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ENERGY BALANCE
Nur IstianahSTMTMEng THP UB 2017
Energy Balance
Total energy entering the system
Total energy leaving the system
Change in the total energy of system =
The first law of thermodynamic states that energy can be neither created nor destroyed
Overall View of an Engineering Process
Using a material balance and an energy balance a food engineering
process can be viewed overall or as a series of units Each unit is a
unit operation
Raw
materials Unit Operation
Further Unit Operation
Previous Unit Operation
By-products
Product
Wastes
Energy
Wastes Energy
Capital
Energy
Labor
Control
Conservation Law
E in = Eout
ΣQ in = Σ Qp + Σ Qbp + Qloss
Efisiensi = Σ Qp ΣQ in
Process
Heat exchange
bull Heating (pasteurisation blansing sterilisation)
bull Cooling
Separation
bull Evaporation
bull Drying
bull Distillation
Mixing Chemical reaction
HEAT BALANCE OF MIXING PROCESS
M1 CP T1 Q1
M2 C2 T2 Q2
M3 C3 T3 Q3
M4 C4 T4 Q4
Neraca energi
An dairy industry produce 100 kg of low fat cream (18 fat 82 water ww) which the ingredients are double cream (48 fat 52 water ww) and milk(35 fat 965 water ww) If double cream 30degC was mixed with milk 50degC Calculate the final temperature of product
28042017 8 NIS - DKP - THP UB - 2015
Excercise
Double cream
30 0C
Milk 50 0C
low fat cream
28042017 9 NIS - DKP - THP UB - 2015
Solution Mass balance
m in = m out
Define double cream as y kg and milk as x kg Total mass balance y + x = 100 kg helliphelliphelliphelliphellip Eq1 Fat mass balance 0035x + 048y = 100(018) helliphelliphelliphelliphellip Eq2 Eq 1 dan 2 0035(100-y) + 048y = 18 35 - 0035y + 048y = 18 y = 3258 kg So helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip X = 6742 kg
28042017 10 NIS - DKP - THP UB - 2015
Q in = Q out
Q in (T ref=0 K) a Double cream Cpdouble cream 167472(048)+41868(052)=2981 Jkg-1K Qindouble cream= mCp(Tm-Tref)
= (3258 kg)(2981 Jkg-1K)(30-0 K) = 291363096 J
b Milk Cpsusu 167472(0035)+41868(0965)=4099 Jkg-1K Qinsusu= mCp(Tm-Tref)
= (6742 kg)(4099 Jkg-1K)(50-0 K) = 829038902 J
28042017 11 NIS - DKP - THP UB - 2015
Q out Cplow fat cream 167472(018)+41868(082)=3735 Jkg-1K Qindouble cream= mCp(Tm-Tref) = 100(3735 Jkg-1K)(T-0degC)=37350(T-0degC)
Kesetimbangan energi Qindouble cream + Qinsusu= Q out low fat cream
291363096 J + 829038902 J = 37350(T-0degC)K T = (291363096 J + 829038902 J) 37350 Jkg-1 T = 4480 degC
28042017 12 NIS - DKP - THP UB - 2015
THANKS FOR YOUR ATTENTION
The best person is one give something useful always
28042017 Nur Istianah-KP1-neraca energi-2015
Energy Balance
Total energy entering the system
Total energy leaving the system
Change in the total energy of system =
The first law of thermodynamic states that energy can be neither created nor destroyed
Overall View of an Engineering Process
Using a material balance and an energy balance a food engineering
process can be viewed overall or as a series of units Each unit is a
unit operation
Raw
materials Unit Operation
Further Unit Operation
Previous Unit Operation
By-products
Product
Wastes
Energy
Wastes Energy
Capital
Energy
Labor
Control
Conservation Law
E in = Eout
ΣQ in = Σ Qp + Σ Qbp + Qloss
Efisiensi = Σ Qp ΣQ in
Process
Heat exchange
bull Heating (pasteurisation blansing sterilisation)
bull Cooling
Separation
