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Electrochemistry Lesson 5 Balancing Half Reactions

Electrochemistry Lesson 5 Balancing Half Reactions

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Electrochemistry Lesson 5 Balancing Half Reactions. Core Concepts What is reduced and oxidized? What gains or loses electrons? What are the oxidizing and reducing agents? 2H + + As 2 O 3 + 2NO 3 - + 2H 2 O  2H 3 AsO 4 + N 2 O 3. Core Concepts - PowerPoint PPT Presentation

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  • ElectrochemistryLesson 5Balancing Half Reactions

  • Core Concepts

    What is reduced and oxidized?What gains or loses electrons?What are the oxidizing and reducing agents? 2H+ + As2O3 + 2NO3- + 2H2O 2H3AsO4 + N2O3

  • Core Concepts

    What is reduced and oxidized?What gains or loses electrons?What are the oxidizing and reducing agents? 2H+ + As2O3 + 2NO3- + 2H2O 2H3AsO4 + N2O3

    You must use oxidation #'s

  • Core Concepts

    What is reduced and oxidized?What gains or loses electrons?What are the oxidizing and reducing agents? +3 +5 +5 +32H+ + As2O3 + 2NO3- + 2H2O 2H3AsO4 + N2O3

  • Core Concepts

    What is reduced and oxidized?What gains or loses electrons?What are the oxidizing and reducing agents? +3 +5 +5 +32H+ + As2O3 + 2NO3- + 2H2O 2H3AsO4 + N2O3

    oxidizedreduced

  • Core Concepts

    What is reduced and oxidized?What gains or loses electrons?What are the oxidizing and reducing agents? +3 +5 +5 +32H+ + As2O3 + 2NO3- + 2H2O 2H3AsO4 + N2O3

    oxidizedreducedloses e'sgains e's

  • Core Concepts

    What is reduced and oxidized?What gains or loses electrons?What are the oxidizing and reducing agents? +3 +5 +5 +32H+ + As2O3 + 2NO3- + 2H2O 2H3AsO4 + N2O3

    oxidizedreducedloses e'sgains e'sred agentox agent

  • PdCl2 reacts with Mn but not Br-.

    Write the spontaneous reaction.

  • PdCl2 reacts with Mn but not Br-.

    Write the spontaneous reaction.

  • PdCl2 reacts with Mn but not Br-.

    Write the spontaneous reaction.

    Pd2++ Mn(s) Pd(s) + Mn2+

  • PdCl2 reacts with Mn but not Br-.

    Write the spontaneous reaction.

    Pd2++ Mn(s) Pd(s) + Mn2+

    Rank the oxidizing agents in decreasing strength.

  • PdCl2 reacts with Mn but not Br-.

    Write the spontaneous reaction.

    Pd2++ Mn(s) Pd(s) + Mn2+

    Rank the oxidizing agents in decreasing strength.

    Pd2+

  • PdCl2 reacts with Mn but not Br-.

    Write the spontaneous reaction.

    Pd2++ Mn(s) Pd(s) + Mn2+

    Rank the oxidizing agents in decreasing strength.

    Br-

    Pd2+

    Mn

  • PdCl2 reacts with Mn but not Br-.

    Write the spontaneous reaction.

    Pd2++ Mn(s) Pd(s) + Mn2+

    Rank the oxidizing agents in decreasing strength.

    Br2Br-

    Pd2+

    Mn

  • PdCl2 reacts with Mn but not Br-.

    Write the spontaneous reaction.

    Pd2++ Mn(s) Pd(s) + Mn2+

    Rank the oxidizing agents in decreasing strength.

    Br2Br-

    Pd2+

    Mn2+Mn

  • PdCl2 reacts with Mn but not Br-.

    Write the spontaneous reaction.

    Pd2++ Mn(s) Pd(s) + Mn2+

    Rank the oxidizing agents in decreasing strength.

    Br2Br-

    Pd2+Pd

    Mn2+Mn

  • PdCl2 reacts with Mn but not Br-.

    Write the spontaneous reaction.

