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Degree SequenceConditions for EqualEdge-Connectivity andMinimum Degree,Depending on theClique Number
Lutz Volkmann*LEHRSTUHL II FUR MATHEMATIK
RWTH AACHEN, 52056 AACHEN, GERMANY
E-mail: [email protected]
Received December 15, 2000; Revised August 26, 2002
DOI 10.1002/jgt.10087
Abstract: Using the well-known Theorem of Turan, we present in thispaper degree sequence conditions for the equality of edge-connectivity andminimum degree, depending on the clique number of a graph. Differentexamples will show that these conditions are best possible and inde-pendent of all the known results in this area. � 2003 Wiley Periodicals, Inc. J Graph
Theory 42: 234–245, 2003
Keywords: edge-connectivity; degree sequence; clique number
——————————————————
*Correspondence to: Lutz Volkmann, Lehrstuhl II fur Mathematik, RWTH Aachen,Templergraben 55, Aachen D-52062 Germany.E-mail: [email protected]
� 2003 Wiley Periodicals, Inc.
1. INTRODUCTION
Sufficient conditions for the equality of the edge-connectivity �ðGÞ ¼ � and the
minimum degree �ðGÞ ¼ � of a graph G were given by several authors. For other
graph theory terminology we follow Chatrand and Lesniak [3]. The most general
results for arbitrary graphs are the following statements.
As a generalization of results of Chartrand [2], Lesniak [7], Plesnık [8], and
Plesnık, Znam [9], Dankelmann and Volkmann [4] (see also the textbook of
Volkmann [13, p. 318ff]) proved the following theorem.
Theorem 1.1 [4]. Let G be a connected graph. If for all 3-distance maximal
pairs of sets X; Y � VðGÞ the condition �ðG½X [ Y �Þ ¼ 0 is fulfilled, then � ¼ �.
For a connected graph G, we define the distance dðu; vÞ between two vertices u
and v as the minimum of the lengths of the u� v paths of G. For two subsets X
and Y of the vertex set VðGÞ in a connected graph G, let dðX;YÞ ¼ minfdðx; yÞ jx 2 X; y 2 Yg. A pair of sets X; Y � VðGÞ with distance dðX;YÞ ¼ 3 is called
3-distance maximal, if there exist no sets X1 6¼ X or Y1 6¼ Y with X � X1 and
Y � Y1 such that dðX1;Y1Þ ¼ 3.
The next result is an improvement of a well-known degree sequence condition
of Bollobas [1].
Theorem 1.2 [5]. Let G be a graph of order n with edge-connectivity � and
degree sequence d1 � d2 � � � � � dn ¼ �. If � � bn=2c or if � � bn=2c � 1 and
Xki¼1
ðdi þ dnþi���1Þ � kðn� 2Þ þ 2� � 1
for some k with 1 � k � �, then � ¼ �.
A further degree sequence condition can also be found in [5].
Theorem 1.3 [5]. Let G be a graph of order n with edge-connectivity � and
degree sequence d1 � d2 � � � � � dn ¼ �. If � � bn=2c or if � � bn=2c � 1 and
X2k
i¼1
dnþ1�i � kn� 3
for some k with 2 � k � �, then � ¼ �.
Theorem 1.4 [6]. Let G be a graph of order n with edge-connectivity �,
clique number ! � p, and degree sequence d1 � d2 � � � � � dn ¼ �. If n �2b�p=ðp� 1Þc � 1 or if n � 2b�p=ðp� 1Þc � 2p and
Xki¼1
di þXð2p�1Þk
i¼1
dnþ1�i � kðp� 1Þnþ 2� � 1
for some k with 1 � k � b�=ðp� 1Þc, then � ¼ �.
DEGREE SEQUENCE CONDITIONS 235
Let G be a graph with vertex set VðGÞ, edge set EðGÞ, and clique number
!ðGÞ ¼ ! � p. Then, the well-known Theorem of Turan [10] leads to
2jEðGÞj� p� 1
pjVðGÞj2:
Using this bound, we present in this paper degree sequence conditions for the
equality of edge-connectivity and minimum degree, depending on the clique
number, which are independent of Theorems 1.1–1.4. Examples will show that
these conditions are best possible, and one of our theorems implies a result of
Dankelmann and Volkmann [4].
