Sheet1DESIGN OF BEAMS FOR TENSIONfc'=30MpaBeam Cross Sectionfy=415MpaWidth=0.3m300mmc / c Length=5mDepth=0.45m450mmDL=16KN/mDepth Eff.=LL=14KN/mBar Dia.=16Unit weight Concrete=25KN/m=0.85QuadraticWeight of beam=L*W*Unit Weight Concretecu.m.A0.593.375cu.m.B-1Ultimate UDL, Wu=1.7(LL) + 1.4(DL)KN/mC0.10350.925KN/mUltimate Moment, Mu={Ultimate UDL*(c/c Length)}/8
edward: maximum moment for simply supported beamKN-m159.141KN-m159140625.000N-mmMu= fc' b d (1-0.59)
edward: Solve for

Rn=Mu/ fc' b d
edward: Coefficient of Resistance

0.1031=1.585discard2=0.110
edward: tension reinforcement index= fc'/fy0.008min.=1.4/fy0.003max.=(0.85 fc' 600)/fy(600+fy)0.023 < max.use rho/steel yieldsAs= b d1072.018sq.mm.N=(4 As)/(3.1416*d^2)5.332pcs.

Sheet2

Sheet3