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SUBJECT : FILE No : Author : Date : Page : 6.0 Fatigue Analysis Cross Section of Bracket Max Ultimate Stress (Smax) form static case in G Factor Max Ultimate 1G Stress (Smax) = R = Smin/Smax = 0.10 ( From Material Data Ref [3]) AFI = = Where: Diameter of the Bolt (D) = Effective Width (W) = Bracket thickness (t) = t/W = 0.1 D/W = 0.2 Kt = 2.20 (From ESDU 09014 Figure 2) 4.8mm 2.5mm 25.00 141 32.99 4.27 MPa 1/Kt*F1*F2*F3*F4*F5*F6*F7*M*E*C 4.80mm 25.00mm 2.50mm X Z Y Kt = 2.20 (From ESDU 09014 Figure 2) F1(countersink effect) = 1.00 ( From Ref [6]) F2(Fastener type effect) = 1.00 ( From Ref [6]) F3( Fastener fitting condition effect) = 1.24 ( From Ref [6]) F4(Effect of preload relaxation in hybrid joint) = 1.00 ( From Ref [6]) F5(Mechanical process effect) = 1.00 ( From Ref [6]) F6(Surface treatment effect) = 0.75 ( From Ref [6]) F7(Lug and bushing effect) = 1.00 ( From Ref [6]) M (2024 T42) = 1.00 ( From Ref [6]) E =(3.175/Radius)^0.08 = 1.02 ( From Ref [6]) C (Constant) = 510 ( From Ref [6]) AFI = 220 q = 0.60 ( From Ref [6]) p = 4.60 ( From Ref [6]) Number of cycles are calculated by following forumule Normal Operating Case Maximum Wing Acceleration (Nz) = ( From Ref [2]) Maximum Stress G = (Smax * Nz) Applied Cylcels Nnormal = (from above equation) Allowable cycles = ( From Ref [2]) d 1DSG = 8.93E+05 2.88E+04 3.23E-02 136.98 MPa 32.05 ( ) ( ) P MAX q s R AFI N × - × = 9 . 0 / 1 10 5

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Page 1: Fatigue Tem

SUBJECT : FILE No :

Author : Date : Page :

6.0 Fatigue Analysis

Cross Section of Bracket

Max Ultimate Stress (Smax) form static case in G Factor

Max Ultimate 1G Stress (Smax) =

R = Smin/Smax = 0.10 ( From Material Data Ref [3])

AFI = =

Where:

Diameter of the Bolt (D) =

Effective Width (W) =

Bracket thickness (t) =

� t/W = 0.1

� D/W = 0.2

� Kt = 2.20 (From ESDU 09014 Figure 2)

4.8mm 2.5mm

25.00

141 32.99

4.27 MPa

1/Kt*F1*F2*F3*F4*F5*F6*F7*M*E*C

4.80mm

25.00mm

2.50mm

X

Z

Y

� Kt = 2.20 (From ESDU 09014 Figure 2)

F1(countersink effect) = 1.00 ( From Ref [6])

F2(Fastener type effect) = 1.00 ( From Ref [6])

F3( Fastener fitting condition effect) = 1.24 ( From Ref [6])

F4(Effect of preload relaxation in hybrid joint) = 1.00 ( From Ref [6])

F5(Mechanical process effect) = 1.00 ( From Ref [6])

F6(Surface treatment effect) = 0.75 ( From Ref [6])

F7(Lug and bushing effect) = 1.00 ( From Ref [6])

M (2024 T42) = 1.00 ( From Ref [6])

E =(3.175/Radius)^0.08 = 1.02 ( From Ref [6])

C (Constant) = 510 ( From Ref [6])

� AFI = 220

q = 0.60 ( From Ref [6])

p = 4.60 ( From Ref [6])

Number of cycles are calculated by following forumule

Normal Operating Case

Maximum Wing Acceleration (Nz) = ( From Ref [2])

Maximum Stress G = (Smax * Nz)

Applied Cylcels Nnormal = (from above equation)

Allowable cycles = ( From Ref [2])

d1DSG =

8.93E+05

2.88E+04

3.23E-02

136.98 MPa

32.05

( )( )

P

MAX

qsR

AFIN

×−×=

9.0/110 5

Page 2: Fatigue Tem

SUBJECT : FILE No :

Author : Date : Page :

Windmilling Case

Stress with amplification and SEI

Initial Descent 18G = (Smax * Q * SEI)

Cruise 17.4G = (Smax * Q * SEI)

Final Descent 5.8G = (Smax * Q * SEI)

Approach & Landing 2G = (Smax * Q * SEI)

Transient 16G = (Smax * Q * SEI)

Applied Number of cylced for Windmilling case

NInitial Descent 18G = (from above equation)

NCruise 17.4G = (from above equation)

NFinal Descent 5.8G = (from above equation)

NApproach & Landing 2G = (from above equation)

NTransient 16G = (from above equation)

Allowable Cycles (N) for 1 hr Mission Ref [1]

Initial Descent 18G = ( From Ref [1])

Cruise 17.4G = ( From Ref [1])

Final Descent 5.8G = ( From Ref [1])

Approach & Landing 2G = ( From Ref [1])

Transient 16G = ( From Ref [1])

1.56E+09

2.69E+11

8.93E+06

20000 Cylcles

25000 Cylcles

6000 Cylcles

2000 Cylcles

20 Cylcles

7.24E+06

87 MPa

27 MPa

9 MPa

83 MPa

3.38E+06

103 MPa

1N

2000

N

6000

N

20

N

25000

N

20000++++=nhrDiversioSEId

dSEI 1 Hr Diversion =

Allowable Cycles (N) for 1 hr Mission Ref [1]

Initial Descent 18G

Cruise 17.4G

Final Descent 5.8G

Approach & Landing 2G

Transient 16G

dSEI 3 Hr Diversion =

total damage (1 hour diversion mission) =

total damage (3 hour diversion mission) =

2000 Cylcles

20 Cylcles

1.88E-02

8.33E-02

5.10E-02

6000 Cylcles

9.38E-03

20000 Cylcles

93000 Cylcles

Landing andApproach Descent FinaltransientCruisedescent Initial

1N

2000

N

6000

N

20

N

25000

N

20000++++=nhrDiversioSEId

Landing andApproach Descent FinaltransientCruisedescent Initial

1N

2000

N

6000

N

20

N

93000

N

20000++++=nhrDiversioSEId

1 2 x )d(dDamage DiversionHr 1 SEI1DSGDiversionhour 1 T otal, <+=

1 )d(dDamage DiversionHr 3 SEI1DSGDiversionhour 3 Total, <+=