Electro Magnetic Testing

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    potential difference

    hysteresis

    electrical resistance

    impedance

    7. Which symbol indicates specific conductivity?

    J

    s

    IACS

    8. The unit of specific conductivity is?

    ohms/mm

    mhos/cm

    coulomb

    milliampere

    9. Which of the following is the reciprocal of specific conductivity?

    specific voltage

    specific gravity

    specific inductance

    specific resistivity

    10. Calculate the magnetic flux density of a 100 ampere load flowing through a non magnetic conducto

    having permeability of 4 p x 20 -7henry/meter at a distance of 0.03m from the conductor?

    0.000666T

    0.00125T

    0.188T

    150.7T

    11. The following formula expresses ? / I = N ? / I =?

    flux linkage

    inductive reactance

    self inductance

    coil impedance

    12. Mutual inductance is a term used to describe?

    magnetic attraction of two elements in an electrical circuit

    the effect of magnetic flux

    the generation of current in one coil resultant from another coils flux linkage

    the chain reaction of flux linkage

    13. The RMS value of an alternating current sinusoidal wave form is calculated?

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    Page 2 of 7Lavender International: Electro Magnetic Assessments: Module 10-1

    9/19/2001http://www.lavender-ndt.com/assessments/et/module10-1.html

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    multiplying peak by 1.43

    dividing peak by 1.43

    multipying peak by 0.707

    dividing peak by 0.707

    14. Which of the following statements are true?

    inductive reactance is inversely proportional to frequency

    inductive reactance is directly proportional to frequency

    increased frequency reduces phase angle

    increased resistance increases frequency

    15. ? Lo is the notation which equates to?

    Zo

    2 p f L for a Loaded coil

    Vo/I

    2 p f L for a coil in the air

    16. Normalisation of a complex plane impedance diagram is achieved by?

    dividing the resistive value by reactive value

    multiplying 2 p f L R

    R - Ro / ? Lo

    dividing the inductive reactance of an unloaded air coil into the loaded values of 2 p f

    L and R

    17. The impedance phasor, Z, lies at an angle ? derived by?

    multiplying the inductive reactance by 0.707dividing resistance by ? L

    multiplying TAN ? by XL

    dividing L by R to achieve TAN ?

    18. Angular frequency in radians per second is defined as a function of?

    2 p f

    2 p / T

    a - p / 2

    2 p / T and a - p / 2

    2 p f and

    19. How many radial degrees is one radian?

    14.32

    28.64

    57.29

    114.59

    20. Complex number calculations for impedance plane diagrams contain which of the following number

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    Page 3 of 7Lavender International: Electro Magnetic Assessments: Module 10-1

    9/19/2001http://www.lavender-ndt.com/assessments/et/module10-1.html

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    types?

    real numbers

    imagninary numbers

    logrithmic numbers

    real and imaginary numbers

    All of the above

    21. Calculate the phase angle given that the probe frequency is 60Hz, the inductance if 20 Henries andcoil resistance is 530 ohms?

    14.2 degrees

    85.9 degrees

    49.2 degrees

    23.5 degrees

    22. Which of the following transducer types are available in electromagnetic inspection?

    feed through

    encircling

    forked

    all the above

    only feed through and encircling

    23. Calculate the standard depth of penetration at a test frequency of 50KHz, ? resistivity in micro ohmcentimetres = 41.7, r=1?

    1.4mm

    14mm

    0.14mm2.8mm

    24. Calculate the fill factor for a 30mm diameter coil on a 27mm diameter copper bar?

    0.063

    0.81

    0.90

    1.11

    25. Which of the following variables could be used to measure none conductivity coating thicknesses?

    fill factor

    edge effect

    lift off

    all the above

    fill factor and lift off only

    26. Lift off is maintained at a constant level?

    to avoid probe contamination

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    Page 4 of 7Lavender International: Electro Magnetic Assessments: Module 10-1

    9/19/2001http://www.lavender-ndt.com/assessments/et/module10-1.html

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    33. When using surface coils on small diamater tube what disadvantages may be encountered?

    reduced speed of inspection

    reduced sensitivity

    increased resolution

    all the above

    34. In modulation analysis why are filters used?

    reduce signal to noise ratio

    reduce effects of small changes in conductivity

    amplify the response from cracks

    seperate edge effect from lift off

    35. When trying to locate cracks in a bar that has a minimum length of 10mm which of the following coilsizes would achieve the best results?

    25mm

    20mm

    15mm

    10mm

    36. Of the following which will greatly affect the conductivity of a material?

    coil diameter

    material thickness

    material temperature

    material diameter

    37. Which of the following are expressions used in electromagnetic inspection?

    algebraic function

    imaginary numbers

    exponential functions

    all the above

    38. The impedance of an empty coil would ??? as an operating frequency decrease?

    increase

    remain the same

    decrease

    frequency has no effect on coil impedance

    > Check Your Answers

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    > Contact Us

    Lavender International, Unit 7, Penistone Station, Sheffield, S36 6HP , United Kingdom

    Page 6 of 7Lavender International: Electro Magnetic Assessments: Module 10-1

    9/19/2001http://www.lavender-ndt.com/assessments/et/module10-1.html

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    Here are the corrections:

    1. any of the above2. automated mass inspection of similar parts at high rates3. any of the above

    4. any of the above5. current6. electrical resistance

    7. s8. mhos/cm

    9. specific resistivity10. 0.000666T11. self inductance

    12. the generation of current in one coil resultant from another coils flux linkage13. multipying peak by 0.707

    14. inductive reactance is directly proportional to frequency

    15. 2 p f L for a coil in the air16. dividing the inductive reactance of an unloaded air coil into the loaded values of 2 p f

    L and R17. dividing L by R to achieve TAN ?

    18. 2 p f and19. 57.2920. All of the above

    21. 85.9 degrees22. all the above

    23. 1.4mm24. 0.81

    25. lift off26. to reduce non relevant output signals27. skin efect

    28. change in part temperature29. shape the field and shield test coil with magnetic material30. lift off errors

    31. stainless steel32. an absolute coil and a differential coil

    33. reduced speed of inspection34. reduce effects of small changes in conductivity35. 10mm

    36. material temperature37. all the above

    38. decrease