    Pd2++ Mn(s) Pd(s) + Mn2+

    Rank the oxidizing agents in decreasing strength.

    Br2Br-

    Pd2+Pd

    Mn2+Mn

    Br2Pd2+Mn2+

  • PdCl2 reacts with Mn but not Br-.

    Write the spontaneous reaction.

    Pd2++ Mn(s) Pd(s) + Mn2+

    Rank the reducing agents in decreasing strength.

    Br2Br-

    Pd2+Pd

    Mn2+Mn

  • PdCl2 reacts with Mn but not Br-.

    Write the spontaneous reaction.

    Pd2++ Mn(s) Pd(s) + Mn2+

    Rank the reducing agents in decreasing strength.

    Br2Br-

    Pd2+Pd

    Mn2+Mn

    MnPdBr-

  • Balancing Redox Half Reactions in Acid Solution

  • Balancing Redox Half Reactions in Acid Solution

    Cr2O72- Cr3+

  • Balancing Redox Half Reactions in Acid Solution

    Cr2O72- Cr3+

    1. Balance the central atom

  • Balancing Redox Half Reactions in Acid Solution

    Cr2O72- Cr3+

    1. Balance the central atom

  • Balancing Redox Half Reactions in Acid Solution

    Cr2O72- 2Cr3+

    1. Balance the central atom

  • Balancing Redox Half Reactions in Acid Solution

    Cr2O72- 2Cr3+

    1. Balance the central atom2.Balance O by adding H2O

  • Balancing Redox Half Reactions in Acid Solution

    Cr2O72- 2Cr3+ + 7H2O

    1. Balance the central atom2.Balance O by adding H2O

  • Balancing Redox Half Reactions in Acid Solution

    Cr2O72- 2Cr3+ + 7H2O

    1. Balance the central atom2.Balance O by adding H2O3.Balance H by adding H+

  • Balancing Redox Half Reactions in Acid Solution

    Cr2O72- + 14H+ 2Cr3+ + 7H2O

    1. Balance the central atom2.Balance O by adding H2O3.Balance H by adding H+

  • Balancing Redox Half Reactions in Acid Solution

    Cr2O72- + 14H+ 2Cr3+ + 7H2O

    1. Balance the central atom2.Balance O by adding H2O3.Balance H by adding H+4.Balance the charge by adding electrons

  • Balancing Redox Half Reactions in Acid Solution +12Cr2O72- + 14H+ 2Cr3+ + 7H2O

    1. Balance the central atom2.Balance O by adding H2O3.Balance H by adding H+4.Balance the charge by adding electrons

  • Balancing Redox Half Reactions in Acid Solution +12+6Cr2O72- + 14H+ 2Cr3+ + 7H2O

    1. Balance the central atom2.Balance O by adding H2O3.Balance H by adding H+4.Balance the charge by adding electrons

  • Balancing Redox Half Reactions in Acid Solutionmost positive side +12+66e- +Cr2O72- + 14H+ 2Cr3+ + 7H2O

    1. Balance the central atom2.Balance O by adding H2O3.Balance H by adding H+4.Balance the charge by adding electrons

  • Balancing Redox Half Reactions in Acid Solutionmost positive side +12+66e- +Cr2O72- + 14H+ 2Cr3+ + 7H2O

    1. Balance the central atom2.Balance O by adding H2O3.Balance H by adding H+4.Balance the charge by adding electrons5.Check charge

  • Balancing Redox Half Reactions in Acid Solutionmost positive side +6+66e- +Cr2O72- + 14H+ 2Cr3+ + 7H2O

    1. Balance the central atom2.Balance O by adding H2O3.Balance H by adding H+4.Balance the charge by adding electrons5.Check charge