2. MAIN RESULTS
Theorem 2.1. Let G be a graph of order n � 6 with edge-connectivity �, clique
number ! � p, and degree sequence d1 � d2 � � � � � dn ¼ �. Furthermore, let
� ¼ 1 when n is even and � ¼ 0 when n is odd. If � � bn=2c or if � � bn=2c � 1
and
X�þ1
i¼1
dnþ1�i � ð� þ 1Þ p� 1
p
nþ 1 þ �
2� 2� þ 2
pðn� 3 þ �Þ ;
then � ¼ �.
Proof. Suppose to the contrary that � < �. Then, there exist two disjoint sets
X;Y � VðGÞ with X [ Y ¼ VðGÞ such that the number of edges jðX; YÞj from X
to Y satisfy the inequality jðX; YÞj < �.We first show that the sets X and Y contain at least � þ 1 vertices, and therefore
� � bn=2c � 1.
Suppose that X contains at most � vertices. Then, we obtain the contradiction
jXj� �Xx2X
degðxÞ � jXjðjXj � 1Þ þ jðX;YÞj � �ðjXj � 1Þ þ jðX;YÞj:
Similarly one can show that jY j � � þ 1.
Now assume without loss of generality that jXj � n2
and let S � X be a ð� þ 1Þ-set that contains the � þ 1 vertices of smallest degree in X. Then, it follows from
our hypothesis
Xv2S
degðvÞ �X�þ1
i¼1
dnþ1�i � ð� þ 1Þ p� 1
p
nþ 1 þ �
2� 2� þ 2
pðn� 3 þ �Þ :
236 JOURNAL OF GRAPH THEORY
This implies
degðuÞ � p� 1
p
nþ 1 þ �
2� 2
pðn� 3 þ �Þ
for every vertex u 2 X � S and hence,
Xv2X
degðvÞ � jXj p� 1
p
nþ 1 þ �
2� 2jXjpðn� 3 þ �Þ : ð1Þ
On the other hand, our assumption � < � and the theorem of Turan lead to
Xv2X
degðvÞ � p� 1
pjXj2 þ � � 1: ð2Þ
Now, we shall investigate three cases:
Case 1. Let 2jXj � n� 3 þ �. It follows from (1)
Xv2X
degðvÞ � jXj p� 1
pðjXj þ 2Þ � 2jXj
pðn� 3 þ �Þ ;
and hence together with (2)
� � 2jXj p� 1
pþ 1 � 2jXj
pðn� 3 þ �Þ � jXj;
a contradiction to jXj � � þ 1.
Case 2. Let 2jXj ¼ n� 1 þ � and let ð� þ 1Þ p�1p
nþ1þ�2
be an integer. Since2�þ2
pðn�3þ�Þ < 1, the condition of our theorem is equivalent with the condition
X�þ1
i¼1
dnþ1�i � ð� þ 1Þ p� 1
p
nþ 1 þ �
2:
As above, this inequality yields
Xv2X
degðvÞ � jXj p� 1
p
nþ 1 þ �
2¼ jXj p� 1
pðjXj þ 1Þ:
Together with (2) we obtain
� � p� 1
pjXj þ 1;
DEGREE SEQUENCE CONDITIONS 237
and therefore
Xv2X
degðvÞ � �jXj � p� 1
pjXj2 þ jXj:
We deduce from (2) the contradiction � � jXj þ 1.
Case 3. Let 2jXj ¼ n� 1 þ � and let ð� þ 1Þ p� 1p
nþ 1þ �2
be no integer. Then,
it follows that
jXj ¼ psþ r with 0 � r � p� 2:
From (1) we obtain
Xv2X
degðvÞ � jXj p� 1
pðjXj þ 1Þ � 2jXj
pðn� 3 þ �Þ ;
and hence together with (2)
� � jXj þ 1 � jXjp
� 2jXjpðn� 3 þ �Þ ¼ jXj þ 1 � s� r
p� psþ r
pðpsþ r � 1Þ :
Since
r
pþ psþ r
pðpsþ r � 1Þ < 1;
we conclude that even
� � jXj þ 1 � s ¼ jXj þ 1 � jXjp
þ r
p� jXj þ 1 � jXj
p:
This leads to
Xv2X
degðvÞ � �jXj � jXj2 þ jXj � jXj2
p:
Hence, we deduce from (2) the contradiction � � jXj þ 1, and the proof is
complete. &
Theorem 2.1 generalizes results of Volkmann [11], [12] as well as a theorem of
Dankelmann and Volkmann [4].