bull Evaporation
bull Drying
bull Distillation
Mixing Chemical reaction
HEAT BALANCE OF MIXING PROCESS
M1 CP T1 Q1
M2 C2 T2 Q2
M3 C3 T3 Q3
M4 C4 T4 Q4
Neraca energi
An dairy industry produce 100 kg of low fat cream (18 fat 82 water ww) which the ingredients are double cream (48 fat 52 water ww) and milk(35 fat 965 water ww) If double cream 30degC was mixed with milk 50degC Calculate the final temperature of product
28042017 8 NIS - DKP - THP UB - 2015
Excercise
Double cream
30 0C
Milk 50 0C
low fat cream
28042017 9 NIS - DKP - THP UB - 2015
Solution Mass balance
m in = m out
Define double cream as y kg and milk as x kg Total mass balance y + x = 100 kg helliphelliphelliphelliphellip Eq1 Fat mass balance 0035x + 048y = 100(018) helliphelliphelliphelliphellip Eq2 Eq 1 dan 2 0035(100-y) + 048y = 18 35 - 0035y + 048y = 18 y = 3258 kg So helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip X = 6742 kg
28042017 10 NIS - DKP - THP UB - 2015
Q in = Q out
Q in (T ref=0 K) a Double cream Cpdouble cream 167472(048)+41868(052)=2981 Jkg-1K Qindouble cream= mCp(Tm-Tref)
= (3258 kg)(2981 Jkg-1K)(30-0 K) = 291363096 J
b Milk Cpsusu 167472(0035)+41868(0965)=4099 Jkg-1K Qinsusu= mCp(Tm-Tref)
= (6742 kg)(4099 Jkg-1K)(50-0 K) = 829038902 J
28042017 11 NIS - DKP - THP UB - 2015
Q out Cplow fat cream 167472(018)+41868(082)=3735 Jkg-1K Qindouble cream= mCp(Tm-Tref) = 100(3735 Jkg-1K)(T-0degC)=37350(T-0degC)
Kesetimbangan energi Qindouble cream + Qinsusu= Q out low fat cream
291363096 J + 829038902 J = 37350(T-0degC)K T = (291363096 J + 829038902 J) 37350 Jkg-1 T = 4480 degC
28042017 12 NIS - DKP - THP UB - 2015
THANKS FOR YOUR ATTENTION
The best person is one give something useful always
28042017 Nur Istianah-KP1-neraca energi-2015
Overall View of an Engineering Process
Using a material balance and an energy balance a food engineering
process can be viewed overall or as a series of units Each unit is a
unit operation
Raw
materials Unit Operation
Further Unit Operation
Previous Unit Operation
By-products
Product
Wastes
Energy
Wastes Energy
Capital
Energy
Labor
Control
Conservation Law
E in = Eout
ΣQ in = Σ Qp + Σ Qbp + Qloss
Efisiensi = Σ Qp ΣQ in
Process
Heat exchange
bull Heating (pasteurisation blansing sterilisation)
bull Cooling
Separation
bull Evaporation
bull Drying
bull Distillation
Mixing Chemical reaction
HEAT BALANCE OF MIXING PROCESS
M1 CP T1 Q1
M2 C2 T2 Q2
M3 C3 T3 Q3
M4 C4 T4 Q4
Neraca energi
An dairy industry produce 100 kg of low fat cream (18 fat 82 water ww) which the ingredients are double cream (48 fat 52 water ww) and milk(35 fat 965 water ww) If double cream 30degC was mixed with milk 50degC Calculate the final temperature of product
28042017 8 NIS - DKP - THP UB - 2015
Excercise
Double cream
30 0C
Milk 50 0C
low fat cream
28042017 9 NIS - DKP - THP UB - 2015
Solution Mass balance
m in = m out
Define double cream as y kg and milk as x kg Total mass balance y + x = 100 kg helliphelliphelliphelliphellip Eq1 Fat mass balance 0035x + 048y = 100(018) helliphelliphelliphelliphellip Eq2 Eq 1 dan 2 0035(100-y) + 048y = 18 35 - 0035y + 048y = 18 y = 3258 kg So helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip X = 6742 kg
28042017 10 NIS - DKP - THP UB - 2015
Q in = Q out
Q in (T ref=0 K) a Double cream Cpdouble cream 167472(048)+41868(052)=2981 Jkg-1K Qindouble cream= mCp(Tm-Tref)
