15
EE105 Fall 2007 Lecture 9, Slide 1 Prof. Liu, UC Berkeley Lecture 9 OUTLINE BJT Amplifiers (cont’d) Common-base topology CB core CB stage with source resistance Impact of base resistance Reading: Chapter 5.3.2 ANNOUNCEMENTS Friday discussion section (103) has been moved back to 5 Evans. HW#5 is now posted. List of frequently misunderstood/forgotten points has been updated.

EE105 Fall 2007Lecture 9, Slide 1Prof. Liu, UC Berkeley Lecture 9 OUTLINE BJT Amplifiers (cont’d) – Common-base topology – CB core – CB stage with source

  • View
    219

  • Download
    0

Embed Size (px)

Citation preview

EE105 Fall 2007 Lecture 9, Slide 1 Prof. Liu, UC Berkeley

Lecture 9

OUTLINE• BJT Amplifiers (cont’d)– Common-base topology– CB core– CB stage with source resistance– Impact of base resistance

Reading: Chapter 5.3.2

ANNOUNCEMENTS• Friday discussion section (103) has been moved back to 5 Evans.• HW#5 is now posted.• List of frequently misunderstood/forgotten points has been updated.

EE105 Fall 2007 Lecture 9, Slide 2 Prof. Liu, UC Berkeley

Common Base (CB) Amplifier• The base terminal is biased at a fixed voltage; the input

signal is applied to the emitter, and the output signal sensed at the collector.

EE105 Fall 2007 Lecture 9, Slide 3 Prof. Liu, UC Berkeley

Small-Signal Analysis of CB Core• The voltage gain of a CB stage is gmRC, which is

identical to that of a CE stage in magnitude and opposite in phase.

Cmv RgA

EE105 Fall 2007 Lecture 9, Slide 4 Prof. Liu, UC Berkeley

Tradeoff between Gain and Headroom • To ensure that the BJT operates in active mode, the

voltage drop across RC cannot exceed VCC-VBE.

T

BECCC

T

Cv V

VVR

V

IA

EE105 Fall 2007 Lecture 9, Slide 5 Prof. Liu, UC Berkeley

Simple CB Stage Example

2.172230130

1 Cmv RgA

VCC = 1.8VIC = 0.2mAIS = 5x10-17 A = 100

k7.67 ,k3.22

2010 Choose

if 354.1

21

211

121

2

RR

RR

VAII

IIVRR

RVV

CCB

BCCb

EE105 Fall 2007 Lecture 9, Slide 6 Prof. Liu, UC Berkeley

Input Impedance of a CB Stage• The input impedance of a CB stage is much smaller

than that of a CE stage.

Am

in Vg

R if 1

EE105 Fall 2007 Lecture 9, Slide 7 Prof. Liu, UC Berkeley

CB Stage with Source Resistance• With the inclusion of a source resistance, the input

signal is attenuated before it reaches the emitter of the amplifier; therefore, the voltage gain is lowered. – This effect is similar to CE stage emitter degeneration.

S

m

Cv

Rg

RA

1

EE105 Fall 2007 Lecture 9, Slide 8 Prof. Liu, UC Berkeley

Practical Example of a CB Stage• An antenna usually has low output impedance;

therefore, a correspondingly low input impedance is required for the following stage.

EE105 Fall 2007 Lecture 9, Slide 9 Prof. Liu, UC Berkeley

Output Impedance of a CB Stage• The output impedance of a CB stage is equal to RC in

parallel with the impedance looking into the collector.

12

1

||

||)||(1

outCout

EOEmout

RRR

rRrrRgR

EE105 Fall 2007 Lecture 9, Slide 10 Prof. Liu, UC Berkeley

Output Impedance: CE vs. CB Stages• The output impedances of emitter-degenerated CE and

CB stages are the same. This is because the circuits for small-signal analysis are the same when the input port is grounded.

EE105 Fall 2007 Lecture 9, Slide 11 Prof. Liu, UC Berkeley

Av of CB Stage with Base Resistance (VA = ∞)

• With base resistance, the voltage gain degrades.

BC

outP

BCm

outBP

Cm

outCmout

RrR

vv

RrRgr

vRr

r

vv

Rg

vvRvgv

E

inBC

out

Cm

outm

E

inPm R

vRrR

v

Rg

vg

rR

vvvg

r

v

1 :P nodeat KCL

1

11

BE

m

C

BE

C

in

out

RR

g

R

RRr

R

v

v

EE105 Fall 2007 Lecture 9, Slide 12 Prof. Liu, UC Berkeley

Voltage Gain: CE vs. CB Stages• The magnitude of the voltage gain of a CB stage with

source and base resistances is the same as that of a CE stage with base resistance and emitter degeneration.

EE105 Fall 2007 Lecture 9, Slide 13 Prof. Liu, UC Berkeley

Rin of CB Stage with Base Resistance (VA = ∞)

• The input impedance of a CB stage with base resistance is equal to 1/gm plus RB divided by (+1). This is in contrast to a degenerated CE stage, in which the resistance in series with the emitter is multiplied by (+1) when seen from the base.

1

1

1

1

B

m

B

x

xin

xxB

m

xm

R

g

Rr

i

vR

ivRr

rg

r

ivgr

vKCL

xB

vRr

rv

EE105 Fall 2007 Lecture 9, Slide 14 Prof. Liu, UC Berkeley

Input Impedance Seen at Emitter vs. Base

Common Base Stage Common Emitter Stage

EE105 Fall 2007 Lecture 9, Slide 15 Prof. Liu, UC Berkeley

Input Impedance Example• To find RX, we have to first find Req, treat it as the base

resistance of Q2 and divide it by (+1).

1

1

1

11

12 B

mmx

R

ggR

1

1

1

B

meq

R

gR