238 JOURNAL OF GRAPH THEORY
Corollary 2.1 [4]. Let G be a graph of order n. If ! � p and
n � 2p
p� 1�
� �� 1;
then � ¼ �.
Proof. If � � bn=2c, then in view of Theorem 2.1, � ¼ �. In the other case,
it follows from the hypothesis that n � 2b pp�1
�c � 1 for n odd and n � 2b pp�1
�c�2 for n even. This implies
X�þ1
i¼1
dnþ1�i � ð� þ 1Þ� � ð� þ 1Þ p� 1
p
nþ 1
2
� �:
According to Theorem 2.1, we conclude that � ¼ �. &
Example 2.1. Let G1 ¼ G2 ¼ K2, H1 ¼ K2;2;...;2, the complete t-partite graph
with t � 3 and the partite sets fx2i�1; x2ig for i ¼ 1; 2; . . . ; t, and H2 ¼ K1;2;2;...;2,
the complete t-partite graph with the partite sets fy2i�1; y2ig for i ¼ 1; 2; . . . ;t � 1, and the partite set fy2t�1g, consisting of one vertex.
We define the graph G as the union of G1;G2;H1, and H2 together with the
following edges. We join all vertices of G1 with all vertices of H1 and we join all
vertices of G2 with all vertices of H2. In addition, G contains the edges x1y1;x2y2; . . . ; x2t�2y2t�2 and x2t�3y2t�4; x2t�2y2t�3; x2t�1y2t�2, as well as x2ty2t�1. The
resulting graph G is of order 4t þ 3 with clique number ! ¼ t þ 2 and minimum
degree � ¼ 2t. Furthermore, G has 2t � 3 vertices of degree � ¼ 2t, two vertices,
namely x2t�2 and x2t�3, of degree 2t þ 2, and 2t þ 4 vertices of degree 2t þ 1.
It follows that
X�þ1
i¼1
dnþ1�i ¼X2tþ1
i¼1
dnþ1�i ¼ 4t2 þ 2t þ 4
and
ð� þ 1Þ p� 1
p
nþ 1
2¼ ð2t þ 1Þ t þ 1
t þ 2ð2t þ 2Þ:
Now, it is easy to see that
4t2 þ 2t þ 4 � ð2t þ 1Þ t þ 1
t þ 2ð2t þ 2Þ;
and consequently, �ðGÞ ¼ �ðGÞ, by Theorem 2.1.
DEGREE SEQUENCE CONDITIONS 239
Finally, it is straightforward to verify that the graph G fulfills neither the
conditions of Corollary 2.1 nor these of Theorems 1.1–1.4.
The next example will show that Theorem 2.1 is best possible, when n is odd.
Example 2.2. Let H1 ¼ K2;2;...;2 and H2 ¼ K3;2;2;...;2, be two complete t-partite
graphs with t � 3, VðH1Þ ¼ fx1; x2; . . . ; x2tg and VðH2Þ ¼ fy1; y2; . . . ; y2tþ1gsuch that fy1; y2; y3g is the partite set with 3 vertices. We define the graph G as the
union of H1 and H2 together with the new edges x1y1; x2y2; . . . ; x2t�2y2t�2. Then,
G is of order 4t þ 1 with clique number ! ¼ t and minimum degree � ¼ 2t � 2.
It follows
X�þ1
i¼1
dnþ1�i ¼X2t�1
i¼1
dnþ1�i ¼ 4t2 � 4t � 1
¼ ð2t � 1Þ t � 1
tð2t þ 1Þ � 4t � 2
tð4t � 2Þ
¼ ð� þ 1Þ p� 1
p
nþ 1
2� 2� þ 2
pðn� 3Þ :
The following example, which shows again that Theorem 2.1 is independent of
Theorems 1.1–1.3, will also be used at the end of this paper.
