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7/28/2019 Engineering Acoustics Lecture 3
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Chapter 2 . . .
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Frequency analysis of sound
Most sounds contain a combination of many
different frequencies.
The frequency analysis of sound is essential for
noise control. Because sound absorption is
frequency dependent.
i.e. The same material absorb different amounts
of sound energy at different frequencies.
e.g. To choose the proper kind of absorber.
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Frequency analysis of sound . . .
Frequency analysis is performed by measuring theoutput of a sound level meter through a band filter,
which passes only a particular frequency range
between f1 and f2. This is called the bandwidth f
(or pass band).
f = f1 f2, if f1 > f2
where f1, f2 cut-off frequencies
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Frequency analysis of sound . . .
The centre frequency
fm =f1f2
It is usually convenient to measure and analyze sound in
ranges of frequencies such as the octave. An octave bandis the range of frequencies between any one frequency
and double that frequency. (i.e.f1=2 f2)
e.g. 75 150 Hz, 150 300 Hz, 300 600 Hz, 600 1200 Hz, 1200
2400 Hz, 2400 4800 Hz, 4800 9600 Hz
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Frequency analysis of sound . . .
Mostly it is sufficient to know the magnitude of the
sound contains within the octave bands. The
preferred center frequencies of acoustic
measurements are;
31.5 Hz, 63 Hz, 125 Hz, 250 Hz, 500 Hz, 1000 Hz, 2000 Hz, 4000Hz, 8000 Hz for octaves.
Frequency analysis of sound is performed using
frequency analyzers such as octaveband analyzer
and 1/3 octave-band analyzer.
Note: 1/3 octave band is obtained by dividing the octave
bandwidth into 3 equal parts.
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Example
A certain noise was analyzed into octave bands. The sound
levels measured in each center frequency are given below.Calculate the combined sound level?
Center frequency (Hz) sound level dB (A)
31.5 60
63 60
125 65
250 70
500 65
1000 65
2000 45
4000 40
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Answer
L = 10 log(106.0+106.0+106.5+107.0+106.5+106.5+104.5+104.0)
= 67.9
= 68 dB (A)
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Measurement conditions
The measurement of sound is done under the following
standard conditions.
1) Free field
2) Reverberant field
3) Semi reverberant field
4) Anechoic field
5) Semi anechoic field
6) Diffuse sound field
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Measurement conditions . . .
1) Free field
This is completely open space where there are no sound
reflections or other modifying factors present.
ReceiverSource
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Measurement conditions . . .
2) Reverberant field
In a reverberant field the sound energy at any pointis the sum of that directly radiated from the sourceand sound levels reflected from adjacent surfaces.
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Measurement conditions . . .
Ei = Er + Et + Ea
In a fully reverberant field all the sound energy
striking the bounding surfaces is reflected without
loss. This simplifies that the bounding surfaces
should be highly reflective.
Ei Er
Et
Ea
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Measurement conditions . . .
3) Semi reverberant field
In a semi reverberant field the prevailing
conditions may be anywhere between free field
and reverberant field conditions.
4) Anechoic field
All the sound measured comes directly from thesource. (All incident energy striking the walls is fully
absorbed)
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Measurement conditions . . .
5) Semi anechoic field
In a semi anechoic field the sound source is mounted
above a hard reflective surface.
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Measurement conditions . . .
Note:
The measurements taken outdoors can be considered
to approximate to free field condition. And show
reasonable agreement with anechoic measurements
provided there is no reflective surfaces nearby.
Measurements taken indoors can be considered as
approximating to diffuse field condition. And show
reasonable agreement with reverberant fieldmeasurements.
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Measurement conditions . . .
6) Diffuse Sound Field
A room is assumed to be completely diffused (Any
closed space is referred to as a room). This means:
1) the acoustical energy is uniformly distributed
throughout the entire room
2) at any point the sound propagation is uniform
in all directions
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Noise Rating
1) Steady noise
2) Time varying noise
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Noise Rating1) Steady noise
When a sound level meter reading fluctuates within arange of less than 5 dB when using the weighting S
then the noise can be treated as steady.
