000 and 2000.

SQL> select ename, sal from emp where sal between 1000 and 2000;

ENAME SAL

---------- ----------

ALLEN 1600

WARD 1250

MARTIN 1250

TURNER 1500

ADAMS 1100

MILLER 1300

6 rows selected.

Q5. List the names of analysts and salesman.

SQL> select ename, job from emp where job='ANALYST' or job='SALESMAN';

ENAME JOB

---------- ---------

ALLEN SALESMAN

WARD SALESMAN

MARTIN SALESMAN

SCOTT ANALYST

TURNER SALESMAN

FORD ANALYST

6 rows selected.

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Q6. List the details of Employees who have joined before end of September 81 .

SQL> select ename from emp where hiredate select ename, job from emp where job !='MANAGER';

ENAME JOB

---------- ---------

SMITH CLERK

ALLEN SALESMAN

WARD SALESMAN

MARTIN SALESMAN

SCOTT ANALYST

KING PRESIDENT

TURNER SALESMAN

ADAMS CLERK

JAMES CLERK

FORD ANALYST

MILLER CLERK

11 rows selected

Q8. List the employees who are not eligible for commission.

SQL> select ename from emp where comm is NULL;

ENAME

----------

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SMITH

JONES

BLAKE

CLARK

SCOTT

KING

ADAMS

JAMES

FORD

MILLER

Q9. List the employees not assigned to any department.

SQL> select ename from emp where deptno is NULL;

no rows selected

Q10. List the employees who are eligible for commission.

SQL> select ename from emp where comm is NOT NULL;

ENAME

----------

ALLEN

WARD

MARTIN

TURNER

Q11. List the details of employees, whose salary is more than 2,500/- and

commission is null.

SQL> select * from emp where sal>2500 and comm is NULL;

EMPNO ENAME JOB MGR HIREDATE SAL COMM

---------- ---------- --------- ---------- --------- ---------- ----------

DEPTNO

----------

7566 JONES MANAGER 7839 02-APR-81 2975

20

7698 BLAKE MANAGER 7839 01-MAY-81 2850

30

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7788 SCOTT ANALYST 7566 19-APR-87 5500

20

EMPNO ENAME JOB MGR HIREDATE SAL COMM

---------- ---------- --------- ---------- --------- ---------- ----------

DEPTNO

----------

7839 KING PRESIDENT 17-NOV-81 5000

10

7902 FORD ANALYST 7566 03-DEC-81 5500

20

Q12. List the number of employees working with the company.

SQL> select count(ename) from emp;

COUNT(ENAME)

------------

14

Q13. List the number of jobs available in the emp table.

SQL> select count(job) from emp;

COUNT(JOB)

----------

14

Q14. List the maximum, minimum, average and sum of salary.

SQL> select max(sal), min(sal), avg(sal), sum(sal) from emp;

MAX(SAL) MIN(SAL) AVG(SAL) SUM(SAL)

---------- ---------- ---------- ----------

5500 800 2430.35714 34025

Q15. List the maximum salary of the employee working as a Salesman.

SQL> select max(sal) from emp where job='SALESMAN';

MAX(SAL)

----------

1600

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Q16. List the average salary of number of employees working in department 20 .

SQL> select avg(sal), count(ename) from emp where deptno=20;

AVG(SAL) COUNT(ENAME)

---------- ------------

3175 2

Q17. List the department number and number of employees in each department.

SQL> select deptno, count(ename) from emp group by deptno;

DEPTNO COUNT(ENAME)

---------- ------------

10 3

20 5

30 6

Q18. List the department number and the total salary payable in each department.

SQL> select deptno, sum(sal) from emp group by deptno;

DEPTNO SUM(SAL)

---------- ----------

10 8750

20 15875

30 9400

Q19. Select the jobs that are unique to department 20.

SQL> select unique(job) from emp where deptno=20;

JOB

---------

ANALYST

CLERK

MANAGER

Q20. List the employee names whose salary is greater than the lowest salary of an

employee belonging to department number 20.