Example 2.3. Let H ¼ K2, H1 ¼ K2;2;...;2, the complete t-partite graph, and
H2 ¼ K3;3;2;2;...;2, the complete ðt � 1Þ-partite graph with t � 3, and denote by V1
and V2, the two partite sets of H2 with 3 vertices. Let a; b, and u be three further
vertices. The vertex set of the graph G is the union of the vertex sets of H;H1;H2
together with a; b, and u. In addition, we join all vertices of H with all vertices of
H2 and the vertices a; b; u with all vertices of H1. Furthermore, we join b with all
vertices of H2 and a with the vertices of V1 [ V2. The resulting graph G is of order
4t þ 5 with clique number ! ¼ t þ 1 and minimum degree � ¼ degðuÞ ¼ 2t. It
follows that
X�þ1
i¼1
dnþ1�i ¼X2tþ1
i¼1
dnþ1�i ¼ 4t2 þ 4t
and
ð� þ 1Þ p� 1
p
nþ 1
2¼ ð2t þ 1Þ t
t þ 1ð2t þ 3Þ:
Because of
4t2 þ 4t � ð2t þ 1Þ t
t þ 1ð2t þ 3Þ;
Theorem 2.1 implies �ðGÞ ¼ �ðGÞ.
240 JOURNAL OF GRAPH THEORY
Our second result is an improvement of Theorem 2.1, when the order of the
graph is even.
Theorem 2.2. Let G be a graph of order n � 6 with edge-connectivity �, clique
number ! � p, and degree sequence d1 � d2 � � � � � dn ¼ �. If � � bn=2c or if
� � bn=2c � 1 and
X2�þ2
i¼1
dnþ1�i � ð� þ 1Þ p� 1
pðnþ 2Þ � 4� þ 4
pðn� 2Þ ;
then � ¼ �.
Proof. Suppose to the contrary that � < �. Then, there exist two disjoint sets
X; Y � VðGÞ with X [ Y ¼ VðGÞ and jðX; YÞj < �. As shown in Theorem 2.1,
jXj; jYj � � þ 1 and � � bn=2c � 1.
Now, let S � X and T � Y be two ð� þ 1Þ-sets that contain the � þ 1 vertices
of smallest degree in X and in Y , respectively. The theorem of Turan yields
Xv2X
degðvÞ � p� 1
pjXj2 þ � � 1; ð3Þ
as well as
Xv2Y
degðvÞ � p� 1
pjY j2 þ � � 1: ð4Þ
First of all, we will show that
Xv2S
degðvÞ < ð� þ 1Þ ðp� 1ÞðjXj þ 1Þp
� � þ 1
pðjXj � 1Þ : ð5Þ
If, we suppose to the contrary that
Xv2S
degðvÞ � ð� þ 1Þ ðp� 1ÞðjXj þ 1Þp
� � þ 1
pðjXj � 1Þ ;
then it follows
Xv2X
degðvÞ � jXj p� 1
pðjXj þ 1Þ � jXj
pðjXj � 1Þ : ð6Þ
Now, we shall investigate two cases:
DEGREE SEQUENCE CONDITIONS 241
Case 1. LetjXj þ 1
pbe an integer. Since
jXjpðjXj�1Þ < 1, it follows from (6)
Xv2X
degðvÞ � jXj p� 1
pðjXj þ 1Þ;
and hence together with (3),
� � jXj p� 1
pþ 1:
This yields
Xv2X
degðvÞ � �jXj � p� 1
pjXj2 þ jXj;
a contradiction to (3) and jXj � � þ 1.
