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Harmonic oscillator force in heavy quarkonia
Kamil Serafin (University of Warsaw)
in collaboration withStanis law G lazek (U. Warsaw, Yale U.), Marıa Gomez-Rocha (ECT*),
Jai More (IIT Bombay),
arXiv: 1705.07629
The Charm and Beauty of Strong Interactions,Trento, Italy, 17th–28th July 2017
K. Serafin Harmonic oscillator force in heavy quarkonia
Outline
1 Renormalized Hamiltonian of QCD
2 Bound state problem in the Fock space and gluon mass ansatz
3 Effective QQ eigenvalue equation
4 Small-x divergences
5 Non-relativistic limit
6 Harmonic oscillator potential
K. Serafin Harmonic oscillator force in heavy quarkonia
Renormalized Hamiltonian of QCD
Outline
1 Renormalized Hamiltonian of QCD
2 Bound state problem in the Fock space and gluon mass ansatz
3 Effective QQ eigenvalue equation
4 Small-x divergences
5 Non-relativistic limit
6 Harmonic oscillator potential
K. Serafin Harmonic oscillator force in heavy quarkonia
Renormalized Hamiltonian of QCD
Front form of Hamiltonian dynamics
@@
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@@
-
x06
x3
���������x+
@@
@@@
@@@I
x−
x+ = x0 + x3
x− = x0 − x3
pµxµ =1
2p−x++
1
2p+x−−p1x1−p2x2 .
p− =m2 + (p⊥)2
p+,
P− =m2 + (p⊥)2
p++µ2 + (k⊥)2
k+
=M2(x , κ) + (P⊥)2
P+,
M2(x , κ) =m2 + κ2
1− x+µ2 + κ2
x,
x =k+
p+ + k+, κ⊥ =
p+k⊥ − k+p⊥
p+ + k+.
K. Serafin Harmonic oscillator force in heavy quarkonia
Renormalized Hamiltonian of QCD
Canonical FF Hamiltonian of QCD
Hcan =m2 + (k⊥1 )2
k+1
b†1b1 +m2 + (k⊥1 )2
k+1
d†1 d1 +(k⊥1 )2
k+1
a†1a1
+ g(δ21.3 t1
23 u2 6ε∗1u3 b†2a†1b3 − δ21.3 t132 v3 6ε∗1v2 d†2 a†1d3 + h.c .
)− g 2δ13.42
∑i5
t512t5
43
1
(k+5 )2
j+12 j+
43 b†1d†3 d4b2 + . . .
= E1
(b†1b1 + d†1 d1 + a†1a1
)+ g
(+ + h.c .
)+ g 2 + . . .
Canonical Hamiltonian is not well defined. We need to regularize it.
K. Serafin Harmonic oscillator force in heavy quarkonia
Renormalized Hamiltonian of QCD
Regularization I
We do not regularize fields but rather interactions.
H = E1
(b†1b1 + d†1 d1 + a†1a1
)+ g
(r21.3 + r21.3 + h.c .
)+ g 2rC 13.42 + . . .
For every quark operator in the interaction vertex we write a factor
e−m2+κ2
x∆2
and for every gluon operator in the vertex we write
e−δ2+κ2
x∆2 .
K. Serafin Harmonic oscillator force in heavy quarkonia
Renormalized Hamiltonian of QCD
Regularization II
r21.3 = e−
m2+κ22/3
x2/3∆2e−δ2+κ2
1/3
x1/3∆2e−
m2
∆2 = e−M2
21 δ+m2
∆2 ,
rC13.42 = θ(z) r25.1r35.4 + θ(−z) r45.3r15.2 ,
K. Serafin Harmonic oscillator force in heavy quarkonia
Renormalized Hamiltonian of QCD
Renormalization Group Procedure for Effective Particles I
∆
Ut-
Ht=s4
@@@@@@@@@@
@@@@@@@@@@
����
������
λ = s−1
Figure: Initial theory → effective theory. RGPEP introduces form factors intovertices, which narrow the Hamiltonian in free-states basis.
K. Serafin Harmonic oscillator force in heavy quarkonia
Renormalized Hamiltonian of QCD
Renormalization Group Procedure for Effective Particles II
The narrowing of the Hamiltonian is realized by the followingdifferential equation,
d
dtHt = [[Hf ,HPt ],Ht ] .
