8/17/2019 Ground Beam
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FERENCE EQUATIONS OUTPU
ACI 318-05
Length of Beam = ft.Initial Depth,h = in.Intial
Width,b = in.
Assumed Bar Size = in.Cover = in.
in. Fc'= psi.
Fy = psi.9.3.2.1 Reduction Factor,Φ =
H, depth below Gr.lvl= ft.Service Surcharge =
lb/ft2
Average soil wt.= lb/ft3
Wu= k/ft
Mu=[ W l2
/8] M = k-ft
Rn=M /Φ bd2 R = 181.33
ρ=0.85Fc'/Fy[1-√(1-2Rn/0.85Fc')] ρ= 0.0031
p in= 0.0033
h=14 in. d=10 in.
REQUIRED STRENGTH:
REINFORCEMENT RATIO:
PROJECT NAME:
DATE: April 1 stt 2016
TITLE: GROUND BEAM DESIGN
GROUND BEAM DESIGN
Depth to Reinforcment, d =
Calculations & Formulas
8/17/2019 Ground Beam
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FERENCE EQUATIONS OUTPU
PROJECT NAME:
DATE: April 1 stt 2016
TITLE: GROUND BEAM DESIGN
Calculations & Formulas
As=ρ bd As= 0.396 in2
0.3068 in
2
2 - 5/8 Bars
Checking Section For Ductility Requirements :
ρ= As/bd ρ= 0.0051
10.3.4 ρ ax= 0.0181 > ρ > ρ in=
a=Asf /0.85f c'b a= 0.45 in
9.3.2.1 ΦMn=Asfy[d-(a/2)] ΦMn= 26.992 kip-ft > 16.32
kip-ft
3/8 in.0.11 in2
11.3.1.1 ϕVc= 2√fc' [bd] Φ Vc= 1.04 kips
11.5.6.1 1/2ΦVc= 0.52 kips
Vu 4.08 kips
11.5.7.2 Vs= [Vu-ϕVc]/ϕ Vs= 4.05 kips
11.5.7.2 s= Asfy/[0.75√Fc bw] s= 32.69 in.
11.5.6.3 s=Avfyd/Vs s= 23.29 in.
11.5.6.3 s= Av/fy/50b s= 22.09 in.
11.5.5.1 ϕVc= 4√fc' [bd] ΦVc= 30.36 kips
Maximum ,s =d/2 = 5 in.
Use s= in.
Tie Reinforcement =As/bar =
SELECTING REINFORCING STEEL:
TRAVERSE REINFORCEMENT :
Okay,Section isDuctile0.0033
As/bar=
No. Of Bars Required = No. Of Bars Used =
Maximum Spacing to provide minimum Av:
8/17/2019 Ground Beam
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REVISION:
FERENCE EQUATIONS OUTPU
PROJECT NAME:
DATE: April 1 stt 2016
TITLE: GROUND BEAM DESIGN
Calculations & Formulas
5/8 bars3/8 @ 6in. c/c spacing
Number Of bars = Size of bars = in.
Depth ToReinforcment = in.
Cover = in.Tie Reinforcement = in.
Traverse Spacing = in.
3/8 stirrups @ 6in. spacing
h=14 in. d=10 in.
b=12 in.
SUMMARY:
