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7/26/2019 estudiante05.pdf
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x
x2
x3
( 23
)10
4.1
0.111 . . .
25
(1 +
2)2
3 3 3
3 1 1
a
|a 2|
7/26/2019 estudiante05.pdf
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x2 + y2 = 1 x2 + y2 = 4 x= y x
12
3
8
4
2
3
1
12
1
9
1
6
1
4
1
3
888 111 = 2 (2 n)2 n n
3, 7, 11, 15, 19, . . .
x
x
ABC
D
BC
E
AC
ABC
ABD
BE C
BDE
16
5
9
4
5
2
7/26/2019 estudiante05.pdf
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S F D A
y = f(x) (1, 3) x (1, 0) (1,1) y=
f(x) + 2
x
(1, 0)
(0, 0)
(13
, 0)
(12
, 0)
x
7/26/2019 estudiante05.pdf
4/4