The generation of transformation Ut is therefore, different comparedto the one used in Phys.Rev. D69 (2004) 065002, it allows fornonperturbative calculations.
But before nonperturbative calculations will be performed we writeperturbative expansion of the solution first,
Ht = Hf + g Ht 1 + g 2 Ht 2 + . . .
K. Serafin Harmonic oscillator force in heavy quarkonia
Renormalized Hamiltonian of QCD
Renormalized Hamiltonian
H = E1
(b†1b1 + d†1 d1 + a†1a1
)+ g
(r21.3 + r21.3 + h.c .
)+ g 2rC 13.42 + . . .
K. Serafin Harmonic oscillator force in heavy quarkonia
Renormalized Hamiltonian of QCD
Renormalized Hamiltonian
Ht = E1
(b†1 tb1 t + d†1 td1 t + a†1 ta1 t
)+ g
(r21.3 + r21.3 + h.c .
)+ g 2rC 13.42
K. Serafin Harmonic oscillator force in heavy quarkonia
Renormalized Hamiltonian of QCD
Renormalized Hamiltonian
Ht = E1
(b†1 tb1 t + d†1 td1 t + a†1 ta1 t
)+ g
(r21.3ft 21.3 + r21.3ft 21.3 + h.c .
)+ g 2rC 13.42
K. Serafin Harmonic oscillator force in heavy quarkonia
Renormalized Hamiltonian of QCD
Renormalized Hamiltonian
Ht = E1
(b†1 tb1 t + d†1 td1 t + a†1 ta1 t
)+ g
(r21.3ft 21.3 + r21.3ft 21.3 + h.c .
)+ g 2rC 13.42ft 13.24
ft 21.3 = e−t(M221−m
2)2
, ft 13.24 = e−t(M213−M
224)2
,
K. Serafin Harmonic oscillator force in heavy quarkonia
Renormalized Hamiltonian of QCD
Renormalized Hamiltonian
Ht = E1
(b†1 tb1 t + d†1 td1 t + a†1 ta1 t
)+ g
(r21.3ft 21.3 + r21.3ft 21.3 + h.c .
)+ g 2rC 13.42ft 13.24
+ g 2r25.1r35.4F Z + g 2r45.3r15.2FZ
ft 21.3 = e−t(M221−m
2)2
, ft 13.24 = e−t(M213−M
224)2
,
K. Serafin Harmonic oscillator force in heavy quarkonia
Renormalized Hamiltonian of QCD
Renormalized Hamiltonian
Ht = E1
(b†1 tb1 t + d†1 td1 t + a†1 ta1 t
)+ g
(r21.3ft 21.3 + r21.3ft 21.3 + h.c .
)+ g 2rC 13.42ft 13.24
+ g 2r25.1r35.4F Z + g 2r45.3r15.2FZ
+ g 2 +
ft 21.3 = e−t(M221−m
2)2
, ft 13.24 = e−t(M213−M
224)2
,
K. Serafin Harmonic oscillator force in heavy quarkonia
Renormalized Hamiltonian of QCD
Renormalized Hamiltonian* I
Mass termsThe quark mass term in Ht2 consists of effective part,
(HmQ t)1.2 =4
3δc1c2 δ1.2
∫[56]k+
1 δ56.1 r 265.1
f 2t 65.1 − 1
M256 −m2
∑σ6
dµν jµ16jν62 ,
and the UV counterterm (which cancels divergence of HmQ t coming fromκ→∞),
(H∗mQ)1.2 =4
3δc1c2 δ1.2
∫[56]k+
2 δ56.2 r65.1r65.21
M256 −m2
∑σ6
dµν jµ16jν62 ,
However, small-x divergences remain,
HmQ t ∼√
2π
tlog
∆
δ.
Analogous expressions can be written for antiquark mass term.
