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Hardy-Weinberg Problems. 2450=bald=q 2 2550 =hairy=p 2 +2pq 5000=total. q=.7 p=1-.7=.3. q 2 = 2450 =.49 5000. . . p 2 + 2pq + q 2 = 1 .592+2(.59x.41)+.412=1 .35 + .48 + .17 = 1. p 2 + 2pq + q 2 = 1 32 + 2(.3x.7)+.72=1 .09 + .42 + .49 = 1 - PowerPoint PPT Presentation
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Hardy-Weinberg Problems
.
X
q2 =2450 =.49 5000
2450=bald=q2 2550=hairy=p2+2pq5000=total
q=.7p=1-.7=.3
p2 + 2pq + q2 = 132 + 2(.3x.7)+.72=1.09 + .42 + .49 = 1 9 + 42 + 49 = 10018 H’s 42 h’s42 H’s 60 H’s60 H’s 102 total genes
42 = .41=q 60 =.59=p 102 102
p2 + 2pq + q2 = 1.592+2(.59x.41)+.412=1.35 + .48 + .17 = 1
Hardy-Weinberg Problems #4 6400=smooth tongued=q2
3600=forked tongued=p2+2pq10,000
6400=q2=.6410,000
q2=.64q=.8
1-q=p1-.8=.2p2 + 2pq + q2 = 1
.22+2(.2 X .8) + .82=1
.04 + .32 + .64= 1 FF Ff ff 4 + 32 + 64 = 1
8 F’s 32 f’s32 F’s 40 F’s40 F’s 72 genes
40=.56=p 32=.44=q72 72
p2 + 2pq + q2 = 1.562+2(.56X.44)+.442=1 .31 + .49 + .19 = 1X
a. freq.of F=.2 freq. of f =.8b. .32 Ffc. freq.of F=.56 freq. of f =.44d. FF=.31 Ff =.49 ff =.19
Hardy-Weinberg Problems #5
3120=brown eyed=q2
1680=black eyed=p2+2pq4800
3120=.65=q2
4800q2=.65q=.81
p=1-.81p=.19
p2 + 2pq + q2 = 1
.192+2(.19 x .81)+.812=1 .04 + .31 + .65 =1 BB Bb bb
Hardy-Weinberg Problems #64860=white=q2
1140=green=p2+2pq6000
4860=q2=.816000 q2=.81
q=.9
p=1-.9p=.1
p2 + 2pq + q2 = 1
.12+2(.1 x .9)+ .92=1
.01 + .18 + .81 =1
GG Gg gg
1 18 81 =100
2G’s 18g’s18G’s 20G’s20G’s 38genes
20=.53=p 18=.47=q38 38
p2 + 2pq + q2 = 1.532 +2(.53 X .47)+.472=1
.28 + .50 + .22 = 1
GG Gg gg .78
green
x
Hardy-Weinberg Problems #7 1600 weak-legged=q2
8400 strong-legged=p2 +2pq10,000
1600=q2=.1610,000
q2=.16q=.4
p=1-.4p=.6
p2 + 2pq + q2 = 1
.62+2(.6 X .4)+.42=1
.36 + .48 + .16 = 1 AA Aa aa
a. .4b. .6c. .36d. .48
Hardy-Weinberg Problems #8180=nude=q2
320=hairy=p2+2pq500
180=q2=.36500 q2=.36
q=.6
p=1-.6p=.4
p2 + 2pq + q2 = 1
.42+2(.4 x .6)+ .62=1
.16 + .48 + .36 =1
HH Hh hh
16x.5 48x.5 36 =100
8 24 3616H’s 24h’s 40H’s24H’s 72h’s 96h’s40H’s 96h’s 136genes
40=.29=p 96=.71=q136 136
p2 + 2pq + q2 = 1.292 +2(.29 X .71)+.712=1
.08 + .41 + .50 = 1
HH Hh hh .49
hairy
a. .4 e. .49b. .48c. .16d. .71
Hardy-Weinberg Problems #9 2400=normal=q2
12600=clumsy=p2+2pq15000
2400=q2=.1615000 q2=.16
q=.4
p=1-.4p=.6
p2 + 2pq + q2 = 1
.62+2(.6 x .4)+ .42=1
.36 + .48 + .16 =1
RR Rr rr 36X.25 48X.25 16
9 12 16
18R’s 12r’s 30R’s12R’s 32r’s 44r’s30R’s 44r’s 74genes
30=.41=p 44=.59=q74 74
p2 + 2pq + q2 = 1.412 +2(.41 X .59)+.592=1
.17 + .48 + .35 = 1
GG Gg gg .65
clumsy
a. .6 e. .48 i. .35b. .4 f. .59c. .36 g. .41d. 16 h. .65
Hardy-Weinberg Problems #10 720=dark=q2
49280=light=p2+2pq50000
720=q2=0.014450000 q2=.0144
q=.12
p=1-.12p=.88
p2 + 2pq + q2 = 1
.882+2(.88 x .12)+ .122=1
.774 + .21 + .0144 =1
RR Rr rr 774X.10 210X.10 14
77.4 21 14
155L’s 21l’s 176L’s 21L’s 28l’s 49l’s176L’s 49l’s 225genes
176=.78=p 49=.22=q225 225 1st gen.
