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Mary J. Bojan Chem 110 1
Gas Phase Equilibrium
Chemical Equilibrium
Equilibrium Constant Keq
Equilibrium constant expression
Relationship between Kp and Kc
Heterogeneous Equilibria
Meaning of Keq
Calculations of Kc
Solving Equilibrium Problems
USING AN EQUILIBRIUM CONSTANT
Information obtained from Kc 1. Predict direction of a reaction Q reaction quotien
2. Obtaining equilibrium concentrations of reactants and
products.
Mary J. Bojan Chem 110 2
Equilibrium is achieved when opposing
processes proceed at equal rates.
equilibria previously discussed
Eg.
N2O4 (g) 2NO2(g)
colorless brown
Mary J. Bojan Chem 110 3
In chemical equilibria, forward and reverse
reactions occur at equal rates: at a macroscopic
level, it looks like nothing is happening.
Mary J. Bojan Chem 110 4
Achieving equilibrium: The relationship between the concentrations of
products and reactants at “equilibrium” will be
the same regardless of starting conditions.
Initial State: reactants only Initial state: products only
Mary J. Bojan Chem 110 5
Equilibrium point of any reaction is
characterized by a single number called the
Equilibrium Constant.
In general: jA + kB pR + qS
Example:
B(g) 2 A (g) N2O4 2 NO (g)
Mary J. Bojan Chem 110 6
What is the equilibrium constant
EXPRESSION (Keq) for the Haber process?
N2(g) + 3H2(g) 2NH3(g)
Mary J. Bojan Chem 110 7
Summarize what we know about Keq.
The ratio of equilibrium concentrations will be constant:
Keq is the equilibrium constant for the reaction.
It is a NUMBER.
Keq (the number) DOES NOT depend on concentration
It’s a function of temperature only.
Notation:
Keq = Kc
Kc R
pS q
A jB
k
concentration […] is
expressed in M (mol/L)
Kp p
p pp
Rp
Sq
Aj
Bk
concentration is expressed
using partial pressures in atm Keq = Kp
Mary J. Bojan Chem 110 8
n
cp (RT)KK
When given Keq how do I know if it is Kc or Kp?
Use context of problem.
If concentrations are given in M,
then Keq = Kc
• If concentrations are given in P,
then Keq = Kp
where n = nprod − nreact
There is a relationship between Kp and Kc.
Mary J. Bojan Chem 110 9
If equilibrium concentrations are known, we
can calculate Kp and Kc.
Equilibrium concentrations of NH3, N2, and H2 were
determined at 472C.
[H2] = 0.1207M
[N2] = 0.0402M
[NH3] = 0.00272M
Find Kc and Kp.
2NH3(g) N2(g) + 3H2(g)
Mary J. Bojan Chem 110 10
Heterogeneous Equilibria involves reactants and products in more than one
phase.
3 Fe(s) + 4 H2O(g) Fe3O4(s) + 4 H2(g)
Keq =Fe3O4[ ] H2[ ]
4
Fe[ ]3
H2O[ ]4
What is [Fe]? [Fe3O4]?
Activities of pure solids and liquids = 1.
Mary J. Bojan Chem 110 11
What is the equilibrium constant expression for
these reactions?
AgCl(s) Ag+(aq) + Cl−(aq)
C6H6(g) + 3H2(g) C6H12(g)
CaCO3(s) CaO(s) + CO2(g)
Mary J. Bojan Chem 110 12
Is Keq large or small??? What does that mean?
Reactants Products
K ≈ 1
reactants
reactants products
products
reactants products
Mary J. Bojan Chem 110 13
Try this problem.
Which one of the following has the greatest tendency to
proceed as written?
1. 4NH3(g) + 3O2(g) 2N2(g) + 6H2O(g) Kp = 11022
2. N2(g) + O2(g) 2NO(g) Kp = 5 1031
3. 2HF(g) F2(g) + H2(g) Kp = 11013
4. 2NOCl(g) 2NO(g) + Cl2(g) Kp = 4.7104
Mary J. Bojan Chem 110 14
Meaning of Keq
Is Keq large or small???
