Force Commutated Inverters

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    Force-CommutatedForce-Commutated

    InvertersInverters

    1

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    Figure 1. The single-phase H-bridge inverter

    The Single-Phase Full-Bridge (H-bridge) Inverter

    It consists of a dc source, four forced-commutated switches, and aload.

    It is the basic building block of the multilevel inverters withindependent dc sources.

    vo

    Vdc

    S1 S3

    S4 S2

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    (i) S1 and S2 closed

    vo !dc

    (ii) S" and S# closed

    vo

    Vdc

    S1

    S2

    vo

    Vdc

    S3

    S4

    vo - !dc

    $igure 2

    (a) (b)

    %he re&uired ac output waveform is s'nthesised from a dc input b'closing and opening the switches in an appropriate se&uence.

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    vo

    Vdc

    S3S1

    (iii) S1 and S" closed

    vo

    (iv) S2 and S# closed

    vo

    Vdc

    S2S4

    vo

    $igure 2

    (c) (d)

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    Switches Closed Output Voltage vo

    S1 and S2 + Vdc

    S3 and S4 - Vdc

    S1 and S3 0

    S2 and S4 0

    Summar'

    ased on the waveform s'nthesis method emplo'ed, twot'pes of inverters can be identified.

    i. S&uare-wave inverters

    ii. *ulse-width modulated (*+) inverters

    %he following discussion focuses on the s&uare-wave inverter. %he*+ inverter will be discussed separatel' elsewhere.

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    The Square-Wave Inverter

    It uses the simplest switching scheme for the full-bridgeconverter to produce a s&uare wave output voltage.

    %he switches connect the load to !dcwhen S1 and S2 are

    closed to !dcwhen S" and S# are closed.

    %he periodic switching of the load voltage between !dc

    and !dcproduces a s&uare wave voltage across the load.

    Output voltage, vo

    Time

    S1 and S2 are closed

    S3 and S4 are closed

    Vdc

    - Vdc

    0

    $igure "

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    Notesi. /lthough this alternating output is non-sinusoidal. It ma' be an

    ade&uate ac waveform for some applications.

    ii. %he current waveform in the load depends on the loadcomponents. $or the resistive load, the current waveformmatches the shape of the output voltage.

    iii. /n inductive load will have a current that has more of asinusoidal &ualit' than the voltage because of the filteringpropert' of the inductance.

    iv. /n inductive load presents some considerations in designing theswitches in the full-bridge circuit because the switch currents

    must be bidirectional.

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    $igure # shows the full-bridge inverter with switches implementedas insulated gate bipolar transistors (I0%s) with feedback diodes.

    peration

    +hen I0%s 31 and 32are turned off, the loadcurrent must becontinuous and will

    transfer to diodes 4" and4#, making the outputvoltage !dc, effectivel'

    turning on the switchpaths " and # before 3"and 3# are turned on.

    I0%s 3" and 3# mustbe turned on before theload current deca's to5ero.

    vo

    Vdc

    Q3

    Q2

    Q1

    Q4

    D1 D3

    D4D2

    $igure #

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    The Half-Bridge Inverter

    vo

    Vdc

    Vdc

    2

    Vdc

    2

    S1

    S2

    Figure 5. hal!-bridge inverter using "#$Ts.

    "n this %ir%uit& the nu'ber (!

    s)it%hes is redu%ed t( 2 b*

    dividing the d% s(ur%e v(ltage

    int( t)( parts )ith the %apa%it(rs

    +1 and +2.

    +1 and +2 are large and e,ual in

    value.

    a%h %apa%it(r )ill have v(ltage

    d%/2 a%r(ss it.

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    Circuit Operation

    a%h %apa%it(r )ill be the sa'e value and

    )ill have v(ltage d%/2 a%r(ss it. hen 1is %l(sed& the l(ad v(ltage is

    -d%/2.

    hen 2is %l(sed& the l(ad v(ltage is

    d%/2.

    utput v(ltage v(is s,uare )ave.

    The v(ltage a%r(ss an (pen s)it%h is t)i%e

    the l(ad v(ltage v(.

    $laning ti'e !(r the s)it%h is re,uired t(prevent a sh(rt-%ir%uit a%r(ss the s(ur%e.