p2 + 2pq + q2 = 1.782 + 2(.78 x .22)+ .222=1 .61 + .34 + .04 =1 RR Rr rr 61X.10 34X.10 4 6 3.4 4
12L’s 3.4l’s 15.4L’s 3.4L’s 8 l’s 11.4 l’s15.4L’s 11.4l’s 26.8genes
15.4=.57=p 11.4=.43=q26.8 26.8 2nd generation
Hardy-Weinberg Problems #10 cont.
p2 + 2pq + q2 = 1
.572+2(.57 x .43)+ .432=1
.32 + .49 + .19 =1
RR Rr rr 32X.1 49X.1 19
3.2 4.9 19
6.4L’s 4.9 l’s 11.3 L’s 4.9L’s 38 l’s 42.9 l’s11.3L’s 42.9l’s 54.1genes
3rd generation11.3=.21=p 42.9=.79=q54.1 54.1
p2 + 2pq + q2 = 1.212 + 2(.21 x .79)+ .792=1 .04 + .33 + .62 =1 RR Rr rr 4X.1 33X.1 62 .4 3.3 62
.8 L’s 3.3 l’s 4.1 L’s 3.3 L’s 62.0 l’s 65.3 l’s 4.1 L’s 65.3 l’s 56 genes
4th generation4.1=.06=p 25.3 =.94=q69.9 69.4
Hardy-Weinberg Problems #11 240=camou=q2
5760=solid=p2+2pq 6000
240=q2=0.046000 q2=.04
q=.2
p=1-.2p=.8
p2 + 2pq + q2 = 1
.82 + 2(.8 x .2) + .22 =1
.64 + .32 + .04 = 1
RR Rr rr 64X.1 32X.1 4
6.4 3.2 4
12.8L’s 3.2 l’s 16 L’s 3.2L’s 8 l’s 11.2 l’s16 L’s 11.2 l’s 27.2 genes
16=.59=p 11.2=.41=q27.2 27.2
p2 + 2pq + q2 = 1(.59)2 + 2(.59 x .41)+ (.41)2=1 .34 + .48 + .17 =.99 RR Rr rr
a. .8 e. .59 b. .2 f. .41c. .32 g. .34d. .64 h. .48
Hardy-Weinberg Problems #12 1200=total sample=p2+2pq+q2 - 27=sickle-cell=q2
1173=p2+2pq
q2=.0225q=.15
p=1- .15p=.85
p2 + 2pq + q2 = 1
.852 + 2(.85 x.15) + .152 =1
.7225 + .255 + .0225 = 1
AA Aa aa 722.5X.2 255 22.5
144.5 255 289A’s 255a’s 255A’s 544A’s 544A’s 799 genes
544=.68=p 255=.32=q799 799
p2 + 2pq + q2 = 1(.68)2 + 2(.68 x .32)+(.32)2=1 .46 + .44 + .10 =.99 AA Aa aa
a. .15b. .85c. .7225d. .255
27=q2=0.02251200
Xe. 68f. .32g. .46h. .44