K. Serafin Harmonic oscillator force in heavy quarkonia
Renormalized Hamiltonian of QCD
Renormalized Hamiltonian* II
Four-body vertex interaction termThe exchange part of Ht 2 consists of the term derived frominstantaneous interactions in the initial Hamiltonian,
(HC QQ t)13.42 = C13.42 rC13.42 = − δ13.42
∑i5
t512t5
43
1
(k+5 )2
j+12 j+
43 rC13.42 ,
and term derived from products of first order initial Hamiltonian vertices,
(HX QQ t)13.42 = − δ13.42
∑i5
t512t5
43
dµν(k5)
k+5
jµ12 jν43
× [θ(z)F Zr25.1r35.4 + θ(−z)FZ r45.3r15.2] ,
F Z =k+
1 (m2 −M252) + k+
4 (m2 −M253)
(m2 −M252)2 + (m2 −M2
53)2 − (M213 −M2
42)2
(1− f25.1f35.4
f13.42
),
FZ =k+
3 (m2 −M254) + k+
2 (m2 −M251)
(m2 −M254)2 + (m2 −M2
51)2 − (M213 −M2
42)2
(1− f15.2f45.3
f13.42
).
K. Serafin Harmonic oscillator force in heavy quarkonia
Bound state problem in the Fock space and gluon mass ansatz
Outline
1 Renormalized Hamiltonian of QCD
2 Bound state problem in the Fock space and gluon mass ansatz
3 Effective QQ eigenvalue equation
4 Small-x divergences
5 Non-relativistic limit
6 Harmonic oscillator potential
K. Serafin Harmonic oscillator force in heavy quarkonia
Bound state problem in the Fock space and gluon mass ansatz
Bound state problem in the Fock space
Structure of the eigenvalue problem
|Ψmeson〉 = |QtQt〉+ |QtQtGt〉+ |QtQtGtGt〉+ ... .
Ht |Ψmeson〉 =
... ... ...... Hf + g 2Ht 2 gHt 1
... gHt 1 Hf + g 2Ht 2
...|QtQtGt〉|QtQt〉
= Emeson
...|QtQtGt〉|QtQt〉
,
K. Serafin Harmonic oscillator force in heavy quarkonia
Bound state problem in the Fock space and gluon mass ansatz
Eigenvalue problem with gluon mass ansatz
Introducing the gluon mass terms to model effects of dotted componentsand interactions, one obtains the corresponding approximate eigenvalueproblem,
H|Ψmeson〉 =
[Hf + µ2 gH1
gH1 Hf + g 2H2
] [|QQG 〉|QQ〉
]= Emeson
[|QQG 〉|QQ〉
],
where µ2 denotes the mass-like operators for gluon in the QQG sector.
µ2 ∼∫
5
µ2(x5, κ5)
k+5
a†5a5 .
K. Serafin Harmonic oscillator force in heavy quarkonia
Effective QQ eigenvalue equation
Reduction to the lowest Fock sector I
Reduction of the space is performed using operation R,
|QQG 〉 = R|QQ〉 .
The general formula for effective Hamiltonian in a subspace of states isthen
Heff =1√
P + R†R(P + R†)H(P + R)
1√P + R†R
.
Perturbative evaluation of the 2nd-order effective Hamiltonian for thelowest component gives
Heff = Hf + g 2H2 +g 2
2H1
(1
El − Hf − µ2+
1
El′ − Hf − µ2
)H1 .
K. Serafin Harmonic oscillator force in heavy quarkonia
Effective QQ eigenvalue equation
Effective QQ eigenvalue equation I
After reduction to QQ sector, the effective eigenvalue equation is
Ht eff|ψQQt〉 =M2 + P⊥2
P+|ψQQt〉 ,
or
(P+ Ht eff − P⊥2)|ψQQt〉 = M2|ψQQt〉 .
The eigenvalue is mass squared instead of mass or the binding energy.
K. Serafin Harmonic oscillator force in heavy quarkonia
Effective QQ eigenvalue equation
Effective QQ eigenvalue equation II
For the color singlet states we define the QQ wave function in thefollowing manner,
|ψQQt〉 =∑c2c4
∑σ2σ4
∫[24] P+ δ(P − k2 − k4)
δc2c4√3ψσ2σ4 (κ⊥24, x2) b†2td
†4t |0〉 .
