11
© Boardworks Ltd 2010 1 of 14 Graphs parabolas by Graphs parabolas by calculating strategic calculating strategic points points

Graphs parabolas by calculating strategic points

Embed Size (px)

DESCRIPTION

Graphs parabolas by calculating strategic points. Strategic points to calculate. Establish orientation of parabola Axis of Symmetry Vertex Roots y- intercept If you do not have 5 points substitute a value for x and calculate the corresponding y. Parabolas. y = ax 2 + bx + c - PowerPoint PPT Presentation

Citation preview

© Boardworks Ltd 20101 of 14

Graphs parabolas by Graphs parabolas by

calculating strategic pointscalculating strategic points

© Boardworks Ltd 20102 of 14

Strategic points to calculate

• Establish orientation of parabola

• Axis of Symmetry

• Vertex

• Roots

• y- intercept

• If you do not have 5 points substitute a value for x and calculate the corresponding y

© Boardworks Ltd 20103 of 14

Parabolas

y = ax2 + bx + c

When the coefficient of x2 is positive the graph is -shaped.

When the coefficient of x2 is negative the graph is -shaped.

© Boardworks Ltd 20104 of 14

Graphs of the form y = ax2 + bx + c

© Boardworks Ltd 20105 of 14

Parabolas

The axis of symmetry is a vertical lineThe equation of a the axis of symmetry is EC

The vertex is located on the axis of symmetry – it has a x-coordinate of Find the y-coordinate by plugging in for x

Parabolas have a vertical axis of symmetry …

…and a turning point called the vertex.

a

bx

2

a

b

2

a

b

2

© Boardworks Ltd 20106 of 14

Sketching graphs of quadratic functions

y = 2x2 – 5x – 3 c = – 3

The parabola crosses the y-axis at the point (0, –3).

The quadratic function y = ax2 + bx + c will cross the y-axis at the point (0, c).

The quadratic function y = ax2 + bx + c will cross the y-axis at the point (0, c).

Sketch the graph of the function y = x2 – 2x – 3.

Axis of symmetry: Vertex

1

)1(2

)2(2

x

x

a

bx

)4,1(

41

3)1(2)1(1 2

yandx

yandx

© Boardworks Ltd 20107 of 14

Sketching graphs of quadratic functions

When a quadratic function factors we can use its factored form to find where it crosses the x-axis. For example:

Sketch the graph of the function y = x2 – 2x – 3.

The function crosses the x-axis when y = 0.

x2 – 2x – 3 = 0

(x + 1)(x – 3) = 0

x + 1 = 0 or x – 3 = 0

x = 3

The function crosses the x-axis at the points (–1, 0) and (3, 0).

x = –1

© Boardworks Ltd 20108 of 14

Sketching graphs of quadratic functions

0

y

x

(–1, 0) (3, 0)

(0, –3)

(1, –4)

We can now sketch the graph.

• Establish orientation of parabola: open up

• Axis of Symmetry x=1• Vertex (1,-4)• y- intercept y=-3• Roots x=-1 or x=3

© Boardworks Ltd 20109 of 14

Sketching graphs of quadratic functions

When a quadratic function is written in the form y = a(x – p)(x – q), it is called

factored form and p and q are the roots of the quadratic function.

When a quadratic function is written in the form y = a(x – p)(x – q), it is called

factored form and p and q are the roots of the quadratic function.

In general:

© Boardworks Ltd 201010 of 14

Graphs of the form y = a(x – p)(x – q)

© Boardworks Ltd 201011 of 14

You try

• Find

a)Establish orientation of parabola

b)Axis of Symmetry

c)Vertex

d)Roots

e)y- intercept

Then graph the parabola

443 2 xxy