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Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 1
Fragmentation in Mass Spectrometry
• Introduction• Ionization• Separation• Fragmentation• Isotope Effects• High Resolution
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 2
Identification of Molecular Ion (1)
As we have seen, it is expected that a chemically pure compoundcontains a mixture of isotopes, based on the natural abundance. Molecular ion assigned on the basis of the most abundant isotope(s).
Conditions for the assignment of M+.:
a) M+. should be the highest m/z in the spectrum, apart from weaksatellite peaks that result from other isotopes.Problems with unstable M+. or chemical impurities.
b) M+. should be a radical cation in EI as it is ionized by removing 1 e.In formula CxHyNzOn (where C is any 4-valent element, H any monovalent,N any 3-valent, and O any divalent)the number of DBE: x – ½.y + ½.z + 1 should be an integer.
c) Value of M+. is even unless there is an odd number of N.
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 3
Identification of Molecular Ion (2)
d) If M+. is correctly assigned, the other peaks at high m/z can be logically explained by loss of neutral parts or molecules
OK: loss of CH3 (M-15), H2O (M-18), CH3O (M-31), CH3C=O (M-43) etc.
Illogical: M-2 till M-14M-21 till M-25M-33, M-37, M-38
If M+. cannot be satisfactorily assigned, look for an other assignment,or try another technique: CI, FAB, MALDI, electrospray …
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 4
Important Factors for Fragmentationa) Energy of the molecular ion and the fragments formed from it
b) Stability of the bonds in the ions
c) For rearrangements: steric factors.It is easier to move an H than a whole group
d) Stability of the formed ions or neutral particlesresonance stabilization such as in an acylium ion
Stevenson’s Rule:Upon dissociation of AB+. → A+ + B. or A. + B+
A+ will be formed if it has the lower ionization energy
In branched radical cations, the largest group is preferentially lost
CH
C4H9
CH3C2H5
+.CH+CH3
C2H5+HC C4H9
CH3C+ C4H9C2H5 C
+C4H9
CH3C2H5> >
H>
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 5
Stevenson’s Rule, Energy DiagramEn
ergy
ABA. + B.
A+ + B.A. + B+
DAB
IAIB
IAB
AB+.APA+
APB+
Ionization Energy (I), the energy required to convert radical into cation
Dissociation Energy (D), energy for homolytic dissociation into radicals
Appearance Potential (AP), energy required for cation to appear in MS
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 6
Ionization Energies for Common Hydrocarbons (1)Energy of Formation of Aliphatic and Olefinic Radicals
and Carbocations from RH and RCl
0
50
100
150
200
250
tBu iPr Et Me Bn All vinyl Ph
R
Ener
gy (k
cal/M
ol)
cationradical
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 7
Ionization Energies for Common Hydrocarbons (2)Formation Energies of Radicals & Carbocations < RH & RCl
0
50
100
150
200
250
300
350
tBu iPr Bn All Et vinyl Ph Me H
Ener
gy (k
cal/M
ol)
cationradical
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 8
Loss of Largest Group from Branched Radical IonStevenson’s Rule:
Upon dissociation of AB+. → A+ + B. or A. + B+
A+ will be formed if it has the lower ionization energyIn branched radical cations, the largest group is preferentially lost
Do not confuse ionization potential and cation/radical stability
CH
C4H9
CH3C2H5
+.CH+CH3
C2H5
+HC C4H9
CH3
C+ C4H9C2H5
C+
C4H9
CH3C2H5
H
.C4H9
.C2H5
.CH3
.H
+
+
+
+
sec. cation + tert. radical
sec. cation + sec. radical
sec. cation + prim. radical
tert. cation + .H
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 9
Metastable Peaks
Metastable ions: arise because of fragmentation after the ion hasleft the ionization chamber
M1+ → M2
+ + (M1 - M2)
The kinetic energy of such a M2+ is smaller than when it would have
been formed in the ionization chamber and accelerated there, and it willbe detected at a lower m/z than expected, and moreover broadened.