Therefore, the eigenvalue equation becomes,
(κ⊥2
13 + M21, t
x1+κ⊥2
13 + M23, t
x3−M2
)ψ13(κ⊥13, x1)
+ g 2
∫[x2κ
⊥24] Ut eff(13, 24)ψ24(κ⊥24, x2) = 0 ,
K. Serafin Harmonic oscillator force in heavy quarkonia
Effective QQ eigenvalue equation
Effective QQ eigenvalue equation III
M21, t = m2 +
4
3g 2
∫[x κ] r 2
65.1 f 2t 65.1
×∑σ6
dµν(k5) jµ16 jν62
(1
m2 −M2− 1
m2 −M2µ
),
M23, t =
The subscript µ in M2µ indicates that the gluon has an effective mass.
K. Serafin Harmonic oscillator force in heavy quarkonia
Effective QQ eigenvalue equation
Effective QQ eigenvalue equation IV
The interaction potential Ut eff(13, 24) contains FF instantaneousinteractions, gluon-exchange terms and counterterms:
Ut eff = HC + Hexch + H∗C ,
The effective instantaneous vertex acquires only a form factor,
HC = − 4
3rC13.24 ft 13.24
j+12 j+
43
(x1 − x2)2,
K. Serafin Harmonic oscillator force in heavy quarkonia
Effective QQ eigenvalue equation
Effective QQ eigenvalue equation V
Hexch = − 4
3dµν(k5) jµ12 jν43
×(θ(x1 − x2)
k+5
r25.1r35.4 F Z+θ(x2 − x1)
k+5
r15.2r45.3 FZ
),
F Z= ft 13.24 F Z+ ft 4.53 ft 1.52R Z,
FZ = ft 13.24 FZ + ft 3.54 ft 2.51RZ ,
K. Serafin Harmonic oscillator force in heavy quarkonia
Effective QQ eigenvalue equation
Effective QQ eigenvalue equation VI
F Z =
(1− ft 1.52ft 4.53
ft 13.24
)k+
1 (m2 −M225) + k+
4 (m2 −M235)
(m2 −M225)2 + (m2 −M2
35)2 − (M213 −M2
24)2,
R Z =1
2
(k+
1
m2 −M225 −
x1
x5µ2
253
+k+
4
m2 −M253 −
x4
x5µ2
253
),
µ2253 is an ansatz for the gluon-mass function. It depends on relative
motion of gluon, 5, with respect to quark, 2, and antiquark, 3, in theintermediate state.
K. Serafin Harmonic oscillator force in heavy quarkonia
Small-x divergences
Outline
1 Renormalized Hamiltonian of QCD
2 Bound state problem in the Fock space and gluon mass ansatz
3 Effective QQ eigenvalue equation
4 Small-x divergences
5 Non-relativistic limit
6 Harmonic oscillator potential
K. Serafin Harmonic oscillator force in heavy quarkonia
Small-x divergences
Small-x divergences I
Because quantization plane is tangent to a light, cone masslessparticles can travel in one direction instantaneously. This producesdivergences.
For example, the gluon propagator dµν contains regular part andsingular part in gluon momentum,
dµν(k5) = −gµν +nµk5 ν + nνk5µ
k+5
.
Instantaneous interaction term,
HC = − 4
3rC13.24 ft 13.24
j+12 j+
43
x25
.
Mass terms and exchange terms are divergent in the integrationregion where x5 = 0 and κ⊥5 = 0.
When µ = 0 it was early found out that divergences cancel.
K. Serafin Harmonic oscillator force in heavy quarkonia
Small-x divergences
Small-x divergences II
Terms arising from µ 6= 0 need to be regulated by µ so that everyterm in the eigenvalue problem is finite when regularization isremoved.
Mass terms are easier to analyze. The divergent integral is∫[xκ]r 2
65.1f 265.1
µ2
x
M2µ −m2
4
x.
The form factor regulates the UV behavior but not the small-x, orlarge volume, behavior.
However, if µ2 ∼ x1+δµ ∼ κ2xδµ , then the integral is finite.
For exchange terms we study parts with low- and high-energyexchange separately.
Ut eff = Uhigh + Ulow + Ug
= ∼ (1− ff )+ ∼ ff + ∼ gµν .
K. Serafin Harmonic oscillator force in heavy quarkonia
Small-x divergences
Small-x divergences III
Low-energy exchange terms are those whose UV behavior isregulated by form factors (in a similar way as in the mass terms).