SQL> select ename from emp where sal>(select min(sal) from emp where deptno=20);

ENAME

----------

ALLEN

WARD

JONES

MARTIN

BLAKE

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CLARK

SCOTT

KING

TURNER

ADAMS

JAMES

ENAME

----------

FORD

MILLER

13 rows selected.

Q21. List the employee names whose salary is greater than the highest salary of an

employee belonging to department number 20.SQL> select ename from emp where sal>(select max(sal) from emp where deptno=20);

ENAME

----------

KING

Q22. List the employees who joined in 1981.

SQL> select ename from emp where hiredate between '31-dec-80' and '01-jan-82';

ENAME

----------

ALLEN

WARD

JONES

MARTIN

BLAKE

CLARK

KING

TURNER

JAMES

FORD

10 rows selected.

Q23. Add number of month to a given date and returns a date after those many

months.

SQL> select hiredate, ADD_months(hiredate, 6)"probation" from emp where ename='SMITH';

HIREDATE probation

--------- ---------

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17-DEC-80 17-JUN-81

Q24. Convert a date into equivalent character string.

SQL> select TO_char(hiredate, 'month,dd,yyyy') from emp where ename='SCOTT';

TO_CHAR(HIREDATE,

-----------------april ,19,1987

Q25. Query to make the first letter capital.

SQL> select INITCAP('the soap') "capitals" from dual;

OUTPUT:

capitals

--------

The Soap

Q26. Query to change the statement from uppercase to lower case.

SQL> select LOWER ('MR.SCOTT MCMILLAN') "LOWER" from dual;

OUTPUT:

LOWER

-----------------

mr.scott mcmillan

Q27. Query to pad the left side of the string with the given set of characters.

SQL> select LPAD('AIMT',15,'*') "LPAD EXAMPLE" from DUAL;

OUTPUT:

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LPAD EXAMPLE

---------------

***********AIMT

Q28. Query to remove all specified characters from the left side of the string.

SQL> SELECT LTRIM('ARMYINSTITUTE','ARMY') "LTRIM EXAMPLE" FROM DUAL;

OUTPUT:

LTRIM EXA

---------

INSTITUTE

Q29. Query to remove all specified characters from the right side of the string.

SQL> SELECT RTRIM('ARMYINSTITUTE', 'INSTITUTE') "RTRIM EXAMPLE" FROM

DUAL;

OUTPUT:

RTRI

----

ARMY

Q30. Query to write a string and grab a specified string from the given set of

characters.

SQL> SELECT SUBSTR('ARMYINSTITUTE',6,4)"SUBSTR" FROM DUAL;

OUTPUT:

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SUBS

----

NSTI

Q31. Query to replace characters.

SQL> SELECT REPLACE('JACK AND JUE','J','BL') "CHANGES" FROM DUAL;

OUTPUT:

CHANGES

--------------

BLACK AND BLUE

Q32. Query to find out the starting location of the pattern of the string.

SQL> SELECT JOB,INSTR(JOB,'LE')FROM EMP;

OUTPUT:

JOB INSTR(JOB,'LE')

--------- ---------------

CLERK 2

SALESMAN 3

SALESMAN 3

MANAGER 0

SALESMAN 3

MANAGER 0

MANAGER 0

ANALYST 0

PRESIDENT 0

SALESMAN 3

CLERK 2

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JOB INSTR(JOB,'LE')

--------- ---------------

CLERK 2

ANALYST 0

CLERK 2

14 rows selected.

27

PART II

PL SQL

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Q1. Write a PL/SQL program to read two numbers and display their sum.

Ans. declare

num1 number(2);

num2 number(2);

num3 number(4);

begin

num1:=&number1;

num2:=&number2;

num3:=num1+num2;

dbms_output.put_line('the sum is:'||num3);

end;

/

Enter value for number1: 3

old 6: num1:=&number1;

new 6: num1:=3;



new 7: num2:=4;

the sum is:7

PL/SQL procedure successfully completed.

