76
Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for Computer Age - Ch. 1 of Unit 1 ) (Principles of Symmetry, Dynamics, and Spectroscopy - Sec. 1-2 of Ch. 1 ) Review:“Abstraction” of bra and ket vectors from a Transformation Matrix Introducing scalar and matrix products Planck's energy and N-quanta (Cavity/Beam wave mode) Did Max Planck Goof? What’s 1-photon worth? Feynman amplitude axiom 1 What comes out of a beam sorter channel or branch-b? Sample calculations Feynman amplitude axioms 2-3 Beam analyzers: Sorter-unsorters The “Do-Nothing” analyzer Feynman amplitude axiom 4 Some “Do-Something” analyzers Sorter-counter, Filter, 1/2-wave plate, 1/4-wave plate http://www.uark.edu/ua/modphys/pdfs/QTCA_Pdfs/QTCA_Text_2013/QTCA_Unit_7_Ch._22_2005.pdf http://www.uark.edu/ua/pirelli/php/light_energy_flux_1.php See also 2005 site: http://www.uark.edu/ua/pirelli/php/amplitude_probability_1.php http://www.uark.edu/ua/modphys/pdfs/QTCA_Pdfs/QTCA_Text_2013/QTCA_Unit_1_Ch._1_2013.pdf 1 Thursday, January 15, 2015

Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

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Page 1: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Group Theory in Quantum MechanicsLecture 2 (1.15.15)

Quantum amplitudes, analyzers, and axioms (Quantum Theory for Computer Age - Ch. 1 of Unit 1 )

(Principles of Symmetry, Dynamics, and Spectroscopy - Sec. 1-2 of Ch. 1 )

Review:“Abstraction” of bra and ket vectors from a Transformation Matrix Introducing scalar and matrix productsPlanck's energy and N-quanta (Cavity/Beam wave mode) Did Max Planck Goof? What’s 1-photon worth? Feynman amplitude axiom 1What comes out of a beam sorter channel or branch-b? Sample calculations Feynman amplitude axioms 2-3Beam analyzers: Sorter-unsorters The “Do-Nothing” analyzer Feynman amplitude axiom 4 Some “Do-Something” analyzers Sorter-counter, Filter, 1/2-wave plate, 1/4-wave plate

http://www.uark.edu/ua/modphys/pdfs/QTCA_Pdfs/QTCA_Text_2013/QTCA_Unit_7_Ch._22_2005.pdf

http://www.uark.edu/ua/pirelli/php/light_energy_flux_1.phpSee also 2005 site:

http://www.uark.edu/ua/pirelli/php/amplitude_probability_1.php

http://www.uark.edu/ua/modphys/pdfs/QTCA_Pdfs/QTCA_Text_2013/QTCA_Unit_1_Ch._1_2013.pdf

1Thursday, January 15, 2015

Page 2: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Review:“Abstraction” of bra and ket vectors from a Transformation Matrix Introducing scalar and matrix productsPlanck's energy and N-quanta (Cavity/Beam wave mode) Did Max Planck Goof? What’s 1-photon worth? Feynman amplitude axiom 1What comes out of a beam sorter channel or branch-b? Sample calculations Feynman amplitude axioms 2-3Beam analyzers: Sorter-unsorters The “Do-Nothing” analyzer Feynman amplitude axiom 4 Some “Do-Something” analyzers Sorter-counter, Filter, 1/2-wave plate, 1/4-wave plate

2Thursday, January 15, 2015

Page 3: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

x x ' x y '

y x ' y y '

⎝⎜⎜

⎠⎟⎟= cosθ −sinθ

sinθ cosθ⎛

⎝⎜⎞

⎠⎟

“Abstraction” of bra and ket vectors from a Transformation MatrixKet or column vectors Bra or row vectors

GivenTransformationMatrix Tm,n′ :

3Thursday, January 15, 2015

Page 4: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Abstracting ket ⏐ n′〉 state vectors from

Transformation Matrix Tm,n′=〈m⏐ n′〉

x x ' x y '

y x ' y y '

⎝⎜⎜

⎠⎟⎟= cosθ −sinθ

sinθ cosθ⎛

⎝⎜⎞

⎠⎟

⇓ ⇓

x ' =x x '

y x '

⎝⎜⎜

⎠⎟⎟= cosθ

sinθ⎛

⎝⎜⎞

⎠⎟

“Abstraction” of bra and ket vectors from a Transformation MatrixKet or column vectors Bra or row vectors

GivenTransformationMatrix Tm,n′ :

4Thursday, January 15, 2015

Page 5: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Abstracting ket ⏐ n′〉 state vectors from

Transformation Matrix Tm,n′=〈m⏐ n′〉

-sin θ

sin θ

〈x′⏐

〈x⏐

〈y⏐

〈y′⏐

cos θ

θ

θ cos θ

Abstracting bra 〈m⏐ state vectorsfrom

Transformation Matrix Tm,n′=〈m⏐ n′〉

x x ' x y '

y x ' y y '

⎝⎜⎜

⎠⎟⎟= cosθ −sinθ

sinθ cosθ⎛

⎝⎜⎞

⎠⎟

⇓ ⇓ ⇓ ⇓

x ' =x x '

y x '

⎝⎜⎜

⎠⎟⎟= cosθ

sinθ⎛

⎝⎜⎞

⎠⎟ , y ' =

x y '

y y '

⎝⎜⎜

⎠⎟⎟= −sinθ

cosθ⎛

⎝⎜⎞

⎠⎟

⇒ x = x x ' x y '( ) = cosθ −sinθ( )

x ' = x x x ' + y y x '

= x cosθ( ) + y sinθ( )

“Abstraction” of bra and ket vectors from a Transformation MatrixKet or column vectors Bra or row vectors

cos θ

sin θ

⏐x〉

⏐y〉

⏐x′〉

⏐y′〉

θ

θ

-sin θ

cos θ

y ' = x x y ' + y y y '

= x −sinθ( ) + y cosθ( )

y = y x ' x ' + y y ' y '

= sinθ( ) x ' + cosθ( ) y '

x = x x ' x ' + x y ' y '

= cosθ( ) x ' + −sinθ( ) y '

(θ=+30°)-Rotated kets {⏐x′〉,⏐y′〉} or {x′, y′} represented in page-aligned {⏐x〉, ⏐y〉} basis.

⇒ y = y x ' y y '( ) = sinθ cosθ( )

(θ=-30°)-Rotated bras {〈x⏐, 〈y⏐} or {x, y} represented in page-aligned {⏐x′〉,⏐y′〉} basis.

x ' = x x x ' + y y x ' = x cosθ( ) + y sinθ( )y ' = x x y ' + y y y ' = x −sinθ( ) + y cosθ( )

x = x x ' x ' + x y ' y ' = cosθ( ) x ' + −sinθ( ) y '

y = y x ' x ' + y y ' y ' = sinθ( ) x ' + cosθ( ) y '

GivenTransformationMatrix Tm,n′ :

Ket vector algebra has the order of Tm,n′ transposed Bra vector algebra has the same order as Tm,n′

5Thursday, January 15, 2015

Page 6: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Review:“Abstraction” of bra and ket vectors from a Transformation Matrix Introducing scalar and matrix productsPlanck's energy and N-quanta (Cavity/Beam wave mode) Did Max Planck Goof? What’s 1-photon worth? Feynman amplitude axiom 1What comes out of a beam sorter channel or branch-b? Sample calculations Feynman amplitude axioms 2-3Beam analyzers: Sorter-unsorters The “Do-Nothing” analyzer Feynman amplitude axiom 4 Some “Do-Something” analyzers Sorter-counter, Filter, 1/2-wave plate, 1/4-wave plate

6Thursday, January 15, 2015

Page 7: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

x x ' x y '

y x ' y y '

⎝⎜⎜

⎠⎟⎟= cosθ −sinθ

sinθ cosθ⎛

⎝⎜⎞

⎠⎟=

x • x'( ) x • y'( )y• x'( ) y• y'( )

⎝⎜⎜

⎠⎟⎟

Transformation matrix Tm,n′=〈m⏐ n′〉 is array of dot or scalar products (dot products) of unit vectors or direction cosines.

Ψ = x x Ψ + y y Ψ = x ' x ' Ψ + y ' y ' Ψ

Any state ⏐Ψ〉 can be expanded in any basis {〈x⏐,〈y⏐}, or {〈x′⏐,〈y′⏐}, ...etc.

x Ψ

y Ψ

⎝⎜⎜

⎠⎟⎟=

x x ' x y '

y x ' y y '

⎝⎜⎜

⎠⎟⎟

x ' Ψ

y ' Ψ

⎝⎜⎜

⎠⎟⎟

or: Ψx

Ψ y

⎝⎜⎜

⎠⎟⎟=

x x ' x y '

y x ' y y '

⎝⎜⎜

⎠⎟⎟

Ψx '

Ψ y '

⎝⎜⎜

⎠⎟⎟

Transformation matrix Tm,n′ relates {〈x⏐Ψ〉,〈 y⏐Ψ〉} amplitudes to {〈x′⏐Ψ〉,〈 y′⏐Ψ〉} .

Hybrid Gibbs-Diracnotation(Ug-ly!)

Proof: 〈x⏐=〈x⏐x′〉〈x′⏐+〈x⏐ y′〉〈 y′⏐ implies: 〈x⏐Ψ〉=〈x⏐x′〉〈x′⏐Ψ〉 +〈x⏐ y′〉〈 y′⏐Ψ〉 Proof: 〈 y⏐=〈 y⏐x′〉〈x′⏐+〈 y⏐ y′〉〈 y′⏐ implies: 〈 y⏐Ψ〉=〈 y⏐x′〉〈x′⏐Ψ〉+〈 y⏐ y′〉〈 y′⏐Ψ〉

⏐x〉

⏐y〉

⏐x′〉

⏐y′〉

θ

θ

⏐Ψ〉

〈y⏐Ψ〉

〈x⏐Ψ〉

⏐x〉

⏐y〉

⏐x′〉

⏐y′〉

θ

θ

⏐Ψ〉〈

y′⏐Ψ〉

〈 x′⏐Ψ〉

{〈x⏐,〈y⏐}components

of ⏐Ψ〉: 〈x⏐Ψ〉=Ψx

〈y⏐Ψ〉=Ψy

{〈x′⏐,〈y′⏐}components

of ⏐Ψ〉: 〈x′⏐Ψ〉=Ψx′

〈y′⏐Ψ〉=Ψy′

〈x⏐Ψ〉

7Thursday, January 15, 2015

Page 8: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

x x ' x y '

y x ' y y '

⎝⎜⎜

⎠⎟⎟= cosθ −sinθ

sinθ cosθ⎛

⎝⎜⎞

⎠⎟=

x • x'( ) x • y'( )y• x'( ) y• y'( )

⎝⎜⎜

⎠⎟⎟

Transformation matrix Tm,n′=〈m⏐ n′〉 is array of dot or scalar products (dot products) of unit vectors or direction cosines.

Ψ = x x Ψ + y y Ψ = x ' x ' Ψ + y ' y ' Ψ

Any state ⏐Ψ〉 can be expanded in any basis {〈x⏐,〈y⏐}, or {〈x′⏐,〈y′⏐}, ...etc.

x Ψ

y Ψ

⎝⎜⎜

⎠⎟⎟=

x x ' x y '

y x ' y y '

⎝⎜⎜

⎠⎟⎟

x ' Ψ

y ' Ψ

⎝⎜⎜

⎠⎟⎟

or: Ψx

Ψ y

⎝⎜⎜

⎠⎟⎟=

x x ' x y '

y x ' y y '

⎝⎜⎜

⎠⎟⎟

Ψx '

Ψ y '

⎝⎜⎜

⎠⎟⎟

Transformation matrix Tm,n′ relates {〈x⏐Ψ〉,〈y⏐Ψ〉} amplitudes to {〈x′⏐Ψ〉,〈y′⏐Ψ〉} .