Again, the large volume or small-x behavior is not regulated by formfactors, but by the gluon mass function.
The same µ2 regulates both mass terms and the low-energyexchange terms.
The high-energy exchange terms do not contain µ2, but do not leadto divergences in the limit δ → 0.
K. Serafin Harmonic oscillator force in heavy quarkonia
Small-x divergences
One quark eigenvalue problem
Proper gluon mass ansatz gives well defined, finite, eigenvalueequation for color singlet QQ states.
One can apply similar reasoning to the eigenproblem of a singlequark, where the gluon mass ansatz may be different.
Ht |Ψquark〉 =
[Hf t + µ2
q gH1 t
gH1 t Hf t + g 2H2 t
] [|QtGt〉|Qt〉
]= Equark
[|QtGt〉|Qt〉
].
The gluon mass ansatz in this problem can be chosen in such a waythat the eigenproblem is divergent.
This is a possibility how confinement could be understood.
K. Serafin Harmonic oscillator force in heavy quarkonia
Non-relativistic limit
Outline
1 Renormalized Hamiltonian of QCD
2 Bound state problem in the Fock space and gluon mass ansatz
3 Effective QQ eigenvalue equation
4 Small-x divergences
5 Non-relativistic limit
6 Harmonic oscillator potential
K. Serafin Harmonic oscillator force in heavy quarkonia
Non-relativistic limit
Non-relativistic limit I
Well defined, finite, eigenproblem for QQ – done.
Heavy quarks in quarkonia are expected to move slowly so that onecan adopt non-relativistic approximation.
We define non-relativistic relative momenta of quarks,
k⊥ij =1
2
κ⊥ij√xixj
, k3ij =
m√
xixj
(xi −
1
2
).
where ij = 13 or ij = 24, and momentum transfer,
~q = ~k13 − ~k24 .
Formally, the non-relativistic limit means that the quark mass goesto infinity, or ~kij/m→ 0.
M2 = (2m + B)2 ≈ 4m2 + 4mB.
K. Serafin Harmonic oscillator force in heavy quarkonia
Non-relativistic limit
Non-relativistic limit II
Performing the limit we obtain familiar looking Schrodinger equation,[|~k13|2
m− B +
δm21, t
2m+δm2
3, t
2m
]ψ13(~k13)
+
∫d3~k24
(2π)3VQQ(~k13 − ~k24)ψ24(~k24) = 0 ,
where
δm2i, t
2m= lim
m→∞
δM2i, t
2m,
VQQ(~k13 − ~k24) = g 2 limm→∞
[1
4m2Ut eff(13, 24)
].
K. Serafin Harmonic oscillator force in heavy quarkonia
Non-relativistic limit
Non-relativistic limit III
If the gluon mass ansatz was zero, the exchange term in thenon-relativistic limit would give only Coulomb potential coming fromthe non-singular part of the gluon propagator (Ug ),
VQQ(~q) = −4
3
4πα
|~q|2f13.24 (for µ = 0) .
The Coulomb term is modified by the form factor f13.24.The interaction becomes non-local and the effect is visible fordistances . s −→ the effective particles have nonzero size!
K. Serafin Harmonic oscillator force in heavy quarkonia
Harmonic oscillator potential
Outline
1 Renormalized Hamiltonian of QCD
2 Bound state problem in the Fock space and gluon mass ansatz
3 Effective QQ eigenvalue equation
4 Small-x divergences
5 Non-relativistic limit
6 Harmonic oscillator potential
K. Serafin Harmonic oscillator force in heavy quarkonia
Harmonic oscillator potential
Harmonic oscillator potential I
For nonzero gluon mass ansatz we have∫d3q
(2π)3VQQ(~q)ψ(~k − ~q) =
∫d3q
(2π)3[VC (~q) + W (~q)]ψ(~k − ~q) .
where
W (~q ) =4
34πα
[1
~q 2− 1
q2z
]×
(θ(z)
µ2253
µ2253 + ~q 2
+ θ(−z)µ2
154
µ2154 + ~q 2
)e−2m2 |~q2|2
q2z
t.