= (3258 kg)(2981 Jkg-1K)(30-0 K) = 291363096 J
b Milk Cpsusu 167472(0035)+41868(0965)=4099 Jkg-1K Qinsusu= mCp(Tm-Tref)
= (6742 kg)(4099 Jkg-1K)(50-0 K) = 829038902 J
28042017 11 NIS - DKP - THP UB - 2015
Q out Cplow fat cream 167472(018)+41868(082)=3735 Jkg-1K Qindouble cream= mCp(Tm-Tref) = 100(3735 Jkg-1K)(T-0degC)=37350(T-0degC)
Kesetimbangan energi Qindouble cream + Qinsusu= Q out low fat cream
291363096 J + 829038902 J = 37350(T-0degC)K T = (291363096 J + 829038902 J) 37350 Jkg-1 T = 4480 degC
28042017 12 NIS - DKP - THP UB - 2015
THANKS FOR YOUR ATTENTION
The best person is one give something useful always
28042017 Nur Istianah-KP1-neraca energi-2015
Conservation Law
E in = Eout
ΣQ in = Σ Qp + Σ Qbp + Qloss
Efisiensi = Σ Qp ΣQ in
Process
Heat exchange
bull Heating (pasteurisation blansing sterilisation)
bull Cooling
Separation
bull Evaporation
bull Drying
bull Distillation
Mixing Chemical reaction
HEAT BALANCE OF MIXING PROCESS
M1 CP T1 Q1
M2 C2 T2 Q2
M3 C3 T3 Q3
M4 C4 T4 Q4
Neraca energi
An dairy industry produce 100 kg of low fat cream (18 fat 82 water ww) which the ingredients are double cream (48 fat 52 water ww) and milk(35 fat 965 water ww) If double cream 30degC was mixed with milk 50degC Calculate the final temperature of product
28042017 8 NIS - DKP - THP UB - 2015
Excercise
Double cream
30 0C
Milk 50 0C
low fat cream
28042017 9 NIS - DKP - THP UB - 2015
Solution Mass balance
m in = m out
Define double cream as y kg and milk as x kg Total mass balance y + x = 100 kg helliphelliphelliphelliphellip Eq1 Fat mass balance 0035x + 048y = 100(018) helliphelliphelliphelliphellip Eq2 Eq 1 dan 2 0035(100-y) + 048y = 18 35 - 0035y + 048y = 18 y = 3258 kg So helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip X = 6742 kg
28042017 10 NIS - DKP - THP UB - 2015
Q in = Q out
Q in (T ref=0 K) a Double cream Cpdouble cream 167472(048)+41868(052)=2981 Jkg-1K Qindouble cream= mCp(Tm-Tref)
= (3258 kg)(2981 Jkg-1K)(30-0 K) = 291363096 J
b Milk Cpsusu 167472(0035)+41868(0965)=4099 Jkg-1K Qinsusu= mCp(Tm-Tref)
= (6742 kg)(4099 Jkg-1K)(50-0 K) = 829038902 J
28042017 11 NIS - DKP - THP UB - 2015
Q out Cplow fat cream 167472(018)+41868(082)=3735 Jkg-1K Qindouble cream= mCp(Tm-Tref) = 100(3735 Jkg-1K)(T-0degC)=37350(T-0degC)
Kesetimbangan energi Qindouble cream + Qinsusu= Q out low fat cream
291363096 J + 829038902 J = 37350(T-0degC)K T = (291363096 J + 829038902 J) 37350 Jkg-1 T = 4480 degC
28042017 12 NIS - DKP - THP UB - 2015
THANKS FOR YOUR ATTENTION
The best person is one give something useful always
28042017 Nur Istianah-KP1-neraca energi-2015
Process
Heat exchange
bull Heating (pasteurisation blansing sterilisation)
bull Cooling
Separation
bull Evaporation
bull Drying
bull Distillation
Mixing Chemical reaction
HEAT BALANCE OF MIXING PROCESS
M1 CP T1 Q1
M2 C2 T2 Q2
M3 C3 T3 Q3
M4 C4 T4 Q4
Neraca energi
An dairy industry produce 100 kg of low fat cream (18 fat 82 water ww) which the ingredients are double cream (48 fat 52 water ww) and milk(35 fat 965 water ww) If double cream 30degC was mixed with milk 50degC Calculate the final temperature of product
28042017 8 NIS - DKP - THP UB - 2015
Excercise
Double cream
30 0C
Milk 50 0C
low fat cream
28042017 9 NIS - DKP - THP UB - 2015
Solution Mass balance
m in = m out