Hybrid Gibbs-Diracnotation(Ug-ly!)

x ' Ψ

y ' Ψ

⎝⎜⎜

⎠⎟⎟=

x ' x x ' y

y ' x y ' y

⎝⎜⎜

⎠⎟⎟

x Ψ

y Ψ

⎝⎜⎜

⎠⎟⎟

or: Ψx '

Ψ y '

⎝⎜⎜

⎠⎟⎟=

x ' x x ' y

y ' x y ' y

⎝⎜⎜

⎠⎟⎟

Ψx

Ψ y

⎝⎜⎜

⎠⎟⎟

Inverse (†=T*=-1) matrix T n′,m relates {〈 x′⏐Ψ〉,〈 y′⏐Ψ〉} amplitudes to {〈x⏐Ψ〉,〈y⏐Ψ〉} .

Hybrid Gibbs-Diracnotation(Still Ug-ly!)

⏐x〉

⏐y〉

⏐x′〉

⏐y′〉

θ

θ

⏐Ψ〉〈

y′⏐Ψ〉

〈 x′⏐Ψ〉

{〈x′⏐,〈y′⏐}components

of ⏐Ψ〉: 〈x′⏐Ψ〉=Ψx′

〈y′⏐Ψ〉=Ψy′

⏐x〉

⏐y〉

⏐x′〉

⏐y′〉

θ

θ

⏐Ψ〉

〈y⏐Ψ〉

〈x⏐Ψ〉{〈x⏐,〈y⏐}components

of ⏐Ψ〉: 〈x⏐Ψ〉=Ψx

〈y⏐Ψ〉=Ψy

〈x⏐Ψ〉

8Thursday, January 15, 2015

Page 9: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Review:“Abstraction” of bra and ket vectors from a Transformation Matrix Introducing scalar and matrix productsPlanck's energy and N-quanta (Cavity/Beam wave mode) Did Max Planck Goof? What’s 1-photon worth? Feynman amplitude axiom 1What comes out of a beam sorter channel or branch-b? Sample calculations Feynman amplitude axioms 2-3Beam analyzers: Sorter-unsorters The “Do-Nothing” analyzer Feynman amplitude axiom 4 Some “Do-Something” analyzers Sorter-counter, Filter, 1/2-wave plate, 1/4-wave plate

9Thursday, January 15, 2015

Page 10: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Planck's energy and N-quanta (Cavity/Beam of volume V with wave mode of frequency ω=2πν)Planck axiom: E-field energy density U in cavity/beam mode-ω is: U=Nω/V =Nhν/V (N “photons”)

h=2π=6.6310-34Js Planck constant

http://www.uark.edu/ua/modphys/pdfs/QTCA_Pdfs/QTCA_Text_2013/QTCA_Unit_7_Ch._22_2005.pdfhttp://www.uark.edu/ua/modphys/pdfs/QTCA_Pdfs/QTCA_Text_2013/QTCA_Unit_1_Ch._1_2013.pdf

10Thursday, January 15, 2015

Page 11: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Planck's energy and N-quanta (Cavity/Beam of volume V with wave mode of frequency ω=2πν)Planck axiom: E-field energy density U in cavity/beam mode-ω is: U=Nω/V =Nhν/V (N “photons”)

x-polarized light

y-polarized light

x'-polarized lightθ

θ

x-counts~| 〈x|x'〉|2 = cos2 θ

y-counts~| 〈y|x'〉|2 = sin2 θ

x-photoncounter

y-photoncounter

Fig. 1.2.3 Photon x-y photon counting x'-state

h=2π=6.63·10-34Js Planck constant

x-axis

x′-ax

isx-axisx′-ax

is

Quantum Theory for the Computer Age - URL is "http://www.uark.edu/ua/modphys/markup/QTCAWeb.html"11Thursday, January 15, 2015

Page 12: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Planck's energy and N-quanta (Cavity/Beam of volume V with wave mode of frequency ω=2πν)Planck axiom: E-field energy density U in cavity/beam mode-ω is: U=Nω/V =Nhν/V (N “photons”)

E-field vector (Ex, Ey) = f·(Ψx, Ψy) where quantum field proportionality constant is f .

h=2π=6.63·10-34Js Planck constant

x-polarized light

y-polarized light

x'-polarized lightθ

θ

x-counts~| 〈x|x'〉|2 = cos2 θ

y-counts~| 〈y|x'〉|2 = sin2 θ

x-photoncounter

y-photoncounter

Fig. 1.2.3 Photon x-y photon counting x'-state

x-axis

x′-ax

isx-axisx′-ax

is

12Thursday, January 15, 2015

Page 13: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Planck's energy and N-quanta (Cavity/Beam of volume V with wave mode of frequency ω=2πν)Planck axiom: E-field energy density U in cavity/beam mode-ω is: U=Nω/V =Nhν/V (N “photons”)

Ex

Ey

⎝⎜⎜

⎠⎟⎟=

Ex (0)eikz−iω t

Ey (0)eikz−iω t

⎜⎜

⎟⎟ ≅

Ex (0)e−iω t

Ey (0)e−iω t

⎜⎜

⎟⎟ = f

Ψx

Ψ y

⎝⎜⎜

⎠⎟⎟

E-field vector (Ex, Ey) = f·(Ψx, Ψy) where quantum field proportionality constant is f .

h=2π=6.63·10-34Js Planck constant

x-polarized light

y-polarized light

x'-polarized lightθ

θ

x-counts~| 〈x|x'〉|2 = cos2 θ

y-counts~| 〈y|x'〉|2 = sin2 θ

x-photoncounter

y-photoncounter

Fig. 1.2.3 Photon x-y photon counting x'-state

x-axis

x′-ax

isx-axisx′-ax

is

13Thursday, January 15, 2015

Page 14: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Planck's energy and N-quanta (Cavity/Beam of volume V with wave mode of frequency ω=2πν)Planck axiom: E-field energy density U in cavity/beam mode-ω is: U=Nω/V =Nhν/V (N “photons”)

Ex

Ey

⎝⎜⎜

⎠⎟⎟=

Ex (0)eikz−iω t

Ey (0)eikz−iω t

⎜⎜

⎟⎟ ≅

Ex (0)e−iω t

Ey (0)e−iω t

⎜⎜

⎟⎟ = f

Ψx

Ψ y

⎝⎜⎜

⎠⎟⎟

E-field vector (Ex, Ey) = f·(Ψx, Ψy) where quantum field proportionality constant is f = f(,ω,V, ε0).

h=2π=6.626 075·10-34Js Planck constantc =2.997 924 58·108 ms-1 Light speed ε0 =8.854·10-12C2N-1m-2Electrostatic constant

N = Ψx

2+ Ψ y

2= x Ψ

* x Ψ + y Ψ* y Ψ

x-polarized light

y-polarized light

x'-polarized lightθ

θ

x-counts~| 〈x|x'〉|2 = cos2 θ

y-counts~| 〈y|x'〉|2 = sin2 θ

x-photoncounter

y-photoncounter

Fig. 1.2.3 Photon x-y photon counting x'-state

Coulomb constant: k =1/4πε0Ψ-amplitude-squares sum to exciton-number N. (...or photon-number N) = 9·109 J/CQuantum

em wavetheory

x-axis

x′-ax

is

x-axis

x′-ax

is

14Thursday, January 15, 2015

Page 15: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Planck's energy and N-quanta (Cavity/Beam of volume V with wave mode of frequency ω=2πν)Planck axiom: E-field energy density U in cavity/beam mode-ω is: U=Nω/V =Nhν/V (N “photons”)

Ex

Ey

⎝⎜⎜

⎠⎟⎟=

Ex (0)eikz−iω t

Ey (0)eikz−iω t

⎜⎜

⎟⎟ ≅

Ex (0)e−iω t

Ey (0)e−iω t

⎜⎜

⎟⎟ = f

Ψx

Ψ y

⎝⎜⎜

⎠⎟⎟

E-field vector (Ex, Ey) = f·(Ψx, Ψy) where quantum field proportionality constant is f = f(,ω,V, ε0).

Poynting energy flux S(J/m2s) or energy density U(J/m3) of light beam.

S = cU , where: U = ε0 Ex

2+ Ey

2⎛⎝⎜

⎞⎠⎟= ε0 Ex

*Ex + Ey*Ey( ) = ε0 Ex (0)2 + Ey (0)2( )

N = Ψx

2+ Ψ y

2= x Ψ

* x Ψ + y Ψ* y Ψ

x-polarized light

y-polarized light

x'-polarized lightθ

θ

x-counts~| 〈x|x'〉|2 = cos2 θ

y-counts~| 〈y|x'〉|2 = sin2 θ

x-photoncounter

y-photoncounter

Fig. 1.2.3 Photon x-y photon counting x'-state

Coulomb constant: k =1/4πε0Ψ-amplitude-squares sum to exciton-number N. (...or photon-number N) = 9·109 J/C

Classicalem wavetheory

Quantumem wavetheory

x-axis

x′-ax

is

x-axisx′-ax

is

h=2π=6.626 075·10-34Js Planck constantc =2.997 924 58·108 ms-1 Light speed ε0 =8.854·10-12C2N-1m-2Electrostatic constant

http://www.uark.edu/ua/pirelli/php/light_energy_flux_1.phpSee also 2005 site:

http://www.uark.edu/ua/pirelli/php/amplitude_probability_1.php

15Thursday, January 15, 2015

Page 16: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Planck's energy and N-quanta (Cavity/Beam of volume V with wave mode of frequency ω=2πν)Planck axiom: E-field energy density U in cavity/beam mode-ω is: U=Nω/V =Nhν/V (N “photons”)

Ex

Ey

⎝⎜⎜

⎠⎟⎟=

Ex (0)eikz−iω t

Ey (0)eikz−iω t

⎜⎜

⎟⎟ ≅

Ex (0)e−iω t

Ey (0)e−iω t

⎜⎜

⎟⎟ = f

Ψx

Ψ y

⎝⎜⎜

⎠⎟⎟

E-field vector (Ex, Ey) = f·(Ψx, Ψy) where quantum field proportionality constant is f = f(,ω,V, ε0).

Poynting energy flux S(J/m2s) or energy density U(J/m3) of light beam.