For fragmentation between electrostatic analyser and magnetic sector:
M* = M22/M1
e.g. C5H9+ (m/z = 69) → C3H5
+ (41) + C2H4 (28)
Calculated m* = (41)2/69 = 24.36, observed m* = 24.4
(It is more difficult to solve this problem in the other direction)
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 10
Types of Fragmentation Reactions (1)
R+.CR3 R. + +CR3
R+.I R. + +I
Alkanes:
Low IE elements
McLafferty & Turecek:
1) Sigma electron ionisation (σ):
2) Radical site initiation (alpha cleavage, α), homolytic dissociation:N > S, R, O, π > Cl, Br > H
Donates an electron,forms new bond to anadjacent atomconcomitant withcleavage of other bond to that atom,moves . site, loss of largestalkyl favoured
R CR2 YR+.
R2C Y+RR. +
Y+R CH2 CH2.
CH2 CH2+YR+.
Saturated
Unsaturatedheteroatom
Allylic
R CR Y RC Y++.R.
R CH2 CH2 CH2+.
+
H2C CH +CH2R. +
R -eR
+
.Retro-Diels-Alder(double α-cleavage)
α2
α,i chargemigration
RHCH2C
++.
RC2H3+. + C4H6
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 11
Types of Fragmentation Reactions (2)
R Y R R+ + .YR+.
OE+. :
R YH2 R+ + .YH2+
EE+ :
McLafferty & Turecek:
3) Charge site initiation (inductive effect, i), heterolytic dissociation:Cl, Br, NO2 > O, S >> N, C
Attracts e pair,cleaves bond,moves + site,most stable + formed
4) Rearrangements (r):Example with Hand unsaturatedreceptor site in ring
Also with saturatedreceptor site,2H, displacement (rd)and elimination (re)
YH rH
+.Y+H.
Y+H.
α
i.+
+
+
HY
HY+
.Charge retention, ion gains H
Charge migration, ion loses H
or
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 12
Fragmentation Reactions(Hesse, Meier, & Zeeh)
Alpha splitting
Benzyl- and Allyl splitting
Splitting of non-activated bonds
Retro-Diels-Alder reaction
McLafferty rearrangement
Onium reaction
Loss of CO
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 13
α-Splitting (Homolytic Dissociation) (1)
2-butanone
The acylium ion formed by lossof the largest alkyl radical ispreferred
O O+
orO+. .
CH3. + CH3CH2.+H3C
O+O+
CH3(15) m/z 57 m/z 43 (29)
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 14
α-Splitting (Homolytic Dissociation) (2) 100
0
50
75
25
20 25 30 35 40 45 50 55 60 65 70
45
3127 59294341
19 28 57
CH C 3HC 2HC3H
OH•
C 2HCH
C3H
OH
CHC3H C 2H
C 3H
CHC3H
OH
C 2H
OH
100
0
50
75
25
15 20 25 30 35 40 45 50 55 60 65 70
59
31
41 43 15 29 5727 39 60
C 3H
OH•
C 3H
C3HC
CC 3H
OH
C 3H
CC3H
C 3H
C 3H
2-butanol
splittingof Et.preferred
t-butanol
only Me.splittingpossible
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 15
α-Splitting (Homolytic Dissociation) (3)
2-AminoethanolIonization by loss of n-electronfrom N(less electronegative than O)which is also a likely startingpoint for radical-site initiatedfragmentation
H2N OH- e
H2N OH+.m/z 61
H2C N+H2
m/z = 30
.CH2OH(31)
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 16
α-Splitting (Homolytic Dissociation) (4)
α-splitting, mainly of Me, but also of H,is the main mechanism of fragmentationin amines because of the electron-donatingability of N
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 17
α-Splitting in MS of Protected Steroid
O
O
Me
Me
+.