Define double cream as y kg and milk as x kg Total mass balance y + x = 100 kg helliphelliphelliphelliphellip Eq1 Fat mass balance 0035x + 048y = 100(018) helliphelliphelliphelliphellip Eq2 Eq 1 dan 2 0035(100-y) + 048y = 18 35 - 0035y + 048y = 18 y = 3258 kg So helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip X = 6742 kg
28042017 10 NIS - DKP - THP UB - 2015
Q in = Q out
Q in (T ref=0 K) a Double cream Cpdouble cream 167472(048)+41868(052)=2981 Jkg-1K Qindouble cream= mCp(Tm-Tref)
= (3258 kg)(2981 Jkg-1K)(30-0 K) = 291363096 J
b Milk Cpsusu 167472(0035)+41868(0965)=4099 Jkg-1K Qinsusu= mCp(Tm-Tref)
= (6742 kg)(4099 Jkg-1K)(50-0 K) = 829038902 J
28042017 11 NIS - DKP - THP UB - 2015
Q out Cplow fat cream 167472(018)+41868(082)=3735 Jkg-1K Qindouble cream= mCp(Tm-Tref) = 100(3735 Jkg-1K)(T-0degC)=37350(T-0degC)
Kesetimbangan energi Qindouble cream + Qinsusu= Q out low fat cream
291363096 J + 829038902 J = 37350(T-0degC)K T = (291363096 J + 829038902 J) 37350 Jkg-1 T = 4480 degC
28042017 12 NIS - DKP - THP UB - 2015
THANKS FOR YOUR ATTENTION
The best person is one give something useful always
28042017 Nur Istianah-KP1-neraca energi-2015
HEAT BALANCE OF MIXING PROCESS
M1 CP T1 Q1
M2 C2 T2 Q2
M3 C3 T3 Q3
M4 C4 T4 Q4
Neraca energi
An dairy industry produce 100 kg of low fat cream (18 fat 82 water ww) which the ingredients are double cream (48 fat 52 water ww) and milk(35 fat 965 water ww) If double cream 30degC was mixed with milk 50degC Calculate the final temperature of product
28042017 8 NIS - DKP - THP UB - 2015
Excercise
Double cream
30 0C
Milk 50 0C
low fat cream
28042017 9 NIS - DKP - THP UB - 2015
Solution Mass balance
m in = m out
Define double cream as y kg and milk as x kg Total mass balance y + x = 100 kg helliphelliphelliphelliphellip Eq1 Fat mass balance 0035x + 048y = 100(018) helliphelliphelliphelliphellip Eq2 Eq 1 dan 2 0035(100-y) + 048y = 18 35 - 0035y + 048y = 18 y = 3258 kg So helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip X = 6742 kg
28042017 10 NIS - DKP - THP UB - 2015
Q in = Q out
Q in (T ref=0 K) a Double cream Cpdouble cream 167472(048)+41868(052)=2981 Jkg-1K Qindouble cream= mCp(Tm-Tref)
= (3258 kg)(2981 Jkg-1K)(30-0 K) = 291363096 J
b Milk Cpsusu 167472(0035)+41868(0965)=4099 Jkg-1K Qinsusu= mCp(Tm-Tref)
= (6742 kg)(4099 Jkg-1K)(50-0 K) = 829038902 J
28042017 11 NIS - DKP - THP UB - 2015
Q out Cplow fat cream 167472(018)+41868(082)=3735 Jkg-1K Qindouble cream= mCp(Tm-Tref) = 100(3735 Jkg-1K)(T-0degC)=37350(T-0degC)
Kesetimbangan energi Qindouble cream + Qinsusu= Q out low fat cream
291363096 J + 829038902 J = 37350(T-0degC)K T = (291363096 J + 829038902 J) 37350 Jkg-1 T = 4480 degC
28042017 12 NIS - DKP - THP UB - 2015
THANKS FOR YOUR ATTENTION
The best person is one give something useful always
28042017 Nur Istianah-KP1-neraca energi-2015
M1 CP T1 Q1
M2 C2 T2 Q2
M3 C3 T3 Q3
M4 C4 T4 Q4
Neraca energi
An dairy industry produce 100 kg of low fat cream (18 fat 82 water ww) which the ingredients are double cream (48 fat 52 water ww) and milk(35 fat 965 water ww) If double cream 30degC was mixed with milk 50degC Calculate the final temperature of product
28042017 8 NIS - DKP - THP UB - 2015
Excercise
Double cream
30 0C
Milk 50 0C
low fat cream
28042017 9 NIS - DKP - THP UB - 2015
Solution Mass balance