K. Serafin Harmonic oscillator force in heavy quarkonia
Harmonic oscillator potential
Harmonic oscillator potential II
Similarly, the self-energy terms can also be expressed in terms of W ,
δm2i t
mψ(~k) = −
∫d3q
(2π)3W (~q)ψ(~k) .
Self-energy terms and effective exchange of gluons combine together,
δm21 t
2mψ(~k) +
δm23 t
2mψ(~k) +
∫d3q
(2π)3W (~q)ψ(~k − ~q)
=
∫d3q
(2π)3W (~q)
[ψ(~k − ~q)− ψ(~k)
].
Taylor expanding the wave function
ψ(~k − ~q) = ψ(~k)− qi∂
∂kiψ(~k) +
1
2qiqj
∂2
∂ki∂kjψ(~k) + . . .
K. Serafin Harmonic oscillator force in heavy quarkonia
Harmonic oscillator potential
Harmonic oscillator potential III
we find the net effect of effective self-energy and effective exchangeto be harmonic oscillator force:∫
d3q
(2π)3W (~q)
1
2(qi )
2 ∂2
∂k2i
ψ(~k) .
Finally, [~k2
m− B
]ψ(~k) +
∫d3q
(2π)3VC ,BF (~q)ψ(~k − ~q)
− 4
3
α
2πb−3
∑i
τi∂2
∂k2i
ψ(~k) = 0 .
The frequencies of harmonic oscillators in transverse and longitudinaldirections should be the same to recover rotational invariance. Thiscan also be achieved using appropriate gluon mass ansatz function.
K. Serafin Harmonic oscillator force in heavy quarkonia
Harmonic oscillator potential
Harmonic oscillator potential IV
In particular, almost constant and large enough µ2 will giveτ1 = τ2 = τ3 =
√π/4.
~τ =
∫ 1
0
dv v(1− v 2)
1− v 2
1− v 2
2v 2
τ(v)
τ(v) =
∫ ∞0
du u2 e−u2
[1 +
u2 v 2
2 (m s)2 (µ s)2
]−1
,
Therefore, the final result could be written in the following way[~k 2
m− 1
2κ∆~k − B
]ψ(~k) +
∫d3q
(2π)3VC ,BF (~q)ψ(~k − ~q) = 0 ,
κ =m
2ω2 =
α
(ms2)3
1
36√
2π.
K. Serafin Harmonic oscillator force in heavy quarkonia
Harmonic oscillator potential
Phenomenological fit of parameters I
Below are the results of numerical calculation obtained by S. G lazekand J. M lynik using the old generator of RGPEP and oldnonrelativistic variables. (Phys. Rev. D 74, 105015 (2006))
K. Serafin Harmonic oscillator force in heavy quarkonia
Harmonic oscillator potential
Phenomenological fit of parameters II
K. Serafin Harmonic oscillator force in heavy quarkonia
Harmonic oscillator potential
Phenomenological fit of parameters III
K. Serafin Harmonic oscillator force in heavy quarkonia
Harmonic oscillator potential
Phenomenological fit of parameters IV
K. Serafin Harmonic oscillator force in heavy quarkonia
Harmonic oscillator potential
Summary
RGPEP together with gluon mass ansatz gives Coulomb force plusharmonic oscillator force between quarks.
Without gluon mass ansatz one is left with only Coulomb potential(like QED, except of color factor 4/3).
Energy of a single quark is infinite.
In the QQ system the harmonic oscillator force arises as an effect ofcancellation between effective mass terms of quarks and antiquark,and an exchange of effective gluon.
The resultant harmonic oscillator is the same as obtained earlierusing different RGPEP generator and different non-relativisticmomentum variables.
K. Serafin Harmonic oscillator force in heavy quarkonia
Harmonic oscillator potential
Outlook
Analysis of Breit-Fermi terms in the new non-relativistic variables.
Numerical calculation including different masses of quarks.
However, the most desired course of study is 4th-order calculation.
Will give precise form of spin dependent interactions.Gluon mass ansatz will be replaced by true QCD effects.
New generator allows for nonperturbative calculations, e.g., of gluonmass.
Also, harmonic oscillator in baryons.
K. Serafin Harmonic oscillator force in heavy quarkonia