  • Balancing Redox Half Reactions in Acid Solution

  • Balancing Redox Half Reactions in Acid Solution

    HV2O53- H2VO3+

  • Balancing Redox Half Reactions in Acid Solution

    HV2O53- H2VO3+

    1. Balance the central atom

  • Balancing Redox Half Reactions in Acid Solution

    HV2O53- 2H2VO3+

    1. Balance the central atom

  • Balancing Redox Half Reactions in Acid Solution

    HV2O53- 2H2VO3+

    1. Balance the central atom2.Balance O by adding H2O

  • Balancing Redox Half Reactions in Acid Solution

    H2O + HV2O53- 2H2VO3+

    1. Balance the central atom2.Balance O by adding H2O

  • Balancing Redox Half Reactions in Acid Solution

    H2O + HV2O53- 2H2VO3+

    1. Balance the central atom2.Balance O by adding H2O3.Balance H by adding H+

  • Balancing Redox Half Reactions in Acid Solution

    H2O + HV2O53- + H+ 2H2VO3+

    1. Balance the central atom2.Balance O by adding H2O3.Balance H by adding H+

  • Balancing Redox Half Reactions in Acid Solution

    H2O + HV2O53- + H+ 2H2VO3+

    1. Balance the central atom2.Balance O by adding H2O3.Balance H by adding H+4.Balance the charge by adding electrons

  • Balancing Redox Half Reactions in Acid Solution -2 H2O + HV2O53- + H+ 2H2VO3+

    1. Balance the central atom2.Balance O by adding H2O3.Balance H by adding H+4.Balance the charge by adding electrons

  • Balancing Redox Half Reactions in Acid Solution -2 +2H2O + HV2O53- + H+ 2H2VO3+

    1. Balance the central atom2.Balance O by adding H2O3.Balance H by adding H+4.Balance the charge by adding electrons

  • Balancing Redox Half Reactions in Acid Solutionmost positive side -2 +2H2O + HV2O53- + H+ 2H2VO3+

    1. Balance the central atom2.Balance O by adding H2O3.Balance H by adding H+4.Balance the charge by adding electrons

  • Balancing Redox Half Reactions in Acid Solution -2 +2H2O + HV2O53- + H+ 2H2VO3+ + 4e-

    1. Balance the central atom2.Balance O by adding H2O3.Balance H by adding H+4.Balance the charge by adding electrons

  • Balancing Redox Half Reactions in Acid Solution -2 +2H2O + HV2O53- + H+ 2H2VO3+ + 4e-

    1. Balance the central atom2.Balance O by adding H2O3.Balance H by adding H+4.Balance the charge by adding electrons5.Check charge

  • Balancing Redox Half Reactions in Acid Solution -2 -2H2O + HV2O53- + H+ 2H2VO3+ + 4e-

    1. Balance the central atom2.Balance O by adding H2O3.Balance H by adding H+4.Balance the charge by adding electrons5.Check charge

  • Balancing Redox Half Reactions in Acid SolutionHBr2O72-H2BrO2-

  • Balancing Redox Half Reactions in Acid SolutionHBr2O72- 2H2BrO2-

  • Balancing Redox Half Reactions in Acid SolutionHBr2O72- 2H2BrO2- + 3H2O

  • Balancing Redox Half Reactions in Acid SolutionHBr2O72-+ 9H+ 2H2BrO2- + 3H2O

  • Balancing Redox Half Reactions in Acid Solution+7-2HBr2O72- + 9H+ 2H2BrO2- + 3H2O

  • Balancing Redox Half Reactions in Acid Solution+7-29e- + HBr2O72- + 9H+ 2H2BrO2- + 3H2O

  • Balancing Redox Half Reactions in Acid Solution+7-29e- + HBr2O72- + 9H+ 2H2BrO2- + 3H2O

    Reduction: electrons are on the left

  • Balancing Redox Half Reactions in Acid Solution-2-29e- + HBr2O72- + 9H+ 2H2BrO2- + 3H2O

  • Balancing Redox Half Reactions in Acid Solution-2-29e- + HBr2O72- + 9H+ 2H2BrO2- + 3H2O

    To balance in base solution.

  • Balancing Redox Half Reactions in Acid Solution-2-29e- + HBr2O72- + 9H+ 2H2BrO2- + 3H2O

    To balance in base solution.