S = cU , where: U = ε0 Ex

2+ Ey

2⎛⎝⎜

⎞⎠⎟= ε0 Ex

*Ex + Ey*Ey( ) = ε0 Ex (0)2 + Ey (0)2( )

Equate U to Planck's N-“photon” quantum energy density Nω/V

N = Ψx

2+ Ψ y

2= x Ψ

* x Ψ + y Ψ* y Ψ

x-polarized light

y-polarized light

x'-polarized lightθ

θ

x-counts~| 〈x|x'〉|2 = cos2 θ

y-counts~| 〈y|x'〉|2 = sin2 θ

x-photoncounter

y-photoncounter

Fig. 1.2.3 Photon x-y photon counting x'-state

Coulomb constant: k =1/4πε0Ψ-amplitude-squares sum to exciton-number N. (...or photon-number N) = 9·109 J/C

Classicalem wavetheory

Quantumem wavetheory

x-axis

x′-ax

is

x-axisx′-ax

is

h=2π=6.626 075·10-34Js Planck constantc =2.997 924 58·108 ms-1 Light speed ε0 =8.854·10-12C2N-1m-2Electrostatic constant

16Thursday, January 15, 2015

Page 17: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Planck's energy and N-quanta (Cavity/Beam of volume V with wave mode of frequency ω=2πν)Planck axiom: E-field energy density U in cavity/beam mode-ω is: U=Nω/V =Nhν/V (N “photons”)

Ex

Ey

⎝⎜⎜

⎠⎟⎟=

Ex (0)eikz−iω t

Ey (0)eikz−iω t

⎜⎜

⎟⎟ ≅

Ex (0)e−iω t

Ey (0)e−iω t

⎜⎜

⎟⎟ = f

Ψx

Ψ y

⎝⎜⎜

⎠⎟⎟

E-field vector (Ex, Ey) = f·(Ψx, Ψy) where quantum field proportionality constant is f = f(,ω,V, ε0).

Poynting energy flux S(J/m2s) or energy density U(J/m3) of light beam.

S = cU , where: U = ε0 Ex

2+ Ey

2⎛⎝⎜

⎞⎠⎟= ε0 Ex

*Ex + Ey*Ey( ) = ε0 Ex (0)2 + Ey (0)2( )

NωV

=U = ε0 Ex2+ Ey

2⎛⎝⎜

⎞⎠⎟= ε0 f 2 Ψx

2+ Ψ y

2⎛⎝⎜

⎞⎠⎟

Equate U to Planck's N-“photon” quantum energy density Nω/V

N = Ψx

2+ Ψ y

2= x Ψ

* x Ψ + y Ψ* y Ψ

x-polarized light

y-polarized light

x'-polarized lightθ

θ

x-counts~| 〈x|x'〉|2 = cos2 θ

y-counts~| 〈y|x'〉|2 = sin2 θ

x-photoncounter

y-photoncounter

Fig. 1.2.3 Photon x-y photon counting x'-state

Coulomb constant: k =1/4πε0Ψ-amplitude-squares sum to exciton-number N. (...or photon-number N) = 9·109 J/C

N

Classicalem wavetheory

Quantumem wavetheory

x-axis

x′-ax

is

x-axisx′-ax

is

h=2π=6.626 075·10-34Js Planck constantc =2.997 924 58·108 ms-1 Light speed ε0 =8.854·10-12C2N-1m-2Electrostatic constant

17Thursday, January 15, 2015

Page 18: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Planck's energy and N-quanta (Cavity/Beam of volume V with wave mode of frequency ω=2πν)Planck axiom: E-field energy density U in cavity/beam mode-ω is: U=Nω/V =Nhν/V (N “photons”)

Ex

Ey

⎝⎜⎜

⎠⎟⎟=

Ex (0)eikz−iω t

Ey (0)eikz−iω t

⎜⎜

⎟⎟ ≅

Ex (0)e−iω t

Ey (0)e−iω t

⎜⎜

⎟⎟ = f

Ψx

Ψ y

⎝⎜⎜

⎠⎟⎟

E-field vector (Ex, Ey) = f·(Ψx, Ψy) where quantum field proportionality constant is f = f(,ω,V, ε0).

Poynting energy flux S(J/m2s) or energy density U(J/m3) of light beam.

S = cU , where: U = ε0 Ex

2+ Ey

2⎛⎝⎜

⎞⎠⎟= ε0 Ex

*Ex + Ey*Ey( ) = ε0 Ex (0)2 + Ey (0)2( )

NωV

=U = ε0 Ex2+ Ey

2⎛⎝⎜

⎞⎠⎟= ε0 f 2 Ψx

2+ Ψ y

2⎛⎝⎜

⎞⎠⎟

Equate U to Planck's N-“photon” quantum energy density Nω/V

N = U ·Vω

=ε0Vω

Ex2+ Ey

2⎛⎝⎜

⎞⎠⎟=ε0Vω

f 2 Ψx2+ Ψ y

2⎛⎝⎜

⎞⎠⎟

Photon number N for beam is:

N = Ψx

2+ Ψ y

2= x Ψ

* x Ψ + y Ψ* y Ψ

x-polarized light

y-polarized light

x'-polarized lightθ

θ

x-counts~| 〈x|x'〉|2 = cos2 θ

y-counts~| 〈y|x'〉|2 = sin2 θ

x-photoncounter

y-photoncounter

Fig. 1.2.3 Photon x-y photon counting x'-state

Coulomb constant: k =1/4πε0Ψ-amplitude-squares sum to exciton-number N. (...or photon-number N) = 9·109 J/C

N

(divide by N)

Classicalem wavetheory

Quantumem wavetheory

x-axis

x′-ax

is

x-axisx′-ax

is

h=2π=6.626 075·10-34Js Planck constantc =2.997 924 58·108 ms-1 Light speed ε0 =8.854·10-12C2N-1m-2Electrostatic constant

18Thursday, January 15, 2015

Page 19: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Planck's energy and N-quanta (Cavity/Beam of volume V with wave mode of frequency ω=2πν)Planck axiom: E-field energy density U in cavity/beam mode-ω is: U=Nω/V =Nhν/V (N “photons”)

Ex

Ey

⎝⎜⎜

⎠⎟⎟=

Ex (0)eikz−iω t

Ey (0)eikz−iω t

⎜⎜

⎟⎟ ≅

Ex (0)e−iω t

Ey (0)e−iω t

⎜⎜

⎟⎟ = f

Ψx

Ψ y

⎝⎜⎜

⎠⎟⎟

E-field vector (Ex, Ey) = f·(Ψx, Ψy) where quantum field proportionality constant is f = f(,ω,V, ε0).

Poynting energy flux S(J/m2s) or energy density U(J/m3) of light beam.

S = cU , where: U = ε0 Ex

2+ Ey

2⎛⎝⎜

⎞⎠⎟= ε0 Ex

*Ex + Ey*Ey( ) = ε0 Ex (0)2 + Ey (0)2( )

NωV

=U = ε0 Ex2+ Ey

2⎛⎝⎜

⎞⎠⎟= ε0 f 2 Ψx

2+ Ψ y

2⎛⎝⎜

⎞⎠⎟

Equate U to Planck's N-“photon” quantum energy density Nω/V

N = U ·Vω

=ε0Vω

Ex2+ Ey

2⎛⎝⎜

⎞⎠⎟=ε0Vω

f 2 Ψx2+ Ψ y

2⎛⎝⎜

⎞⎠⎟

1= U ·VNω

=ε0VNω

Ex2+ Ey

2⎛⎝⎜

⎞⎠⎟=ε0Vω

f 2

Photon number N for beam is:

N = Ψx

2+ Ψ y

2= x Ψ

* x Ψ + y Ψ* y Ψ

x-polarized light

y-polarized light

x'-polarized lightθ

θ

x-counts~| 〈x|x'〉|2 = cos2 θ

y-counts~| 〈y|x'〉|2 = sin2 θ

x-photoncounter

y-photoncounter

Fig. 1.2.3 Photon x-y photon counting x'-state

Coulomb constant: k =1/4πε0Ψ-amplitude-squares sum to exciton-number N. (...or photon-number N) = 9·109 J/C

N

(divided by N)

Classicalem wavetheory

Quantumem wavetheory

x-axis

x′-ax

is

x-axisx′-ax

is

h=2π=6.626 075·10-34Js Planck constantc =2.997 924 58·108 ms-1 Light speed ε0 =8.854·10-12C2N-1m-2Electrostatic constant

19Thursday, January 15, 2015

Page 20: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Planck's energy and N-quanta (Cavity/Beam of volume V with wave mode of frequency ω=2πν)Planck axiom: E-field energy density U in cavity/beam mode-ω is: U=Nω/V =Nhν/V (N “photons”)

Ex

Ey

⎝⎜⎜

⎠⎟⎟=

Ex (0)eikz−iω t

Ey (0)eikz−iω t

⎜⎜

⎟⎟ ≅

Ex (0)e−iω t

Ey (0)e−iω t

⎜⎜

⎟⎟ = f

Ψx

Ψ y

⎝⎜⎜

⎠⎟⎟

E-field vector (Ex, Ey) = f·(Ψx, Ψy) where quantum field proportionality constant is f = f(,ω,V, ε0).

Poynting energy flux S(J/m2s) or energy density U(J/m3) of light beam.

S = cU , where: U = ε0 Ex

2+ Ey

2⎛⎝⎜

⎞⎠⎟= ε0 Ex

*Ex + Ey*Ey( ) = ε0 Ex (0)2 + Ey (0)2( )

NωV

=U = ε0 Ex2+ Ey

2⎛⎝⎜

⎞⎠⎟= ε0 f 2 Ψx

2+ Ψ y

2⎛⎝⎜

⎞⎠⎟

Equate U to Planck's N-“photon” quantum energy density Nω/V

N = U ·Vω

=ε0Vω

Ex2+ Ey

2⎛⎝⎜

⎞⎠⎟=ε0Vω

f 2 Ψx2+ Ψ y

2⎛⎝⎜

⎞⎠⎟

1= U ·VNω

=ε0VNω

Ex2+ Ey

2⎛⎝⎜

⎞⎠⎟=ε0Vω

f 2

Photon number N for beam is:

f = ω

Vε0

N = Ψx

2+ Ψ y

2= x Ψ

* x Ψ + y Ψ* y Ψ

quantum field constant f

x-polarized light

y-polarized light

x'-polarized lightθ

θ

x-counts~| 〈x|x'〉|2 = cos2 θ

y-counts~| 〈y|x'〉|2 = sin2 θ

x-photoncounter

y-photoncounter

Fig. 1.2.3 Photon x-y photon counting x'-state

Coulomb constant: k =1/4πε0Ψ-amplitude-squares sum to exciton-number N. (...or photon-number N) = 9·109 J/C

N

Classicalem wavetheory

Quantumem wavetheory

(divided by N)

x-axis

x′-ax

is

x-axisx′-ax

is

h=2π=6.626 075·10-34Js Planck constantc =2.997 924 58·108 ms-1 Light speed ε0 =8.854·10-12C2N-1m-2Electrostatic constant

20Thursday, January 15, 2015

Page 21: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Planck's energy and N-quanta (Cavity/Beam of volume V with wave mode of frequency ω=2πν)Planck axiom: E-field energy density U in cavity/beam mode-ω is: U=Nω/V =Nhν/V (N “photons”)

Ex

Ey

⎝⎜⎜

⎠⎟⎟=

Ex (0)eikz−iω t

Ey (0)eikz−iω t

⎜⎜

⎟⎟ ≅

Ex (0)e−iω t

Ey (0)e−iω t

⎜⎜

⎟⎟ = f

Ψx

Ψ y

⎝⎜⎜

⎠⎟⎟

E-field vector (Ex, Ey) = f·(Ψx, Ψy) where quantum field proportionality constant is f = f(,ω,V, ε0).

Poynting energy flux S(J/m2s) or energy density U(J/m3) of light beam.

