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Electromagnetic induction
rr
kQE ˆ
2=
v
20 ˆ
4 r
rvqB
×=v
v
πµ
So far we have found that
Electric charges create E-fields
Moving electric charges create B-fields
But this is not the whole story!
2
Electromagnetic induction
Electric Fields can also be created by a changing Magnetic Field.
Magnetic Fields can also be created by a changing Electric Field.
This is described by “Faraday’s Law”.
This will help complete the set of equations called Maxwell’s
equations of electricity and magnetism.
Electricity and Magnetism can be unified in a single theory!
The electricity and magnetic forces are manifestations of a
single “electromagnetic interaction”
Electromagnetic induction
Magnetic Flux
Magnetic Flux
The flux through an element of area is:
To calculate the flux through the surface, we
need to integrate:
For the simple case of a flat surface, we obtain:
B
φ
Magnetic flux
7
Clicker Question
At what angle of orientation of the surface is the
flux through the surface half of the maximum
possible flux?
A) φ = 0 degrees
B) φ = 30 degrees
C) φ = 45 degrees
D) φ = 60 degrees
E) None of the above
B
φ
Faraday’s Law of Induction
8
dt
d BΦ−=εTwo new quantities introduced.
1. Magnetic Flux = ΦB
2. Electro Motive Force (EMF) = ε
A changing (time-dependent) magnetic field “induces” (generates) an EMF ε.
The magnitude of the EMF equals minus the rate of change of the flux.
Important observations:
• Recall: EMF is not a force, but a source of voltage
capable of generating power.
• The EMF is called “motional” EMF, to distinguish
from “chemical” EMF (batteries)
• Recall: The magnetic flux through a closed surface is
zero! (Gauss’ Law for B-fields)
• The surface for Faraday’s Law is an open surface!
10
Clicker Question
We have a square imaginary loop with side of length a.
There is a Magnetic Field that is uniform throughout the
region as shown. How does the Magnetic Flux magnitude
|ΦB| change if we halve the Magnetic Field strength and
double the sides of the square loop?
A) Flux goes to ½ original value
B) Flux goes to ¼ original value
C) Flux goes to 2 times original value
D) Flux does not change
E) None of the above
X B
Changing the magnetic flux
11
1. Change the strength of the Magnetic Field
2. Change the area of the loop
3. Change the orientation of the loop (A vector) and the B-field
12
A loop of wire is moving rapidly through a uniform magnetic field as
shown. Is a non-zero EMF induced in the loop?
A) No, there in no EMF
B) Yes, there is an EMF
Clicker Question
13
A loop of wire is spinning rapidly about a stationary axis in uniform
magnetic field as shown.
True or False: There is a non-zero EMF induced in the loop.
A) False, zero EMF
B) True, there is an induced EMF
Clicker Question
and the angle φ is changing.
φcosBAF =
Direction of the EMF around a loop
Lenz’s Law
15
The (-) negative sign in Faraday’s Law is more of a reminder.
Lenz’s Law is just another way to express Faraday’s Law. Moreover,
it can be deduced from it.
dt
d BΦ−=ε
The induced EMF tends to induce a current in the
direction that opposes the changes in magnetic flux
Lenz’s Law
16
If we move the magnet closer to the loop, what is the direction of
the induced EMF and thus the direction of the current in the loop?
∫ ⋅=Φsurf
B AdBvv
1. The Magnetic
Flux is increasing.
2. Therefore 0>Φdt
d B
3. Induced current must create B-field
that fights the change!
Lenz’s Law
17
0>Φdt
d B
Induced current must create B-field that
fights the change!
An induced B-field down through the loop
will create a slight decrease in ΦB.
Thus, we have determined the direction of
the induced current and EMF.
i
B
Lenz’s Law
18
“The Magnetic Flux ΦB
Up Through the Loop is Increasing.
To Fight this Change, an Induced B-field is made that
Decreases the Flux Up Through the Loop.
This is accomplished by the induced current.”
Lenz’s law (summary)
20
A bar magnet is positioned below a loop of wire. The magnet is
pulled down, away from the loop. As viewed from above, is the
induced current in the loop clockwise, counterclockwise, or zero?
A: clockwise B: counter-clockwise
eyeball
C: zero
Answer: Counterclockwise.
As the magnet is pulled away, the flux is decreasing. To
fight the decrease, the induced B-field should add to the
original B-field.
Clicker Question
i
B
21
A loop of wire is sitting in a uniform, constant magnet field as
shown. Suddenly, the loop is bent into a smaller area loop. During
the bending of the loop, the induced current in the loop is ...
A: zero
B: clockwise
C: counterclockwise
B(in) B(in)
Answer: Clockwise. The flux into the page is decreasing as the
loop area decreases. To fight the decrease, we want the
induced B to add to the original B. By the right hand rule
(version II) , a clockwise induced current will make an induced B
into the page, adding to the original B.
