Design and Sizing Wwtp

Dr. SBiological Wastewater Treatment

Designed By: Ramy R. SalemAdvisor : Dr. Husam Al-Najar

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Biological Wastewater Treatment

Designed by : Ramy R. Salem

Advisor : Dr. Husam Alnajar Activated Sludge System

INPUT DATA

Flow = 12700BOD5 (soluble) = 84 mg/L

(BOD5)total = 30 mg/LSuspended Solids(SS)= 30 mg/L

(BOD5)soluble in effluent = 11.1 mg/L

Micro-organism Growth Constant

µm = 2.5 Concentration of Biomass(X) =

Kd = 0.05

Y = 0.5

Ks= 100

5.0056319

Minimum Sludge retension time (day) = 0.9163347 dayS/F = 5.4626679 OK

2.0408163 S>Smin OK Hydranlic detension time θ (day ) = 0.0486438

617.77605

Food to micro-organism ratio in the reactor (F/M) = 0.57561312 OKmg BOD5 / mg MLVSS .d

Biomass production per day (Px) (Kg/d) = 461.79183

46.179183

7257.1429

5442.8571

Oxygen reqirements = 270.08559 kg O2/d

m3/d

d-1

d-1

mg VSS/mg BOD5 removed

mg BOD5/L

The Solid retension time θc (day) =

S min

Volume of the tank (m3) =

Waste Flow rate Qw (m3/d) =

Effluent Flow rate Qe (m3/d) =

Recycle Flow Qr (m3/d) =

Activated Sludge System BOD removal

Concentration of Biomass(X) = 3000 mg MLVSS/L 1600

4800

Xr = 10000 mg VSS/L

12700 7257.143

84

5442.857 46.17918

S (mg/L)= 11.1 S (mg/L)= 11.1

Xr = 10000

Q0(m3/d)= Qe(m3/d)=

S0 (mg/L)= Xe neigligable

Qr(m3/d)= Qw(m3/d)=

Areation tank Areation tank Sed tankSed tank

Designed By : Ramy R. Salem


INPUT DATA




Micro-organism (N) Growth Constant

(µm)n = 0.25

(Kd)n = 0.04(Y)n = 0.2 mg VSS/mg NH4-N removed (Ks)n= 0.4



Kd = 0.05

Y = 0.5

Ks= 100

10

Minimum Sludge retension time (day) = 0.0761905 day

S/F = 2.1 OK


2437.1532

Food to micro-organism ratio in the reactor (F/M) = 0.16543892 OK

m3/d

d-1

d-1

mg/L

d-1

d-1


mg BOD5/L


S min


mg BOD5 / mg MLVSS .dBiomass production per day (Px) (Kg/d) = 408.42013

110.37077

7765.7506

5194.2494





Activated Sludge System BOD Removal & Nitrification

TKN0 = 40

TKN = 1


4800

Xr = 10000 mg MLVSS/L

12960

84

40

mg/L

mg/L

Q0(m3/d)= Qe(m3/d)=


TKN0(mg/L) = TKN0(mg/L) =


5194.249

S (mg/L)= 6.382979 S (mg/L)=

Xr =

Qr(m3/d)= Qw(m3/d)=

7765.751

0.509091

110.3708

6.382979

10000



INPUT DATA




Micro-organism (N) Growth Constant

(µm)n = 0.25

(Kd)n = 0.04(Y)n = 0.2 mg VSS/mg NH4-N removed (Ks)n= 0.4



Kd = 0.05

Y = 0.5

Ks= 100

BOD Removal

5.0056319


S/F = 5.4626679 OK


1260.8469

m3/d

d-1

d-1

mg/L

d-1

d-1


mg BOD5/L


S min


Food to micro-organism ratio in the reactor (F/M) = 0.57561312 OKmg BOD5 / mg MLVSS .d


47.010523

10739.981

2287.0588


54.054054Minimum Sludge retension time (day) = 4.7619048 day

Hydranlic detension time θ (day ) = 0.0888889

1147.8213

Food to micro-organism ratio in the reactor (F/M) = 0.3 mg TKN/mg Vss.d0


3.1852041

10634.227

2278.7628

2301.4821

104643.27




NH3 Removal (Nitrification)