    The !eedba% di(des are re,uired t(

    pr(vide a %(ntinuit* (! %urrent !(r indu%tive

    l(ads.

    vo

    Vdc

    Vdc

    2

    Vdc

    2

    vo

    Vdc

    Vdc

    2

    Vdc

    2

    a

    (b)

    Figure 6 Hal!-bridge e,uivalent %ir%uit )hen a 1is %l(sed& b 2is %l(sed.

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    The (utput v(ltage is a re%tangular a% )ave!(r' (! !re,uen%*

    rads2

    T

    =

    here T is the s)it%hing peri(d (! the "#$Ts. Fre,uen%* (! the inverter

    (utput v(ltage %an be %hanged b* %(ntr(lling T.

    The (utput )ave!(r' !eeds the l(ad )hi%h 'a* in general %('prise +

    %('p(nents.

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    T1 T3 T5

    T4 T6 T2

    +

    :

    $ +

    Three-Phase Step-ave !oltage Source Inverters (!SI)

    $ridge %(n!igurati(n is '(st %(''(nl* used !(r generating p(l*phase(utput be%ause the trans!(r'er re,uired in this %ase is n(t as %('pli%ated

    as in the %ase (! (ther inverter %ir%uits.

    F(r high p()er appli%ati(ns ;use !ast-s)it%hing th*rist(rs inverter-grade

    )hi%h are available in high v(ltage and %urrent ratings.

    F(r l()- and 'ediu' p()er appli%ati(ns ; use "#$Ts

    $igure 6

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    $asi%all*& t)( di!!erent '(des (! (perati(n %an be (btained !r(' this %ir%uits !re,uen%*.

    The (utput v(ltage a'plitude 'a* be varied b* %hanging the d%

    input v(ltage.

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    or,ed .a%ple "

    three-phase "#$T bridge inverter has a )*e-%(nne%ted resistive l(ad

    = 2 ?. "! the inverter !re,uen%* is 50 H@ and the + input v(ltage iss= 220 & !ind the average& A& and pea %urrents !l()ing thr(ugh

    the "#$T.

    T1 T3 T5

    T4 T6 T2

    220

    2 B 2 B 2 B

    :

    $ +

    $igure 18

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    Solution

    Here = 2 ?& ! = 50 H@& s = 220 & T = 1/! = 0.02 se%. The r's line-t(-

    line v(ltage is

    SsLL VtdVV3

    2!"

    132

    0

    2 ==

    The phase v(ltage is

    V103#$%V220&3

    414#1

    3

    2

    3==== S

    LLP V

    VV

    The line %urrent is

    AR

    VI PL '(#(12

    $%#103===

    The l(ad p()er is

    )1$12%#4((1#'(&103#$%&33 === PPO

    IVP

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    The average suppl* %urrent is

    API OS 31$#*3220

    ==

    verage transist(r %urrent is

    AI

    i SavT 44#243

    31$#*3

    3!" ===

    $e%ause the line %urrent is shared b* t)( "#$Ts& the A "#$T

    %urrent is

    +$*#3$2

    '(#(1

    2!" ===

    L

    rmsT

    I

    i

    Cea "#$T %urrent is

    +(1#'(2&3$#$*,&2!" rms ===peakiT

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    or,ed .a%ple *

    three-phase bridge inverter (perating in the 180('(de is !ed !r(' a

    d% s(ur%e (! 200 . "! the l(ad is star-%(nne%ted (! 10 B/phase pure

    resistan%e& deter'ine the r's l(ad %urrent& the r's %urrent rating (! the

    th*rist(rs& and the l(ad p()er.

    T1 T3 T5

    T4 T6 T2

    9+= 200

    10 B

    :

    $ +

    10 B 10 B

    i i$ i+

    $igure 2

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    Solution

    F(r 180('(de (! (perati(n&

    pea l(ad %urrent

    +13#33103

    2002!" =

    =peakiL

    A l(ad

    43#%3

    $$#$33#13$$#$!"222=++=rmsi

    L

    Th*rist(r r's %urrent

    +$*#$$

    $$#$33#13$$#$!"

    222

    =++

    =rmsiT

    (ad p()er

    )2$$*31034#% 2 ==L

    P

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    "*$o-/ode

    "n this parti%ular '(de (! (perati(n& t)( th*rist(rs )ill be %(ndu%ting at

    an* ti'e& e.g.& th*rist(rs T1 and T6 )ill %(ndu%t !(r 60(

    and then !(r theneDt 60(& T1 and T2 )ill %(ndu%t. F(r the neDt %*%le (! 60(& T2 and T3 )ill

    %(ndu%t.