    1.Balance in acid

  • Balancing Redox Half Reactions in Acid Solution-2-29e- + HBr2O72- + 9H+ 2H2BrO2- + 3H2O

    To balance in base solution.

    1.Balance in acid2.Add OH- to each side to neutralize H+

  • Balancing Redox Half Reactions in Acid Solution-2-29e- + HBr2O72- + 9H+ 2H2BrO2- + 3H2O 9OH- 9OH-To balance in base solution.

    1.Balance in acid2.Add OH- to each side to neutralize H+

  • Balancing Redox Half Reactions in Acid Solution-2-29e- + HBr2O72- + 9H+ 2H2BrO2- + 3H2O 9OH- 9OH-To balance in base solution. 9H2O

    1.Balance in acid2.Add OH- to each side to neutralize H+

  • Balancing Redox Half Reactions in Acid Solution9e-+HBr2O72- + 9H2O 2H2BrO2- + 3H2O + 9OH- To balance in base solution.

    1.Balance in acid2.Add OH- to each side to neutralize H+3.Simplify

  • Balancing Redox Half Reactions in Acid Solution 69e-+HBr2O72- + 9H2O 2H2BrO2- + 3H2O + 9OH- To balance in base solution.

    1.Balance in acid2.Add OH- to each side to neutralize H+3.Simplify

  • Balancing Redox Half Reactions in Acid Solution 9e-+HBr2O72- + 6H2O 2H2BrO2- + 9OH- To balance in base solution.

    1.Balance in acid2.Add OH- to each side to neutralize H+3.Simplify

  • Balancing Redox Half Reactions in Acid Solution 9e-+HBr2O72- + 6H2O 2H2BrO2- + 9OH- To balance in base solution.

    1.Balance in acid2.Add OH- to each side to neutralize H+3.Simplify4.Check charge

  • Balancing Redox Half Reactions in Acid Solution-11 9e-+HBr2O72- + 6H2O 2H2BrO2- + 9OH- To balance in base solution.

    1.Balance in acid2.Add OH- to each side to neutralize H+3.Simplify4.Check charge

  • Balancing Redox Half Reactions in Acid Solution-11-11 9e-+HBr2O72- + 6H2O 2H2BrO2- + 9OH- To balance in base solution.

    1.Balance in acid2.Add OH- to each side to neutralize H+3.Simplify4.Check charge

  • Balance in alkaline solution.

    Au+ClO- HAuCl42-

  • Balance in alkaline solution.

    Au+4ClO- HAuCl42-

  • Balance in alkaline solution.

    Au+4ClO- HAuCl42-

  • Balance in alkaline solution.

    Au+4ClO- HAuCl42-+ 4H2O

  • Balance in alkaline solution.

    9H+ +Au+4ClO- HAuCl42-+ 4H2O

  • Balance in alkaline solution.+5-29H+ + Au+ 4ClO- HAuCl42-+ 4H2O

  • Balance in alkaline solution.+5-29H+ + 7e- + Au+ 4ClO- HAuCl42-+ 4H2O

  • Balance in alkaline solution.-2-29H+ + 7e- + Au+ 4ClO- HAuCl42-+ 4H2O

  • Balance in alkaline solution.-2-29H+ + 7e- + Au+ 4ClO- HAuCl42-+ 4H2O9OH-9OH-

  • Balance in alkaline solution.9H+ + 7e- + Au+ 4ClO- HAuCl42-+ 4H2O9OH-9OH- 9H2O

  • Balance in alkaline solution.9H2O + 7e- + Au+ 4ClO- HAuCl42-+ 4H2O + 9OH-

  • Balance in alkaline solution.

    9H2O + 7e- + Au+ 4ClO- HAuCl42-+ 4H2O + 9OH-

  • Balance in alkaline solution.59H2O + 7e- + Au+ 4ClO- HAuCl42-+ 4H2O + 9OH-

  • Balance in alkaline solution.5H2O + 7e- + Au + 4ClO- HAuCl42-+ 9OH-

  • Balance in alkaline solution.-11-115H2O + 7e- + Au + 4ClO- HAuCl42-+ 9OH-