Oxygen reqirements (kg O2/d) =

Volume of air to be supplied(m3/d) =

Activated Sludge System BOD Removal & Nitrification (Seperated processes)

TKN0 = 40

TKN = 1


4800


12960 10672.94

84

40 40

1260.8

mg/L

mg/L

Q0(m3/d)= Qe(m3/d)=




2287.059

S (mg/L)= 11.1 S (mg/L)=

mg TKN/mg Vss.d

Qr(m3/d)= Qw(m3/d)=

12912.9895 12909.8

1

1147.821

Qe(m3/d)= Qe(m3/d)=

TKN0(mg/L) = Sed tankSed tank

NitrificationNitrification Sed tankSed tank

47.01052 3.185204

11.1

Qw(m3/d)=



INPUT DATA




The denitrifying bacteria

(µm)d = 0.4

(Kd) = 0.04(Y)d = 0.9 mg VSS/mg NO3-N Kdn= 0.16 mg NO3-N



Kd = 0.05

Y = 0.5

Ks= 100

5.271538462



652.2055178

m3/d

d-1

d-1

d-1

d-1


mg BOD5/L

NH3 Removal (Denitrification)




36.36613402

12839.17567

5.518089346

4.4827586Minimum Sludge retension time (day) = 2.7777778 day


1119.1258

Food to micro-organism ratio in the reactor (F/M) = 0.3 mg TKN/mg Vss.d


37.447669

10634.227

2278.7628

2242.4698

101960.1




NH3 Removal (Nitrification)






Oxygen reqirements (kg O2/d) =

Volume of air to be supplied(m3/d) =

Activated Sludge System Denitrification

TKN0 = 39

TKN = 1X 3000 mg MLVSS/L


4800


12960 10672.94

84

39 39

1260.8

mg/L

mg/L

Q0(m3/d)= Qe(m3/d)=



Areation tank(m3) Areation tank(m3) Sed tankSed tank

linked with the process of BOD removal and nitrification seperetly . You can change the value form this sheet.

2287.059S (mg/L)= 11.1 S (mg/L)=

mg TKN/mg Vss.d

Qr(m3/d)= Qw(m3/d)=

12912.9895 12875.54

1

1119.126

Qe(m3/d)= Qe(m3/d)=

TKN0(mg/L) = Sed tankSed tank

Nitrification(m3)Nitrification(m3) Sed tankSed tank

Denitrification(m3)

Denitrification(m3)

linked with the process of BOD removal and nitrification seperetly . You can change the value form this sheet.

NOTE

47.01052 2.278763 37.44811.1

Qr(m3/d)= Qw(m3/d)=

12839.18

652.2055

Qe(m3/d)=

Denitrification(m3)

Denitrification(m3) Sed

tankSed tank

5.518089 36.36613Qr(m3/d)= Qw(m3/d)=

Designed by : Ramy R. Salem

Advisor : Dr. Husam Alnajar OXIDATION DICHES

INPUT DATA

Flow = 20000Influent BOD5 (soluble) = 300 mg/L

(BOD5)total = 33.9 mg/LSuspended Solids(SS)= 30 mg/L

(BOD5)soluble in effluent = 15 mg/L


µm = 2.5

Kd = 0.03

Y = 0.5

Ks= 30

The Solid retension time θc (day) = 30Hydranlic detension time θ (hours ) = 15

20000Concentration of Biomass(X) = 4750 mg MLVSS/L OK

Food to micro-organism ratio in the reactor (F/M) = 0.063 OK

Biomass production per day (Px) (Kg/d) = 0

0

1904.7619

18095.238

m3/d

d-1

d-1


mg BOD5/L

S min





No Sludge Production

Allow Sludge Production

Oxygen reqirements = 5700 kg O2/d

OXIDATION DICHESBOD removal,Nitrification & denitrification

1600

4800

Xr = 10000 mg VSS/L

20000 1904.762

300

20000

18095.24 0

S (mg/L)= 15 S (mg/L)= 15

Xr = 10000

Q0(m3/d)= Qe(m3/d)=


Qr(m3/d)= Qw(m3/d)=

OD Tank(m3)OD Tank(m3)Sed tankSed tank

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Design and Sizing Wwtp