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My Research and Development

No Student Height(m)

Weight (kg)

1 Hasan 1.65 80

2 Hasanah 1.52 36

3 Irfan 1.73 67

4 Irham 1.53 46

5 Luqman 1.81 67

6 Muhammad 1.54 43

7 Mukhlis 1.6 43

8 Mukmin 1.64 49

9 Nafis 1.6 50

10 Najib 1.6 60

11 Najwa 1.56 42

12 Nas Affiy 1.69 70

13 Rashidi 1.56 49

14 Rasydan 1.6 48

15 Rasyidah 1.56 42

16 Rizmin 1.56 51

17 Syamil 1.69 63

18 Syamim 1.61 65

19 Syazwan 1.6 51

20 Ubai 1.7 59

21 Umar 1.6 50

22 Zaid 1.62 55

23 Zaim 1.64 59

24 Zayyad 1.66 45

25 Zuhairi 1.63 65

The Data Tabulation


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(i)Representing the data from the frequency

table by using three different stastical graphs

(1) Histogram [based on the information from table 1]

Weight (kg) 31-40 41-50 51-60 61-70 71-80 81-90 91-100Frequency 2 24 13 8 2 0 1Lower 30.5 40.5 50.5 60.5 70.5 80.5 90.5

Upper 40.5 50.5 60.5 70.5 80.5 90.5 100.5Table 2

(2) Frequency Polygon [based on the information from table 1]


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Weight (kg) Frequenc Midpoint21-30 0 25.5

31-40 2 35.5

41-50 24 45.551-60 13 55.5

61-70 8 65.571-80 2 75.5

81-90 0 85.591-100 1 95.5

101-110 0 105.5

(3) Comulative Frequency Graph (Ogive)

Frequenc

y

Weight

(kg)


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[based on the information from table 1]

Weight

(kg)

Upper

boundry

Frequenc

y

Cumulati

frequency

21-30 30.5 0 0

31-40 40.5 2 2

41-50 50.5 24 2651-60 60.5 13 39

61-70 70.5 8 4771-80 80.5 2 49

81-90 90.5 0 49

91-100 100.5 1 50

101-110 110.5 0 50

(ii) Mean, median and mode for the weight of the

50 students.


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Weight (kg) Midpoint(m) Frequency (f) Cumulati

frequency

m x f

31-40 35.5 2 2 71

41-50 45.5 23 25 109251-60 55.5 14 39 721.5

61-70 65.5 8 47 524

71-80 75.5 2 49 151

81-90 85.5 0 49 091-100 95.5 1 50 95.5

50 2655

(1)Mean

Mean = fx

= 2( 35.5) + 24(45.5) + 13(55.5) + 8(65.5) + 2(75.5) +

0(85.5) + 1(95.5)

Mean

= 53.1kg

(2)Median

Median = L + . _

Median = 40.5 +

Median = 50.5

(3)Mode

The class interval that having the highest frequency is 41-50

Hence, the mode is 24.

(4)Explaination

Mean is the best measure of central tendency to represent the data

because:

The mean represent all the value of the weight of the 50

students.

Mean also more precise and accurate compare to the median

and mode.

f

(2+24+13+8+2+

2F

fm

N

Median

lies

22

23

50

C

10


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(i) Raw Data ( Ungrouped data) [based on theinformation from table 1]

= x2

Mean, = x

2 2

70 4900 80 2025

54 2916 36 6400

48 2304 67 1296

41 1681 46 4489

60 3600 67 2116

53 2809 43 4489

40 1600 43 1849

48 2304 49 1849

49 2401 50 2401

95 9025 60 2500

50 2500 42 3600

70 4900 70 1764

47 2209 49 4900

48 2304 48 240147 2209 42 2304

72 5184 51 1764

49 2401 63 2601

45 2025 65 3969

53 2809 51 4225

45 2025 59 2601

60 3600 50 3481

41 1681 55 2500

59 3481 59 3025

52 2704 45 3481

45 2025 65 2025

1341 75597 1355 74055

1341+1355

=2630

75597+74055 =

146085

x 2N

xN

= 2630

X is the weight of the 50

Sum

50

52.6x

The Standard Deviation Of The

Weight [using three different methods]


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Mean, =

Standard deviation for ungrouped data,

= x2

= 146085

= 12.44 kg

(ii) Grouped data [based on the information from table 2( pg2) ]

Standard Deviation for grouped data ,

= fx2

= fx2

Weight (kg) Frequency

31-40 2

41-50 24

51-60 13

61-70 871-80 2

81-90 091-100 1

N

x 2

50 52.62

f x 2

f x 2


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= fx

= 2655

= 52.6

= fx2

= 147092.5

= 13.23 kg

(iii) Grouped data [make another table using different classinterval ]