O
O
Me
Me
+.
or
O+
O
Me
O+
O
Me
H. MeO+
O
Me.O+
O
m/z 99
H. Me
O+
O
Me
.Me
O+
O
Me.H
MeO+
O
Me
.
O+
Om/z 125
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 18
Formation of Stable Allylic Carbocation
R CH2 CH2 CH2+.
H2C CH +CH2R. +
+
EI of 1-heptene
EI of 4-methyl-1-hexene
m/z 41
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 19
Formation of Stable Benzylic Carbocation (1)
EI of butylbenzene
.+
or .+ .C4H9
+
(57)
+
m/z = 77m/z = 51C2H2
α
.C3H7(43)
+
+
+ +
m/z = 65m/z = 91
(26)
C2H2(26)
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 20
Formation of Stable Benzylic Carbocation (2)
The EI-MS of o-Cl-toluene andbenzyl chloride are similar, bothare dominated by the tropyliumion
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 21
σ-Electron Ionization, Non-activated Bonds
EI-MS of an unbranchedalkane shows an almostrandom fragmentationpattern (homologousseries, differing in theno. of CH2 groups), everyσ-bond is as likely to breakas the other one.
In the branched alkane,the possibility to haverelatively stable secondarycarbocations as opposedto primary ones influencesthe fragmentation pattern.
Stevenson’s rule,loss of largest alkyl
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 22
Alkyl halide spectra (1)
C7H14 F+.H
C7H14 F+
H. HF(20)(118)
C7H14+.
O.E. ion
variousfragments
n-heptyl F: strong C-F bonds,electronegativity of Fmakes + on F unattractive,HF formation attractiveNo M+. observed
n-heptyl I: less electronegative, less basic,I+ (m/z 127) or I. (with R+, m/z 99) feasible,but base peak at m/z 57 (C4H9+) ?!
R+.I R. + +I (m/z127)
or R+ (m/z 99) + .Im/z 226
σ
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 23
Alkyl halide spectra (2)
X+.
m/z = 57
+ + X.
X+. .
43
X++
m/z = M - 43
(X = F, 67)X = Cl, 91/93X = Br, 135/137(X = I, 183)
(X = F, 53)(X = Cl, 77/79)(X = Br, 121/123)(X = I, 169)
α
i
Fragments containing Br, Clrecognized by satellite peaksAn α splitting with cyclization isimportant (base peak for Cl)An i splitting with cyclization isalso important (base peak forI, Br)
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 24
Retro-Diels-Alder (1)
Retro-Diels-Alder, not pericyclic
Charge retention or migration,depending on R
NB: α followed by α or i gives another OE ion
See the example of4-phenyl-cyclohexene
chargemigration
R = Ph, 100 %
HCH2C
++.
R -eR
+
.Retro-Diels-Alder
R
+
.or
R
+
.α
α i
HCH2C
+R R .
+
chargeretention
R = H, 80 %
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 25
Retro-Diels-Alder (2)
O
α-ionone
O
β-iononeO.+ O
+
+ .CH3
See the example of the iononesα-ionone gives the expected Retro-DAβ-ionone has a competing loss of methyl group
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 26
1,2,3,4-Tetrahydrocarbazole
HN+.
C2H4
HN
HN +.
HN .+ H
N .+
C2H4
m/z 143
m/z 171
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 27
5,7-dihydroxy-4’-methoxyisoflavonone
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 28
McLafferty Rearrangement
YH rH
+.Y+H.
Y+H.
α
i.+
+
+
HY
HY+
.Charge retention, ion gains H
Charge migration, ion loses H
or
CH2CH2
OH rH
+.O+H.
α+
HO+
.Charge retention, ion gains H
CH3
C2H5
H3C
C2H5
H3C
C2H5(42)
m/z 6220 %
m/z 104
In McLafferty rearrangement(H rearrangement with unsaturatedreceptor site) a H from the carbon inγ position relative to a C=Y double bond istransferred to the Y atom, accompanied bya β-splitting. This can be with chargeretention (α) or charge migration (i).