    T1

    T2

    T3

    T4

    T5

    T6

    )it%hing

    Ti'e

    $igure 21

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    This '(de (! (perati(n has the advantage that there is n( p(ssibilit* (! a

    sh(rt %ir%uit a%r(ss the d% input as the peri(d (! 60(elapses bet)een the

    end (! %(ndu%ti(n (! (ne th*rist(r and the beginning (! %(ndu%ti(n (! the

    (ther th*rist(r (! the sa'e bran%h.

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    T"& T On Others Off

    $= +

    $+=

    += -+

    9+

    :

    $ +

    $igure 22

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    T"& T On Others Off

    =ANV

    =CN

    V

    =BNV9+

    :

    $ +

    $igure 2"

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    Figure 24. +('plete phase v(ltage )ave!(r's !(r 120(%(ndu%ti(n.

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    Figure 25. +('plete line-t(-line v(ltage )ave!(r's !(r 120(%(ndu%ti(n.

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    Figure *0+('plete %urrent )ave!(r's (! a three-phase bridge

    inverter )ith 120(%(ndu%ti(n and resistive l(ad.

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    T1 T3 T5

    T4 T6 T2

    9+= 200

    10 B

    :

    $ +

    10 B 10 B

    i i$ i+

    .a%ple +

    three-phase bridge inverter (perating in the 120('(de is !ed !r(' a

    d% s(ur%e (! 200 . "! the l(ad is star-%(nne%ted (! 10 B/phase pure

    resistan%e& deter'ine the r's l(ad %urrent& the r's %urrent rating (!

    the th*rist(rs& and the l(ad p()er.

    $igure 26

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    Solution

    F(r 120('(de (! (perati(n&

    pea l(ad and th*rist(r %urrent

    +10102

    200!" =

    =peakiL

    A l(ad %urrent

    +1$#'3

    01010!"

    222

    =++

    =rmsiL

    +'#(310!" ==rmsiT

    A th*rist(r %urrent

    (ad p()er

    )20003101$#' 2 ==L

    P

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    The H-bridge and the hal!-bridge inverters %an be %lassi!ied as t)(-

    level inverters.

    e%entl*& 'ultilevel v(ltage inverters have eD%ited )idespread

    interest.

    Aultilevel inverters (!!er better per!(r'an%e than t)(-level inverters&but the* are '(re %('pleD and %(stl* and are e'pl(*ed pri'aril* in

    high-v(ltage appli%ati(ns.

    /ultilevel Inverters

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    s'nthesi5es a desired voltage from several independentsources of dc voltages, which ma' be obtained from eitherbatteries, fuel cells, or solar cells.

    %his inverter topolog' can avoid e9tra clamping diodes or

    voltage-balancing capacitors.

    / 6-level cascaded-inverters based inverter, for e9ample, willhave three independent 4: sources and three full-bridgecells.

    inimum harmonic distortion can be obtained b' controllingthe conducting angles at different inverter level.

    / single-phase m-level configuration of such an inverter is shown in$ig 27

    Multilevel Inverters with Independent DC Sources

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    $or a three-phase s'stem, the output voltage of the three cascadedinverters can be connected in either w'e or delta configuration.

    $igure 28. / general three-phase w'e-configuration multilevel cascaded-inverter.

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    Figure 30 illustrate the basi% idea !(r

    realising a single-phase di(de-%la'ped 'ultilevel inverter&

    spe%i!i%all* a !ive-level inverter.

    1iode-Cla%ped /ultilevel Inverters

    80E

    Figure 30. #eneri% !ive-level inverter.

    Vdc

    Vdc

    4

    Vdc

    4

    Vdc

    4

    Vdc

    4

    S1

    S3

    S4

    S(

    S2

    vo

    V1

    V2

    V3

    V4

    V(

    'ultilevel inverter %ir%uit that has the

    advantage (! using a single d% s(ur%e

    rather than 'ultiple s(ur%es is the

    di(de-%la'ped 'ultilevel inverter.

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    +ir%uit design The !(ur %apa%it(rs +1 thr(ugh +4 'ae

    up a v(ltage divider&

    The %entre n(de (! the divider and (ne

    ter'inal (! the l(ad are gr(unded.

    :(de v(ltages %reated are 1thr(ugh

    5& )ith %entre n(de v(ltage 3= 0.

    nl* (ne (! the !ive s)it%hes 1 thr(ugh

    5 are %l(sed at an* (ne ti'e

    "nstantane(us l(ad v(ltage is e,ual t(the %(rresp(nding n(de v(ltage (! the

    %l(sed s)it%h.