Reactants Products
Cu+2(aq) + 4NH3(aq) Cu(NH3)4+2(aq) Keq =
Ni+2(aq) + 6NH3(aq) Ni(NH3)6+2(aq) Keq =
Mary J. Bojan Chem 110 15
Meaning of Keq
Is Keq large or small???
Reactants Products
PbI2(s) Pb+2(aq) + 2I– (aq)
Keq = reactants
reactants products
products
Mary J. Bojan Chem 110 16
More Relationships
What is Keq if the reaction is doubled??
2HI(g) H2(g) + I2(g) C
Keq =
What is Keq for the reverse reaction?
2H2(g) + 2 I2(g) 4HI(g) B
Keq =
Keq =
H2(g) + I2(g) 2HI(g) A
Mary J. Bojan Chem 110 17
At a certain temperature, Kc for the following
reaction is 16.
H2(g) + I2(g) 2 HI(g)
HI(g) ½ H2(g) + ½ I2(g)
At the same temperature, what is Kc for this reaction?
1. 1/16
2. 4
3. 1/4
4. 16
5. there is not enough information to answer this
question.
Mary J. Bojan Chem 110 18
General Approach to Equilibrium Constant
Problems
1. Write the balanced reaction.
2. Write the general form for Keq.
3. Set up a data table:
(may need algebraic unknowns)
initial conditions
changes in concentrations
equilibrium concentrations
4. Substitute equilibrium concentrations into the
expression for Keq and solve.
Mary J. Bojan Chem 110 19
Equilibrium problem solving: calculating Keq
1.00 mole of SO2(g) and 1.00 mole of O2(g) are added to a 1.00 L
container and react until equilibrium is achieved. At equilibrium,
the container has 0.919 moles of SO3(g).
Find Kc at 1000K.
Mary J. Bojan Chem 110 20
Equilibrium problem solving: calculating Keq
A one L container holds 224g of Fe and 5.00 mole of
H2O(). It is heated to 1000K and reaches equilibrium.
56g of Fe are left unreacted. What is Kc at 1000K?
3Fe(s) + 4H2O(g) Fe3O4(s) + 4H2(g)
I. initial
C. change
E. equilibrium
Mary J. Bojan Chem 110 21
The reaction quotient Q can be used to
predicting the direction of a reaction.
Note: the concentrations used are NOT equilibrium
concentrations.
Reaction quotient Q
aA + bB cC + dD
Q =C[ ]
cD[ ]
d
A[ ]a
B[ ]b
Mary J. Bojan Chem 110 22
We use Q to predict the direction of a
reaction.
When Q < Kc
reaction moves to right (produces product)
When Q > Kc
reaction moves to left (produces reactant)
When Q = Kc system IS at equilibrium
Q < K Q = K Q > K
K K K
Q
Q
Q
Mary J. Bojan Chem 110 23
2HI(g) H2(g) + I2(g)
If we put 0.1 mole of HI in a 1L container, what will
happen?
1 reaction shifts to right
2 reaction shifts to left
3 no change occurs
Kc =H2[ ] I2[ ]HI[ ]
2 =1.25 ´10-3
If the initial concentrations of all three gases in the
vessel are 0.1 mol/L, what will happen?
Mary J. Bojan Chem 110 24
We can use Keq to obtain equilibrium concentrations
of reactants and products.
Initially [IBr] = [I2] = [Br2] = 0.0500 M
What are the final concentrations of reactants and products? Kc = 2.50 10−3
2IBr(g) Br2(g) + I2(g)
I.
C.
E.
Mary J. Bojan Chem 110 25
The Haber process is the
industrial process used to make ammonia
N2(g) + 3H2(g) 2NH3(g) + heat
Mary J. Bojan Chem 110 26
Factors that affect equilibrium
What happens to a system at equilibrium when it is
disturbed by changing
concentration
volume
pressure
temperature
Answer: Le Chatelier’s Principle
If a system at equilibrium is disturbed, the system will shift
its equilibrium position to minimize the effect of the
disturbance.
