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DIFFERTIATORA circuit which produced the differentiation of input at its output is called as differentiator
There are two types of differentiator Ideal differentiator Practical differentiator
Ideal differentiator
The active differentiator circuit can be obtained by exchanging the position of resistor R and capacitor C in the basic active integrator circuit.
The op-amp differentiator circuit as shown in fig
.
Fig. Ideal Active Op-amp differentiator
VA=VB=0
Apply KCL
I1=CI ddt (VIN-VA) …... eq. 1.
If=V A−VoR f ..… eq. 2.
Equating 1 & 2eq.
C1ddt (Vin-VA)=VA−Vo
Rf
VA=0
C1 ddt Vin =
VoRf
Vo=-RfC1ddt Vin
This indicates that output is directly proportional to the C1Rf
times the differentiation of the input and product C1Rf is called as time constant differentiator.
Disadvantages of an Ideal Differentiator
The gain of differentiator increases as the frequency increases. Thus at some high frequency the differentiator may become unstable and break into the oscillation. There is possibility that of op-amp may go into the saturation
Also the input impedance decreases as the frequency increases. This make the circuit very much sensitive to the noise. Thus when such noise gets amplified due to high gain at high frequency, noise may completely override the differentiated output.
Hence the differentiator circuit suffers from the limitations on its stability and noise problems, at high frequencies. These problems can be corrected using some additional parameters in the basic differentiator circuit. Such a differentiator circuit is called as practical differentiator circuit.
Practical differentiatorThe noise and stability at high frequency can be
corrected, in the practical differentiator circuit using the resistance R1 in series with C1 and the capacitor Cr in parallel with resistance Rf .
The circuit is shown in the figure. The resistance Rcomp
is used for bias compensation.
Equation of gain
|A|=ffa
1+(ffb
)2
Where fa & fb are two break frequencies.
Fa=1
2π RfC1
Fb=1
2π R1C1
Step to design practical differentiator:-
Select Fa as the highest frequency of input signal & it is
given by Fa=1
2π RfC1
Select value of capacitor C1 below 1µF and calculate Rf
Let Fb =10Fa where, Fb=1
2π R1C1
Finally R1C1=RfCf and Rcomp=R1||Rf
EXAMPLE
Design a practical differentiator circuit that will differentiate an input signal with the fmax=100Hz
Given data :
Fa=100Hz
C1=0.1µf
Fa=1
2π RfC1
Rf= 1
2π∗100∗0.1∗10−6
Rf=15.91*103
Rf=15.91KHz
Let , Fb =10Fa
=10*100
=1000Hz
Fb=1
2π R1C1
R1= 12π FbC 1
R1= 1
2π∗1000∗0.1∗10−6
R1=1.59¿103
R1=1.59KHz
R1C1=RfCf
1.59¿103*0.1∗10−6=15.91*103*Cf
Cf=1.59¿103∗0.1∗10−6
15.91∗103
Cf=9.9937*10−9F Rcomp=R1||Rf
Rf=15.91KHz
=R1∗RfR1+Rf
=1.59¿103∗15.91∗103
1.59¿103+15.91∗103
Rcomp=1.44*103