    Vdc

    Vdc

    4

    Vdc

    4

    Vdc

    4

    Vdc

    4

    S1

    S3

    S4

    S(

    S2

    vo

    V1

    V2

    V3

    V4

    V(

    $igure "1

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    F(r the sa'e nu'ber (! n(de v(ltage levels& the nu'ber (! v(ltage-

    divider %apa%it(rs in the di(de-%la'ped t(p(l(g* %an be redu%ed b*

    hal! using a bridge stru%ture& as sh()n in Figure 32.

    d%

    v(

    +ir%uit (perati(n

    The d% v(ltage s(ur%e is

    %(nne%ted t( a pair (! series

    %apa%it(rs a%h %apa%it(r %harged t(

    d%/2

    The (utput v(ltage has !ive

    levels& na'el*& d%& d%/2& 0&

    -d%/2& and ;d%.

    $igure "2

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    2nal3sis for one-half of circuit for v24 !dc

    d%

    v= d%

    1

    2

    3

    4

    ith 1 and 2 %l(sed and 3

    and 4 (pen& v= d%.

    The di(des are (!! !(r this

    %(nditi(n.

    $igure ""

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    2nal3sis for one-half of circuit for v24 $

    d%

    v= 0

    1

    2

    3

    4

    ith 1 and 2 (pen and 3

    and 4 %l(sed& v= 0.

    The di(des are als( (!! !(r this

    %(nditi(n.

    $igure "#

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    sing a si'ilar anal*sis& the right hal! (! the bridge %an als( pr(du%e

    the v(ltages d%& 0 & and d%/2.

    The (utput v(ltage is the di!!eren%e (! the v(ltages bet)een ea%h

    hal! bridge& resulting in the !ive levels&

    dcdcdcdc V-,V

    2

    1-,0,V

    2

    1,V

    ov

    A(re (utput v(ltage levels are a%hieved )ith additi(nal %apa%it(rs and

    s)it%hes.

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    Three-Phase 1iode-Cla%ped /ultilevel Inverters

    1. ie the single-phase !ull-bridge %ir%uit& the hal!-bridge single-phase

    inverters %an be eDpanded t( three-phase appli%ati(ns.

    2. Figure 36 sh()s a three-phase di(de-%la'ped 'ultilevel inverter

    %ir%uit.

    3. This %ir%uit %an be (perated t( have a stepped-level (utput si'ilart( the siD-step %(nverter& (r& as is '(st (!ten the %ase& it %an be

    (perated t( have a pulse-)idth-'(dulated (utput.

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    d%

    80E

    Figure 36. three-phase di(de-%la'pled 'ultilevel

    inverter.

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    Summary1. In high power s'stem, the multilevel inverters can appropriatel'

    replace the e9ist s'stem that use traditional multi-pulseconverters without the need for transformers.

    2. /ll three multilevel inverters can be used in reactive powercompensation without having the voltage unbalance problem.

    ". In back-to-back intertie application, however, it is not possible touse multilevel inverter using cascaded-inverters with separate 4:sources because a short circuit will be introduced when two back-to-back inverter are not switching s'nchronousl'.

    #. n the other hand, the structure of separated dc sources is wellsuited for various renewable energ' sources such as fuel cell,photovoltaic, biomass, etc.

    ;. %his structure is, therefore, suited for an ac power suppl' invehicle s'stem utilities.

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    1. %able 1.# compares the power component re&uirements perphase leg among the three multilevel voltage source inverter

    mentioned above.2. %able 1.# shows that the number of main switches and maindiodes, needed b' the inverters to achieve the same numberof voltage levels, is the same.

    ". :lamping diodes do not need in fl'ing-capacitor and cascaded-inverter configuration, while balancing capacitors do not need

    in diode clamp and cascaded-inverter configuration.#. Implicitl', the multilevel converter using cascaded-inverters

    re&uires the least number of components.

    /nother advantage of cascaded-inverter is circuit la'outfle9ibilit'. odulari5ed circuit la'out and packaging is possible

    because each level has the same structure, and there are noe9tra clamping diodes or voltage balancing capacitor. %henumber of output voltage levels can be easil' ad=usted b'adding or removing the full-bridge cells.

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    Table 2. Comparison of power component

    requirements per phase leg between the separateDC sources- and diode-clamped multilevelinverters.