Estimating Sum and Differences

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    Lesson 18

    ESTIMATING SUM AND DIFFERENCE OF

    WHOLE NUMBERS AND DECIMALS

    Lesson Objectives:

    After understanding the lesson, you must be

    able to:1. Define estimation.

    2. Know the two methods in making estimates.

    3. Learn how to estimate sum and difference and

    how it is done.

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    Estimation is a way of answering a problem

    which does not require an exact answer. An estimate is

    all that is needed when an exact value is not possible.

    Estimation is easy to use and or to compute. Rounding isone way of making estimation. Each decimal number is

    rounding to some place value, usually to the greatest

    value and the necessary operation is performance on the

    rounded decimal numbers.

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    Two methods are used in making

    estimation, the rounding off the desired

    digit one and finding the sum of the firstdigit only. We have learned how to

    round decimal numbers in this section,

    first only the front digits are used. If an

    improved or refined estimate is desired,the next digits are used.

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    When large decimal numbers are involved, it is wise to

    estimate before computing the exact and user is expectedto be about or close to the estimate.

    Method 1: Sum of the First Digit only

    Estimate in Addition

    3.455 + 2.672 + 5.135

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    Rounded off to thenearest ones

    3.455 3.000

    2.672 3.000

    + 5.134 + 5.00011.000

    Rounded off to the nearesttenths

    3.455 0.500

    2.672 0.700

    + 5.134 + 0.100

    1.300

    to be added the first estimate

    if desired or required.

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    Thus the sum 3.455 + 2.672 +

    5.134 can be roughly

    estimated by 11.000. If a

    better estimate is required or

    desired, then add 1.300 to get11.300.

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    Estimate 5.4721472.976543

    Rounded to the nearest ones

    Actual Subtraction

    5.472147 5.000000 5.472147

    - 2.976543 - 3.000000 - 2.976543

    2.000000 2.495604

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    Method 2: Rounding Method

    a. Estimate the sum by rounding method in place of

    whole numbers.

    Example:6.567 7.000

    5.482 5.000+ 4.619 +5.000

    17.000

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    b. Estimate the difference by rounding method.

    Example: 14.525 15.000

    - 11.018 - 11.000

    4.000

    By the rounding method, the first example is

    estimated by 17.000 and the second one by 4.000. The

    actual value of the sum of example no.1 is 16.668 and

    the difference of example no. 2 is 3.507 respectively.

    Both methods give a reasonable estimate.

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    Remember:

    In estimating the sums, first round each addend

    to its greatest place value position. Then add. If the

    estimate is close to the exact sum, it is a good estimate.

    Estimating helps you expect the exact answer to beabout a little less or a little more than the estimate.

    However, in estimating difference, first round the

    decimal number to the nearest place value asked for.

    Then subtract the rounded decimal numbers. Check theresult by actual subtraction.

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    I. Estimates the sum and difference to the

    greatest place value. Check how close the

    estimated sum (E.S.) / estimated difference(E.D.) by getting the actual sum (A.S.) and

    actual difference (A.D.).

    A. Actual Sum/ Estimated Sum1. 3.417 3.000 2. 36.243 36.000

    2.719 3.000 29.641 30.000

    + 1.829 + 2.00 + 110.278 + 110.000

    A.S. E.S. A.S. E.S.

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    3. 648.937 649.000 4. 871.055 871.000

    214.562 215.000 276.386 276.000

    + 450.211 + 450.000 + 107.891 + 108.000

    A.S. E.S. A.S. E.S.

    5. 374.738 375.000 6. 342.165 342.000

    469.345 469.000 178.627 179.000

    + 213.543 + 213.500 + 748.715 + 749.000

    A.S. E.S. A.S. E.S.

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    B. Actual Difference/ Estimated Difference

    7. 14.255 14.000 8. 28.267 28.000

    - 11.812 - 12.000 - 16.380 - 16.000

    A.D. E.D A.D. E.D.

    9. 345.678 346.000 10. 92.365 92.000

    - 212.792 - 213.000 - 75.647 - 76.000

    A.D. E.D. A.D. E.D.

    11. 62.495 62.000 12. 9.2875 9.0000- 17.928 - 18.000 - 6.8340 - 7.0000

    A.D. E.D. A.D. E.D.

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    Match a given decimals with the correct estimated sum /

    difference to the greatest placevalue.

    The shortest verse in the Bibleconsists of two words.

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    To find out, connect each decimals with he correct estimated

    sum / difference to the greatest place value. Write the letter

    that corresponds to the correct answer below it.

    1. 36.5+18.91+55.41 U. 939.00

    2. 639.27-422.30 S. 216.00

    3. 48.21+168.2 P. 2.00004. 285.15+27.35+627.30 E. 146.000

    5. 8.941-8.149 W. 28.10

    6. 18.95+9.25 J. 111.00

    7. 129.235+16.41 T. 537.008. 9.2875-6.834 S. 1.000

    9. 989.15-451.85 E. 217.00

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    _____ ______ ______ ______ ______

    1 2 3 4 5

    _____ ______ ______ ______6 7 8 9