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10. Exponential and Logarithmic Functions
10.1 The Nature of Exponential Functions
In power expressions such as 𝑥3 or 𝑥5, the exponents are constants.
A function whose independent variable appears in the role of an exponent such
as 3𝑥 is called an exponential function.
• Simple exponential function
𝑦 = 𝑓 𝑡 = 𝑏𝑡 (1)
𝑦 : the dependent variables, 𝑡 : the independent variable,
𝑏 : a fixed base of the exponent.
• Generalized Exponential Function
𝑦 = 𝑓 𝑡 = 𝑎𝑏𝑐𝑡 (2)
𝑦
𝑡0
𝑦
𝑡0 2𝑡𝑡𝑡0
1
𝑦 = 𝑏𝑡
𝑦 = 𝑏2𝑡
𝑡0
𝑦 = 𝑏𝑡
𝑦 = 2𝑏𝑡
4
2
1
Figure 10.2
• A Preferred Base (Napier’s constant)
𝑒 = 2.71828 . . .
• Natural Exponential Function
𝑦 = 𝑒𝑡 , 𝑦 = 𝑒3𝑡 , 𝑦 = 𝐴𝑒𝑟𝑡
𝑦 = exp 𝑡 , 𝑦 = exp 3𝑡 , 𝑦 = 𝐴exp 𝑟𝑡 ,
• The Derivative of Natural Exponential Function
𝑑
𝑑𝑡𝑏𝑡 = 𝑏𝑡 ln 𝑏
𝑑
𝑑𝑡𝑒𝑡 = 𝑒𝑡 ,
𝑑
𝑑𝑡𝐴𝑒𝑟𝑡 = 𝑟𝐴𝑒𝑟𝑡
10.2 Natural Exponential Functions and the Problem of Growth
• The Number 𝑒
Let
𝑓 𝑚 = 1 +1
𝑚
𝑚. (3)
The function 𝑓 𝑚 is increasing in 𝑚.
𝑓 1 = 1 +1
1
1= 2
𝑓 2 = 1 +1
2
2= 2.25
𝑓 3 = 1 +1
3
3= 2.37037…
𝑓 4 = 1 +1
4
4= 2.44141…
⋮
The function of 𝑓 𝑚 is bounded from above.
𝑓 𝑚 = 1 +𝑚1
1
𝑚+
𝑚2
1
𝑚2 + ∙ ∙ ∙ +𝑚𝑚
1
𝑚𝑚
= 1 +1
1!+
1
2!1 −
1
𝑚+ ∙ ∙ ∙ +
1
𝑚!1 −
1
𝑚∙ ∙ ∙ 1 −
𝑚−1
𝑚
≤ 1 +1
1!+
1
2!+
1
3!+ ∙ ∙ ∙ +
1
𝑚!
≤ 1 + 1 +1
22+
1
23+ ∙ ∙ ∙ +
1
2𝑚−1
= 1 +1−
1
2𝑚
1−1
2
< 1 +1
1−1
2
= 1 + 2 = 3 (4)
• 𝑓 𝑚 is bounded from above (𝑓 𝑚 < 3)
• 𝑓 𝑚 is monotonically increasing in 𝑚
⇒ 𝑓 𝑚 → a certain number as 𝑚 → ∞.
Definition of 𝒆 : 𝑒 ≡ lim𝑚→∞
𝑓 𝑚 = 2.71828. . . (5)
• The approximation value of 𝑒
Consider the Maclaurin series of 𝜙 𝑥 = 𝑒𝑥.
𝜙 𝑥 = 𝜙 0 +𝜙′ 0
1!𝑥 +
𝜙′′ 0
2!𝑥2 + ∙ ∙ ∙ +
𝜙 𝑛 0
𝑛!𝑥𝑛 + 𝑅𝑛
= 1 + 𝑥 +1
2!𝑥2 + ∙ ∙ ∙ +
1
𝑛!𝑥𝑛 + 𝑅𝑛, (6)
where 𝑅𝑛 =𝜙 𝑛+1 𝑝
𝑛+1 !𝑥𝑛+1 =
𝑒𝑝
𝑛+1 !𝑥𝑛+1 (0 < 𝑝 < 𝑥). (7)
Since 𝑅𝑛 → 0 as 𝑛 → ∞, we have
𝑒𝑥 = 1 + 𝑥 +1
2!𝑥2 +
1
3!𝑥3 +
1
4!𝑥4 +
1
5!𝑥5 +∙ ∙ ∙ (8)
Substituting 𝑥 = 1, we find that
𝑒 = 1 + 1 +1
2!+1
3!+1
4!+1
5!+∙ ∙ ∙
= 2 + 0.5 + 0.1666667 + ∙ ∙ ∙
≅ 2.7182819 (9)
• An Economic Interpretation of 𝑒
The number 𝑒 can be interpreted as the result of a special process of interest
compounding.