Weight Class f fx x 2 fx2

31-40 35.5 2 71 1260.25 2520.5

41-50 45.5 24 1092 2070.25 49686

51-60 55.5 13 721.5 3080.25 40043.25

61-70 65.5 8 524 4290.25 34322

71-80 75.5 2 151 5700.25 11400.581-90 85.5 0 0 7310.25 0

91-100 95.5 1 95.5 9120.25 9120.25

f=50 fx= fx2 =

f x

50

f x 2

50 52.6

2


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Standard Deviation for grouped data ,

= fx2

= fx

= 2670

= 53.4

Weight (kg) Frequency

31-35 0

36-40 2

41-45 1046-50 14

51-55 7

56-60 661-65 3

66-70 5

71-75 1

76-80 1

81-85 0

86-90 0

91-95 1

Weight Class f fx x 2 fx2

31-35 33 0 0 1089 0

36-40 38 2 76 1444 288841-45 43 10 430 1849 18490

46-50 48 14 672 2304 32256

51-55 53 7 371 2809 19663

56-60 58 6 348 3364 2018461-65 63 3 189 3969 11907

66-70 68 5 340 4624 2312071-75 73 1 73 5329 532976-80 78 1 78 6084 608481-85 83 0 0 6889 086-90 88 0 0 7744 091-95 93 1 93 8649 8649

f= fx= fx2 = 148570

f

x 2

f x

50


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= fx2

= 148570

= 10.94 kg

My Futher Exploration

f x 2

50

53.42 The conclusion that I can make is, the valueare not different too much fom each other. For

Example the c(i) is 12.44, c(ii) is 13.23 and c(iii)

is 10.94. So, the range is 2.29 only. Therefore,these three type of standard deviation can be

use to find the most accurate standard

deviation for a certain grouped or ungrouped


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(i) The percentage of underweight students

Underweight = 11

Underweight = 22 %

Student

Height (m)

Weight (kg)

BMI Category

261.65 80 29.3

8 Over

271.52 36 15.5

8 Under

28

1.73 67 22.3

9 Normal

291.53 46 19.6

5 Normal

301.81 67 20.4

5 Normal

311.54 43 18.1

3 Under

321.6 43 16.8

0 Under

331.64 49 18.2

2 Under

34

1.6 50 19.5

3 Normal

351.6 60 23.4

4 Normal

361.56 42 17.2

6 Under

371.69 70 24.5

1 Normal

381.56 49 20.1

3 Normal

391.6 48 18.7

5 Normal

401.56 42 17.2

6 Under

411.56 51 20.9

6 Normal

421.69 63 22.0

6 Normal

431.61 65 25.0

8 Over

441.6 51 19.9

2 Normal

451.7 59 20.4

2 Normal

461.6 50 19.5

3 Normal

471.62 55 20.9

6 Normal

481.64 59 21.9

4 Normal

491.66 45 16.3

3 Under

501.63 65 24.4

6 Normal

50 100


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(ii) The percentage of obess students

Based on the table in the page above, we know that the students in 4 Ibnu

Rusyd, 4 Ibnu Khaldun and 4 Al-Razi do not obess. Only 4 of them are

underweight. This situation happened maybe due to the students eating

habits. Besides that 90% of these students are scholls athlets. The

students that are overweight maybe they didnt obey to the food pyramid.

Let we see the percentage of the the overweight students :

Overweight = 4

Underweight = 8 %

(iii) Drawing an ogive of the students [based on BMItable]

Category U.Boundry Frequency C.Frequency

12-14 14.5 0 0

15-17 17.5 7 718-20 20.5 25 32

21-23 23.5 11 43

24-26 26.5 4 47

27-29 29.5 3 50

50


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As a student, to ensure that the campaign will success, I can

take part in every activity that it have. Besides that I will

motivate my friend using the information that I have got from

this project. I will tell them the effect of obesity to them such as

heart attack, diabeties and stroke. More over , I also can help

my friend that are obess by giving them a lot of physicalexercise and some tips to them how to balance body weight.

Futhermore, my father is a doctor. So, I can bring my fathers

research about obesity and food that he was made last year. I

also will help teachers and who ever to ensure this campaign

reach it objective.

Based on the research, I see that there is no obess students in

SMKAS. Although this research only take 50 students, but this

50 students are represent the whole students in SMKAS.

Parallax error maybe happened in this research. So, I use many

ways of calculation information to find the accurate and best

result.

Only 4 students overweight in this research. It represent

only 8% of the whole research. This shows that the students

have good eating habits and the canteen also sell the food high

in vitamin and protien. The overweight students are A.Amirul,

Amirul, Hassan and Syamim. For me, they have many chances

to balance their weight. With teachers help, I think they canstay in normal category.

Obesity are very dangerous because it can lead to death.

So, It is vcery important to prevent it by eating using food

Obesity Awareness

Campaign

Conclusion


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pyramid. Only this way can prevent who ever from obess and

suffer in many kinds of dangerous diseases. Besies that, by

taking part in Obesity Wareness Campaign also can make some

one avoiding obesity.

M Hasanuddin B Abu Bakar

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