Clicker Question
22
Is there an induced current in this circuit? If so, what is its
direction?
A. Yes, clockwise
B. Yes, counterclockwise
C. No
Clicker Question
* There is zero Magnetic Flux at all times through the loop.
23
A current-carrying wire is pulled
away from a conducting loop in the
direction shown. As the wire is
moving, is there a clockwise current
around the loop, a counterclockwise
current or no current?
A. There is a clockwise current around the loop.
B. There is a counterclockwise current around the loop.
C. There is no current around the loop.
Clicker Question
24
Example with numbers:
V10 cm
10 cm
B (increasing)
Suppose there are 1000 loops to the wire coil.
Area = (0.1m)2=0.01 m2
dB/dt = +0.1 Tesla/second
dt
dBABA
dt
d
dt
d B ==Φ= )(|| ε
Volts001.0)1.0)(01.0(|| ==ε
Voltdt
dN
dt
Nd BB 1)1()(
|| =Φ=Φ=ε
Generators
25
Generators use Faraday’s Law to convert mechanical energy into
electrical energy.
This is the opposite of motors which convert electrical into
mechanical energy.
The alternator
26
• Wire loop in a constant external B-field.
• Turning a crank makes the loop rotate.
• This then induces a current in the wire loop.
X X
B B
i (induced)
The alternator
27
• Wire loop in a constant external B-field.
• Turning a crank makes the loop rotate.
• This then induces a current in the wire loop.
28
Clicker Question
X
X
B
Bi
Instead of turning a crank and inducing a current, what if you hook
up the wire loop to a battery and push current through it.
What happens to the loop?
A) Nothing
B) It feels a net force
C) It feels a net torque
D) The current stops flowing
Note that the wire loop is a rectangle that is slightly rotated
from the plane of the page.
29
Generator Motor
Converts mechanical energy
into electrical energy.
Crank or otherwise
mechanically turns a wire loop
in an external B-field. This
induces an electric current in
the loop.
Converts electrical energy into
mechanical energy.
Battery creates a current in a
loop. This interacts with an
external B-field to create a
mechanical torque.
The “sliding bar generator”
30
Sliding metal bar on metal rails
L
x=vt
v
X X X X X XB
Bar is pulled by an
external agent to the
right at constant
velocity.
There is a uniform B-
field surrounding the
rails and loop
system.
The “sliding bar generator”
31
L
x=vt
v
X X X X X XB
This creates a wire loop
whose area is growing with
time.
LvtLxA ==
Thus, the Magnetic Flux is increasing with time!
BLvLvtdt
dBBA
dt
d
dt
dB ===Φ )()(
32
L
x=vt
v
X X X X X XB
Clicker Question
What is the direction of
the induced EMF and
thus current in the wire
loop?
A) Clockwise
B) Counter Clockwise
Motional EMF induced BLv=ε
The “sliding bar generator”
33
There is another way to see why the current in the bar is up.
Charges in the bar are moving to the right
with the bar itself.
v
X
B
There is a B-field in this region.
Thus, there is an upward force on the charges.
(up) qvBBvqF =×=v
v
v
Thus, there is an upward current in the bar!
i
The “sliding bar generator”
34
v
X
B
i
One more consequence….
If there is an upward current in the wire and there
is an external B-field, the we get?
(left) ILBBLIFMag =×=vvv
FM
But, there is also the external agent pulling the
rod to the right.
FAgent
If the velocity is constant, what is true about the
forces? They must be equal and opposite!
A conducting loop is halfway into a magnetic field. Suppose the magnetic field begins to increase rapidly in strength. What happens to the loop?
A. The loop is pushed upward, toward the top of the page.B. The loop is pushed downward, toward the bottom of the page.C.The loop is pulled to the left, into the magnetic field.D.The loop is pushed to the right, out of the magnetic field.E. The tension is the wires increases but the loop does not move.
Clicker Question
Eddy currents
If a metal object (something in which electric charges can move) and an external source of Magnetic Field are in relative motion so that there is changing Magnetic Flux through the metal, then Faraday says there is an EMF and thus an Eddy current.
If the metal is moving, then the direction of the current is always such as to cause a force which opposes the motion (slows the metal).
Eddy currents: Applications
Eddy Current Brakes on Trains
Since there is no direct contact, there is minimal friction.Thus the brakes do not wear down!
Eddy currents: Applications
Metal detector Portable metal detector
Eddy currents: Applications
Induction CooktopWorks via changing B-field, inducing a current in the pot or wok (which must be metal). This current then leads to power loss as heating of the pot. The cooktop surface which is not metal and does not conduct, does not get hot.
