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Defence Technology & Systems Course DTS 5121 - Air Systems AF 06 : Aircraft Performance Assoc. Prof. Gerard Leng Coordinator - Aeronautical Engineering Group, ME Dept., NUS Adjunct Principal Member of the Technical Staff, DSO National Labs.

Defence Technology & Systems Course DTS 5121 - Air …dynlab.mpe.nus.edu.sg/mpelsb/dts5121/Perf1n.pdf · References G. Leng, ME Dept, NUS M.E. Eshelby, “Aircraft Performance: Theory

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Def

ence

Tec

hnol

ogy

& S

yste

ms C

ours

eD

TS 5

121

-Air

Syst

ems

AF

06 :

Airc

raft

Perf

orm

ance

Ass

oc. P

rof.

Ger

ard

Leng

Coo

rdin

ator

-A

eron

autic

al E

ngin

eerin

g G

roup

, ME

Dep

t., N

US

Adj

unct

Prin

cipa

l Mem

ber o

f the

Tec

hnic

al S

taff

, DSO

Nat

iona

l Lab

s.

G. L

eng,

ME

Dep

t, N

US

Trai

ning

Pro

gram

me

1 : O

f Thr

ust,

Pow

er a

nd W

eigh

tor

wha

t fac

tors

affe

ct a

ircr

aft p

erfo

rman

ce ?

2 : C

ruis

e Pe

rfor

man

ce -

Ran

ge a

nd E

ndur

ance

or h

ow fa

st a

nd h

ow lo

ng c

an th

e ai

rcra

ft fly

?

3 : T

akeo

ff a

nd L

andi

ng P

erfo

rman

ceor

how

muc

h ru

nway

do

we

need

?

4 : C

limb

and

Turn

Per

form

ance

or h

ow n

imbl

e is

the

airc

raft

?

G. L

eng,

ME

Dep

t, N

US

Ref

eren

ces

•M

.E. E

shel

by, “

Airc

raft

Perf

orm

ance

: The

ory

and

Prac

tice”

, A

IAA

Edu

catio

n Se

ries 2

000

•Jo

opW

agen

mak

ers,

“Airc

raft

Perf

orm

ance

Eng

inee

ring”

, Pr

entic

e H

all,

1991

•A

ngel

o M

iele

, “Fl

ight

Mec

hani

cs :

The

ory

of F

light

Pat

hs”,

Pe

rgam

on, 1

962

G. L

eng,

ME

Dep

t, N

US

Som

e co

mm

on te

rms a

nd c

onve

rsio

n fa

ctor

s

Airc

raft

engi

ne d

ata

(esp

ecia

lly U

S en

gine

s) d

on’t

use

SI u

nits

!

a) k

nots

(kt)

–un

it of

spee

d =

0.5

151

m/s

b) p

ound

(lb

or lb

f) –

unit

of fo

rce

= 4.

448

N

c) p

ound

mas

s (lb

or l

bm) –

unit

of m

ass =

0.4

54 k

g

d) h

orse

pow

er (h

p) -

unit

of p

ower

= 0

.745

7 kW

e) n

autic

al m

ile (n

m) –

unit

of d

ista

nce

= 1’

of l

atitu

de a

t equ

ator

= 6

080

ft =

185

3 m

G. L

eng,

ME

Dep

t, N

US

The

basi

c id

ea o

f thr

ust p

rodu

ctio

n

Thru

st

~

d (m

ass f

low

x e

xhau

st v

eloc

ity)

dt

G. L

eng,

ME

Dep

t, N

US

How

doe

s a tu

rboj

et w

ork

?

G. L

eng,

ME

Dep

t, N

US

Wor

ld’s

firs

t jet

eng

ines

Han

s von

Oha

in’s

HS3

BFr

ank

Whi

ttle’

sW1

G. L

eng,

ME

Dep

t, N

US

Exam

ple

: Eng

ine

upgr

ade

A4S

to A

4S-1

G. L

eng,

ME

Dep

t, N

US

J65-

W-2

0 tu

rboj

et

G. L

eng,

ME

Dep

t, N

US

Rep

lace

men

t eng

ine

F404

-GE-

100D

turb

ofan

G. L

eng,

ME

Dep

t, N

US

F404

-GE-

400

cuta

way

dia

gram

G. L

eng,

ME

Dep

t, N

US

Que

stio

n : H

ow d

oes a

turb

ofan

wor

k ?

G. L

eng,

ME

Dep

t, N

USF4

04-G

E-10

0D

spec

ifica

tions

•M

axim

um th

rust

: 11

,000

lbs.

48

.9 k

N•

Wei

ght:

1,82

0 lb

s 82

6 kg

Leng

th:

89 in

ches

22

6 cm

Inle

t dia

met

er:

31 in

ches

79

cm

Max

dia

met

er:

35 in

ches

89

cm

Airf

low

: 14

2 lb

s/se

c

64 k

g/se

c •

Pres

sure

ratio

: 25

-to-1

•B

ypas

s rat

io*

0.34

* B

ypas

s rat

io

=

(mas

s of a

ir th

roug

h fa

n) /

( mas

s of a

ir th

roug

h co

re)

G. L

eng,

ME

Dep

t, N

US

Com

paris

on :

J65-

W-2

0 an

d F4

04-G

E-10

0D

Engi

ne T

/W *

TSFC

(kg/

hr)/N

**

826

1251

Engi

ne w

eigh

t (W

/g)

k

48.9

37.4

Max

thru

st (T

) kN

F404

-GE-

100D

J65-

W-2

0

* N

ot to

be

conf

used

with

the

airc

raft

thru

st to

wei

ght r

atio

** T

SFC

is th

e th

rust

spec

ific

fuel

con

sum

ptio

nTS

FC is

def

ined

as f

uel-f

low

rate

per

uni

t of t

hrus

t pro

duce

d (N

or l

bf)

Fuel

-flo

w ra

te is

mea

sure

d in

uni

ts o

f mas

s of f

uel f

low

per

hou

r (kg

/hr o

r lbm

/hr)

G. L

eng,

ME

Dep

t, N

US

War

ning

! TS

FC is

not

non

dim

ensi

onal

!

( lb

m/ h

r )( 0

.454

kg/

hr)

----

----

----

---

=--

----

----

----

----

--lb

f4.

448

N

=(k

g/hr

) / N

G. L

eng,

ME

Dep

t, N

US

The

payo

ff

•30

%le

ss ta

ke-o

ff ti

me

•15

% h

ighe

r das

h sp

eed

•35

%fa

ster

acc

eler

atio

n

•40

%in

crea

sed

rate

of c

limb

(RO

C)

•M

ax sp

eed

at se

a le

vel:

610

knot

s (11

30 k

m/h

)

•M

ax c

ruis

e sp

eed

at 3

0 kf

t(10

km

): 44

6 kn

ots (

826

km/h

)

Com

men

ts ?

G. L

eng,

ME

Dep

t, N

US

Wer

e th

ere

prob

lem

s in

airf

ram

e/en

gine

inte

grat

ion

?

G. L

eng,

ME

Dep

t, N

US

Exer

cise

: F1

6A a

nd F

16D

Que

stio

n :

Wha

t’s th

e di

ffer

ence

?