m in = m out
Define double cream as y kg and milk as x kg Total mass balance y + x = 100 kg helliphelliphelliphelliphellip Eq1 Fat mass balance 0035x + 048y = 100(018) helliphelliphelliphelliphellip Eq2 Eq 1 dan 2 0035(100-y) + 048y = 18 35 - 0035y + 048y = 18 y = 3258 kg So helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip X = 6742 kg
28042017 10 NIS - DKP - THP UB - 2015
Q in = Q out
Q in (T ref=0 K) a Double cream Cpdouble cream 167472(048)+41868(052)=2981 Jkg-1K Qindouble cream= mCp(Tm-Tref)
= (3258 kg)(2981 Jkg-1K)(30-0 K) = 291363096 J
b Milk Cpsusu 167472(0035)+41868(0965)=4099 Jkg-1K Qinsusu= mCp(Tm-Tref)
= (6742 kg)(4099 Jkg-1K)(50-0 K) = 829038902 J
28042017 11 NIS - DKP - THP UB - 2015
Q out Cplow fat cream 167472(018)+41868(082)=3735 Jkg-1K Qindouble cream= mCp(Tm-Tref) = 100(3735 Jkg-1K)(T-0degC)=37350(T-0degC)
Kesetimbangan energi Qindouble cream + Qinsusu= Q out low fat cream
291363096 J + 829038902 J = 37350(T-0degC)K T = (291363096 J + 829038902 J) 37350 Jkg-1 T = 4480 degC
28042017 12 NIS - DKP - THP UB - 2015
THANKS FOR YOUR ATTENTION
The best person is one give something useful always
28042017 Nur Istianah-KP1-neraca energi-2015
An dairy industry produce 100 kg of low fat cream (18 fat 82 water ww) which the ingredients are double cream (48 fat 52 water ww) and milk(35 fat 965 water ww) If double cream 30degC was mixed with milk 50degC Calculate the final temperature of product
28042017 8 NIS - DKP - THP UB - 2015
Excercise
Double cream
30 0C
Milk 50 0C
low fat cream
28042017 9 NIS - DKP - THP UB - 2015
Solution Mass balance
m in = m out
Define double cream as y kg and milk as x kg Total mass balance y + x = 100 kg helliphelliphelliphelliphellip Eq1 Fat mass balance 0035x + 048y = 100(018) helliphelliphelliphelliphellip Eq2 Eq 1 dan 2 0035(100-y) + 048y = 18 35 - 0035y + 048y = 18 y = 3258 kg So helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip X = 6742 kg
28042017 10 NIS - DKP - THP UB - 2015
Q in = Q out
Q in (T ref=0 K) a Double cream Cpdouble cream 167472(048)+41868(052)=2981 Jkg-1K Qindouble cream= mCp(Tm-Tref)
= (3258 kg)(2981 Jkg-1K)(30-0 K) = 291363096 J
b Milk Cpsusu 167472(0035)+41868(0965)=4099 Jkg-1K Qinsusu= mCp(Tm-Tref)
= (6742 kg)(4099 Jkg-1K)(50-0 K) = 829038902 J
28042017 11 NIS - DKP - THP UB - 2015
Q out Cplow fat cream 167472(018)+41868(082)=3735 Jkg-1K Qindouble cream= mCp(Tm-Tref) = 100(3735 Jkg-1K)(T-0degC)=37350(T-0degC)
Kesetimbangan energi Qindouble cream + Qinsusu= Q out low fat cream
291363096 J + 829038902 J = 37350(T-0degC)K T = (291363096 J + 829038902 J) 37350 Jkg-1 T = 4480 degC
28042017 12 NIS - DKP - THP UB - 2015
THANKS FOR YOUR ATTENTION
The best person is one give something useful always
28042017 Nur Istianah-KP1-neraca energi-2015
Double cream
30 0C
Milk 50 0C
low fat cream
28042017 9 NIS - DKP - THP UB - 2015
Solution Mass balance
m in = m out
Define double cream as y kg and milk as x kg Total mass balance y + x = 100 kg helliphelliphelliphelliphellip Eq1 Fat mass balance 0035x + 048y = 100(018) helliphelliphelliphelliphellip Eq2 Eq 1 dan 2 0035(100-y) + 048y = 18 35 - 0035y + 048y = 18 y = 3258 kg So helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip X = 6742 kg
28042017 10 NIS - DKP - THP UB - 2015
Q in = Q out