S = cU , where: U = ε0 Ex

2+ Ey

2⎛⎝⎜

⎞⎠⎟= ε0 Ex

*Ex + Ey*Ey( ) = ε0 Ex (0)2 + Ey (0)2( )

NωV

=U = ε0 Ex2+ Ey

2⎛⎝⎜

⎞⎠⎟= ε0 f 2 Ψx

2+ Ψ y

2⎛⎝⎜

⎞⎠⎟

Equate U to Planck's N-“photon” quantum energy density Nω/V

N = U ·Vω

=ε0Vω

Ex2+ Ey

2⎛⎝⎜

⎞⎠⎟=ε0Vω

f 2 Ψx2+ Ψ y

2⎛⎝⎜

⎞⎠⎟

1= U ·VNω

=ε0VNω

Ex2+ Ey

2⎛⎝⎜

⎞⎠⎟=ε0Vω

f 2

Photon number N for beam is:

f = ω

Vε0 =

Ex2+ Ey

2

N for N -photons

N = Ψx

2+ Ψ y

2= x Ψ

* x Ψ + y Ψ* y Ψ

quantum field constant f

x-polarized light

y-polarized light

x'-polarized lightθ

θ

x-counts~| 〈x|x'〉|2 = cos2 θ

y-counts~| 〈y|x'〉|2 = sin2 θ

x-photoncounter

y-photoncounter

Fig. 1.2.3 Photon x-y photon counting x'-state

Coulomb constant: k =1/4πε0Ψ-amplitude-squares sum to exciton-number N. (...or photon-number N) = 9·109 J/C

N

Classicalem wavetheory

Quantumem wavetheory

(divided by N)

x-axis

x′-ax

is

x-axisx′-ax

is

h=2π=6.626 075·10-34Js Planck constantc =2.997 924 58·108 ms-1 Light speed ε0 =8.854·10-12C2N-1m-2Electrostatic constant

21Thursday, January 15, 2015

Page 22: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Review:“Abstraction” of bra and ket vectors from a Transformation Matrix Introducing scalar and matrix productsPlanck's energy and N-quanta (Cavity/Beam wave mode) Did Max Planck Goof? What’s 1-photon worth? Feynman amplitude axiom 1What comes out of a beam sorter channel or branch-b? Sample calculations Feynman amplitude axioms 2-3Beam analyzers: Sorter-unsorters The “Do-Nothing” analyzer Feynman amplitude axiom 4 Some “Do-Something” analyzers Sorter-counter, Filter, 1/2-wave plate, 1/4-wave plate

22Thursday, January 15, 2015

Page 23: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

E-field energy density U in cavity mode-ω is: U=ωN/V (V=cavity volume) E-field Poynting flux S=cU in beam mode-ω is: S=ωn/σ (σ =beam area)

Planck’s quantum axioms gives field energy and flux that appear to be linear in its frequency ω.

Energy ε for classical harmonic oscillation is quadratic in frequency ω and amplitude A. ε = (const.) ω2A2 = 1/2 m ω2A2

Energy U for classical electromagnetic cavity mode is quadratic in frequency ω and vector potential A. U = ε0 (|Ex|2+|Ey|2) = ε0 |E|2 = ε0 ω2|A|2 where: E =-∂t A =iω A

Did Max Planck Goof? After his 1900 (U=ωN)-axiom paper, Max Planck felt despondent and that his (U=ωN)-axiom was a career-ending goof. Here is one paradox (and its resolution):

Paradox: We know...

But:...

http://www.uark.edu/ua/modphys/pdfs/QTCA_Pdfs/QTCA_Text_2013/QTCA_Unit_7_Ch._22_2005.pdf23Thursday, January 15, 2015

Page 24: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

const.= f = ω

Vε0 =

Ex2+ Ey

2

N=

E

Nfor N -photons

quantum field constant f

E-field energy density U in cavity mode-ω is: U=ωN/V (V=cavity volume) E-field Poynting flux S=cU in beam mode-ω is: S=ωn/σ (σ =beam area)

Planck’s quantum axioms gives field energy and flux that appear to be linear in its frequency ω.

Energy ε for classical harmonic oscillation is quadratic in frequency ω and amplitude A. ε = (const.) ω2A2 = 1/2 m ω2A2

Energy U for classical electromagnetic cavity mode is quadratic in frequency ω and vector potential A. U = ε0 (|Ex|2+|Ey|2) = ε0 |E|2 = ε0 ω2|A|2 where: E =-∂t A =iω A

Did Max Planck Goof? After his 1900 (U=ωN)-axiom paper, Max Planck felt despondent and that his (U=ωN)-axiom was a career-ending goof. Here is one paradox (and its resolution):

Paradox: We know...

But:...

Quick Resolution:Given constant (N=1)-quantum field factor f, squared |E|= f√N is linear in ω: |E|2= f 2N= ωN/Vε0

ε0|E|2= ωN/V = Uε0 ω2|A|2 = ωN/V

24Thursday, January 15, 2015

Page 25: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

const.= f = ω

Vε0 =

Ex2+ Ey

2

N=

E

Nfor N -photons

quantum field constant f

E-field energy density U in cavity mode-ω is: U=ωN/V (V=cavity volume) E-field Poynting flux S=cU in beam mode-ω is: S=ωn/σ (σ =beam area)

Planck’s quantum axioms gives field energy and flux that appear to be linear in its frequency ω.

Energy ε for classical harmonic oscillation is quadratic in frequency ω and amplitude A. ε = (const.) ω2A2 = 1/2 m ω2A2

Energy U for classical electromagnetic cavity mode is quadratic in frequency ω and vector potential A. U = ε0 (|Ex|2+|Ey|2) = ε0 |E|2 = ε0 ω2|A|2 where: E =-∂t A =iω A

Did Max Planck Goof? After his 1900 (U=ωN)-axiom paper, Max Planck felt despondent and that his (U=ωN)-axiom was a career-ending goof. Here is one paradox (and its resolution):

Paradox: We know...

But:...

Quick Resolution:Given constant (N=1)-quantum field factor f, squared |E|= f√N is linear in ω: |E|2= f 2N= ωN/Vε0

ε0|E|2= ωN/V = Uε0 ω2|A|2 = ωN/V

Formal Resolution:Harmonic Oscillator Hamiltonian : H = (p2+ω 2x2 )/2

H = ω

2 a† · a + a · a†( )

factors into : H = ω

2( ωx−ip / ω )

2( ωx+ip / ω )

2+ω

2( ωx+ip / ω )

2( ωx−ip / ω )

2

25Thursday, January 15, 2015

Page 26: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

const.= f = ω

Vε0 =

Ex2+ Ey

2

N=

E

Nfor N -photons

quantum field constant f

E-field energy density U in cavity mode-ω is: U=ωN/V (V=cavity volume) E-field Poynting flux S=cU in beam mode-ω is: S=ωn/σ (σ =beam area)

Planck’s quantum axioms gives field energy and flux that appear to be linear in its frequency ω.

Energy ε for classical harmonic oscillation is quadratic in frequency ω and amplitude A. ε = (const.) ω2A2 = 1/2 m ω2A2

Energy U for classical electromagnetic cavity mode is quadratic in frequency ω and vector potential A. U = ε0 (|Ex|2+|Ey|2) = ε0 |E|2 = ε0 ω2|A|2 where: E =-∂t A =iω A

Did Max Planck Goof? After his 1900 (U=ωN)-axiom paper, Max Planck felt despondent and that his (U=ωN)-axiom was a career-ending goof. Here is one paradox (and its resolution):

Paradox: We know...

But:...

Quick Resolution:Given constant (N=1)-quantum field factor f, squared |E|= f√N is linear in ω: |E|2= f 2N= ωN/Vε0

ε0|E|2= ωN/V = Uε0 ω2|A|2 = ωN/V

Formal Resolution:Harmonic Oscillator Hamiltonian : H = (p2+ω 2x2 )/2

H = ω

2 a† · a + a · a†( ) = ω a†a+2

1⋅1( ) factors into : H = ω

2( ωx−ip / ω )

2( ωx+ip / ω )

2+ω

2( ωx+ip / ω )

2( ωx−ip / ω )

2 aa†=a†a+1( )

26Thursday, January 15, 2015

Page 27: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

const.= f = ω

Vε0 =

Ex2+ Ey

2

N=

E

Nfor N -photons

quantum field constant f

E-field energy density U in cavity mode-ω is: U=ωN/V (V=cavity volume) E-field Poynting flux S=cU in beam mode-ω is: S=ωn/σ (σ =beam area)

Planck’s quantum axioms gives field energy and flux that appear to be linear in its frequency ω.

Energy ε for classical harmonic oscillation is quadratic in frequency ω and amplitude A. ε = (const.) ω2A2 = 1/2 m ω2A2

Energy U for classical electromagnetic cavity mode is quadratic in frequency ω and vector potential A. U = ε0 (|Ex|2+|Ey|2) = ε0 |E|2 = ε0 ω2|A|2 where: E =-∂t A =iω A

Did Max Planck Goof? After his 1900 (U=ωN)-axiom paper, Max Planck felt despondent and that his (U=ωN)-axiom was a career-ending goof. Here is one paradox (and its resolution):

Paradox: We know...

But:...

Quick Resolution:Given constant (N=1)-quantum field factor f, squared |E|= f√N is linear in ω: |E|2= f 2N= ωN/Vε0

ε0|E|2= ωN/V = Uε0 ω2|A|2 = ωN/V

Formal Resolution:Harmonic Oscillator Hamiltonian : H = (p2+ω 2x2 )/2

H = ω

2 a† · a + a · a†( ) = ω a†a+2

1⋅1( ) factors into : H = ω

2( ωx−ip / ω )

2( ωx+ip / ω )

2+ω

2( ωx+ip / ω )

2( ωx−ip / ω )

2

H.O. quantum energy eigenvalues: ωN = ω(N +1/2)

aa†=a†a+1( )

27Thursday, January 15, 2015

Page 28: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Review:“Abstraction” of bra and ket vectors from a Transformation Matrix Introducing scalar and matrix productsPlanck's energy and N-quanta (Cavity/Beam wave mode) Did Max Planck Goof? What’s 1-photon worth? Feynman amplitude axiom 1What comes out of a beam sorter channel or branch-b? Sample calculations Feynman amplitude axioms 2-3Beam analyzers: Sorter-unsorters The “Do-Nothing” analyzer Feynman amplitude axiom 4 Some “Do-Something” analyzers Sorter-counter, Filter, 1/2-wave plate, 1/4-wave plate

28Thursday, January 15, 2015

Page 29: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

const.= f = ωVε0

=Ex

2+ Ey

2

N=

E

Nfor N -photonsquantum field

constant f

E-field energy density U in cavity mode-ω is: U=ωN/V (V=cavity volume) E-field Poynting flux S=cU in beam mode-ω is: S=ωn/σ (σ =beam area)

Planck’s quantum axioms gives field energy and flux that appear to be linear in its frequency ω.

Energy ε for classical harmonic oscillation is quadratic in frequency ω and amplitude A. ε = (const.) ω2A2 = 1/2 m ω2A2

Energy U for classical electromagnetic cavity mode is quadratic in frequency ω and vector potential A. U = ε0 (|Ex|2+|Ey|2) = ε0 |E|2 = ε0 ω2|A|2 where: E =-∂t A =iω A

What’s a photon worth? What field is there for N=1 in a cavity of energy (U=ωN) ? or n=1 in a beam of Poynting flux (S=ωn/σ)?