For the measurement of steady noise A-weightingsimple sound level meter is used.
The average value is taken as the reading,
; n total number of readings
}{0
10Ln
10L2
10L1
0
In
10................10(10I10log
L
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Noise Rating . . .
2) Time Varying Noise
The level of many noise varies with time.
e.g. traffic noise, impulse noiseetc
For the measurement of such noise an integrating
sound level meter is used.
It automatically calculates and indicates the value ofequivalent continuous sound level (Leq) for a given time
interval T together with the value of T.
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Equivalent continuous sound level
LAeq,T -> Equivalent Continuous A weighted sound level
within a specified time interval, T.
This is defined as
Where P(t) is the instantaneous A weighted soundpressure.
T = t2 t1
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Equivalent continuous sound level . . .
This is the sound level in dB (A) of a
continuous steady sound which has the same
A-weighted sound energy within a specified
time interval , T as the fluctuating sound
being measured.
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Equivalent continuous sound level . . .
e.g.
Suppose;
sound level L1 acts during time t1,
sound level L2 acts during t2,
sound level L3 acts during t3,
..
sound level Ln acts during tn.
Let T = Total time over which the LAeq,T is required.
T = t1 + t2 + t3+ + tn
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Equivalent continuous sound level . . .
10L1x10II
01
Let
=>
)(0
11
I
I10logL
}{T
10t................10t10t10log
10Ln
n
10L2
2
10L1
1
}{TI
tI........tItI10log
0
nn2211TAeq,
L
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Example
Calculate LAeq,8 over an eight hour period for a
worker exposed to the following noise levels and
duration.
Noise Level dB (A) Duration (hours)
94 2
89 3
98 0.583 2.5
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Answer
LAeq,8 = 91.4 dB (A)
}{8
2.5x100.5x103x102x1010log1083109810891094
Aeq,8L
}{T
10t................10t10t10log10
Ln
n
10L2
2
10L1
1TAeq,
L
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Personal Daily Noise Exposure Level
The equivalent continuous A weighted sound level
over an 8 hour period is called personal daily noiseexposure level, according to the Noise at Work
Regulations, 1989.
This is used for assessing noise exposure in the work
place.
In the regulations recommended level foroccupational noise is a personal daily noise
exposure level of 85 dB (A).
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Personal Daily Noise Exposure Level . . .
i.e. 1st action level is 85 dB (A)
This is taken as the industrial first action levelfor occupational noise.
The second action level is 90 dB (A).
Above this value it is possibly hazardous and earprotection (muff or plugs) must be provided to the
workers or change their work shifts.
A 12 hour LAeq,T value of 75 dB (A) is the common
limit for construction site noise.
Above this level site operations can be stopped by
legal action
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Example
What is the maximum time for which an employee
may spend in a particular work shop where thenoise level is 106 dB (A) without using ear
protection if his noise dose is not to exceed an
equivalent continuous noise level of 90 dB (A) over
the period of 8 hour work shift?
Assume that for the rest of the shift the employee is
subjected to a constant sound level of 85 dB (A).
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Answer
Let t be the required time.
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Example
The noise of a construction site is caused by the following.
Source dB (A) Duration (hrs)
Compressor 89 8
Excavator 85 2
Truck 78 6
Pump 76 7
Calculate the equivalent continuous sound level
over a 12 hour working day of a worker exposed to
the above noise levels.
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Answer
L = 10 log
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Noise exposure from single discrete events
In many situations the total noise exposure over
a period of time is made up from a number of
different individual events such as passing of an
air craft over head or a train near by or a short
bursts of machinery noise.
The measurements of noise from different
events will be made over different durations.
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Noise exposure from single discrete events
For comparison of different types of events itwould be convenient if the equivalent
continuous sound level is averaged over the
same duration.
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Reference book:
Acoustics and noise control
2nd edition
B J Smith, R J Peters and S Owen
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Practical schedule
3 Practical
2 - Outdoors
1 Industrial visit
Assignments:
Three (3) in-class assignments, each carry 10 marks.
3 for performance
7 for assignment