Q in (T ref=0 K) a Double cream Cpdouble cream 167472(048)+41868(052)=2981 Jkg-1K Qindouble cream= mCp(Tm-Tref)
= (3258 kg)(2981 Jkg-1K)(30-0 K) = 291363096 J
b Milk Cpsusu 167472(0035)+41868(0965)=4099 Jkg-1K Qinsusu= mCp(Tm-Tref)
= (6742 kg)(4099 Jkg-1K)(50-0 K) = 829038902 J
28042017 11 NIS - DKP - THP UB - 2015
Q out Cplow fat cream 167472(018)+41868(082)=3735 Jkg-1K Qindouble cream= mCp(Tm-Tref) = 100(3735 Jkg-1K)(T-0degC)=37350(T-0degC)
Kesetimbangan energi Qindouble cream + Qinsusu= Q out low fat cream
291363096 J + 829038902 J = 37350(T-0degC)K T = (291363096 J + 829038902 J) 37350 Jkg-1 T = 4480 degC
28042017 12 NIS - DKP - THP UB - 2015
THANKS FOR YOUR ATTENTION
The best person is one give something useful always
28042017 Nur Istianah-KP1-neraca energi-2015
Solution Mass balance
m in = m out
Define double cream as y kg and milk as x kg Total mass balance y + x = 100 kg helliphelliphelliphelliphellip Eq1 Fat mass balance 0035x + 048y = 100(018) helliphelliphelliphelliphellip Eq2 Eq 1 dan 2 0035(100-y) + 048y = 18 35 - 0035y + 048y = 18 y = 3258 kg So helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip X = 6742 kg
28042017 10 NIS - DKP - THP UB - 2015
Q in = Q out
Q in (T ref=0 K) a Double cream Cpdouble cream 167472(048)+41868(052)=2981 Jkg-1K Qindouble cream= mCp(Tm-Tref)
= (3258 kg)(2981 Jkg-1K)(30-0 K) = 291363096 J
b Milk Cpsusu 167472(0035)+41868(0965)=4099 Jkg-1K Qinsusu= mCp(Tm-Tref)
= (6742 kg)(4099 Jkg-1K)(50-0 K) = 829038902 J
28042017 11 NIS - DKP - THP UB - 2015
Q out Cplow fat cream 167472(018)+41868(082)=3735 Jkg-1K Qindouble cream= mCp(Tm-Tref) = 100(3735 Jkg-1K)(T-0degC)=37350(T-0degC)
Kesetimbangan energi Qindouble cream + Qinsusu= Q out low fat cream
291363096 J + 829038902 J = 37350(T-0degC)K T = (291363096 J + 829038902 J) 37350 Jkg-1 T = 4480 degC
28042017 12 NIS - DKP - THP UB - 2015
THANKS FOR YOUR ATTENTION
The best person is one give something useful always
28042017 Nur Istianah-KP1-neraca energi-2015
Q in = Q out
Q in (T ref=0 K) a Double cream Cpdouble cream 167472(048)+41868(052)=2981 Jkg-1K Qindouble cream= mCp(Tm-Tref)
= (3258 kg)(2981 Jkg-1K)(30-0 K) = 291363096 J
b Milk Cpsusu 167472(0035)+41868(0965)=4099 Jkg-1K Qinsusu= mCp(Tm-Tref)
= (6742 kg)(4099 Jkg-1K)(50-0 K) = 829038902 J
28042017 11 NIS - DKP - THP UB - 2015
Q out Cplow fat cream 167472(018)+41868(082)=3735 Jkg-1K Qindouble cream= mCp(Tm-Tref) = 100(3735 Jkg-1K)(T-0degC)=37350(T-0degC)
Kesetimbangan energi Qindouble cream + Qinsusu= Q out low fat cream
291363096 J + 829038902 J = 37350(T-0degC)K T = (291363096 J + 829038902 J) 37350 Jkg-1 T = 4480 degC
28042017 12 NIS - DKP - THP UB - 2015
THANKS FOR YOUR ATTENTION
The best person is one give something useful always
28042017 Nur Istianah-KP1-neraca energi-2015
Q out Cplow fat cream 167472(018)+41868(082)=3735 Jkg-1K Qindouble cream= mCp(Tm-Tref) = 100(3735 Jkg-1K)(T-0degC)=37350(T-0degC)
Kesetimbangan energi Qindouble cream + Qinsusu= Q out low fat cream
291363096 J + 829038902 J = 37350(T-0degC)K T = (291363096 J + 829038902 J) 37350 Jkg-1 T = 4480 degC
28042017 12 NIS - DKP - THP UB - 2015
THANKS FOR YOUR ATTENTION
The best person is one give something useful always
28042017 Nur Istianah-KP1-neraca energi-2015
THANKS FOR YOUR ATTENTION
The best person is one give something useful always
28042017 Nur Istianah-KP1-neraca energi-2015