Classical:

Quantum:

Quantum field:Given constant (N=1)-quantum field factor f, squared |E|= f√N is linear in ω: |E|2= f 2N= ωN/Vε0

ε0|E|2= ωN/V = Uε0 ω2|A|2 = ωN/V

H.O. quantum energy eigenvalues: ωN = ω(N +1/2)

Example: V=(1/4micron)3 cubic cavity fundamental (1/2-wave for 600THz green) with N=106 photons

h=2π=6.626 075·10-34Js c =2.997 924 58·108 ms-1 ε0 =8.854·10-12C2N-1m-2

c =2.99 792 458·108 ms-1 ε0=8.842·10-12C2N-1m2 e=1.602 177·10-19Coul

29Thursday, January 15, 2015

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const.= f = ωVε0

=Ex

2+ Ey

2

N=

E

Nfor N -photons

= Ex2+ Ey

2= E for 1-photon

quantum field constant f

E-field energy density U in cavity mode-ω is: U=ωN/V (V=cavity volume) E-field Poynting flux S=cU in beam mode-ω is: S=ωn/σ (σ =beam area)

Planck’s quantum axioms gives field energy and flux that appear to be linear in its frequency ω.

Energy ε for classical harmonic oscillation is quadratic in frequency ω and amplitude A. ε = (const.) ω2A2 = 1/2 m ω2A2

Energy U for classical electromagnetic cavity mode is quadratic in frequency ω and vector potential A. U = ε0 (|Ex|2+|Ey|2) = ε0 |E|2 = ε0 ω2|A|2 where: E =-∂t A =iω A

What’s a photon worth? What field is there for N=1 in a cavity of energy (U=ωN) ? or n=1 in a beam of Poynting flux (S=ωn/σ)?

Classical:

Quantum:

Quantum field:Given constant (N=1)-quantum field factor f, squared |E|= f√N is linear in ω: |E|2= f 2N= ωN/Vε0

ε0|E|2= ωN/V = Uε0 ω2|A|2 = ωN/V

H.O. quantum energy eigenvalues: ωN = ω(N +1/2)

Example: V=(1/4micron)3 cubic cavity fundamental (1/2-wave for 600THz green) with N=106 photons

c =2.99 792 458·108 ms-1 ε0=8.842·10-12C2N-1m2 e=1.602 177·10-19Coul

h=2π=6.626 075·10-34Js c =2.997 924 58·108 ms-1 ε0 =8.854·10-12C2N-1m-2

30Thursday, January 15, 2015

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E-field energy density U in cavity mode-ω is: U=ωN/V (V=cavity volume) E-field Poynting flux S=cU in beam mode-ω is: S=ωn/σ (σ =beam area)

Planck’s quantum axioms gives field energy and flux that appear to be linear in its frequency ω.

Energy ε for classical harmonic oscillation is quadratic in frequency ω and amplitude A. ε = (const.) ω2A2 = 1/2 m ω2A2

Energy U for classical electromagnetic cavity mode is quadratic in frequency ω and vector potential A. U = ε0 (|Ex|2+|Ey|2) = ε0 |E|2 = ε0 ω2|A|2 where: E =-∂t A =iω A

What’s a photon worth? What field is there for N=1 in a cavity of energy (U=ωN) ? or n=1 in a beam of Poynting flux (S=ωn/σ)?

Classical:

Quantum:

Quantum field:Given constant (N=1)-quantum field factor f, squared |E|= f√N is linear in ω: |E|2= f 2N= ωN/Vε0

H.O. quantum energy eigenvalues: ωN = ω(N +1/2)

Example: V=(1/4micron)3 cubic cavity fundamental (1/2-wave for 600THz green) with N=106 photons Energy per N=1 photon = hυ=6.63·10-34Js·600·10 12/s =4.0·10-19J=2.5eV

c =2.99 792 458·108 ms-1 ε0=8.842·10-12C2N-1m2 e=1.602 177·10-19Coul

const.= f = ωVε0

=Ex

2+ Ey

2

N=

E

Nfor N -photons

= Ex2+ Ey

2= E for 1-photon

quantum field constant f

ε0|E|2= ωN/V = Uε0 ω2|A|2 = ωN/V

h=2π=6.626 075·10-34Js c =2.997 924 58·108 ms-1 ε0 =8.854·10-12C2N-1m-2

31Thursday, January 15, 2015

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E-field energy density U in cavity mode-ω is: U=ωN/V (V=cavity volume) E-field Poynting flux S=cU in beam mode-ω is: S=ωn/σ (σ =beam area)

Planck’s quantum axioms gives field energy and flux that appear to be linear in its frequency ω.

Energy ε for classical harmonic oscillation is quadratic in frequency ω and amplitude A. ε = (const.) ω2A2 = 1/2 m ω2A2

Energy U for classical electromagnetic cavity mode is quadratic in frequency ω and vector potential A. U = ε0 (|Ex|2+|Ey|2) = ε0 |E|2 = ε0 ω2|A|2 where: E =-∂t A =iω A

What’s a photon worth? What field is there for N=1 in a cavity of energy (U=ωN) ? or n=1 in a beam of Poynting flux (S=ωn/σ)?

Classical:

Quantum:

Quantum field:Given constant (N=1)-quantum field factor f, squared |E|= f√N is linear in ω: |E|2= f 2N= ωN/Vε0

H.O. quantum energy eigenvalues: ωN = ω(N +1/2)

Example: V=(1/4micron)3 cubic cavity fundamental (1/2-wave for 600THz green) with N=106 photons Energy per N=1 photon = hυ=6.63·10-34Js·600·10 12/s =4.0·10-19J=2.5eV E-field for N=1 photon =|E|=√(hυ/Vε0)=1.7·10 6Volts/m

c =2.99 792 458·108 ms-1 ε0=8.842·10-12C2N-1m2 e=1.602 177·10-19Coul

const.= f = ωVε0

=Ex

2+ Ey

2

N=

E

Nfor N -photons

= Ex2+ Ey

2= E for 1-photon

quantum field constant f

ε0|E|2= ωN/V = Uε0 ω2|A|2 = ωN/V

h=2π=6.626 075·10-34Js c =2.997 924 58·108 ms-1 ε0 =8.854·10-12C2N-1m-2

32Thursday, January 15, 2015

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E-field energy density U in cavity mode-ω is: U=ωN/V (V=cavity volume) E-field Poynting flux S=cU in beam mode-ω is: S=ωn/σ (σ =beam area)

Planck’s quantum axioms gives field energy and flux that appear to be linear in its frequency ω.

Energy ε for classical harmonic oscillation is quadratic in frequency ω and amplitude A. ε = (const.) ω2A2 = 1/2 m ω2A2

Energy U for classical electromagnetic cavity mode is quadratic in frequency ω and vector potential A. U = ε0 (|Ex|2+|Ey|2) = ε0 |E|2 = ε0 ω2|A|2 where: E =-∂t A =iω A

What’s a photon worth? What field is there for N=1 in a cavity of energy (U=ωN) ? or n=1 in a beam of Poynting flux (S=ωn/σ)?

Classical:

Quantum:

Quantum field:Given constant (N=1)-quantum field factor f, squared |E|= f√N is linear in ω: |E|2= f 2N= ωN/Vε0

H.O. quantum energy eigenvalues: ωN = ω(N +1/2)

Example: V=(1/4micron)3 cubic cavity fundamental (1/2-wave for 600THz green) with N=106 photons Energy per N=1 photon = hυ=6.63·10-34Js·600·10 12/s =4.0·10-19J=2.5eV E-field for N=1 photon =|E|=√(hυ/Vε0)=1.7·106Volts/m Energy per N=106 photons =106 hυ=1066.63·10-34Js·600·10 12/s =4.0·10-13J=2.5MeV

c =2.99 792 458·108 ms-1 ε0=8.842·10-12C2N-1m2 e=1.602 177·10-19Coul

const.= f = ωVε0

=Ex

2+ Ey

2

N=

E

Nfor N -photons

= Ex2+ Ey

2= E for 1-photon

quantum field constant f

ε0|E|2= ωN/V = Uε0 ω2|A|2 = ωN/V

h=2π=6.626 075·10-34Js c =2.997 924 58·108 ms-1 ε0 =8.854187817·10-12C2N-1m-2

33Thursday, January 15, 2015

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Was Planck’s linear-in-frequency-υ energy axiom a Goof ?

Not at all. It’s really not linear-in-frequency after all.

The ε0 |E|2 =h N·υ axiom IS in fact a product of TWO frequencies!

The 2nd “frequency” is COUNT RATE N.

As shown later: Both frequencies transform by Relativistic Doppler factor e±ρ: Coherent frequency is light quality: υ′= e±ρ υ. Incoherent frequency is light quantity: N ′=e±ρ N.

This would imply that the |E|-field also transforms like a frequency: |E| ′ = =e±ρ |E|.

Indeed, E-field amplitude is a frequency, too!

34Thursday, January 15, 2015

Page 35: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Review:“Abstraction” of bra and ket vectors from a Transformation Matrix Introducing scalar and matrix productsPlanck's energy and N-quanta (Cavity/Beam wave mode) Did Max Planck Goof? What’s 1-photon worth? Feynman amplitude axiom 1What comes out of a beam sorter channel or branch-b? Sample calculations Feynman amplitude axioms 2-3Beam analyzers: Sorter-unsorters The “Do-Nothing” analyzer Feynman amplitude axiom 4 Some “Do-Something” analyzers Sorter-counter, Filter, 1/2-wave plate, 1/4-wave plate

35Thursday, January 15, 2015

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Feynman amplitude axiom 1 Feynman-Dirac Interpretation of

〈j⏐k′ 〉=Amplitude of state-j afterstate-k′ is forced to choose

from available m-type states

(1) The probability axiomThe first axiom deals with physical interpretation of amplitudes . Axiom 1: The absolute square gives probability for occurrence in state-j of a system that started in state-k'=1',2',..,or n' from one sorter and then was forced to choose between states j=1,2,...,n by another sorter.

j k '

2= j k ' * j k '

j k '

36Thursday, January 15, 2015

Page 37: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

β-tiltedspin-dn beam(blocked)

spin-up ↑electroncounter mz

mzN

S

β

β

↑-counts~| 〈↑| '〉|2 = cos2 β/2=cos2θ

↓-counts~| 〈↓| '〉|2 = sin2 β/2= sin2θ

spin-dn ↓electroncounter

β-tiltedspin-up'-beam

β=2θ

electron spinvector Stilted byβ=2θ

is analogous to:polarizationvector Etilted byθ=β/2

θ

β

θ θ

Fig. 1.2.4 Electron up-dn-spin counting of a tilted spin-up (↑′)-state

Amplitude axioms apply to all intensity-conserving systemsThis includes, first of all, spin-1/2 electron, proton,…,13C,… particles (Fermions)

∧probability

37Thursday, January 15, 2015

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β-tiltedspin-dn beam(blocked)

spin-up ↑electroncounter mz

mzN

S

β

β

↑-counts~| 〈↑| '〉|2 = cos2 β/2=cos2θ

↓-counts~| 〈↓| '〉|2 = sin2 β/2= sin2θ

spin-dn ↓electroncounter

β-tiltedspin-up'-beam

β=2θ

electron spinvector Stilted byβ=2θ

is analogous to:polarizationvector Etilted byθ=β/2

θ

β

θ θ

Fig. 1.2.4 Electron up-dn-spin counting of a tilted spin-up (↑′)-state

Amplitude axioms apply to all intensity-conserving systemsThis includes, first of all, spin-1/2 electron, proton,…,13C,… particles (Fermions)