Case 2. LetjXj þ 1
pbe no integer. Then, it follows that
jXj ¼ psþ r with 0 � r � p� 2:
Then, the inequalities (3) and (6) imply
� � jXj þ 1 � jXjp
� jXjpðjXj � 1Þ ¼ jXj þ 1 � s� r
p� psþ r
pðpsþ r � 1Þ :
Since
r
pþ psþ r
pðpsþ r � 1Þ < 1;
we conclude that even
� � jXj þ 1 � s ¼ jXj þ 1 � jXjp
þ r
p� jXj þ 1 � jXj
p:
This yields
Xv2X
degðvÞ � �jXj � jXj2 þ jXj � jXj2
p;
and hence, we deduce from (3)
� � jXj þ 1;
242 JOURNAL OF GRAPH THEORY
a contradiction, and the proof of (5) is complete. Using (4), we can show
analogously
Xv2T
degðvÞ < ð� þ 1Þ ðp� 1ÞðjY j þ 1Þp
� � þ 1
pðjYj � 1Þ : ð7Þ
The inequalities (5) and (7) lead to
Xv2S
degðvÞ þXv2T
degðvÞ < ð� þ 1Þ p� 1
pðnþ 2Þ � � þ 1
pðjXj � 1Þ
� � þ 1
pðjYj � 1Þ :ð8Þ
Now, it is easy to show that
� þ 1
pðjXj � 1Þ þ� þ 1
pðjY j � 1Þ �4� þ 4
pðn� 2Þ :
As a consequence of (8) we see that
X2�þ2
i¼1
dnþ1�i < ð� þ 1Þ p� 1
pðnþ 2Þ � 4� þ 4
pðn� 2Þ ;
a contradiction to our hypothesis. This completes the proof of the theorem. &
Example 2.4. Let L1 and L2 two copies of the complete graph K2 and H1 and H2
two copies of the complete t-partite graph K2;2;...;2 with t � 2, VðH1Þ ¼fx1; x2; . . . ; x2tg, and VðH2Þ ¼ fy1; y2; . . . ; y2tg. We define the vertex set of the
graph G as the union of the vertex sets of L1; L2;H1, and H2. In addition, we join
all vertices of L1 with all vertices of H1 and all vertices of L2 with all vertices of
H2. Furthermore, we join xi with yi for i ¼ 1; 2; . . . ; 2t and x1 with y2 and x2 with
y1. The resulting graph G is of order 4t þ 4 with clique number !ðGÞ ¼ t þ 2 and
minimum degree �ðGÞ ¼ 2t þ 1. It follows that
X2�þ2
i¼1
dnþ1�i ¼X4tþ4
i¼1
dnþ1�i ¼ 8t2 þ 12t þ 8;
and
ð� þ 1Þ p� 1
pðnþ 2Þ ¼ ð2t þ 2Þ t þ 1
t þ 2ð4t þ 6Þ:
DEGREE SEQUENCE CONDITIONS 243
Now, it is easy to see that
8t2 þ 12t þ 8 � ð2t þ 2Þ t þ 1
t þ 2ð4t þ 6Þ;
and consequently, �ðGÞ ¼ �ðGÞ, by Theorem 2.2.
It is straightforward to verify that the graph G fulfills neither the conditions
of Theorems 1.1–1.4 nor of Theorem 2.1. In addition, Example 2.3 doesn’t fulfill
the conditions of Theorem 2.2. Consequently, Theorem 2.2 is independent of
Theorem 2.1.
The next example will show that Theorem 2.2 is best possible when n is even.
Example 2.5. Let H1 ¼ H2 ¼ K2;2;...;2, be the complete t-partite graphs with
t � 3, VðH1Þ ¼ fx1; x2; . . . ; x2tg, and VðH2Þ ¼ fy1; y2; . . . ; y2tg. We define the
graph G as the union of H1 and H2 together with the new edges x1y1; x2y2; . . . ;x2t�2y2t�2. Then, G is of order 4t with clique number !ðGÞ ¼ t and minimum
degree �ðGÞ ¼ 2t � 2. It follows
X2�þ2
i¼1
dnþ1�i ¼X4t�2
i¼1
dnþ1�i ¼ 8t2 � 8t � 2
¼ ð2t � 1Þ t � 1
tð4t þ 2Þ � 8t � 4
tð4t � 2Þ
¼ ð� þ 1Þ p� 1
pðnþ 2Þ � 4� þ 4
pðn� 2Þ :
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DEGREE SEQUENCE CONDITIONS 245