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Force Inclined

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Page 1: Force Inclined

8/19/2019 Force Inclined

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FNFF

 w  

Page 2: Force Inclined

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FNFF

 w  

Page 3: Force Inclined

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FN

FF

 w  

 

 w x

 w  y

 

= sin θ  

= sin θ  

= s i n ( θ )  = cos θ  

= cos θ  

= c o s ( θ ) 

Page 4: Force Inclined

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= + =  

= + =  

= s i n ( θ ) 

= c o s ( θ ) 

+ = 0 

 + () cos(θ) = 0 

= c o s ( θ ) 

=  

=cos(θ) 

= + =  

cos(θ) 

+ s i n ( θ ) =  

sin θ cos(θ) =   sin θ cos(θ) =  

0

Page 5: Force Inclined

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= sin θ cos(θ)  

= 0 

0= sin θ cos(θ)  

0

= sin θ cos(θ) 

cos θ = sin θ  

= sin θ

cos θ

= θ  

If a =0

= θ  

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Examples

• Find the acceleration of a crate sliding down a 400 inclined plane

if the coefficient of friction between the surfaces is 0.55

• = sin θ cos(θ) = 9.8 2 sin 40 0.55cos(40)  

• = ? ? ? =

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