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Duality Theory
對偶理論
One of the most important discoveries in the early development of linear programming was the concept of duality.
Every linear programming problem is associated with another linear programming problem called the dual.
The relationships between the dual problem and the original problem (called the primal) prove to be extremely useful in a variety of ways.
The dual problem uses exactly the same parameters as the primal problem, but in different location.
Primal and Dual Problems
Primal Problem Dual Problem
Max
s.t.
Min
s.t.
n
jjjxcZ
1
,
m
iii ybW
1
,
n
jijij bxa
1
,
m
ijiij cya
1,
for for.,,2,1 mi .,,2,1 nj
for .,,2,1 mi for .,,2,1 nj ,0jx ,0iy
In matrix notation
Primal Problem Dual Problem
Maximize
subject to
.0x .0y
Minimize
subject tobAx cyA
,cxZ ,ybW
Where and are row vectors but and are column vectors.
c myyyy ,,, 21 b x
Example
Maxs.t.
Min
s.t.
Primal Problemin Algebraic Form
Dual Problem in Algebraic Form
,53 21 xxZ ,18124 321 yyyW
1823 21 xx
122 2 x41x
0x,0x 21
522 32 yy
33 3 y1y
0y,0y,0y 321
Max
s.t.
Primal Problem in Matrix Form
Dual Problem in Matrix Form
Min
s.t.
,5,32
1
x
xZ
18
12
4
,
2
2
0
3
0
1
2
1
x
x
.0
0
2
1
x
x .0,0,0,, 321 yyy
5,3
2
2
0
3
0
1
,, 321
yyy
18
12
4
,, 321 yyyW
Primal-dual table for linear programmingPrimal Problem
Coefficient of: RightSide
Rig
ht
Sid
eDu
al P
rob
lem
Co
effi
cien
to
f:
my
y
y
2
1
21
11
a
a
22
12
a
a
n
n
a
a
2
1
1x 2x nx
1c 2c ncVI VI VI
Coefficients forObjective Function
(Maximize)
1b
mna2ma1ma
2bmb
Coe
ffic
ient
s fo
r O
bjec
tive
Fun
ctio
n(M
inim
ize)
One Problem Other Problem
Constraint Variable
Objective function Right sides
i i
Relationships between Primal and Dual Problems
Minimization Maximization
Variables
Variables
Constraints
Constraints
0
0
0
0
Unrestricted
Unrestricted
The feasible solutions for a dual problem are
those that satisfy the condition of optimality for
its primal problem.
A maximum value of Z in a primal problem
equals the minimum value of W in the dual
problem.
Rationale: Primal to Dual Reformulation
Max cxs.t. Ax b x 0
L(X,Y) = cx - y(Ax - b) = yb + (c - yA) x
Min yb
s.t. yA c
y 0
Lagrangian Function )],([ YXL
X
YXL
)],([
= c-yA
The following relation is always maintained
yAx yb (from Primal: Ax b)
yAx cx (from Dual : yA c)
From (1) and (2), we have (Weak Duality)
cx yAx yb
At optimality
cx* = y*Ax* = y*b
is always maintained (Strong Duality).
(1)
(2)
(3)
(4)
“Complementary slackness Conditions” are
obtained from (4)
( c - y*A ) x* = 0
y*( b - Ax* ) = 0
xj* > 0 y*aj = cj , y*aj > cj xj* = 0
yi* > 0 aix* = bi , ai x* < bi yi* = 0
(5)
(6)
Any pair of primal and dual problems can be
converted to each other.
The dual of a dual problem always is the primal
problem.
Min W = yb,
s.t. yA c
y 0.
Dual ProblemMax (-W) = -yb,
s.t. -yA -c
y 0.
Converted to Standard Form
Min (-Z) = -cx,
s.t. -Ax -b
x 0.
Its Dual Problem
Max Z = cx,
s.t. Ax b
x 0.
Converted toStandard Form
Mins.t.
64.06.0
65.05.0
7.21.03.0
21
21
21
xx
xx
xx
0,0 21 xx
21 5.04.0 xx
Mins.t.
][y 64.06.0
][y 65.05.0
][y 65.05.0
][y 7.21.03.0
321
-221
221
121
xx
xx
xx
xx
0,0 21 xx
21 5.04.0 xx
Maxs.t.
.0,0,0,0
5.04.0)(5.01.0
4.06.0)(5.03.0
6)(67.2
3221
3221
3221
3221
yyyy
yyyy
yyyy
yyyy
Maxs.t.
.0, URS:,0
5.04.05.01.0
4.06.05.03.0
667.2
321
321
321
321
yyy
yyy
yyy
yyy
Application of
“Complementary Slackness Conditions”.
Example: Solving a problem with 2 functional constraints by graphical method.
0 , ,
104
3043..
372max
321
321
321
321
xxx
xxx
xxxts
xxxZ Optimal solution:
x1=10
x2=0
x3=0