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HAWKES LEARNING SYSTEMS math courseware specialists Copyright © 2010 Hawkes Learning Systems. All rights reserved. Hawkes Learning Systems: College Algebra Section 2.1a: Linear Equations in One Variable

Hawkes Learning Systems: College Algebra

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Hawkes Learning Systems: College Algebra. Section 2.1a: Linear Equations in One Variable. Objectives. Equivalent equations and the meaning of solutions. Solving linear equations. Solving absolute value equations. Equations and the Meaning of Solutions. - PowerPoint PPT Presentation

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Page 1: Hawkes  Learning Systems: College Algebra

HAWKES LEARNING SYSTEMS

math courseware specialists

Copyright © 2010 Hawkes Learning Systems. All rights reserved.

Hawkes Learning Systems:College Algebra

Section 2.1a: Linear Equations in One Variable

Page 2: Hawkes  Learning Systems: College Algebra

HAWKES LEARNING SYSTEMS

math courseware specialists

Copyright © 2010 Hawkes Learning Systems. All rights reserved.

Objectives

o Equivalent equations and the meaning of solutions.o Solving linear equations. o Solving absolute value equations.

Page 3: Hawkes  Learning Systems: College Algebra

HAWKES LEARNING SYSTEMS

math courseware specialists

Copyright © 2010 Hawkes Learning Systems. All rights reserved.

Equations and the Meaning of Solutions

o An equation is a statement that two algebraic expressions are equal.

o To solve an equation means to find the solution(s): value(s) of the variable that make the equation true.

o The set of all such values is called the solution set.

Page 4: Hawkes  Learning Systems: College Algebra

HAWKES LEARNING SYSTEMS

math courseware specialists

Copyright © 2010 Hawkes Learning Systems. All rights reserved.

Types of Equations

There are three types of equations:

1. A conditional equation has a countable number of solutions. For example, x + 7 = 12

has one solution, 5. The solution set is {5}.

2. An identity is true for all real numbers and has an infinite number of solutions. For example,

is true for all real number values of . The solution set is R.

3. A contradiction is never true and has no solution. For example, is false for any value of . The solution set is Ø.

x6x x

x

2( 1)x x x x

Page 5: Hawkes  Learning Systems: College Algebra

HAWKES LEARNING SYSTEMS

math courseware specialists

Copyright © 2010 Hawkes Learning Systems. All rights reserved.

Linear Equations in One Variable

A linear equation in one variable, such as the variable , is an equation that can be transformed into the form,

where and are real numbers and . Such equations are also called first-degree equations, as appears to the first power.

x

0ax b

a b 0a

x

Page 6: Hawkes  Learning Systems: College Algebra

HAWKES LEARNING SYSTEMS

math courseware specialists

Copyright © 2010 Hawkes Learning Systems. All rights reserved.

Linear Equations and Equivalent Equations

o We solve linear equations by performing the same operations on both sides of the equation.

o This results in simpler equivalent equations that are easier to solve and have the same solution.

Page 7: Hawkes  Learning Systems: College Algebra

HAWKES LEARNING SYSTEMS

math courseware specialists

Copyright © 2010 Hawkes Learning Systems. All rights reserved.

Solving Linear Equations

To solve a linear equation (in x): 1. Simplify each side of the equation separately by

removing any grouping symbols and combining like terms. 2. Add or subtract the same expression(s) on both sides of the

equation in order to get the variable term(s) on one side and the constant term(s) on the other side of the equation and simplify.

3. Multiply or divide by the same nonzero quantity on both sides of the equation in order to get the numerical coefficient of the variable term to be one.

4. Check your answer by substitution in the original equation.

Page 8: Hawkes  Learning Systems: College Algebra

HAWKES LEARNING SYSTEMS

math courseware specialists

Copyright © 2010 Hawkes Learning Systems. All rights reserved.

Example: Solving Linear Equations

Step 1: Simplify

Step 2: Add or Subtract

Step 3: Multiply or Divide

3 5 4 7x x x

3 5 5 7x x

12 2x

6 x

Solve:

Page 9: Hawkes  Learning Systems: College Algebra

HAWKES LEARNING SYSTEMS

math courseware specialists

Copyright © 2010 Hawkes Learning Systems. All rights reserved.

Example: Solving Linear Equations

The solution set is R.

2( 7) 14x x x

2 14 14x x x

Solve:

Page 10: Hawkes  Learning Systems: College Algebra

HAWKES LEARNING SYSTEMS

math courseware specialists

Copyright © 2010 Hawkes Learning Systems. All rights reserved.

Example: Solving Linear Equations

The solution set is R.

6 7 22 12 8

4 8 8

y y Solve:

Page 11: Hawkes  Learning Systems: College Algebra

HAWKES LEARNING SYSTEMS

math courseware specialists

Copyright © 2010 Hawkes Learning Systems. All rights reserved.

Example: Solving Linear Equations

No Solution

0.03 0.67( 5) 0.7 3.44w w w

0.03 0.67 3.35 0.7 3.44w w w

0.7 3.35 0.7 3.44w w

Solve:

The solution set is Ø.

Page 12: Hawkes  Learning Systems: College Algebra

HAWKES LEARNING SYSTEMS

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Copyright © 2010 Hawkes Learning Systems. All rights reserved.

Example: Solving Linear EquationsSolve.

Page 13: Hawkes  Learning Systems: College Algebra

HAWKES LEARNING SYSTEMS

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Copyright © 2010 Hawkes Learning Systems. All rights reserved.

Solving Absolute Value Equations

The absolute value of any quantity is either the original quantity or its negative (opposite). This means that, in general, every occurrence of an absolute value term in an equation leads to two equations with the absolute value signs removed, if c > 0. Note: if c < 0, it has no solution.

ax b c means

ax b c or ax + b = -c

Page 14: Hawkes  Learning Systems: College Algebra

HAWKES LEARNING SYSTEMS

math courseware specialists

Copyright © 2010 Hawkes Learning Systems. All rights reserved.

Example: Solving Absolute Value Equations

Step 1: Rewrite the absolute value equation without absolute values.

3 2 5x

3 2 5x

3 7x

7

3x 1x

Step 2: Solve the two equations

or 3x – 2 = -5

or 3x = -3

or

Solve:

Page 15: Hawkes  Learning Systems: College Algebra

HAWKES LEARNING SYSTEMS

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Copyright © 2010 Hawkes Learning Systems. All rights reserved.

Example: Absolute Value Equations

4 3 2 0x Solve:

|4x + 3| = -2 False, absolute value is never negative. No solution; the solution set is Ø.

Solve: |6x – 2| = 06x – 2 = 06x = 2x = ⅓

If |ax + b| = 0, then ax + b = 0.

Page 16: Hawkes  Learning Systems: College Algebra

HAWKES LEARNING SYSTEMS

math courseware specialists

Copyright © 2010 Hawkes Learning Systems. All rights reserved.

Example: Absolute Value EquationsSolve.

|x – 4| = |2x + 1|