Ee10 f14 Final

  • Upload
    iv-chen

  • View
    236

  • Download
    0

Embed Size (px)

Citation preview

  • 7/26/2019 Ee10 f14 Final

    1/15

    EE 10, Fall 2014, Final ExamDecember 19, 2014

    Instructions: This exam booklet consists of four problems, blank sheets for the solutions,

    reference sheets with mathematical identities, and additional blank sheets. Please follow

    these instructions while answering your exam:

    1. Write your name and student identification number below.

    2. Write the names of students to your left and right as well.

    3. You have 3 hours to finish your exam.

    4. Write your solutions in the provided blank sheets after each problem.

    5. The sheets marked Scratch will NOT be graded. These sheets are provided for

    your rough calculations only.

    6. Write your solutions clearly. You may box in your final answer. Illegible solutions will

    NOT be graded.

    7. Be brief.

    8. Open Book & open notes only. NO homework solution!

    NAME:______________________________________

    STUDENT ID:_________________________________

    NAMES OF ADJACENT STUDENTS:

    LEFT:__________________________________

    RIGHT:_________________________________

  • 7/26/2019 Ee10 f14 Final

    2/15

    2

    Problem Score

    #1

    #2

    #3

    #4

    Total 100

  • 7/26/2019 Ee10 f14 Final

    3/15

    3

    Problem 1:

    a. Determine the value of Vc(t) and()

    just after time t = 0.

    b. Determine the complete solution of Vc(t) for the case when Vs(t) = where = 109.Use C1 = 20pF, C2 = 10 pF, L= 1nH, R = 10 Ohms for this part.

    (15 + 15 = 30 points)

    Figure 1.

  • 7/26/2019 Ee10 f14 Final

    4/15

    4

  • 7/26/2019 Ee10 f14 Final

    5/15

    5

    Problem 2: Refer to Figure 2 for this problem. The inductor has an initial current i L(0-) = Io. VB

    is a DC source.

    a. Derive an expression for the current iL(t) for t 0.

    ( 10 points)

    Figure 2.

  • 7/26/2019 Ee10 f14 Final

    6/15

    6

  • 7/26/2019 Ee10 f14 Final

    7/15

    7

    Problem 3: Refer to the figure for this problem.

    a. Derive a phasor domain Thevenin equivalent of the network shown in Fig. 3a.

    b. Derive an expression for the angle by which v1(t) leads is(t), in the circuit shown in Fig.3b.

    c. For what value of o(possibly in terms of L,C, and p), is the voltage v1(t) in phase withis(t)?

    (5 + 5 +10 = 20 points)

    Figure 3.

  • 7/26/2019 Ee10 f14 Final

    8/15

    8

  • 7/26/2019 Ee10 f14 Final

    9/15

    9

    Problem 4: Refer to Figure 4 for this problem. Assume is(t) = Acost. With A > 0.

    a. Draw the phasor domain equivalent circuit of the circuit shown.

    b. Write equations that describe sinusoidal steady state circuit behavior. Use the mesh cur-

    rent method with the shown loop currents.

    Assume M = L1 =L2 for the following parts:

    c. Solve for i1(t), i2(t), and i3(t) in the phasor domain.

    d. What is the sinusoidal steady state voltage across the resistor? Why?

    e. Draw a phasor diagram showing the phasors of i1(t), i2(t), i3(t), and v1(t), v2(t), and vc(t).Use the voltage across the resistor as your reference (i.e. assume it has zero phase).

    (5 + 5 + 10 + 10 + 10 = 40 points)

    Figure 4.

  • 7/26/2019 Ee10 f14 Final

    10/15

    10

  • 7/26/2019 Ee10 f14 Final

    11/15

    11

  • 7/26/2019 Ee10 f14 Final

    12/15

    12

    Reference Sheet #1

    Trigonometric Identities:

    0

    0

    sin cos 90 cos 2

    cos sin 90 sin 2

    cos cos cos sin sin

    sin cos cos sin sin

    cos cos 2 cos 2 cos 2

    cos cos 2 sin 2 sin 2

    sin sin 2 sin 2 sin 2

    sin sin 2 cos 2 sin 2

    cos 2 2 co

    A A A

    A A A

    A B A B A B

    A B A B A B

    A B A B A B

    A B A B A B

    A B A B A B

    A B A B A B

    A

    2 2 2 2

    3

    3

    2 2 1

    s 1 cos sin 1 2 sin

    sin 2 2 sin cos

    cos 3 4 cos 3cos

    sin 3 3sin 4 sin

    cos sin cos tan

    A A A A

    A A A

    A A A

    A A A

    a A b A a b A b a

    Complex Arithmetic:

    1 1 1 2

    1 1 1 2

    1 2 1 2 1 2

    1 2 1 2 1 2

    2 2 1

    1 2 1 2 1 2 1 2

    Re Re ReIm Im Im

    Re Re Re Im Im

    Im Re Im Im Re

    cos sin

    where , tan

    where cos , sin

    ,

    1 1

    j

    j

    j

    z z z zz z z z

    z z z z z z

    z z z z z z

    e j

    x jy re r x y y x

    re x jy x r y r

    z z z z angle z z angle z angle z

    z z

    * *

    , 1

    ,

    angle z angle z

    x jy x jy angle z angle z

    Quadratic Equations:2

    2 4The roots of 0 are

    2

    b b acax bx c x

    a

  • 7/26/2019 Ee10 f14 Final

    13/15

    13

    = 109

  • 7/26/2019 Ee10 f14 Final

    14/15

    14

  • 7/26/2019 Ee10 f14 Final

    15/15

    15