Suppose that, starting out with a principal of $1, we find a banker to offer us
the interest rate of 100% per annum. If interest is to be compounded once a
year, the value of our asset at the end of the year will be $2.
𝑉 1 = initial principal × 1 + interest rate
= 1 × 1 +100%
1
1
= 2(10)
Suppose that interest is compounded semiannually. Then, we have
𝑉 2 = 1 +100%
2× 1 +
100%
2= 1 +
1
2
2(11)
If the frequency of compounding in 1 year is 𝑚, our year end asset value is
𝑉 𝑚 = 1 +1
𝑚
𝑚(12)
When 𝑚 → ∞, the value of the asset at the end of 1 year will be
lim𝑚→∞
𝑉 𝑚 = 𝑒 (13)
The number of 𝑒 can be interpreted as the year-end value to which a principal of
$1 will grow if interest at the rate of 100% per annum is compounded
continuously.
10.3 Logarithms
• The Meaning of Logarithm
The log of 𝑦 to the base 𝑏 is the power to which the base 𝑏 must be raised to attain the value 𝑦.
𝑦 = 𝑏𝑡 ⇔ 𝑡 = log𝑏 𝑦 (14)
ln 𝑥 ⇔ log𝑒 𝑥.
Examples log4 16 = log4 42 = 2 log10 1000 = log10 10
3 = 3
log10 0.01 = log10 10−2 = −2
ln 𝑒2 = log𝑒 𝑒2 = 2 ln 1 = log𝑒 𝑒
0 = 0
ln1
𝑒= log𝑒 𝑒
−1 = −1
• Rules of Logarithms
Rule I : ln 𝑢𝑣 = ln 𝑢 + ln 𝑣 𝑢, 𝑣 > 0Rule II : ln 𝑢/𝑣 = ln 𝑢 − ln 𝑣 𝑢, 𝑣 > 0Rule III : ln 𝑢𝑎 = 𝑎 ln 𝑢 𝑢 > 0Rule IV : log𝑏 𝑢 = log𝑏 𝑒 log𝑒 𝑢 𝑢 > 0
Rule V : log𝑏 𝑒 =1
log𝑒 𝑏
Proof of Rule I.
𝑢𝑣 = 𝑒ln 𝑢𝑒ln 𝑣 = 𝑒ln 𝑢+ln 𝑣 and 𝑢𝑣 = 𝑒ln 𝑢𝑣
⇒ ln𝑢𝑣 = ln 𝑢 + ln 𝑣
10.4 Logarithm Functions
• Log Functions and Exponential Functions
Log functions are inverse functions of certain exponential functions.
𝑡 = log𝑏 𝑦 and 𝑡 = ln 𝑦 (15)
𝑦 = 𝑏𝑡 and 𝑦 = 𝑒𝑡 (16)
Inverse function
• The Graphical Form
𝑦 = 𝑒𝑡 and 𝑡 = ln 𝑦 are drawn as follows.
𝑡
𝑦0
𝑦
𝑡0
45°
1
𝑦 = 𝑒𝑡
𝑡 = ln 𝑦
Figure 10.3 mirror-relationship
45°
1
We consider the inverse of 𝑦 = 𝐴𝑒𝑟𝑡.
Taking the natural log of both sides of this exponential function,
ln 𝑦 = ln 𝐴𝑒𝑟𝑡 = ln𝐴 + 𝑟𝑡 ln 𝑒 = ln𝐴 + 𝑟𝑡, (17)
Solving for 𝑡,
𝑡 =ln 𝑦−ln 𝐴
𝑟.
(18)
As inverse function of monotonically increasing functions, logarithmic
functions must also be monotonically increasing.
ln 𝑦1 = ln 𝑦2 ⟺ 𝑦1 = 𝑦2
ln 𝑦1 > ln 𝑦2 ⟺ 𝑦1 > 𝑦2 (19)
For any base 𝑏 > 1,
ቑ
0 < 𝑦 < 1𝑦 = 1𝑦 > 1
⟺ ൞
log𝑏 𝑦 < 0log𝑏 𝑦 = 0log𝑏 𝑦 > 0
(20)
• Base Conversion
Let us consider the conversion of 𝐴𝑏𝑐𝑡 into 𝐴𝑒𝑟𝑡.
𝑒𝑟 = 𝑏𝑐 ⟹ ln𝑒𝑟 = ln 𝑏𝑐
⟹ 𝑟 = 𝑐 ln 𝑏 (21)
Thus,
𝐴𝑏𝑐𝑡 = 𝐴𝑒 𝑐 ln 𝑏 𝑡