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Quiz on Monday on 8-1 to 8-3 and 8-5
Bell Ringer
1. Use the Distributive Property to factor the polynomial 3ab2 + 15a2b2 + 27ab3.
2. 15w – 3v
3. Video on Factoring by Grouping
Solve Equations
A. Solve (x – 2)(4x – 1) = 0. Check the solution.
If (x – 2)(4x – 1) = 0, then according to the Zero Product Property, either x – 2 = 0 or 4x – 1 = 0.
(x – 2)(4x – 1) = 0 Original equation
x – 2 = 0 or 4x – 1 = 0 Zero Product Property
x = 2 4x = 1 Solve each equation.
Divide.
Solve Equations
(x – 2)(4x – 1) =0 (x – 2)(4x – 1) = 0
Check Substitute 2 and for x in the original equation.
(2 – 2)(4 ● 2 – 1) = 0? ?
(0)(7) = 0? ?
0 = 0 0 = 0
Solve Equations
B. Solve 4y = 12y2. Check the solution.
Write the equation so that it is of the form ab = 0.
4y = 12y2 Original equation
4y – 12y2 = 0 Subtract 12y2 from each side.
4y(1 – 3y) = 0 Factor the GCF of 4y and 12y2, which is 4y.
4y = 0 or 1 – 3y = 0 Zero Product Property
y = 0 –3y = –1 Solve each equation.Divide.
Solve Equations
Answer: The roots are 0 and . Check by substituting
0 and for y in the original equation.
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Use Factoring
FOOTBALL A football is kicked into the air. The height of the football can be modeled by the equation h = –16x2 + 48x, where h is the height reached by the ball after x seconds. Find the values of x when h = 0.
h = –16x2 + 48x Original equation
0 = –16x2 + 48x h = 0
0 = 16x(–x + 3) Factor by using the GCF.
16x = 0 or –x + 3 = 0 Zero Product Property
x = 0 x = 3 Solve each equation.Answer: 0 seconds, 3 seconds