Mary J. Bojan Chem 110 27
Le Chatelier’s Principle: To illustrate this principle
use the following chemical system in a closed 1L
container.
Hrxn = 92.4kJ/mol T = 700C
Initial conditions:
[N2] = 3.00 M [H2] = 4.50 M [NH3] = 0
At equilibrium:
[N2] = 2.00M [H2] = 1.50 M [NH3] = 1.41 M
What is Kc?
N2(g) + 3H2(g) 2NH3(g) + heat
Mary J. Bojan Chem 110 28
Use LeChatelier’s principle to answer the
following questions
1. What will happen to [NH3] if 3.0 moles of H2 are
added to the system at equilibrium?
Increase the amount of a reactant or product
2. What will happen if the volume decreases from 1.0L
to 0.5L?
Increase P by decreasing volume
3. What will happen if 5.0 moles of inert gas is added
to the system?
Increase pressure by adding an inert gas.
4. What will happen if the temperature is increased to
1000K?
Mary J. Bojan Chem 110 29
1. What will happen to [NH3] if 3.0 moles of H2 are
added to the system at equilibrium?
System is no longer at equilibrium.
Which direction will it go to get to equilibrium?
N2(g) + 3H2(g) 2NH3(g) + heat
Using LeChatelier’s principle:
Reactant or product added to a mixture at equilibrium will cause
reaction to shift in the direction that consumes part of the added
material.
Mary J. Bojan Chem 110 30
2. Which direction will the reaction proceed if the
volume is decreased to 0.5L?
RTPsoVasV
n][][,][
LeChatelier’s principle:
Since pressure is increased by disturbance, reaction
will shift in direction that will reduce pressure
N2(g) + 3H2(g)
4 moles
2NH3(g)
2 moles
Mary J. Bojan Chem 110 31
3. What happens when 5.0 moles of an inert gas are
added?
Inert gas: gas that does not participate in the reaction.
How does an inert gas effect the concentrations of
reactants and products?
LeChatelier’s principle:
N2(g) + 3H2(g)
4 moles
2NH3(g)
2 moles
Mary J. Bojan Chem 110 32
Examples
Yellow colorless red
N2O2(g)
colorless
Fe+3(aq) + SCN– (aq) FeSCN+2(aq)
Change concentration
Change pressure
2NO2(g)
brown
Mary J. Bojan Chem 110 33
changing concentration (or V so that [ ] changes) puts a
stress on the system.
Stresses do not change Keq!
Q changes; system shifts to re-establish equilibrium
Q K
Summary
WHAT IF TEMPERATURE CHANGES? • Keq changes
• change depends on whether the reaction is
exothermic or endothermic.
H +H
Mary J. Bojan Chem 110
34
4. What happens when the temperature is increased to
1000K?
Treat heat like a product (exothermic) or reactant (endothermic).
Hrxn = −92.4 kJ/mol
N2(g) + 3H2(g) 2NH3(g) + heat
Le Chatelier’s Principle:
heat is added to a system, the reaction will shift in the
direction that absorbs heat
Reaction is exothermic (heat is a product) so adding heat
will cause reaction to shift to left.
Mary J. Bojan Chem 110 35
4. What happens when the temperature is decreased?
heat + Co[H2O]62+ (aq) + 4Cl−(aq) CoCl4
2− (aq)+ 6H2O()
pink blue
Treat heat like a product (exothermic)
or reactant (endothermic).
Example: endothermic reaction
Mary J. Bojan Chem 110 36
Summarize N2(g) + 3H2(g) 2NH3(g) + heat
Problem: rate of reaction increases as T increases, BUT equilibrium
constant decreases at higher T.
To produce ammonia:
Do we want high or low temperature?
Do we want high or low pressure?
Liquefy ammonia as process
proceeds. WHY?