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Equilibria:Polyprotic weak acids For example, phosphoric acid, H 3 PO 4 H 3 PO 4 H 2 PO 4 -1 + H +1 K A1 = 7.5*10 -3 H 2 PO 4 -1 HPO 4 -2 + H +1 K A2 = 6.2*10 - 8 HPO 4 -2 PO 4 -3 + H +1 K A3 = 4.8*10 -13

Equilibria:Polyprotic weak acids

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Equilibria:Polyprotic weak acids. For example, phosphoric acid, H 3 PO 4 H 3 PO 4  H 2 PO 4 -1 + H +1 K A1 = 7.5*10 -3 H 2 PO 4 -1  HPO 4 -2 + H +1 K A2 = 6.2*10 -8 HPO 4 -2  PO 4 -3 + H +1 K A3 = 4.8*10 -13 H +1 T = H +1 1 + H +1 2 + H +1 3 ~ H +1 1. - PowerPoint PPT Presentation

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Page 1: Equilibria:Polyprotic weak acids

Equilibria:Polyprotic weak acids

For example, phosphoric acid, H3PO4

H3PO4 H2PO4-1 + H+1 KA1= 7.5*10-3

H2PO4-1

HPO4-2 + H+1 KA2= 6.2*10-8

HPO4-2 PO4

-3 + H+1 KA3= 4.8*10-13

H+1T = H+1

1 + H+12 + H+1

3 ~ H+11

Page 2: Equilibria:Polyprotic weak acids

Equilibria: Salts

Illustrated using a simple =1/-1 salt

There are 4 reactions to consider.

1. CatAn Cat+1 + An-1

2. Cat+1 + H2O CatOH + H+1 KA = KW/KB

3. An-1 + H2O Han + OH-1 KB = KW/KA

4. H2O H+1 + OH-1 KW

Page 3: Equilibria:Polyprotic weak acids

Equilibria: Salts We may classify salts into 4 groups, depending on

the source of the cation and anion. SBSA (NaCl), WBSA (NH4Cl), SBWA (NaF), WB WA (NH4F). The pH of the final solution will be influenced by one or more of the previous reactions.

Reactions influencing solution pH

Rxn # SBSA WBSA SBWA WBWA

2 X X

3 X X

4 X X X X

Page 4: Equilibria:Polyprotic weak acids

Equilibria: Salts

WAWB salts are especially interesting. The pH is influenced by both the cation and anion hydrolysis reactions.

1. Cat+1 + H2O CatOH + H+1 KA = KW/KB

2. An-1 + H2O Han + OH-1 KB = KW/KA

The pH of the final solution will depend on the size of KA & KB. KA > KB, acidic, etc.

Page 5: Equilibria:Polyprotic weak acids

Equilibria: Titrations If one titrates an acetic acid solution with

a sodium hydroxide solution. There are 4 stages in the titration.

1. Only acetic acid, pH = -log(CAKA)/2

2. Buffer, pH = pKA + log [A-]

[HA]

3. WASB salt, pOH = -log(CAKB)/2

note, must find new “acid” concentration

3. Strong base pH = 14 - pOH

Page 6: Equilibria:Polyprotic weak acids

Equilibria: Solubility & Solubility Products

If a salt is “insoluble” or sparingly soluble, one may write an equilibrium expression for the reaction with water.

MXAY(S) XM+Y(aq) + YA-X

(aq)

KSP = [M+Y]X[A-X]Y

e.g.

CaF2(S) Ca+2(aq) + 2F-1

(aq) KSP = [Ca+2]1[F-1]2

KSP = 4.2*10-11

Page 7: Equilibria:Polyprotic weak acids

Equilibria: Solubility & Solubility Products

We prepare a solution which is 1.0*10-4M in copper(I) and 2.0*10-3M in lead(II). To this solution we slowly add sodium iodide. Which will precipitate first, CuI or PbI2? The KSP’s are respectively, 5.3*10-12 and 1.4*10-8.