Note that McLafferty rearrangements are relatively exceptional(cf. retro Diels-Alder, CO loss) in producing another OE ion.
Example: a relatively long ketone
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 29
EI-MS of methyl butanoate
CH2CH2
CH2
OH rH
+.O+H.
α+
HO+
.OCH3 OCH3OCH3(28)
m/z 74
m/z 102
or
CH3CH2
CH2
O+.
OCH3
α
CH3O.(31)
O+
OCH3m/z 59
CO(28)
CH3O+
m/z 31
or
CH3CH2
CH2
O+.
OCH3
α
CH3CH2CH2.(43)
O+
m/z 71 CO(28)
CH3CH2CH2+
m/z 43
The alkyl chain of the acid partof the ester is long enough togive a McLafferty rearrangement,in addition to α-fragmentationand subsequent loss of CO.
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 30
Loss of COO
H O
HH H H
+.
CO
+.
H.+
m/z 94 m/z 66m/z 65
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 31
Some Loss of COO
O
+.
m/z 192
+.O+.
m/z 164 m/z 136
C O
+.+
m/z 65m/z 96
+.m/z 68
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 32
No Loss of COO+.
m/z 98
O+
H. Me
O+
.O+
CH2.C3H7 m/z 55
+O
CH2m/z 57
H
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 33
Cyclohexylamine
+N
CH2m/z 84
Et
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 34
Onium Reaction
YRH+.
HYR+
. HYR+.
YRH+
HYR+ HYR
+
In the Onium reaction(H rearrangement withsaturated receptor site)a H is transferred fromsomewhere in an alkylchain to the heteroatomof initial ionization.
Y can be O (oxonium),N (nitronium), etc.
In OE ions, H is transferredwith one e; in EE ions it is ahydride shift, H as H- with 2 e.
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 35
Onium reaction, Ether
O+.
O+
H
m/z 102
m/z 87
m/z 31
C4H8 (56)
.CH3
α
Onium
or+O
H Me
m/z 45O+
Me CH2
m/z 59O+
CH2
HO+CH2
m/z 31
.C3H7
HO+CH2
α
McLafferty C3H6 (42) Onium
C2H4 (28)
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 36
Onium reaction, Amine
N
MeMe
Me+.
N+
Me
Me
N+H
Me
Me
H
m/z 129
m/z 114
m/z 58
C4H8 (56)
.CH3
α
Onium
orN+
HMe
Me
Me
McLafferty
m/z 72Me
N+Me CH2
m/z 86Me
N+Me CH2
Me
Onium
H+N
Me CH2
m/z 44
.C3H7
C3H6 (42) C3H6 (42)
α
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 37
Standard Interpretation Procedure(McLafferty & Turecek) (1)
1) Study all available information (spectroscopic, chemical, samplehistory). Give explicit directions for obtaining spectrum.Verify m/z assignments.
2) Using isotopic abundances, where possible deduce the elementalcomposition of each peak in the spectrum; calculate rings plusdouble bonds.
3) Test molecular ion identity; must be highest peak in mass spectrum,odd-electron ion, and give logical neutral losses. Check with CI or othersoft ionization.
4) Mark ‘important’ ions: odd electron and those of high abundance,highest mass, and/or highest mass in a group of peaks.
Department of Organic Chemistry, IMM, Radboud University Nijmegen
Instrumental Analysis in Molecular Chemistry 38
Standard Interpretation Procedure(McLafferty & Turecek) (2)
5) Study general appearance of the spectrum; molecular stability,labile bonds.
6) Postulate and rank possible structural assignments for:- important low-mass ion series;- important primary neutral fragments from M+. indicated by
high-mass ions (loss of largest alkyl favoured) plus those fromcollision activation;
- important characteristic ions.
7) Postulate molecular structures; test again reference spectrum,against spectra of similar compounds, or against spectra predictedfrom mechanisms of ion decompositions.