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new 6: num1:=4;



new 7: num2:=6;

the area of triangle is:12


Q4. Program to display area of rectangle.

Ans. declare

num1 number(2);

num2 number(2);

num3 number(4);

begin

num1:=&number1;

num2:=&number2;

num3:=num1*num2;

dbms_output.put_line('the area of rectangle is:'||num3);

end;

/



new 6: num1:=3;



new 7: num2:=8;

the area of rectangle is:24


Q5. Program to display sum, difference, multiplication and division.

Ans. declare

A1 number(4);

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B1 number(4);

C1 number(4);

D1 varchar(4);

begin

A1:=&number1;

B1:=&number2;

D1:=&varchar1;

if D1:='+'

then C1:=A1+B1;

dbms_output.put_line('The sum is:'||C1);

else if D1:='-'

then C1:=A1-B1;

dbms_output.put_line('The subtraction is:'||C1);

else if D1:='*'

then C1:=A1*B1;

dbms_output.put_line('The multiplication is:'||C1);

else D1:='/'

C1:=A1/B1;

dbms_output.put_line('The division is:'||C1);

end if;

end;

Q6. Program to display that if the number is greater than the other it swaps the two

number otherwise it doubles them.

Ans. Declare

X number(2);

Y number(2);

Z number(2);

S number(2);

D number(2);

D1 number(4);

Begin

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X:=& number1;

Y:=& number2;

If X>Y

Then

Z:=X;

X:=Y;

Y:=Z;

Dbms_output.put_line(X||Y);

Else

D=2XY;

D1=2XY;

Dbms_output.put_line(D||D1);

End if;

End;

Q7. Program to print first N natural number & their sum.

Ans. Declare

N number;

Sum number:=0;

Begin

N:=&number;

For I IN 1.....N

loop

SUM=SUM+I;

Dbms_output.put_line(som of first n natural number||SUM);

End;

Q8. Program to print table

Ans. Declare

N number(2);

T number(2);

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Begin

N:=&num1;

For I IN 1.....10

Loop

T=N*I;

Dbms_output.put_line(the table is:||T);

End;

Q9. Program to print table through while loop.

Ans. Declare

I number:=0;

Begin

While I

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Empno=eno;

If salary>3000

Update emp set sal=sal+.05*sal;

Where empno=eno;

End if;

End;

Q.11. Write a PL/SQL code that traps zero divide exceptions while calculating price

to earnings ratio with a company symbol xyz.

Ans. Declare

Pre ratio number(3,1);

Begin

Select price/earnings into price ratio from stock

Where symbol=xyz;

Exceptions

When zero divides then

Insert into stocks (symbol, ratio) values(xyz,NULL);

Commit;

When other

Then rollback;

End;

Q.12. Write a PL/SQL code to obtain details of employee drawing maximum salary.

Add his/her details into a table new sal (empno, ename, salary) after incrementing

salary by Rs.700.

Ans. Declare

Eno emp.empno%type;

Name emp.ename%type;

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Salary emp.sal%type;

Begin

Select empno,ename,sal into eno,ename,salary from emp where sal=(select max(sal) from emp);

Salary=salary+700;

Insert into new sal values (Eno,ename,salary);

End;

Q13. Write a PL/SQL code in reference with Explicit cursor.

Ans.Declare

Cursor emp_cur IS

Select * from emp;

Emprec emp% rowtype;

Begin

If not emp_cur IS open

Then open emp_cur

End if

Fetch emp_cur into emprec

While emp_cur % found

Loop

Dbms_output.put_line(emp_cur % row count);

End loop;

Close emp_cur;

End;

Q14. Write a PL/SQL code in reference with implicit cursor.

Ans. Declare

My sql numer(7,2);

Rec number;

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Begin

Select sal into my sql from emp where empno=7788;

When sal>mysql

IF sql % found

Then

Dbms_output.put_line(mysql)

If sql % row count>0

Then

Rec:=sql % row count;

Dbms_output.put_line(rec);

End if;

End;

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