∧probability

38Thursday, January 15, 2015

Page 39: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

β-tiltedspin-dn beam(blocked)

spin-up ↑electroncounter mz

mzN

S

β

β

↑-counts~| 〈↑| '〉|2 = cos2 β/2=cos2θ

↓-counts~| 〈↓| '〉|2 = sin2 β/2= sin2θ

spin-dn ↓electroncounter

β-tiltedspin-up'-beam

β=2θ

electron spinvector Stilted byβ=2θ

is analogous to:polarizationvector Etilted byθ=β/2

θ

β

θ θ

Fig. 1.2.4 Electron up-dn-spin counting of a tilted spin-up (↑′)-state

Amplitude axioms apply to all intensity-conserving systemsThis includes, first of all, spin-1/2 electron, proton,…,13C,… particles (Fermions)

∧probability

39Thursday, January 15, 2015

Page 40: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

β-tiltedspin-dn beam(blocked)

spin-up ↑electroncounter mz

mzN

S

β

β

↑-counts~| 〈↑| '〉|2 = cos2 β/2=cos2θ

↓-counts~| 〈↓| '〉|2 = sin2 β/2= sin2θ

spin-dn ↓electroncounter

β-tiltedspin-up'-beam

β=2θ

electron spinvector Stilted byβ=2θ

is analogous to:polarizationvector Etilted byθ=β/2

θ

β

θ θ

Fig. 1.2.4 Electron up-dn-spin counting of a tilted spin-up (↑′)-state

Amplitude axioms apply to all intensity-conserving systemsThis includes, first of all, spin-1/2 electron, proton,…,13C,… particles (Fermions)

⏐x〉

⏐y〉

θ

⏐Ψ〉〈y⏐Ψ〉

〈x⏐Ψ〉

∧probability

=E/f

40Thursday, January 15, 2015

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〈↑⏐Ψ〉

β-tiltedspin-dn beam(blocked)

spin-up ↑electroncounter mz

mzN

S

β

β

↑-counts~| 〈↑| '〉|2 = cos2 β/2=cos2θ

↓-counts~| 〈↓| '〉|2 = sin2 β/2= sin2θ

spin-dn ↓electroncounter

β-tiltedspin-up'-beam

β=2θ

electron spinvector Stilted byβ=2θ

is analogous to:polarizationvector Etilted byθ=β/2

θ

β

θ θ

Fig. 1.2.4 Electron up-dn-spin counting of a tilted spin-up (↑′)-state

Amplitude axioms apply to all intensity-conserving systemsThis includes, first of all, spin-1/2 electron, proton,…,13C,… particles (Fermions)

⏐x〉

⏐y〉

θ

⏐Ψ〉〈y⏐Ψ〉

〈x⏐Ψ〉

⏐↑〉

⏐↓〉

β/2

⏐Ψ〉〈↓⏐Ψ〉

∧probability

=E/f

spin-“up”

spin-“dn”

41Thursday, January 15, 2015

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〈↑⏐Ψ〉

β-tiltedspin-dn beam(blocked)

spin-up ↑electroncounter mz

mzN

S

β

β

↑-counts~| 〈↑| '〉|2 = cos2 β/2=cos2θ

↓-counts~| 〈↓| '〉|2 = sin2 β/2= sin2θ

spin-dn ↓electroncounter

β-tiltedspin-up'-beam

β=2θ

electron spinvector Stilted byβ=2θ

is analogous to:polarizationvector Etilted byθ=β/2

θ

β

θ θ

Fig. 1.2.4 Electron up-dn-spin counting of a tilted spin-up (↑′)-state

Amplitude axioms apply to all intensity-conserving systemsThis includes, first of all, spin-1/2 electron, proton,…,13C,… particles (Fermions)

⏐x〉

⏐y〉

θ

⏐Ψ〉〈y⏐Ψ〉

〈x⏐Ψ〉

⏐↑〉

⏐↓〉

β/2

⏐Ψ〉〈↓⏐Ψ〉

∧probability

=E/f

spin-“up”

spin-“dn”

x-polarization

y-po

lari

zatio

n

When “down” isonly 90° from “up”… ...that’s U(2) space!

42Thursday, January 15, 2015

Page 43: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Review:“Abstraction” of bra and ket vectors from a Transformation Matrix Introducing scalar and matrix productsPlanck's energy and N-quanta (Cavity/Beam wave mode) Did Max Planck Goof? What’s 1-photon worth? Feynman amplitude axiom 1What comes out of a beam sorter channel or branch-b? Sample calculations Feynman amplitude axioms 2-3Beam analyzers: Sorter-unsorters The “Do-Nothing” analyzer Feynman amplitude axiom 4 Some “Do-Something” analyzers Sorter-counter, Filter, 1/2-wave plate, 1/4-wave plate

43Thursday, January 15, 2015

Page 44: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

x-polarized light

y-polarized light

x'-polarized light

y'-polarized light

θ=30°

x-polarized light

θ=30°

Q:What comes out of an analyzer channel or branch-b? A: Want to determine or calculate: its base state |b〉, its amplitude 〈b|Ψ〉, and its probability |〈b|Ψ〉|2 using T-matrices

x-axis

x′-ax

is

x-axis

x′-ax

is

http://www.uark.edu/ua/modphys/pdfs/QTCA_Pdfs/QTCA_Text_2013/QTCA_Unit_1_Ch._1_2013.pdf

44Thursday, January 15, 2015

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x-polarized light

y-polarized light

x'-polarized light

y'-polarized light

θ=30°

x-polarized light

θ=30°

〈x'|x〉 〈x'|y〉

〈y'|x〉 〈y'|y〉√3/2 1/2-1/2 √3/2

=

〈x|x'〉 〈x|y'〉

〈y|x'〉 〈y|y'〉√3/2 -1/21/2 √3/2

=

Q:What comes out of an analyzer channel or branch-b? A: Want to determine or calculate: its base state |b〉, its amplitude 〈b|Ψ〉, and its probability |〈b|Ψ〉|2 using T-matrices

x-axis

x′-ax

is

x-axis

x′-ax

is

45Thursday, January 15, 2015

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x-polarized light

y-polarized light

x'-polarized light

y'-polarized light

θ=30°

x-polarized light

θ=30°

|x〉Amplitude=

1.0Probability=

1.0

BaseState

〈x'|x〉 〈x'|y〉

〈y'|x〉 〈y'|y〉√3/2 1/2-1/2 √3/2

=

〈x|x'〉 〈x|y'〉

〈y|x'〉 〈y|y'〉√3/2 -1/21/2 √3/2

=

Q:What comes out of an analyzer channel or branch-b? A: Want to determine or calculate: its base state |b〉, its amplitude 〈b|Ψ〉, and its probability |〈b|Ψ〉|2 using T-matrices

x-axis

x′-ax

is

x-axis

x′-ax

is

46Thursday, January 15, 2015

Page 47: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

Q:What comes out of an analyzer channel or branch-b? A: Want to determine or calculate: its base state |b〉, its amplitude 〈b|Ψ〉, and its probability |〈b|Ψ〉|2 using T-matrices

x-polarized light

y-polarized light

x'-polarized light

y'-polarized light

θ=30°

x-polarized light

θ=30°

|x〉Amplitude=

1.0Probability=

1.0

BaseState

|x'〉〈x'|x〉

BaseState

Amplitude=√3/2=0.867

Probability=0.75

〈x'|x〉 〈x'|y〉

〈y'|x〉 〈y'|y〉√3/2 1/2-1/2 √3/2

=

〈x|x'〉 〈x|y'〉

〈y|x'〉 〈y|y'〉√3/2 -1/21/2 √3/2

=

x-axis

x′-ax

is

x-axis

x′-ax

is

47Thursday, January 15, 2015

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x-polarized light

y-polarized light

x'-polarized light

y'-polarized light

θ=30°

x-polarized light

θ=30°

|x〉Amplitude=

1.0Probability=

1.0

BaseState

|x'〉〈x'|x〉

BaseState

Amplitude=√3/2=0.867

Probability=0.75

|y'〉〈y'|x〉Amplitude=

-1/2=-0.500 Probability=

0.25

BaseState

|x〉〈x`|x〉

〈y`|x〉

〈y|

〈x'|x〉 〈x'|y〉

〈y'|x〉 〈y'|y〉√3/2 1/2-1/2 √3/2

=

〈x|x'〉 〈x|y'〉

〈y|x'〉 〈y|y'〉√3/2 -1/21/2 √3/2

=

Q:What comes out of an analyzer channel or branch-b? A: Want to determine or calculate: its base state |b〉, its amplitude 〈b|Ψ〉, and its probability |〈b|Ψ〉|2 using T-matrices

x-axis

x′-ax

is

x-axis

x′-ax

is

48Thursday, January 15, 2015

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x-polarized light

y-polarized light

x'-polarized light

y'-polarized light

θ=30°

x-polarized light

θ=30°

|x〉Amplitude=

1.0Probability=

1.0

BaseState

|x'〉〈x'|x〉

BaseState

Amplitude=√3/2=0.867

Probability=0.75

|y'〉〈y'|x〉Amplitude=

-1/2=-0.500 Probability=

0.25

BaseState

|x〉〈x`|x〉

〈y`|x〉

〈y|

|x〉〈x|x'〉〈x'|x〉BaseState

Amplitude=(√3/2)(√3/2)=0.750

Probability=0.5625

〈x'|x〉 〈x'|y〉

〈y'|x〉 〈y'|y〉√3/2 1/2-1/2 √3/2

=

〈x|x'〉 〈x|y'〉

〈y|x'〉 〈y|y'〉√3/2 -1/21/2 √3/2

=

Q:What comes out of an analyzer channel or branch-b? A: Want to determine or calculate: its base state |b〉, its amplitude 〈b|Ψ〉, and its probability |〈b|Ψ〉|2 using T-matrices

x-axis

x′-ax

is

x-axis

x′-ax

is

49Thursday, January 15, 2015

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x-polarized light

y-polarized light

x'-polarized light

y'-polarized light

θ=30°

x-polarized light

θ=30°

|x〉

|x'〉〈x'|x〉

|y'〉〈y'|x〉

|x〉〈x|x'〉〈x'|x〉

|y〉〈y|x'〉〈x'|x〉

BaseState

Amplitude=1.0

Probability=1.0

Amplitude=√3/2=0.867

Probability=0.75

BaseState

Amplitude=-1/2=-0.500

Probability=0.25

BaseState

BaseState

Amplitude=(√3/2)(√3/2)=0.750

Probability=0.5625

BaseState

Amplitude=(1/2)(√3/2)=0.433

Probability=0.1875

〈x'|x〉 〈x'|y〉

〈y'|x〉 〈y'|y〉√3/2 1/2-1/2 √3/2

=

〈x|x'〉 〈x|y'〉

〈y|x'〉 〈y|y'〉√3/2 -1/21/2 √3/2

=

|x〉〈x`|x〉

〈y`|x〉

|x〉

|x`〉〈y|x`〉

〈x|x`〉

〈y| 〈y|

Q:What comes out of an analyzer channel or branch-b? A: Want to determine or calculate: its base state |b〉, its amplitude 〈b|Ψ〉, and its probability |〈b|Ψ〉|2 using T-matrices

x-axis

x′-ax

is

x-axis

x′-ax

is

50Thursday, January 15, 2015

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|Ψ〉-beam(input)

〈b1|Ψ〉

〈b2|Ψ〉

〈b1|Ψ〉〈c1|b1〉

〈b1|Ψ〉〈c2|b1〉

〈b1|Ψ〉〈c2|b1〉〈d1|c2〉

〈b1|Ψ〉〈c2|b1〉〈d2|c2〉

〈b1|Ψ〉〈c2|b1〉〈d2|c2〉〈e1|d2〉

〈b1|Ψ〉〈c2|b1〉〈d2|c2〉〈e2|d2〉

c

b

d

e

Fig. 1.3.10 Beams-amplitude products for successive beam sorting

ep DoCn Bm Ψ = ep do do cn cn bm bm Ψ

51Thursday, January 15, 2015

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Review:“Abstraction” of bra and ket vectors from a Transformation Matrix Introducing scalar and matrix productsPlanck's energy and N-quanta (Cavity/Beam wave mode) Did Max Planck Goof? What’s 1-photon worth? Feynman amplitude axiom 1What comes out of a beam sorter channel or branch-b? Sample calculations Feynman amplitude axioms 2-3Beam analyzers: Sorter-unsorters The “Do-Nothing” analyzer Feynman amplitude axiom 4 Some “Do-Something” analyzers Sorter-counter, Filter, 1/2-wave plate, 1/4-wave plate

52Thursday, January 15, 2015

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(1) The probability axiomThe first axiom deals with physical interpretation of amplitudes . Axiom 1: The absolute square gives probability for occurrence in state-j of a system that started in state-k'=1',2',..,or n' from one sorter and then was forced to choose between states j=1,2,...,n by another sorter.