Induced electric field
40
In the case where the loop or metal is stationary and the Magnetic
field is changing, then there is no Magnetic force on the charges in
the wire (since v=0)
BvqFM
v
v
v
×=
Thus, the only way to explain the induced current in the wire is to
admit that there is the creation of a new Electric Field!
Motional EMF revisited
41
∫ ⋅=Loop
ldEvv
εTechnically, the EMF around a closed Loop is defined as:
But, recall that Voltage is defined as:
∫ ⋅−=∆ ldEVvv
Was not this integral around a closed loop always zero?
The motional EMF is not always zero around a closed loop !
Faraday’s Law reformulated
42
dt
d BΦ−=ε
∫∫ ⋅−=⋅surfaceLoop
AdBdt
dldE
vvvv
How do the loop and the surface relate?
Motional EMF revisited
43
∫∫ ⋅−=⋅surfLoop
AdBdt
dldE
vvvv
Bexternal
R [ ])()2( 2RBdt
dRE ext ππ
vv
−=
Motional EMF revisited
44
B
Wire LoopIf B = constant,
Then Magnetic Flux = constant
dΦB/dt = 0
EMF = 0 and Voltmeter reads 0.
If B =increasing,
Then Magnetic Flux = changing
|dΦB/dt| > 0
EMF > 0 and Voltmeter reads > 0.
What if the wire loop was not there?
V
Induced electric field
45
A changing B-field creates a new kind of E-field.
BIf B is decreasing � E-field is CCW
E
B
E
If B is increasing � E-field is Clockwise
Induced electric field
46
The (non-Coulomb) E-field is very different from the Coulomb E-
field created by single electric charges.
qB
E
E
0≠⋅= ∫Loop
ldEvv
ε0=⋅−=∆ ∫ ldEVvv
Time dependent B-fieldsSo far we have seen that a time varying flux can be generated by moving a magnet, or by
mechanically changing the surface area…
But what about changing the magnitude of the field?
From Ampere’s Law:
Replacing in Faraday’s Law we obtain:
Videos
http://www.youtube.com/watch?v=jBrneA-wQGA
Tesla
Ampere’s Law revisited
49
Maxwell realized that Ampere’s Law must be incompletebecause he discovered a situation where it gave the wrong
answer!
?0 +=⋅∫ encildB µvv
Ampere’s Law revisited
50
Current I(t) Current I(t)
+++++
-----
1. As the currents are flowing, one has Magnetic Fields around the wires.2. Charge is also building up on the plates, creating an increasing Electric Field
between them.
B BE
Consider a charging capacitor. The charge builds up in the plates, and there is a time-dependent current flowing through the wires I(t)
51
Current I Current I
+++++
-----
B=?
Clicker Question
Consider the Biot-Savart Law for Magnetic Fields.Is there a Magnetic Field at the point labeled between the plates?A)Yes, there is a B-FieldB)No, there is zero B-field
∫∫×==2
0 ˆ
4 r
rLdIBdBtot
v
vv
πµ
52
Current I Current I
+++++
-----
B=?
Clicker Question
Now consider an Amperian Loop as drawn. According to Ampere’s Law is there a Magnetic Field at the point labeled between the plates?A)Yes, there is a B-FieldB)No, there is zero B-field
Something must be wrong with Ampere’s Law!
Ampere’s Law revisited
Both surfaces have the same boundary, if Ampere’s law applies, then the result should be the same, independently of the surface we choose.
Current I Current I
+++++
-----
Ampere’s Law revisited
Both surfaces have the same boundary, if Ampere’s law applies, then the result should be the same, independently of the surface we choose.
Ampere’s law: solving the paradox
The changing Electric Field inside the capacitor must act like a current enclosed for Ampere’s Law.
∫ ⎟⎠
⎞⎜⎝
⎛ Φ+=⋅dt
dIldB E
enc 00 εµvv
Where ∫ ⋅=Φ AdEE
vv
Maxwell defined a fictitious “displacement current”:
Thus, a changing Electric Field creates a Magnetic Field !
dt
dI E
D
Φ= 0ε
The displacement current
EEAEdd
ACVQ Φ==== 00
0 )( εεε
CE
D Idt
dQ
dt
dI ==Φ= 0ε
The B-field in between the plates is exactly the same as the field created by the current outside.The fictitious “displacement current” gives an idea of continuity of the current, even though there is no charge flowing in the space separating the plates
Between the plates: 0;0 =Φ= CE
D Idt
dI ε
Outside the capacitor: 0;0 ≠= CD II
Maxwell’s equations
0εencl
Surf
QAdE =⋅∫rr
Gauss’ Law for E-fields
0=⋅∫SurfAdBrr
Gauss’ Law for B-fields
⎟⎠
⎞⎜⎝
⎛ Φ+=⋅∫ dt
dIldB E
thruloop 00 εµrr
Ampere’s Law
dt
dldE B
loop
Φ−=⋅∫rr
Faraday’s Law