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D= b 2 4 ac 2 a A = [ 1 2 3 4 ] 1 3 ( x 2 +5 x +6 ) dx f ( x )= x+ 2 log x 2 x 2 +1

Erma susanti pratikum 1 ict

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Page 1: Erma susanti pratikum 1 ict

D=−b±√b2−4ac2a

A=[1 23 4 ]

∫1

3

(x2+5 x+6 )dx

f ( x )=x+2log x2

x2+1