Feynman amplitude axiom 1 (Given above p.35 )Feynman-Dirac Interpretation of

〈j⏐k′ 〉=Amplitude of state-j afterstate-k′ is forced to choose

from available m-type states

j k '2= j k ' * j k '

j k '

53Thursday, January 15, 2015

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(1) The probability axiomThe first axiom deals with physical interpretation of amplitudes . Axiom 1: The absolute square gives probability for occurrence in state-j of a system that started in state-k'=1',2',..,or n' from one sorter and then was forced to choose between states j=1,2,...,n by another sorter.

(2) The conjugation or inversion axiom (time reversal symmetry) The second axiom concerns going backwards through a sorter or the reversal of amplitudes. Axiom 2: The complex conjugate of an amplitude equals its reverse:

j k ' *

Feynman amplitude axioms 1-2Feynman-Dirac Interpretation of

〈j⏐k′ 〉=Amplitude of state-j afterstate-k′ is forced to choose

from available m-type states

j k '2= j k ' * j k '

j k '

j k ' *

= k ' j

j k '

54Thursday, January 15, 2015

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(1) The probability axiomThe first axiom deals with physical interpretation of amplitudes . Axiom 1: The absolute square gives probability for occurrence in state-j of a system that started in state-k'=1',2',..,or n' from one sorter and then was forced to choose between states j=1,2,...,n by another sorter.

(3) The orthonormality or identity axiom The third axiom concerns the amplitude for "re measurement" by the same analyzer. Axiom 3: If identical analyzers are used twice or more the amplitude for a passed state-k is one, and for all others it is zero:

(2) The conjugation or inversion axiom (time reversal symmetry) The second axiom concerns going backwards through a sorter or the reversal of amplitudes. Axiom 2: The complex conjugate of an amplitude equals its reverse:

j k ' *

Feynman amplitude axioms 1-3Feynman-Dirac Interpretation of

〈j⏐k′ 〉=Amplitude of state-j afterstate-k′ is forced to choose

from available m-type states

j k '2= j k ' * j k '

j k '

j k ' *

= k ' j

j k '

j k = δ jk =

1 if: j=k0 if: j ≠ k

⎧⎨⎪

⎩⎪

⎫⎬⎪

⎭⎪= j ' k '

55Thursday, January 15, 2015

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Review:“Abstraction” of bra and ket vectors from a Transformation Matrix Introducing scalar and matrix productsPlanck's energy and N-quanta (Cavity/Beam wave mode) Did Max Planck Goof? What’s 1-photon worth? Feynman amplitude axiom 1What comes out of a beam sorter channel or branch-b? Sample calculations Feynman amplitude axioms 2-3Beam analyzers: Sorter-unsorters The “Do-Nothing” analyzer Feynman amplitude axiom 4 Some “Do-Something” analyzers Sorter-counter, Filter, 1/2-wave plate, 1/4-wave plate

56Thursday, January 15, 2015

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Θ

"Sensitive"

RegionInput beam

ΨIN-polarized

x-polarized

y-polarized

Output beam

ΨOUT

-polarized

Fig. 1.3.1 Anatomy of ideal optical polarization analyzer in its “Do nothing” mode

Beam Analyzers: Fundamental Quantum Processes (Sorter-Unsorter pairs)

57Thursday, January 15, 2015

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Θ

"Sensitive"

RegionInput beam

ΨIN-polarized

x-polarized

y-polarized

Output beam

ΨOUT

-polarized

Fig. 1.3.1 Anatomy of ideal optical polarization analyzer in its “Do nothing” mode

Initial polarization angleθinitial=θθ

Final polarization angleθfinal=θ

polarizationunchanged by“Do-Nothing”

analyzerinitial

=2θ

θ xy-analyzer(Θanalyzer=0°)

Fig. 1.3.2 Computer sketch of simulated polarization analyzer in "do-nothing" mode

Beam Analyzers: Fundamental Quantum Processes (Sorter-Unsorter pairs)

58Thursday, January 15, 2015

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Review:“Abstraction” of bra and ket vectors from a Transformation Matrix Introducing scalar and matrix productsPlanck's energy and N-quanta (Cavity/Beam wave mode) Did Max Planck Goof? What’s 1-photon worth? Feynman amplitude axiom 1What comes out of a beam sorter channel or branch-b? Sample calculations Feynman amplitude axioms 2-3Beam analyzers: Sorter-unsorters The “Do-Nothing” analyzer Feynman amplitude axiom 4 Some “Do-Something” analyzers Sorter-counter, Filter, 1/2-wave plate, 1/4-wave plate

59Thursday, January 15, 2015

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(4) The completeness or closure axiomThe fourth axiom concerns the "Do-nothing" property of an ideal analyzer, that is, a sorter followed by an "unsorter" or "put-back-togetherer" as sketched above.Axiom 4. Ideal sorting followed by ideal recombination of amplitudes has no effect:

Beam Analyzers: Fundamental Quantum Processes (Sorter-Unsorter pairs)

Θ

"Sensitive"

RegionInput beam

ΨIN-polarized

x-polarized

y-polarized

Output beam

ΨOUT

-polarized

Fig. 1.3.1 Anatomy of ideal optical polarization analyzer in its “Do nothing” mode

Feynman amplitude axiom 4

j" m ' =

k=1

n∑ j" k k m '

60Thursday, January 15, 2015

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(4) The completeness or closure axiomThe fourth axiom concerns the "Do-nothing" property of an ideal analyzer, that is, a sorter followed by an "unsorter" or "put-back-togetherer" as sketched above.Axiom 4. Ideal sorting followed by ideal recombination of amplitudes has no effect:

Beam Analyzers: Fundamental Quantum Processes (Sorter-Unsorter pairs)

Θ

"Sensitive"

RegionInput beam

ΨIN-polarized

x-polarized

y-polarized

Output beam

ΨOUT

-polarized

Fig. 1.3.1 Anatomy of ideal optical polarization analyzer in its “Do nothing” mode

Feynman amplitude axiom 4

j" m ' =

k=1

n∑ j" k k m '

May use axioms 1-3to prove special case:

1 = m ' m ' by 3

by 1

1=k=1

n∑ k m '

2

by 1

1=k=1

n∑ k m ' * k m '

by 2

k=1

n∑ m ' k k m '

= m ' m '

61Thursday, January 15, 2015

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(1) The probability axiomThe first axiom deals with physical interpretation of amplitudes . Axiom 1: The absolute square gives probability for occurrence in state-j of a system that started in state-k'=1',2',..,or n' from one sorter and then was forced to choose between states j=1,2,...,n by another sorter.

(3) The orthonormality or identity axiom The third axiom concerns the amplitude for "re measurement" by the same analyzer. Axiom 3: If identical analyzers are used twice or more the amplitude for a passed state-k is one, and for all others it is zero:

(2) The conjugation or inversion axiom (time reversal symmetry) The second axiom concerns going backwards through a sorter or the reversal of amplitudes. Axiom 2: The complex conjugate of an amplitude equals its reverse:

j k ' *

Feynman amplitude axioms 1-4Feynman-Dirac Interpretation of

〈j⏐k′ 〉=Amplitude of state-j afterstate-k′ is forced to choose

from available m-type states

j k '2= j k ' * j k '

j k '

j k ' *

= k ' j

j k '

j k = δ jk =

1 if: j=k0 if: j ≠ k

⎧⎨⎪

⎩⎪

⎫⎬⎪

⎭⎪= j ' k '

(4) The completeness or closure axiomThe fourth axiom concerns the "Do-nothing" property of an ideal analyzer, that is, a sorter followed by an "unsorter" or "put-back-togetherer" as sketched above.Axiom 4. Ideal sorting followed by ideal recombination of amplitudes has no effect:

j" m ' =

k=1

n∑ j" k k m '

62Thursday, January 15, 2015

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x'-polarized light

y'-polarized light x'

y

xy'Θout -polarized light

(a)“Do-Nothing”Analyzer

(b)Simulation setting ofinput

polarization2Θin =βin=200°

tilt of analyzer

analyzer activity angle Ω(Ω=0 means do-nothing)

Ω

inputpolarization

Θin =βin/2=100°

Θanalyzer=-30°

Θout =Θin

in

No change if analyzerdoes nothing

analyzerβ

analyzerΘ = -30°

=2Θ

Θin=100°

63Thursday, January 15, 2015

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x'-polarized light

y'-polarized light x'

y

xy'Θout -polarized light

(a)“Do-Nothing”Analyzer

(b)Simulation setting ofinput

polarization2Θin =βin=200°

tilt of analyzer

analyzer activity angle Ω(Ω=0 means do-nothing)

Ω

inputpolarization

Θin =βin/2=100°

Θanalyzer=-30°

Θout =Θin

in

No change if analyzerdoes nothing

analyzerβ

analyzerΘ = -30°

=2Θ

Θin=100°

Imagine final xy-sorter analyzes output beam into x and y-components.

Amplitude in x or y-channel is sum over x' and y'-amplitudes 〈x'|Θin〉=cos(Θin−Θ) 〈y'|Θin〉=sin(Θin−Θ) with relative angle Θin−Θ of Θin to Θ-analyzer axes-(x',y')

64Thursday, January 15, 2015

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x'-polarized light

y'-polarized light x'

y

xy'Θout -polarized light

(a)“Do-Nothing”Analyzer

(b)Simulation setting ofinput

polarization2Θin =βin=200°

tilt of analyzer

analyzer activity angle Ω(Ω=0 means do-nothing)

Ω

inputpolarization

Θin =βin/2=100°

Θanalyzer=-30°

Θout =Θin

in

No change if analyzerdoes nothing

analyzerβ

analyzerΘ = -30°

=2Θ

Θin=100°

Imagine final xy-sorter analyzes output beam into x and y-components.x

y

Amplitude in x or y-channel is sum over x' and y'-amplitudes 〈x'|Θin〉=cos(Θin−Θ) 〈y'|Θin〉=sin(Θin−Θ) with relative angle Θin−Θ of Θin to Θ-analyzer axes-(x',y')in products with final xy-sorter: lab x-axis: 〈x|x'〉 = cosΘ = 〈y|y'〉 y-axis: 〈y|x'〉 = sinΘ = -〈x|y'〉.

x'-polarized light

y'-polarized light x'

y

xy'Θout -polarized light

(a)“Do-Nothing”Analyzer

(b)Simulation setting ofinput

polarization2Θin =βin=200°

tilt of analyzer

analyzer activity angle Ω(Ω=0 means do-nothing)

Ω

inputpolarization

Θin =βin/2=100°

Θanalyzer=-30°

Θout =Θin

in

No change if analyzerdoes nothing

analyzerβ

analyzerΘ = -30°

=2Θ

Θin=100°

65Thursday, January 15, 2015

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x'-polarized light

y'-polarized light x'

y

xy'Θout -polarized light

(a)“Do-Nothing”Analyzer

(b)Simulation setting ofinput

polarization2Θin =βin=200°

tilt of analyzer

analyzer activity angle Ω(Ω=0 means do-nothing)

Ω

inputpolarization

Θin =βin/2=100°

Θanalyzer=-30°

Θout =Θin

in

No change if analyzerdoes nothing

analyzerβ

analyzerΘ = -30°

=2Θ

Θin=100°

Imagine final xy-sorter analyzes output beam into x and y-components.

