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8/11/2019 FAC Numerical Methods1 Notes
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.A. B. C. D.
A. 0B. 0C. D.
A. B. C.
D.
A. B. C. D.
A. cm 2 B. cm 2 C. 2 D. 145 cm 2
A. B. C. D.
Calculate
A. 1B. 1.96135C. 15.38760D. Cannot be determined
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?
A. B. C. D.
A. B. C. D.
A. B. C. D.
Q11. Calculate–
A. B. C. D.
Q12A. 0.B. 0.
C.
0.D. 0.
Q13 If P = 35, then what is the value of ?A. B. 33.59945C. D. 58.38105
Q14. Calculate–
A. 0034B. 0.04358C. 0.20067D. 0.08715
Q15A. 0.40B. 0.39C. 0.39D.
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Solutions
Solution: A
Using calculator, the value of
Solution: CThe value of is
Solution: B9.6
Solution: D
Solution: A
Area of triangle = = 154 cm 2
Solution: C=9.054
Solution: BUsing calculator, the value is 1.96135
Solution: D)
Solution: B
Solution: A
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Q11.Solution: BUsing calculator, the values are
Q12Solution: D
Q13Solution: C
= =
Q14.Solution: AUsing calculator, the value is 0.10034
Q15Solution: DThe value of rounded to 2 decimal place is
Q16Solution: B=
Q17.Solution: AA = C⟹ 3044.016 = 3843⟹ 0.79211 =⟹ ln(0.79211)= × ln(1.06)⟹
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Q18Solution: AA = C (1+ ) n
3
⟹ 1.27729 = (1+r) 3
⟹ ln(1.27729)=3×ln(1+r)⟹ 0.24474 = 3×ln(1+r)⟹ ln(1+r)= 0.08158⟹ (1+r)=r = 0.085
Q19Solution: A
+
= 10000 = 32193.85082
Q20.Solution: B
= 9.32819 = 9.32920( ).