Amplitude in x or y-channel is sum over x' and y'-amplitudes 〈x'|Θin〉=cos(Θin−Θ) 〈y'|Θin〉=sin(Θin−Θ) with relative angle Θin−Θ of Θin to Θ-analyzer axes-(x',y')in products with final xy-sorter: lab x-axis: 〈x|x'〉 = cosΘ = 〈y|y'〉 y-axis: 〈y|x'〉 = sinΘ = -〈x|y'〉.

x-Output is: 〈x|Θout〉= 〈x|x'〉〈x'|Θin〉+〈x|y'〉〈y'|Θin〉=cosΘcos(Θin-Θ) - sinΘsin(Θin-Θ)=cos Θin y-Output is: 〈y|Θout〉= 〈y|x'〉〈x'|Θin〉+〈y|y'〉〈y'|Θin〉=sinΘcos(Θin-Θ) - cosΘsin(Θin-Θ)=sin Θin. (Recall cos(a+b)=cosa cosb-sina sinb and sin(a+b)=sina cosb+cosa sinb )

66Thursday, January 15, 2015

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x'-polarized light

y'-polarized light x'

y

xy'Θout -polarized light

(a)“Do-Nothing”Analyzer

(b)Simulation setting ofinput

polarization2Θin =βin=200°

tilt of analyzer

analyzer activity angle Ω(Ω=0 means do-nothing)

Ω

inputpolarization

Θin =βin/2=100°

Θanalyzer=-30°

Θout =Θin

in

No change if analyzerdoes nothing

analyzerβ

analyzerΘ = -30°

=2Θ

Θin=100°

Imagine final xy-sorter analyzes output beam into x and y-components.

x-Output is: 〈x|Θout〉= 〈x|x'〉〈x'|Θin〉+〈x|y'〉〈y'|Θin〉=cosΘcos(Θin-Θ) - sinΘsin(Θin-Θ)=cos Θin y-Output is: 〈y|Θout〉= 〈y|x'〉〈x'|Θin〉+〈y|y'〉〈y'|Θin〉=sinΘcos(Θin-Θ) - cosΘsin(Θin-Θ)=sin Θin. (Recall cos(a+b)=cosa cosb-sina sinb and sin(a+b)=sina cosb+cosa sinb )

Amplitude in x or y-channel is sum over x' and y'-amplitudes 〈x'|Θin〉=cos(Θin−Θ) 〈y'|Θin〉=sin(Θin−Θ) with relative angle Θin−Θ of Θin to Θ-analyzer axes-(x',y')in products with final xy-sorter: lab x-axis: 〈x|x'〉 = cosΘ = 〈y|y'〉 y-axis: 〈y|x'〉 = sinΘ = -〈x|y'〉.

Conclusion: 〈x|Θout〉 = cos Θout = cos Θin or: Θout= Θin so “Do-Nothing” Analyzer in fact does nothing.

67Thursday, January 15, 2015

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Review:“Abstraction” of bra and ket vectors from a Transformation Matrix Introducing scalar and matrix productsPlanck's energy and N-quanta (Cavity/Beam wave mode) Did Max Planck Goof? What’s 1-photon worth? Feynman amplitude axiom 1What comes out of a beam sorter channel or branch-b? Sample calculations Feynman amplitude axioms 2-3Beam analyzers: Sorter-unsorters The “Do-Nothing” analyzer Feynman amplitude axiom 4 Some “Do-Something” analyzers Sorter-counter, Filter, 1/2-wave plate, 1/4-wave plate

68Thursday, January 15, 2015

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(1) Optical analyzer in sorter-counter configuration

Initial polarization angleθ=β/2 = 30°

θ

x-counts~| 〈x|x'〉|2= cos2 θ =

y-counts~| 〈y|x'〉|2= sin2 θ=

xy-analyzer( βanalyzer =0°)

Analyzer reduced to a simple sorter-counter by blocking output of x-high-road and y-low-road with counters

Fig. 1.3.3 Simulated polarization analyzer set up as a sorter-counter

69Thursday, January 15, 2015

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(1) Optical analyzer in sorter-counter configuration

Initial polarization angleθ=β/2 = 30°

θ

x-counts~| 〈x|x'〉|2= cos2 θ =

y-counts~| 〈y|x'〉|2= sin2 θ=

xy-analyzer( βanalyzer =0°)

Analyzer reduced to a simple sorter-counter by blocking output of x-high-road and y-low-road with counters

Fig. 1.3.3 Simulated polarization analyzer set up as a sorter-counter

y-output~| 〈y|x'〉|2= sin2 θ=

x-counts~| 〈y|x'〉|2=(Blocked and filtered out)

Initial polarization angleθ=β/2 = 30°

θxy-analyzer( βanalyzer =0°)

Analyzer blocks one path which may have photon counter without affecting function.

(2) Optical analyzer in a filter configuration (Polaroid© sunglasses)

Fig. 1.3.4 Simulated polarization analyzer set up to filter out the x-polarized photons

70Thursday, January 15, 2015

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Review:“Abstraction” of bra and ket vectors from a Transformation Matrix Introducing scalar and matrix productsPlanck's energy and N-quanta (Cavity/Beam wave mode) Did Max Planck Goof? What’s 1-photon worth? Feynman amplitude axiom 1What comes out of a beam sorter channel or branch-b? Sample calculations Feynman amplitude axioms 2-3Beam analyzers: Sorter-unsorters The “Do-Nothing” analyzer Feynman amplitude axiom 4 Some “Do-Something” analyzers Sorter-counter, Filter, 1/2-wave plate, 1/4-wave plate

71Thursday, January 15, 2015

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(3) Optical analyzers in the "control" configuration: Half or Quarter wave plates

θ

Initial polarization angle

θ=β/2 = 30°(a)

Half-wave plate

(Ω=π)Final polarization angle

θ=β/2 = 150°(or -30°)

(b) Quarter-wave

plate

(Ω=π/2)Final polarization is

untilted elliptical

θ

Initial polarization angle

θ=β/2 = 30°

Ω

Ω

Analyzer phase lag

(activity angle)

Analyzer phase lag

(activity angle)

xy-analyzer

(βanalyzer

=0°)

xy-analyzer

(βanalyzer

=0°)

72Thursday, January 15, 2015

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(3) Optical analyzers in the "control" configuration: Half or Quarter wave plates

θ

Initial polarization angle

θ=β/2 = 30°(a)

Half-wave plate

(Ω=π)Final polarization angle

θ=β/2 = 150°(or -30°)

(b) Quarter-wave

plate

(Ω=π/2)Final polarization is

untilted elliptical

θ

Initial polarization angle

θ=β/2 = 30°

Ω

Ω

Analyzer phase lag

(activity angle)

Analyzer phase lag

(activity angle)

xy-analyzer

(βanalyzer

=0°)

xy-analyzer

(βanalyzer

=0°)

Fig. 1.3.5 Polarization control set to shift phase by (a) Half-wave (Ω = π) , (b) Quarter wave (Ω= π/2)

73Thursday, January 15, 2015

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Similar to "do-nothing" analyzer but has extra phase factor e-iΩ = 0.94-i 0.34 on the x'-path .x-output: y-output:

(b)Simulation

x'-polarized light

y'-polarized light

β/2=Θ= -30°

Θin =βin/2=100°plane-polarized light

x'

y

x

y'

Elliptically

polarized light ω=20°phase shift

(a)Analyzer Experiment

Phase shift→ Ω

Output polarization

changed by analyzer

phase shift

setting of

input

polarization

2Θin =βin=200°Θin=100°

Θ=-30°

=2Θanalyzerβ

x Ψout = x ′x e−iΩ ′x Ψin + x ′y ′y Ψin = e−iΩ cosΘcos Θin − Θ( ) − sinΘ sin Θin − Θ( )

y Ψout = y ′x e−iΩ ′x Ψin + y ′y ′y Ψin = e−iΩ sinΘcos Θin − Θ( ) + cosΘ sin Θin − Θ( )

74Thursday, January 15, 2015

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ReΨy

ReΨx

ReΨy

ReΨx-√3/2

1/2

-30°

1/2√3/2

θ=

ω t = 0ω t = 0

ω t = πω t = π

0 12

3

4

5

6

78-7-6

-5

-4

-3

-2-1

01

2

3 4 5

6

78

-7-6

-5

-4-3

-2-1

(2,4)(3,5)(4,6)

(5,7)

(6,8)

(7,-7)

x-position

x-velocity vx/ω(c) 2-D Oscillator

Phasor Plot

(8,-6)(9,-5)

y-velocity

vy/ω

(x-Phase

45° behind the

y-Phase)

y-position

φ counter-clockwise

if y is behind x

clockwise

orbit

if x is behind y

(1,3) Left-

handed

Right-

handed

(0,2)

Fig. 1.3.6 Polarization states for (a) Half-wave (Ω = π) , (b) Quarter wave (Ω= π/2) (c) (Ω=−π/4)

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Page 76: Group Theory in Quantum Mechanics Lecture 2 Quantum ...€¦ · Group Theory in Quantum Mechanics Lecture 2 (1.15.15) Quantum amplitudes, analyzers, and axioms (Quantum Theory for

40Ellipsis in Middle1.3.1 A y-polarized light beam of unit amplitude (1 photon/sec.) enters an active analyzer that is tilted by 30° as shown below. The active analyzer puts a + = 90° phase factor e-i+ in the x' beam.Fill in the blanks with numbers or symbols that tell as much as possible about what is present at each channel or branch.

x-polarized light

y-polarized light

x'-polarized light

y'-polarized light

! = 30°

y-polarized light

y

y

y'

"x'|x# "x'|y#

"y'|x# "y'|y#____ ________ ____

="x|x'# "x|y'#

"y|x'# "y|y'#=

____ ________ ____

|y#1.0

|__#_____State of x' channel

Amplitude= 1.0Probability= 1.0

Amplitude= ___________Probability=___________

State of inputchannel

Amplitude= ___________Probability=___________

Amplitude= ___________Probability=___________

Amplitude= ___________Probability=___________

|__#_____State of y' channel

|__#_________State of output x channel

|__#_________State of output y channel

Probability=___________

__________________State of middle channel

middle channel

Note: The x' and y'quantities will not begraded. Use for work.

© 2013 W.G.Harter Chapter 1 – Amplitudes, Analyzers, and Matrices 1-

40

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